Answer:
1/6 x 1/6 = 1/36
1/36 is our probability of getting two heads and four tails.
The management of KSmall Industries is considering a new method of assembling a computer. The current assembling method requires a mean time of 66 minutes with a standard deviation of 3.0 minutes. Using the new method, the mean assembly time for a random sample of 24 computers was 61 minutes.
a. Using the 0.10 level of significance, can we conclude that the assembly time using the new method is faster?
b. What is the probability of a Type II error? (Round "Critical values" to 2 decimal places and round your final answer to 4 decimal places.)
Answer:
Part a:
Since the calculated z= 8.1649 falls in the critical region z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.
Part b:
P (Type II Error)= 0.6628
Step-by-step explanation:
The null and alternate hypothesis are
H0: μ1 ≥ μ2 against the claim Ha: μ1 < μ2
This is left tailed test
The critical region for this test at 0.10 ∝ is z < ± 1.28
The test statistic
z= x1-x2/ s/√n
z= 66-61/ 3/√24
z= 5/0.61238
z= 8.16486
Since the calculated z= 8.1649 falls in the critical region z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.
Part b:
P (Type II Error) = P ( accept H0/ H0 is false)
z ( ∝)= X-u/s/√n
1.28= X-61/0.61238
X= 61.7838
So I will incorrectly fail to reject the null as long as a draw a sample mean that greater than 61.7838
The probability of a Type II error is given by
P (z> 61.7838-66/24)
P (z>- 0.42161)
From the tables
P (z>- 0.42161)= 0.6628
HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
50%
- Animals
Home
Economics -
20%
30%
- Farm Mechanics
There were 2500 entries at the county fair. The circle graph tells what types of entries were made.
How many were Farm Mechanics entries?
Answer:
750 were Farm Mechanics.
Step-by-step explanation:
30% of 2500 is 750.
Hope this helps
Can someone explain how to do this
Answer:
28 x 6
Step-by-step explanation:
You times 28 with 6 snice, there are 6 sides.
28 x 6 = 168 meters
Answer: 168 meters
Using the product of the means equals the product of the extremes, solve for x, to the nearest tenth. 4:9=x:6
Cross multiply:
4 x 6 = 9x
24 = 9x
Divide both sides by 9
X = 24/9
X = 2.7 ( rounded to the nearest tenth)
The most expensive type of life insurance is
O limited-payment life insurance
O term insurance
O endowment life insurance
O whole-life insurance
Helpppppppppppppppppppp
Answer:
95°
Step-by-step explanation:
95°
They are vertical angles.
Answer:
95 degree write it fast jakakkaoaoa
What is sec 0 when cot 0 = -4/2?
Answer:
[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]
Step-by-step explanation:
[tex]Cot0=-4\sqrt{2}[/tex]
[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]
[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]
[tex]=\frac{4\sqrt{66} }{32}[/tex]
[tex]=\frac{\sqrt{66} }{8}[/tex]
--------------------
hope it helps...
have a great day!!
You have been given the task of designing a study concerning the lifetimes of five different types of electric motor. The initial question to be addressed is whether there are differences in mean lifetime among the five types. There are 20 motors, four of each type, available for testing. A maximum of five motors can be tested in a day. The ambient temperature differs from day to day, and this can affect motor lifetime.
a. Describe how you would choose the five motors to test each day. Would you use a completely randomized design? Would you use any randomization at all?
b. If X;j represents the measured lifetime of a motor of type i tested on day j, express the test statistic for testing the null hypothesis of equal lifetimes in terms of the Xir
Answer:
a-As the only factor of interest is type of electric motor, thus instead of using 1-factor randomization, a randomized block design is used where at maximum one motor of each type is tested every day.
b- The test statistic is given as
[tex]F_{I-1,(I-1)(J-1)}=\dfrac{12\left(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}\right) }{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}[/tex]
Step-by-step explanation:
a-
This is done such that the days are considered as blocks and the randomization is only occuring within the block. The order of testing is random. However the condition is implemented such that one motor of each type is tested each day.
