Answer:Testing
Explanation:Once a scientist has made a hypothesis, what would they typically do TESTING nextn
Once a scientist has made a hypothesis, they would typically do testing, therefore the correct answer is option B
What is the scientific claim?Scientific claims are statements made in science based on an experiment.
These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.
When a scientist performs a fair test is one in which all other circumstances are maintained while just one variable is changed at a time.
Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these situations, they will communicate the findings of their experiment before revising their original hypotheses and predictions in light of the new knowledge they have gained.
The right response is option B because once a scientist has made a theory, they usually do testing.
Learn more about the scientific claims, here
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we hammer the broader side of a nail and not its sharp end to put it in wood .why ?
Explanation:
We hammer the broader side of a nail instead of its sharp end to put it in wood. It is a concept based on the pressure exerted.
The force acting per unit area of an object is called pressure exerted. It means that pressure is inversely proportional to the area of cross section i.e. area increases, pressure decreases and vice versa.
The broader side of a nail has more area as compared to the sharp end. It means that the broader side will exert less pressure on them which make it easier for us to fix it into the wood.
An average family of four uses roughly 1200 Liters of water per day (1L. - 1000 cm3). A lake that covers 50 km² with a uniform depth and
supplies water to a local town with a population of 40,000 people would lose depth every year due to water consumption form
the locals, Ignore evaporation, rain, creeks and rivers.
Answer:
#_total = 4.38 10⁹ liter
Explanation:
For this exercise we can use a direct proportion rule (rule of three). If 4 people use 1200 liters how much water 1 person consumes
#_water = 1 person (1200 liter / 4 person)
#water = 300 liters
Now we look for the consumption of this person in a year, if 1 person consumes 300 liters 1 day, how many liters they consume in a year (365 days)
#_water_person_total = 365 days (300 liters / 1 day)
#_water_person_total = 109500 liters
This is the water consumption of 1 person in a year, the total of 40000 people how much they consume
#_total = 40000 person (109500 liter / 1 person)
#_total = 4.38 10⁹ liter
If we removed the producers from this food web, how would it affect the balance of the ecosystem?
In a food web, the removal of any trophic level upsets the balance within the web and can cause its eventual collapse. Because producers capture solar energy and convert it to food energy, their loss would affect every other level of the food web.
Explanation:The removal of the producers would cause the collapse of the entire food web. Primary consumers or herbivores, which feed on producers directly, would die off. The next to be affected would be the secondary consumers or carnivores that eat the primary consumers. Higher level consumers would suffer as organisms from lower trophic levels start to die off. Decomposers would break down the bodies of dead organisms, returning their basic elements and compounds to the environment. However, even these dead organisms would run out and the entire food web would collapse.
Hope you like the answer.
A man of mass 75kg stands on a weighing machine in a lift. Determine the reading of the weighing machine when the lift is moving: 1. Upwards with an acceleration of 2m/s² 2. Downwards with a constant velocity of 1.5m/s 3. Downwards with an acceleration of 2.5m/s²
Explanation:
Given that,
Mass of a man, m = 75 kg
(1) We need to find the reading of the weighing machine when the lift is moving upwards with an acceleration of 2 m/s². When the lift is moving upward, reading of the weighing machine is given by :
R = m(g+a)
R = 75 (9.8+2)
R = 885 N
(2) When the lift is moving downwards with a constant velocity of 1.5m/s. It means that the lift is at rest. So, the reading is :
R = mg
R = 75 (9.8)
R = 735 N
(3) When the lift is moving downwards with an acceleration of 2.5 m/s². In this case,
R = m(g-a)
R = 75 (9.8-2.5)
R = 547.5 N
Hence, this is the required solution.
Which of the following best describes a consumer?
0. a business owner who sells clothes
0. someone who studies economics
O. a farmer who sells his crops
O. a person who buys goods and services
Answer:
a business who buys goods and services
The period of a pendulum is the time it takes the pendulum to swing back and forth once. If the only dimensional quantities that the period depends on are the acceleration of gravity, g, and the length of the pendulum, ℓ, what combination of g and ℓ must the period be proportional to? (Acceleration has SI units of m • s-2.)
