Answers
Answer:
17 1/3 52/3
Step-by-step explanation:
3x+y=38
3x+2y=52
-y=14
y=-14
3x+-14=38
3x-14=38
3x=38+14
3x=52
3x/3=52/3
x=171\3
17 is a whole number then 1 divided by 3 . thus is x
Related Questions
The 12 pair pack of socks includes 4 pairs of Polo, 5 pairs of plain white socks, and a few grey pairs. What is the Possibility of pulling a pair of grey sock two times in a row? The first pair is not to be returned.
Answers
Answer:
2/11
Step-by-step explanation:
12-4-5=3
So now we know that we have:
4 pairs of polo socks
5 pairs of plain white socks
3 pairs of grey socks
To pull a grey sock one time is 3/12 since there are 12 total socks and 3 pairs of grey socks but since we remove a sock, in the second time, the probability would be 2/11.
Hope this helps! Brainliest?
Select all the equations
represented by this tape diagram.
A. 6 + 6 + 6 + 6 + 6 = ?
B. 5 + 6 = ?
C. ? = 6.5
D. ? = 6.6.6.6.6
E. ? = 5 = 6
F.5 = ?= 6
Answers
Answer:
D.
is the correct answer
On a piece of paper, Graph y
Answers
Some angles are shown. Complete each of the 2 activities for this Task. Activity 1 of 2 The measure of angle NOP is 140°. Which of these equations could be used to find the measure of angle NOQ? A. 23+x=140 B. x−23=140 C. 23×x=140 D. 140÷23=x Activity 2 of 2 What is the measure, in degrees, of angle NOQ?
Answers
Answer:
A. 23+x=140
Step-by-step explanation:
The angle addition postulate states that the measure of a larger angle formed by two or more smaller angles placed side by side is the the sum of the smaller angles. The angle addition postulate states that if B is in the interior of AOC , then:
m∠AOB + m∠BOC = m∠AOC.
From the image:
∠NOP = ∠NOQ + ∠QOP
∠NOP = 140, ∠NOQ = x, ∠QOP = 23
substituting:
140 = x + 23
x = 140 - 23 = 117
∠NOQ = 117°
Help a bab out please?
Answers
Answer:
the answer is 55
Step-by-step explanation:
if you have a straight line each side equals 180 degrees so take 60+65 which equals 125 then do 180-125 and you get 55
how to determine a polynomial expression
Answers
Answer:
hope this helps
Step-by-step explanation:
for an expression to be a polynomial term, it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions.
Answer:
For an expression to be in polynomial form , the following conditions must be met :
No square roots of variablesNo fractional or negative power on the variableNo variables in the denominator of any fraction.what is the factor of 3x^{2} +9x-12=0[/tex]
Answers
Or even better 3(x + 4)(x - 1)
Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement. (a) Suppose I draw n times. Let X., be the number of times I saw a green ball followed by a yellow ball. Calculate the expectation Ex, (b) Let y be the number of times I drew a green ball before the first white draw. Calculate E[Y]. Can you give an intuitive explanation for your answer
Answers
Answer:
[tex]E(X_n)=\frac{2(n-1)}{27}[/tex]
[tex]E(y)=\frac{14}{9}[/tex]
Step-by-step explanation:
From the question we are told that:
Sample size n=9
Number of Green [tex]g=4[/tex]
Number of yellow [tex]y=4[/tex]
Number of white [tex]w=4[/tex]
Probability of Green Followed by yellow P(GY) ball
[tex]P(GY)=\frac{4}{9}*\frac{3}{9}[/tex]
[tex]P(GY)=\frac{4}{27}[/tex]
Generally the equations for when n is even is mathematically given by
[tex]Probability of success P(S)=\frac{4}{27}[/tex]
[tex]Probability of Failure P(F)=\frac{27-4}{27}[/tex]
[tex]Probability of Failure P(F)=\frac{23}{27}[/tex]
Therefore
[tex]E(X_n)=\frac{n}{2}*P[/tex]
[tex]E(X_n)=\frac{n}{2}*\frac{4}{27}[/tex]
[tex]E(X_n)=\frac{2n}{27}[/tex]
Generally the equations for when n is odd is mathematically given by
[tex]\frac{n-1}{2}[/tex]
[tex]E(X_n)=\frac{n-1}{2}*\frac{4}{27}[/tex]
[tex]E(X_n)=\frac{2(n-1)}{27}[/tex]
b)
Probability of drawing white ball
[tex]P(w)=\frac{2}{9}[/tex]
Therefore
[tex]E(w)=\frac{1}{p}[/tex]
[tex]E(w)=\frac{1}{\frac{2}{9}}[/tex]
[tex]E(w)=\frac{9}{2}[/tex]
Therefore
[tex]E(y)=[E(w)-1]\frac{4}{9}[/tex]
[tex]E(y)=[\frac{9}{2}-1]\frac{4}{9}[/tex]
[tex]E(y)=\frac{14}{9}[/tex]
1. What is the center and radius of the given circle (x – 3)² + (y + 8)² = 39?
Answers
Answer:
Center (3, -8), radius = [tex]\sqrt{39}[/tex]
Step-by-step explanation:
The Standard Form for the equation of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
The center is the point (h, k) and the radius is r.