b-
The F-Value is given as
[tex]F-Value=\dfrac{MSA}{MSAB}[/tex]
Here MSA is given as
[tex]MSA=\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex]Similarly MSAB is given as
[tex]MSAB=\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{.j}[/tex] is the column-wise mean which is given as [tex]\bar{X}_{.j}=\dfrac{1}{I}\Sigma^I_{i=1}X_{ij}[/tex][tex]X_{ij}[/tex] is the any motor j of type iBy putting these values and simplifying, equation becomes:
[tex]F-Value=\dfrac{MSA}{MSAB}\\\\F-Value=\dfrac{\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}}{\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}}\\\\F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{5-1}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(5-1)(4-1)}}\\\\[/tex]
This is further simplified as
[tex]F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{4}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\[/tex]
The numerator can be written as
[tex]F-Value=\dfrac{\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{12(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..})}{{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}}\\[/tex]
1. Find (f(g(2)) for f(x)= 3x² and g(x)= 5 - x.
Answer: 27
Step-by-step explanation:
What are some of the applications for exponential functions?
Designing identification tags
Conversion of measurements
Assigning phone numbers
Finding perimeter
Determining the number of subsets in a given set
Answer:
Option B and D are correct
Step-by-step explanation:
Exponential functions are really useful in the real world situation. They can be used to solve following
a) Population Models
b) Determination of area and perimeters
c) Determine time related things such as half life, time of happening of an event etc.
d) Useful for solving financial problems such as computing investments etc.
Hence, option B and D
Can someone help? I hate math so much lol I don’t understand
Answer:
±6
Step-by-step explanation:
Given the mathematical expression;
√36 < √42 < √49
But, √36 = 6 * 6 = 6²
√49 = 7 * 7 = 7²
Simplifying further, we would substitute the new values respectively;
±[6] < √42 < ±[7]
Therefore, evaluating √36 is equal to ±6.
Pls help me if u can
Answer:
523.33 cm³
Step-by-step explanation:
Formula of volume of sphere
[tex] = \frac{4}{3} \pi {r}^{3} [/tex]
The volume of the sphere
[tex] = \frac{4}{3} \times 3.14 \times {5}^{3} [/tex]
[tex] = \frac{1570}{3} [/tex]
[tex] = 523.3333333...[/tex]
= 523.33 cm³ (rounded to the nearest hundredth)
The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and universities. Suppose we take a poll (random sample) of 3653 students classified as Juniors and find that 3005 of them believe that they will find a job immediately after graduation. What is the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. (0.812, 0.833) (0.806, 0.839) (0.81, 0.835) (0.816, 0.829)
Answer:
(0.806, 0.839)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
Suppose we take a poll (random sample) of 3653 students classified as Juniors and find that 3005 of them believe that they will find a job immediately after graduation.
This means that [tex]n = 3653, \pi = \frac{3005}{3653} = 0.823[/tex]
99% confidence level
So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.823 - 2.575\sqrt{\frac{0.823*0.177}{3653}} = 0.806[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.823 + 2.575\sqrt{\frac{0.823*0.177}{3653}} = 0.839[/tex]
The answer is (0.806, 0.839)
What number must be added to -9 to equal +4?
Answer:
[tex]13[/tex]
Step-by-step explanation:
let the unknown number be x
[tex]x + ( - 9) = 4 \\ x - 9 = 4 \\ x = 4 + 9 \\ x = 13[/tex]
hope this helps you.
Can I have the brainliest please?
Have a nice day!
Find the surface area of the prism.
2 in.
2 in.
6 in.
Answer:
56 m^2
Explanation: L=2, H=2, W=2, d = 6.63324958 m, TSA = 56 m^2, LSA = 48 m^2, TSA = 4 m^2, BSA = 4 m^2, V = 24 m^3
hey I need help with my coordinates
Ok send the picture so I can help you.
Answer:
what is the question? I can help
Step-by-step explanation:
Convert 400 meters (m) to feet (ft). Round your answer to two decimal places. (1 metre = 3.28084 feet)
Answer:
1m----------3.28084ft
400m---------xft
x=(400*3.28084)/1
x=1,312.33 ft
Step-by-step explanation:
A Solve each problem.
1. Henry flies his plane at 240 mph for 3 hours. How far does he travel?
Distance = speed x time
Distance = 240 x 3 = 720 miles
Answer:
henry doesn't travel but plane travel
Step-by-step explanation:
240m×3hour240m×60×60sec2592000m/sHow many odd numbers are between 10 and 50?