Answer: √(L/g)
Explanation:
Here we only work with the units:
The unit of the period is units of time, so we have:
[T] = [s]
Now, the units of the length of the pendulum are units of distance:
[L] = [m]
And the units of the acceleration are:
[g] = [m/s^2]
Now, we want to work with those two in such way that the end result is only in seconds.
First, we can see that in g we have seconds square, so we know that we should use a square root.
Then we can divide L by g in order to remove the distance unit, and to have the time unit in the numerator
[L/g] = [m*s^2/m] = [s^2]
Now we apply the square root:
[√(L/g)] = [√s^2] = [s]
Then the combination is: √(L/g)
T = k*√(L/g)
where k is the constant of proportionality.
A ball is thrown upward from an initial height of 1.5m the ball reaches a height of 5m then falls to the ground . What Is the distance traveled by the ball?
Answer:
The distance traveled by the ball is 8.5 m
Explanation:
Initial height of the ball, h₁ = 1.5 m above the ground
final height of the ball, h₂ = 5m
Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m
Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m
Total distance traveled = upward distance + downward distance
Total distance traveled = 3.5 m + 5m = 8.5 m
Therefore, the distance traveled by the ball is 8.5 m
What form of energy does a block of chocolate have?
Answer:
Chemical Energy
Explanation:
What is The distance traveled by a vehicle in 12 minutes,if it’s speed is 35km/h
Answer: 7 km
Explanation: 12 minutes is 1/5 of an hour. 35/5=7
Bus starts from rest if the acceleration of the bus is 0.5 MS square what will be the velocity at the end of two minutes and what distance will it cover during that time
Answer:
1. 60 m/s.
2. 3600 m.
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Time (t) = 2 mins
Final Velocity (v) =?
Distance travelled (s) =?
1. Determination of the velocity at the end of 2 minutes.
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Time (t) = 2 mins = 2 x 60 = 120 secs
Final Velocity (v) =?
v = u + at
v = 0 + (0.5 x 120)
v = 60 m/s
Therefore, the velocity at the end of 2 minutes is 60 m/s.
2. Determination of the distance travelled.
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Final velocity (v) = 60 m/s
Distance travelled (s) =..?
v² = u² + 2as
60² = 0 + 2 x 0.5 x s
3600 = 1 x s
s = 3600 m
Therefore, the distance travelled is 3600 m.
Please help me ASAP...
A train increases its speed steadily from 10 m/s to 20 m/s in 1 minute.
a What is its average speed during this time, in m/s?
b How far does it travel while increasing its speed?
Answer:
A: 15 m/s
B: 900 Meters
Explanation:
A. Average speed is equal to final velocity plus initial velocity divided by two
Va= (20+10)/2 = 15 m/s
B.
distance = speed × time
D= 15 m/s * 60s = 900 Meters
Answer:
Answer is in the attachment.
Explanation:
Hope this helps.
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What areas of the work force can science be applied to?
Select all that apply
government regulatlon
healthcare
a telemarketing
environmental engineering
banking
Answer:
All of the work of lifeExplanation:
In all works of life science can be applied, in-fact science has already been applied already, even in the humanities, social sciences and art related studies sciences is being applied,
Furthermore, the application of science and technology knows no boundaries, and as science is advancing day by day, expanding to new frontiers and breaking new limits so is it application to all works of life and relevance everyday.
What is the equation for burning a fossil fuel
Answer:
Fuel + O2 → CO2 + H2O
Explanation:
( TRUE false )
1.)manuals are the organic matter.
2.)combine is used for sowing the seeds.
3.) the first agricultural task is sowing of seeds.
4.) many plants are first grown in Kinder Gardens and then sown in fields.
5.) earthworm are farmer friendly.
6.)substance that kills
pests are called weedicides.
7.) animals which provide us both egg and flesh are called milch animals.
8.) Grains should be dried in Sun before storage.
9.)wheat,gram,barley,potato, are kharif crops.