Match up the given equation with the standard form.
[tex](x-h)^2=(x-3)^2 \rightarrow h=3\\(y-k)^2=(y+8)^2 \rightarrow k=-8[/tex]
That last bit can be tricky, k = -8, not 8. Watch the signs!
a ball is shot out of a homemade air cannon. It flies through the air such that its height, as a function of time, is given by: h= -16t^2 + 64t + 10. where h is the height of the ball in feet and t is the time since it was fired in seconds. Max estimates that it takes 4 seconds for the ball to hit the ground and Cole estimates it takes 5 second. Algebraically determine who is closer and support your answer.
Answers
Answer:
Max
Step-by-step explanation:
the function given that h = -16t³+64t+10
the general function Equation:
h = at²+bt+c
=> t at the highest point is defined by t = -b/2a
= -64/2(-16) = -64/-32 = 2 second
the total times that the ball hits the ground
= 2× 2 seconds = 4 seconds.
so, Max is right
Answer:
Solution given:
Let h=0=when the ball hit the ground,the height=0.
h= -16t^2 + 64t + 10.
0=16t²-64t-10
8t²-32t-5=0
∆=[tex] \frac{32±\sqrt{32²+4*5*8}}{2*8}=\frac{8±\sqrt{74}}{4}[/tex]
taking positive
t1=[tex] \frac{8+\sqrt{74}}{4}=4.15seconds[/tex]
t2=[tex] \frac{8-\sqrt{74}}{4}(t2<O)(neglected)[/tex]
So
t=4.15seconds closer to 4seconds.So
Max is closer.
[tex] please \: anyone \: help \:me \\ \\ go \: to \: my \: previous \: question \: [/tex]
Answers
Answer:
Bhimrao Ramji Ambedkar, (born April 14, 1891, Mhow, India—died December 6, 1956, New Delhi), leader of the Dalits (Scheduled Castes; formerly called untouchables) and law minister of the government of India (1947–51).
ExplanationBorn of a Dalit Mahar family of western India, he was as a boy humiliated by his high-caste schoolfellows. His father was an officer in the Indian army. Awarded a scholarship by the Gaekwar (ruler) of Baroda (now Vadodara), he studied at universities in the United States, Britain, and Germany. He entered the Baroda Public Service at the Gaekwar’s request, but, again ill-treated by his high-caste colleagues, he turned to legal practice and to teaching. He soon established his leadership among Dalits, founded several journals on their behalf, and succeeded in obtaining special representation for them in the legislative councils of the government. Contesting Mahatma Gandhi’s claim to speak for Dalits (or Harijans, as Gandhi called them), he wrote What Congress and Gandhi Have Done to the Untouchables (1945).
In 1947 Ambedkar became the law minister of the government of India. He took a leading part in the framing of the Indian constitution, outlawing discrimination against untouchables, and skillfully helped to steer it through the assembly. He resigned in 1951, disappointed at his lack of influence in the government. In October 1956, in despair because of the perpetuation of untouchability in Hindu doctrine, he renounced Hinduism and became a Buddhist, together with about 200,000 fellow Dalits, at a ceremony in Nagpur. Ambedkar’s book The Buddha and His Dhamma appeared posthumously in 1957, and it was republished as The Buddha and His Dhamma: A Critical Edition in 2011, edited, introduced, and annotated by Aakash Singh Rathore and Ajay Verma.
Step-by-step explanation:
hope it is helpful to you
Just help me out
Brainlist will be given
Answers
Answer:
Answer is 18 , because you add 15 and 3 which makes 18 so your answrer is x=18
Step-by-step explanation:
really hope this helped , please give me brainlest :) .
AC = 15 x 1.8 = 27
So x = 17
(this is for ABE similar to ACD)
15+3=18
18/15= 1.2
scale factor= 1.2
10x1.2= 12
12-10=2
x=2
(this is for AEB similar to ADC)
Figure ABCD is a kite. Find the
value of x.
B
A 2x + 10
С
2x
D
x = [?]