Answer:
There are 20 odd numbers between 10 and 50
Step-by-step explanation:
Here are all the odd numbers! Hope this helps!
11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49
what is the midpoint of a segment with endpoints at (-4,-8) and (8,10)
Answer: Midpoint: (2, 1)
Step-by-step explanation:
Midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)
(-4 + 8)/2 = 2
(-8 + 10)/2 = 1
Answer: (2, 1)
Pleeeeeeeaaase answer quick. With explanation. Will give 40 points
Answer:
See attached
Step-by-step explanation:
Review the picture
A sweater costs $25. The store marks up the price by 85%. What is the selling price of the sweater?
(50 pts will mark brainliest) The perimeter of a rectangle is 48 inches. The width of the rectangle is 4 inches more than 3 times the length of the rectangle. What are the dimensions of the rectangle?
Answer:
The rectangle is 5 inches long by 19 inches wide.
Step-by-step explanation:
Let's start by listing what we know:
The perimeter of a rectangle is 48 inches.The width of the rectangle is 4 inches more than 3 times the length of the rectangle.Let's represent the width with "w" and length with "l", and make a system of equations based on what we know.
[tex]\left \{ {{2w + 2l = 48} \atop {w = 3l + 4}} \right.[/tex]
Now, let's solve the system of equations using substitution:
[tex]2w + 2l = 48[/tex]
[tex]2 (3l + 4) + 2l = 48[/tex]
[tex]6l + 8 + 2l = 48[/tex]
[tex]8l + 8 = 48[/tex]
[tex]8l = 40[/tex]
[tex]l = 5[/tex]
The length of the rectangle is 5 inches.
Now, let's use this to solve for the width.
[tex]w = 3l + 4[/tex]
[tex]w = 3(5) + 4[/tex]
[tex]w = 15 + 4[/tex]
[tex]w = 19[/tex]
The width of the rectangle is 19 inches.
Let's check our work:
[tex]2w + 2l = 48[/tex]
[tex]2(19) + 2(5) = 48[/tex]
[tex]38 + 10 = 48[/tex]
[tex]48 = 48[/tex]
The results match, so our answer is correct.
The rectangle is 5 inches long by 19 inches wide.
!NO LINKS, NO FILES!
please :)
Answer:
the area is 72
Step-by-step explanation:
Answer the following questions by choosing whether the first situation is less, equally, or more likely to happen than the second.
PART A
The probability of a chance event is 0.32, is likely to happen when compared to 1/3
Answer:
probably g
Step-by-step explanation:
Question 9 of 10
True or False? A circle could be circumscribed about the quadrilateral below.
Answer:
t
Step-by-step explanation:
A circle can be circumscribed about the given quadrilateral, the answer is: A. True.
We know that,
To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.
Opposite angles of a circumscribed polygon are supplementary.
Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.
Learn more about circumscribed polygon on:
brainly.com/question/1423054
#SPJ7
PLSS HELP ASAP!!
13 points when answered:) Thank you!!
Answer:
The wright answer is A
Step-by-step explanation:
[tex] \sqrt{20} = 4.47 \\ \frac{14}{3} = 4.67 \\ 4.47 < 4.5 < 4.67[/tex]
Mercedes can select from 2 types of apples and 3 types of pears. If she randomly selects 1 apple and 1 pear, how many possible choices does she have?
answer:
2,3
2,2
2,1
1,2
1,1
1,3
Those are the possible choices of selecting apples and pears.
If she randomly selects 1 apple and 1 pear then the possible choices are 6.
What is Probability?It is a branch of mathematics that deals with the occurrence of a random event.
Given that, Mercedes can select from 2 types of apples and 3 types of pears.
Mercedes randomly selects 1 apple and 1 pear.
We need to find the number of possible choices does she have.
(2,3)(2,2)(2,1),(1,2)(1,1)(1,3)
The probability of choosing 1 apple from 2 apples will be 1/2.
The probability of choosing 1 pear from 3 pears will be 1/3.
Now the probability of choosing a apple and a pear will be
1/2×1/3
1/6
Hence, If she randomly selects 1 apple and 1 pear then the possible choices are 6.
To learn more on probability click:
https://brainly.com/question/11234923
#SPJ2
Someone PLease help me
Find the area of the composite figure.
9 ft
4 ft
6 ft
