ok and again i just dont understand well so this is why i am asking so many times and u guys and girls are getting alot of points

Step-by-step explanation:

jkkkkkkkkkkkkkkkkkkkkk

Answer:

[tex]2 \sqrt{35} [/tex]

Answer:

The answer in each numeral is:

Step-by-step explanation:

To obtain the result in each case, you must replace the variable (n) by the value that appears in the second case, I'll explain it with the first exercise:

As you can see, in the second doesn't appear f(n), but f(4), that means you must replace the "n" in the equation by 4, if we do this, we obtain:

The first answer is 28, now we'll continue with the next exercises:

In this form, you can prove the answers are: 28, -19, -33, and -9 respectively.

Answer:

the answer to this question is 36.86989°

Answer:  a+b+c/3

Step-by-step explanation:

mean= sum of all values/number of values

Answer:

cscθ = 5/4, secθ = 5/3

Step-by-step explanation:

First, let's view the drawing that I have attached, with the dot in the bottom left representing the origin. We know that cosecant and secant are the reciprocals of sin and cos respectively, and in order to find sin and cos, we must find the opposite, adjacent, and hypotenuse sides. The hypotenuse is opposite the right angle, equal to √(8²+6²) = 10

Next, we can find sin and cos of θ . sinθ = 8/10=4/5, making cscθ the reciprocal of 4/5, or 5/4

Similarly, cosθ = 6/10=3/5, and secθ = 5/3

Answer:

Option A:

x^2 + (y - 2)^2 = 9

Step-by-step explanation:

We know that the equation for a circle centered in the point (a, b) and of radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

So the first thing we need to find is the center of the circle.

We can see that the center is at:

x = 0

y = 2

Then the center is at the point (0, 2)

Now we want our circle to pass through point 2, located at a distance of 2 units from the radius of the first circle.

So the distance between the center and point 2 is 2 units plus the radius of the smaller circle:

And the radius of the smaller circle is one unit.

Then, the radius of a circle centered at (0, 2) that passes through point 2 is:

R = 1 + 2 = 3

Then we have a circle centered at (0, 2) and of radius R = 3

Replacing these in the equation for a circle we get:

(x - 0)^2 + (y - 2)^2 = 3^2

x^2 + (y - 2)^2 = 9

The correct option is A

Answer:

Set of alternative optimal solution : 0 ≤ z ≤ 1.5

Hence There will be an infinite set of Alternative optimal solution

Step-by-step explanation:

considering Cx1 = 4

∴ C = 4 / x1

Cx2 = 6

∴ 4x2 - 6x1  = 0

2x2 - 3x1 = 0 ------ ( 1 )

considering Cx3 = 6

C = 6/x3

Cx4 = 3

∴ (6/x3) x4 - 3 = 0

= 2x4 - x3 = 0 ---- ( 2 )

attached below is the remaining part of the solution

set of alternative optimal solution : 0 ≤ z ≤ 1.5

There will be an infinite set of Alternative optimal solution

Answer:

C. 47 deg

Step-by-step explanation:

m<A = 180 - 94 - 39 = 47

m<D = m<A = 47

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph that includes the point (1, 3) will be the one that is a graph of ...

  y = 3^x

Answer:

D. 56

Step-by-step explanation:

The general solution for the number of combinations with repetition is represented by the following expression:

[tex]x = \frac{(n + r - 1)!}{r!\cdot (n-1)!}[/tex] (1)

Where:

[tex]n[/tex] - Total number of elements.

[tex]r[/tex] - Number of the sample.

If we know that [tex]n = 6[/tex] and [tex]r = 3[/tex], then the number of combinations with repetition:

[tex]x = \frac{(6+3-1)!}{3!\cdot (6-1)!}[/tex]

[tex]x = 56[/tex]

Hence, correct answer is D.

Answer:

x=6

Step-by-step explanation:

Answer:

Interval Notation:

(6,∞)

Inequality Form:

x>6

there ya go

Answer:

8xy+12y/5

Step-by-step explanation:

write the division as a fraction

4(2x+3)/5 y

Calaucte the product

4y(2x+3)/5

Distbtute 4y through the parentheis  

8xy+12y/5

which gives you 8xy+12y/5

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Pick a point (such as K, L, or M). Count one grid square to the left and 7 up. That is its new location.