Enter
Answers
Answer:
x = 20
Step-by-step explanation:
The diagonals of a kite are perpendicular to each other, so the 4 angles at the intersection are right.
The sum of the 3 angles in a triangle sum to 180° , then
2x + 2x + 10 + 90 = 180
4x + 100 = 180 ( subtract 100 from both sides )
4x = 80 ( divide both sides by 4 )
x = 20
Answer:
20 is the answer
Step-by-step explanation:
Correct for Acellus!
what is the domain of the function g(x)
pls help what are the answers a through f
Answers
Answer:
Domain : (-∞, ∞)
Step-by-step explanation:
Domain of a function is a set of x-values of the function.
Therefore, all x-values at which the given function is defined will be the domain of the function.
From the graph attached,
Given function is defined for all x-values.
Domain : Set of all real numbers.
Or Domain : (-∞, ∞)
hrs 45 min 67+ hrs 3. min 67
Answers
Answer:
hrs 50 min 14
Step-by-step explanation:
hrs 45 min 67 = hrs 46 min 7
hrs 3. min 67 = hrs 4 min 7
Total
hrs 46 min 7
+ hrs 4 min 7
————————
hrs 50 min 14
I also need help with this lol
Answers
Answer:
Luca
Step-by-step explanation:
Juan 566/734 = 0.7711
Luca 7/9= 0.7777
Luca has a greater percentage
help me solve this pleaseeee
Answers
Answer:
f(n) = 6n + 12
Step-by-step explanation:
There is a common difference in consecutive number of seats, that is
42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6
This indicates the sequence is arithmetic with nth term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 18 and d = 6 , then
f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12
A school conference room can seat a maximum of 103 people. The principal and two counselors need to meet with the school's student athletes to discuss eligibility requirements. If each student must bring a parent with them, what is the maximum number of students that can attend each meeting?
Answers
Answer: 50
Step-by-step explanation:
Given
There are maximum of 103 people in room and principal and 2 counselor need to discuss eligibility requirements.
If each student must bring a parent with them
No of seats left after principal and 2 counselor occupied the seats are 103-3=100
A student and parent occupies at least 2 seats. For maximum students, only one parent is feasible.
So, maximum no of students are
[tex]\Rightarrow \dfrac{100}{2}=50[/tex]
What is the equation for a parabola if the vertex is at (5,4) and goes through the point (3,-8)
Answers
Answer:
[tex]y=-3(x-5)^2+4[/tex]
Step-by-step explanation:
Hi there!
Given the vertex of a parabola and a point, it's easiest to organize the equation in vertex form:
[tex]y=a(x-h)^2+k[/tex] where the vertex is located at [tex](h,k)[/tex] and a is a numerical value
1) Plug the vertex into the equation
[tex]y=a(x-h)^2+k[/tex]
Plug in the vertex (5,4)
[tex]y=a(x-5)^2+4[/tex]
2) Solve for a
[tex]y=a(x-5)^2+4[/tex]
Plug in the given point (3,-8) and solve for a
[tex]-8=a(3-5)^2+4\\-8=a(-2)^2+4\\-8=4a+4[/tex]
Subtract 4 from both sides
[tex]-8-4=4a+4-4\\-12=4a[/tex]
Divide both sides by 4
[tex]\frac{-12}{4} = \frac{4a}{4} \\-3=a[/tex]
Therefore, a=-3. Plug this back into [tex]y=a(x-5)^2+4[/tex]:
[tex]y=-3(x-5)^2+4[/tex]
I hope this helps!
Math help please help fast
Answers
Step-by-step explanation:
Angle C: 50 degrees
Angle E: 55 degrees
Angle D: 50 degrees
Angle A: 125 degrees
Angle B: 75 degrees
please help me I will mark as a brainliest
Answers
Answer:
think that this might help you
Lisa uses 2 pieces of copper wire, each 9 feet long, for
each robot she builds. If she started with a 500-yard roll
of copper wire, which of the following represents the
number of yards of wire left on the roll after 'Lisa built r
robots? (3 feet = 1 yard)
Answers
Answer:
yards of wire left on the roll = 500 - r(3)
Step-by-step explanation:
9 feet = 3 yards we need to find how much wire is left on the roll after she builds a certain amount of robots. she uses 9 feet or 3 yards per robot so we have to multiply the amount of robots (r) by 3 yards and subtract that from 500 yards or the total amount of wire she has and that gives us the total amount of wire she has left. Hope this helps.