10.) the crops on in June /July and harvested in September/ October are called rabi crops.
plz answerzz fast
Answer:
number 6 is wrong
the answer is pesticides
2.combines are used for harvesting or threshing.so number 2 is wrong
at least you tried
Explanation:
there is no such thing as weedicides
Answer:
1. True
2.True
3.False
4. True
5. True
6.False
7.False
8.True
9.False
10.False
A golfer misjudges a putt and leaves her ball way short, the ball going only half of the way to the hole. If the speed of the ball leaving the putter in the first case was vo and the force of resistance due to the grass remains the same, what speed should she have given to the ball to make the original putt?
Answer:
Using
1/2mv^2 = work done by friction
work done = force x distance
lets call the force 3 N
lets call v = 3 m/s
lets call mass = 2 kg
0.5 x 2 x 3^2 = 9 J
9/3N = 3 m/s
now times 3 m/s by square root of 2 of which is 1.4142
3 x 1.4142= 4.2426 m/s
0.5 x 2 x 4.2426^2 = 18
18/2N = 9 m
Students are going to conduct an experiment to study the effect of a net force applied to an object on the object’s motion. In each trial of the experiment, the students will apply a net force on the object. They also need to take two other measurements. What are the other quantities they should measure in each trial of the experiment?(1 point) velocity and time mass and acceleration mass and velocity acceleration and time
Answer:
A. velocity and time
Explanation:
A force can be define as an agent which has the capacity to change the state of an object. It can either increase the velocity of a body, change its direction of motion or cause a moving object to come to rest.
From Newton's second law of motion;
F = ma
where F is the force on the object, m is the mass of the object and a is the acceleration of the object. The unit of force is kgm/[tex]s^{2}[/tex] or Newtons.
a = [tex]\frac{change in velocity}{change in time}[/tex]
In the given question, apart from the mass of the object which is constant, the students should take the measurements of the velocity and time in each trial so as to calculate the required acceleration.
Answer:
mass and acceleration!
Explanation:
Because i am in class just like you and got it wrong because i didn't choose my first answer:(
whats suface tension
Answer: "Surface tension is a film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid, which tends to minimize surface area."
Hope this helps!
Answer:
Explanation:
Surface tension is the property of a liquid surface. It is an effect where the surface of the liquid is strong.
example - small insects can walk on water as they do not have enough weight to penetrate it.
This image might help you
Hope it helps
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A 1.00-kg glider attached to a spring with a force constant 25.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = -2.80 cm (that is, the spring is compressed by 2.80 cm). (a) Find the period of the glider's motion. How does the period depend on the mass and the spring constant? Does it depend on the amplitude of oscillation? s (b) Find the maximum values of its speed and acceleration. speed m/s acceleration m/s2 (c) Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s2, and t is in s. Use the following as necessary: t.) x(t) = v(t) = a(t) =
Answer:
a) T = 1.26 s , b) v_max = 0.14 m / s , a_max = 0.7 m / s²
c) x = 0.028 cos (5 t) , v = - 0.14 sin 5t, a = - 0.7 cos 5t
Explanation:
This is a simple harmonic motion exercise that is described by the equation
x = A cos (wt +Ф)
with
w = √ (k / m)
let's apply this expression to our case
a) Angular velocity is related to frequency
w = 2π f
frequency and period are related
f = 1 / T
we substitute
2π / T = √ (k / m)
T = 2π √(m / k)
let's calculate
T = 2π √(1/25)
T = 1.26 s
In the expression for the period, the amplitude does not appear, therefore there is no dependence, as long as Hooke's law is fulfilled, which is correct for small amplitudes.