Answer:

hope it helps you..........

Answer:

[tex]CV=0.2[/tex] ---- dataset 1

[tex]CV = 7.2[/tex] --- dataset 2

Step-by-step explanation:

Given

[tex]A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,[/tex][tex]33100[/tex]

[tex]B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11[/tex]

Required

The coefficient of variation of each

Dataset A

Calculate the mean

[tex]\mu = \frac{\sum x}{n}[/tex]

[tex]\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}[/tex][tex]\mu = \frac{418900}{14}[/tex]

[tex]\mu = 29921.43[/tex]

Next, calculate the standard deviation using:

[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]

So, we have:

[tex]\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}[/tex]

[tex]\sigma= \sqrt{\frac{487723571.42857}{14}}[/tex]

[tex]\sigma= \sqrt{34837397.959184}[/tex]

[tex]\sigma= 5902.32[/tex]

So, the coefficient of variation is:

[tex]CV=\frac{\sigma}{\mu}[/tex]

[tex]CV=\frac{5902.32}{29921.43}[/tex]

[tex]CV=0.2[/tex] --- approximated

Dataset B

Calculate the mean

[tex]\mu = \frac{\sum x}{n}[/tex]

[tex]\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}[/tex]

[tex]\mu = \frac{46.79}{11}[/tex]

[tex]\mu = 4.25[/tex]

Next, calculate the standard deviation using:

[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]

[tex]\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}[/tex]

[tex]\sigma = \sqrt{\frac{3.859}{11}}[/tex]

[tex]\sigma = \sqrt{0.35081818181}[/tex]

[tex]\sigma = 0.593[/tex]

So, the coefficient of variation is:

[tex]CV=\frac{\sigma}{\mu}[/tex]

[tex]CV = \frac{4.25}{0.5903}[/tex]

[tex]CV = 7.2[/tex] -- approximated

Answer: 22

Step-by-step explanation: 44:2=22

Answer:

B

Step-by-step explanation:

I'm not really shure tho

Answer:

D. -0.5

Step-by-step explanation:

AB dilated by scale factor -0.5 to produce AB'.

the length of AB = 4 units and the length of AB' = 2 units, the direction is backward, so the scale factor is - 2/4 = -0.5

Answer:

Step-by-step explanation:

Answer:

y=(x/2)+5

Step-by-step explanation:

Slope-intercept form is y=mx+b where m is the slope and b is the y-intercept form. To get that, we need y by itself so we have to add 3x to both sides: 6y=30+3x. Now we divide by 6 and rearrange the right side: y=(3x+30)/6.

y = (3x/6)+(30/6) => y = (x/2)+5. We also know that the slope is 1/2 and the y-intercept is 5 because of the slope-intercept equation.

Answer:

19.01%

Step-by- step explanation:

[tex]Percentage = \frac{1.35 billion }{ 7.1 billion } \times 100[/tex]

                [tex]= \frac{ 1.35 \ times 1, 000, 000, 000} {7.1 \times 1,000,000,000} \times 100\\\\\\=\frac{1.35}{7.1} \times 100 = 19.01 \%[/tex]

Answer:

(a)=50%(b)=2.1and(c)=16.1

Step-by-step explanation:

Hope this helps

Answer:

[tex]=280[/tex] [tex]in^2[/tex]

Step-by-step explanation:

----------------------------------------

Let's find the surface area of the pink rectangular prism first.

[tex]2*10=20+20=40[/tex]

[tex]4*10=40+40=80[/tex]

[tex]4*2=8+8=16[/tex]

[tex]40+80+16=136[/tex]

The surface area for the pink rectangular prism is [tex]136[/tex] [tex]in^2[/tex].

-------------------->>>>>

Now, let's find the surface area of the green rectangular prism.

[tex]4*7=28+28=56[/tex]

[tex]4*7=28+28=56[/tex]

[tex]4*4=16+16=32[/tex]

[tex]56+56+32=144[/tex]

The surface area for the green rectangular prism is 144 [tex]in^2[/tex].