- 3/8 + 1/6
i kinda just didn't pay attention in class, i just need an explaination of how to solve it and im good to go
Answers
Answer:
[tex]{ \tt{ - \frac{3}{8} + \frac{1}{6} }} \\ { \bf{l.c.m \: of \: 8 \: and \: 6 = 24}} \\ { \tt{formular = \frac{(l.c.m \times denominator \div numerator)}{l.c.m} }} \ \\ \\ = \frac{(24 \times 8 \div - 3) + (24 \times6 \div 1)}{24} \\ = - \frac{5}{24} [/tex]
how do you determine the second deriviative of x^3-7x^2+36
Answers
Answer:
6x -14
Step-by-step explanation:
x^3-7x^2+36
Take the first derivative
3x^2 -14x
Now take the derivative again
6x -14
Answer:
6x - 14
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightCalculus
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Step-by-step explanation:
Step 1: Define
Identify
f(x) = x³ - 7x² + 36
Step 2: Differentiate
Basic Power Rule: f'(x) = 3x³⁻¹ - 2 · 7x²⁻¹ + 0Simplify: f'(x) = 3x² - 14xBasic Power Rule: f''(x) = 2 · 3x²⁻¹ - 1 · 14x¹⁻¹Simplify: f''(x) = 6x - 14Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
What is the solution to the system of equations graphed below?
Answers
(1, 2) because that's where the lines intersect!
Answer: (1, 2)
Step-by-step explanation:
The solution of the systems of equations graphed can be found where the two linear lines intersect. In this graph, the lines intersect at 1 in the x-axis (the line with arrows that runs from left to right" and at 2 in the y-axis (the line with arrows that runs north to south).
Please use the following image for the next 7 questions. Keep in mind that because XY is tangent to circle M, XM and XM form a right angle.
XM = 11 and YM = 36.
What is the area of circle M?
What is the circumference of circle M?
Find the length of XY .
Find the measure of angle M.
Find the area of triangle XYM.
Find the area of the minor sector that has been created as part of triangle XYM.
Find the arc length of the minor arc from point X to the point where YM intersects with the circle.
Answers
It is 34.90
Step-by-step explanation:
Your welcome!
Help me please help me please help me please !!!!!!!!!!!!!
Answers
Answer: y = 1/4x - 1.
Step-by-step explanation: This line has a slope (rise over run) of 1/4, and a y-intercept of -1. Plugging those values into slope-intercept form (y = mx + b) gives you the answer.
Choose all the equations that are true if y = 6. 52.37 – 46.37 = y 45y =445 8y = 48 3.2 + y = 9 y ÷ 4 = 24
Answers
Answer:
52.37 – 46.37 = y
8y = 48
Step-by-step explanation:
Choose all the equations that are true if y = 6. 52.37 – 46.37 = y 45y =445 8y = 48 3.2 + y = 9 y ÷ 4 = 24
We solve for y in all the equations :
52.37 – 46.37 = y
52.37 – 46.37 = 6 (True)
45y =445
Divide both sides by 45
45y/45 = 445/45
y = 9.888 (False)
8y = 48
y = 48/8
y = 6 (True)
3.2 + y = 9
y = 9 - 3.2
y = 5.8 (false)
y ÷ 4 = 24
y/4 = 24
y = 24 * 4 = 96 ( false)
In ΔPQR, r = 9 inches, p = 6.6 inches and ∠Q=6°. Find the area of ΔPQR, to the nearest 10th of a square inch
Answers
Answer:
2.8 square inches
Step-by-step explanation:
Area of the triangle PQR = 1/2 rp sin <Q
Given
r = 9in
p = 6.6in
<Q =6°
Substitute into the formula;
Area of the triangle PQR = 1/2 * 9 * 6 sin6°
Area of the triangle PQR = 9 * 3 sin6°
Area of the triangle PQR = 27 sin6°
Area of the triangle PQR = 27(0.1045)
Area of the triangle PQR = 2.82
Hence the area to the nearest 10th of a square inch is 2.8 square inches
Answer:
3.104 which is equal to 3.1 it your answer.
Step-by-step explanation:
I did it on DeltaMath
Solve 2x-5/x-2 ≤ 1
please answer fast
Answers
Answer:
x<=-3
Step-by-step explanation:
2x-5/x-2 <= 1
Multiply both sides by x-2
2x-5<=x-2 (anything times 1 is that number.)
add 5 to both sides
2x<=x-3
subtract x from both sides
x<=-3
Answer:
Step-by-step explanation:
[tex]\frac{2x-5}{x-2} \leq 1\\case ~1. both ~numerator~and~denominator \geq 0\\x\neq 2\\2x-5\leq x-2\\x\leq 3\\so~0\leq x<2U2<x\leq 3\\case~2.\\both~numerator~and~denominator<0\\2x-5\geq x-2\\x>3\\which~is~rejected~as~it~gives~both~2x-5~and ~x-2>0[/tex]