b) in the initial equation we have the position as a function of time, let's use the definition of speed and acceleration
v = dx / dt
v = - A w sin (wt + Ф)
the speed is maximum when the sine is -1
v_max = A w
w = √ (k / m)
w = √ 25/1
w = 5 rad / s
the amplitude of the movement is equal to the maximum compression of the spring
A = 2.8 cm = 0.028 m
we substitute
v_max = 0.028 5
v_max = 0.14 m / s
acceleration
a = dv / dt
a = - A w² cos (wt + Ф)
the acceleration is maximum when the cosine is -1
a_max = A w²
let's calculate
a_max = 0.028 5²
a_max = 0.7 m / s²
c) let's start by finding the phase constant
v = -A w cos (wt + Ф)
at t = 0 they indicate that the system has v = 0
0 = -A w sin (0 + Ф)
Ф = sin⁻¹ 0
Ф = 0
we write the equation
x = 0.028 cos (5 t)
v = - A w sin (wt + Ф)
v = - 0.028 5 sin (5t + 0)
v = - 0.14 sin 5t
acceleration
a = - A w² cos (wt + Ф)
a = - 0.028 5 2 cos (5 t + 0)
a = - 0.7 cos 5t
. Mass of a man is 40 kg. find his weight (g=9.8 m/s?)
Answer: 392N
Explanation: W=mg
W= 40x9.8
= 392N
Answer:
[tex]\large \boxed{\sf 392.4 \ N}[/tex]
Explanation:
[tex]\sf Weight \ (N) =mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)[/tex]
[tex]W=mg[/tex]
[tex]W=40 \times 9.81[/tex]
[tex]W= 392.4[/tex]
Gravity is affected by the ?
Answer:
Mass and distance
Explanation:
The force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases. Hence, answer is mass and distance
Pls help! If you know the answer
Answer:
-40
Explanation:
-40= (9/5)(-40) + 32
=-72 + 32
-40=-40
A physical inventory on December 31 shows 3500 units on hand. Bonita sells the units for $15 each. The company has an effective tax rate of 20%. Bonita uses the periodic inventory method. The weighted-average cost per unit is
Un pez llamado PARGO ROJO vive a grandes profundidades. Si se pesca, al salir a la superficie puede tomar el aspecto de la foto porque su vejiga natatoria aumenta de volumen al disminuir la presión. La ley que lo explica es...
Answer:
Hay diversas leyes que podemos usar acá.
Acá sabemos que la vejiga aumenta su tamaño al reducir la presión, esto tiene sentido, pues al haber menos presión, hay menos fuerza que comprime la vejiga, lo que le permite aumentar su volumen.
Acá tenemos una relación inversa de la forma: V = K/P
Una relación inversa donde la presión esta en el denominador y K es un termino que no depende ni del volumen ni de la presión.
Entonces, a medida que aumenta P, el denominador aumenta, por lo que el valor del volumen decrece.
Un ejemplo de una ecuación similar es la del gas ideal, por ejemplo, para un gas ideal dentro de un globo de volumen V para una dada presión P:
V = nRT/P
donde n es el numero de moles, R es la constante termodinámica y T es la temperatura, acá podemos ver que esta ecuación tiene la misma forma fundamental que la escrita arriba.
To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.337 m from rest
Answer:
The velocity of the stone is 2.57 m/s.
Explanation:
Given that
Height = 0.337 m
We need to calculate the velocity of the stone
Using equation of motion
[tex]v^2-u^2=2gh[/tex]
Where, v = velocity of stone
u = initial velocity
g = acceleration due to gravity
h = height
Put the value into the formula
[tex]v^2-0=2\times9.8\times 0.337[/tex]
[tex]v=\sqrt{2\times9.8\times0.337}[/tex]
[tex]v=2.57\ m/s[/tex]
Hence, The velocity of the stone is 2.57 m/s.
If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, the angular acceleration of the tires is:_______
Answer:
The angular acceleration is 3.33 rad/s²
Explanation:
Here is the preceding problem as well as the given problem:
A boy rides his bicycle 2.00 km. The wheels have radius 30.0 cm. What is the total angle the tires rotate through during his trip?
21.
If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, what is the angular acceleration of the tires?
Explanation:
To determine the angular acceleration, we will first find the linear accelerationFrom one of the equations of kinematics for linear motion
v = u + at
Where v is the final speed
u is the initial speed
a is the linear acceleration
and t is time
From the question, the boy starts from rest, hence,
u = 0.0 m/s
v = 10.0 m/s
t = 10.0 s
a = ??