-------------------->>>>>

Now let's add the surface area of both rectangular prisms to find the surface area of the composite figure.

[tex]136+144=[/tex]

[tex]=280[/tex] [tex]in^2[/tex]

----------------------------------------

Hope this is helpful.

9514 1404 393

Answer:

  224 in²

Step-by-step explanation:

There are a couple of ways to go at this. Here, we choose to figure the areas of each of the prisms individually, then subtract the "hidden" area where they are joined together.

The area of a prism is ...

  A = 2(LW +H(L+W))

Pink area:

  A = 2(10·4 +2(10+4)) = 2(40 +28) = 136 . . . square inches

Green area:

  A = 2(7·4 +4(7+4)) = 2(28 +44) = 144 . . . square inches

One 4 in × 7 in face of the green prism meets with a similar area of the pink prism, so the area hidden at that interface is 2(4·7) = 56 square inches. Then the total surface area of the composite figure is ...

  SA = 136 in² +144 in² -56 in² = 224 in²

Answer:

0.8 you yes both of them has the same answer , so it is a true portion

Step-by-step explanation:

Answer:

Yes.

Step-by-step explanation:

[tex]\frac{4}{5} =\frac{48}{60}[/tex]

This is a true proportion because when you cross multiply you get the same product.

[tex]48*5=240[/tex]

[tex]4*60=240[/tex]

Answer:

15 gallons of milk at 3 week

15/3= 5

for a month 5 * 4 =20

in a year 12 * 20 = 240

Step-by-step explanation:

Answer:

[tex]m =-4[/tex]

Step-by-step explanation:

Given

[tex]p(m-3 , -6) = p(-7 , -6)[/tex]

Required

Find m

[tex]p(m-3 , -6) = p(-7 , -6)[/tex]

By comparison:

[tex]m-3 = -7[/tex]

Add 3 to both sides

[tex]m = -7+3[/tex]

[tex]m =-4[/tex]

Answer:B

Step-by-step explanation:

This is the only possible answer trust me

Answer:

[tex]\tan{\theta} = \frac{\sqrt{11}}{11}[/tex]

Step-by-step explanation:

Cosecant:

The cosecant is one divided by the sine. Thus:

[tex]\csc{\theta} = \frac{1}{\sin{\theta}}[/tex]

Tangent is sine divided by cosine, so we first find the sine, then the cosine, to find the tangent.

Sine and cosine:

[tex]\sin{\theta} = \frac{1}{\csc{\theta}} = \frac{1}{2\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{6}[/tex]

[tex]\sin^{2}{\theta} + \cos^{2}{\theta} = 1[/tex]

[tex]\cos^{2}{\theta} = 1 - \sin^{2}{\theta}[/tex]

[tex]\cos^{2}{\theta} = 1 - (\frac{\sqrt{3}}{6})^2[/tex]

[tex]\cos^{2}{\theta} = 1 - \frac{3}{36}[/tex]

[tex]\cos^{2}{\theta} = \frac{33}{36}[/tex]

First quadrant, so the cosine is positive. Then

[tex]\cos^{2}{\theta} = \sqrt{\frac{33}{36}} = \frac{\sqrt{33}}{6}[/tex]

Tangent:

Sine divided by cosine. So

[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}} = \frac{\frac{\sqrt{3}}{6}}{\frac{\sqrt{33}}{6}} = \frac{\sqrt{3}}{\sqrt{33}} = \frac{\sqrt{3}}{\sqrt{3}\sqrt{11}} = \frac{1}{\sqrt{11}} \times \frac{\sqrt{11}}{\sqrt{11}} = \frac{\sqrt{11}}{11}[/tex]

The answer is:

[tex]\tan{\theta} = \frac{\sqrt{11}}{11}[/tex]

Answer:

whats the question

Step-by-step explanation:

Answer:

x = 5q - 15

Step-by-step explanation:

[tex]\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15[/tex]

Answer and Step-by-step explanation:

The 3D shape shown is a rectangle. This is the net-form of a rectangle.

#teamtrees #PAW (Plant And Water)

Answer:

rectangular prism

Step-by-step explanation:

a rectangle is not 3d. a rectangle is 2d. the correct answer is a rectangular prism.