From, v = u + at
a = [tex]\frac{ v - u}{t}[/tex]
a = [tex]\frac{10 - 0}{10}[/tex]
a = 1 m/s²
Now, for the angular acceleration, [tex]\alpha[/tex]
The relationship between linear acceleration, a and angular acceleration, [tex]\alpha[/tex] is
a = [tex]\alpha[/tex]r
where r is radius
From the previous question, r = 30.0cm = 0.3m
From the equation, a = [tex]\alpha[/tex]r
[tex]\alpha[/tex] = a / r
[tex]\alpha[/tex] = 1 / 0.3
[tex]\alpha[/tex] = 3.33 rad/s²
If a body is moving in the horizontal axis with a velocity Vx= 6m/s and in the vertical axis Vy=8m/s What is the angle Theta above the horizontal axis of the velocity of the body V? A. Theta = 45.0 degrees B.Theta = 63.3 degrees C. Theta = 53.1 degrees D. Theta = 43.7 degrees
Answer: C
Explanation: It's a lot of math.
The option that gives the correct value for the angle theta above the horizontal axis of the velocity of the body, v is option C.
C. 53.1°
The given parameters are;
The velocity of the body relative to the horizontal axis, vₓ = 6 m/s
The velocity of the body relative to the vertical axis, [tex]v_y[/tex] = 8 m/s
Required;
The measure of the angle theta above above the horizontal axis of the velocity of the body, v
Solution:
The velocity of the body can be represented vectorially as follows;
v = 6·i + 8·j
The vectoral form gives the legs of the right triangle that has the magnitude and direction as the hypotenuse side
Therefore;
[tex]\theta = arctan \left(\dfrac{8}{6} \right) \approx \underline{53.1^{\circ}}[/tex]
Learn more about the vectors here:
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If a suitcase has a mass of 20 kg, what is the force of gravity acting on it?
Explanation:
Assuming the suitcase is near the surface of the earth, g = 9.8 m/s².
F = ma
F = (20 kg) (9.8 m/s²)
F = 196 N
What two factors determine how much potential energy an object has?
Answer:
The mass of the object and its height in the gravitational field of the Earth.
Explanation:
If we are talking about gravitational potential energy which is defined as:
[tex]U=m\,*\,g\,*\,h[/tex]
being "m" the object's mass, "g" the acceleration due to gravity, and "h" the height at which the object is located relative to the conventionally picked level for zero of potential energy.
As long as the value of "g" is constant, the only two variables that determine the gravitational potential energy are the mass (m) of the object and its relative height (h).
Answer:
The objects weight and height above Earth's surface
Explanation:
K12 :)
numeria
problems
lifted
Joy
1
لوووو
G. Solue the
following
A load
800 Nis
effort
If
the load is
laced at
a distance
Lo cun from
achat will be the
effort distance ?
Solher load ( l = 8oon
Effort
(e) = 200N
the fularum,
Answer:
[tex] \boxed{40 \: cm}[/tex]Explanation:
Load ( L ) = 800 N
Effort ( E ) = 200 N
Load distance ( LD ) = 10 cm
Effort distance ( ED ) = ?
now, Let's find the effort distance:
[tex] \mathsf{L \times LD = E \times ED}[/tex]
Plug the values
[tex] \mathsf{800 \times 10 = 200 \times ED}[/tex]
Multiply the numbers
[tex] \mathsf{8000 = 200 \: ED}[/tex]
Swipe the sides of the equation
[tex] \mathsf{200 \: ED = 8000}[/tex]
Divide both sides of the equation by 200
[tex] \mathsf{ \frac{200 \: ED }{200} = \frac{8000}{200} }[/tex]
Calculate
[tex] \mathsf{ED \: = \: 40 \: cm}[/tex]
Hope I helped!
Best regards!
Using your own word, tell me what is the difference between an element and a compound? Make sure to give an example of each.
Answer:
Hey there!
Elements only contain one type of atom, and a compound contains atoms of different elements chemically combined together. For example, gold is an element, because it only is made of gold atoms, where water or H2O is a compound.
Let me know if this helps :)
Answer:
A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. Elements contain only one type of atom.
Example:
Explanation:
