Othologous. are found where?

Answers

Answer 1

Answer:

Explanation:

Science (genetics, molecular biology, genomics) genes or gene products that are homologous (descended from a common ancestor) and are found in separate species due only to the speciation event (not to gene duplication).

Answer 2

Answer:

I think youcan collect the genes from two species and compare each gene to one another and if two genes identify each other. I never really heard of them being found but created srry if this isnt any help you can delete my question if needed

Explanation:


Related Questions

which life cycle stage is found in plants but not animals ​

Answers

Answer:

Multicellular haploid

OAmalOHopeO

Plants have multicellular haploid and multicellular diploid stages in their life cycle.

Gametes develop in the multicellular haploid gametophyte . Fertilization gives rise to a multicellular diploid sporophyte, which produces haploid spores via meiosis.What is multicellular haploid  stage?The haploid multicellular stage produces specialized haploid cells by mitosis that fuse to form a diploid zygote.The zygote undergoes meiosis to produce haploid spores. Each spore gives rise to a multicellular haploid organism by mitosis.

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Human being get energy from

Answers

Are you asking how humans get energy?
Any food they consume or sleep. Hope this helps

identify the following organism and state to which phylum it belongs​

Answers

Answer:

it belongs to Coelenterata phylum.

What is the function of the mitochondria?
A. Stores the cell's DNA
B. Builds proteins
C. Produces energy for the cell by respiration
OD. Stores the cell's glucose
Reset Selection

Answers

C. Mitochondria is like the power plant of the cell and produces its energy.

Answer:

Produces energy for the cell by respiration

Explanation:

The glucose obtained from food is broken down to pyruvic acid in the cytoplasm. This pyruvic acid is broken down into oxygen, water and energy rich ATP molecules in the Mitochondria.

Why should body temperature not be allowed to fluctuate too much? ​

Answers

Answer:

Because that can destroy the helpful enzymes in the body, and therefore cause a lot of problems or maybe cause death

Carnivore that feeds on primary consumers
Question 3 Multiple Choice Worth 3 points
(01.01 LC)
Which of the following is an example of a decomposer?

Answers

we need the options in order to answer

Digestion is primarily controlled by the _____.

Answers

Stomach and large and small intestine
gastron,secretin and cholecystokinin

List 3 variable that Anurag should keep the same

Answers

Answer:

seawater ,upside-down funnel and seaweed

Explanation:

¿Qué afirmación(es) es(son) correcta(s)?:
a) El dióxido de azufre de la quema de carbón en centrales
eléctricas protege contra la lluvia ácida.
b) Los óxidos de nitrógeno de las emisiones de combustión
provocan el aumento del pH en el agua de lluvia.
c) Una solución ácida de dióxido de carbono en agua de lluvia se
llama lluvia ácida.
d) El dióxido de azufre junto con los óxidos de nitrógeno son las
principales causas de la lluvia ácida.

Answers

Explanation:

jwjejeueuru4ibwsbbefbrvbrbebdbfhhdhdhdbdbdfbd3 eebdddd

Phân tích các quy luật hoạt động thần kinh cấp cao ở trẻ và vận dụng trong thiết lập thói quen học tập và kỉ luật ở học sinh tiểu học.

Answers

Answer:

very different than ducks do u want it is not the

The meaning of ALARA in radiation?

Answers

Answer:

The guiding principle of radiation safety is “ALARA”. ALARA stands for “as low as reasonably achievable”.

What variable should Anurag change in his experiment

Answers

Answer:

For geological carbon sequestration, the reaction of aqueous CO2 with silicate rock permits carbonate formation, achieving permanent carbon sequestration.A

Explanation:

The body regulates the amount of hormones are released by using feedback loops. A __ feedback loop increases the response whereas a __ feedback loop decreases the response.

Answers

Please mark brainliest

Answer

The answer for first fill in the blank is “ positive”
The answer for second fill in the blank is negative

Positive feedback loop increases the response whereas a negative feedback loop decreases the response.

What is positive feedback?

Positive feedback is the amplification of a body's response to a stimulus. For example, in childbirth, when the head of the fetus pushes up against the cervix (1) it stimulates a nerve impulse from the cervix to the brain (2).

A feedback mechanism resulting in the inhibition or the slowing down of a process.

Examples of processes that utilise negative feedback loops include homeostatic systems, such as thermoregulation (if body temperature changes, mechanisms are induced to restore normal levels), blood sugar regulation (insulin lowers blood glucose when levels are high ,glucagon raises blood glucose when levels are low).

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The nitrogen cycle is the using and reusing of nitrogen in an ecosystem. True or false?

Answers

Answer:

True

Explanation:

Nitrogen is a fundamental component of both inorganic and organic compounds, where it is the main constituent of biomolecules such as nucleic acids (DNA, RNA) and proteins. The nitrogen cycle refers to the biogeochemical processes by which nitrogen circulates between the components of an ecosystem, i.e., between organisms (like plants and decomposers), and non-living things (i.e., soil, water, air). This cycle consists of several processes which include, among others, nitrogen fixation (i.e., the process by which nitrogen in the atmosphere is converted into ammonia), nitrification (i.e., the oxidation of ammonia is oxidized into nitrite and subsequent transformation of nitrites into nitrates), denitrification (where nitrate is reduced), anaerobic ammonia oxidation and putrefaction.

A man bought a goldfish in a pet shop. Upon returning home, he put the goldfish in a bowl of recently boiled water that had been cooled quickly. A few minutes later the fish was found dead. Explain what happened to the fish

Answers

Answer:

lack of oxygen in the water

Explanation:

The fish most likely died from lack of oxygen in the water. This is because fishes actually use their gills to extract and breathe in the oxygen from the water while also expelling carbon dioxide from their lungs. Similar to how humans breathe. When the water was boiled it caused the dissolved gases to be expelled, which includes oxygen. Therefore, without the necessary oxygen in the water, the fish ultimately suffocated.

Boiling the water reduce its amount of dissolved oxygen which is needed by the fish to breathe, that's why the fish died after few minutes.

What is dissolved oxygen?

Dissolved oxygen is the amount of oxygen present in the water.

The organisms live to consume dissolved oxygen to breathe.

The amount of dissolved oxygen is high in the current water like rivers than in the still water like pond.

If the amount of DO is high in the water, it causes bubble gas disease in the aquatic organisms.

If the amount of DO is low in the water than, fishes and other aquatic organism cant survive due to low oxygen level.

Thus, boiling the water reduce its amount of dissolved oxygen which is needed by the fish to breathe, that's why the fish died after few minutes.

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Our body needs both vitamin and mineral in a small quantity ,still they are important why?​

Answers

Answer:

Vitamins and minerals are considered essential nutrients—because acting in concert, they perform hundreds of roles in the body. They help shore up bones, heal wounds, and bolster your immune system. They also convert food into energy, and repair cellular damage.

what are the advantage of the presence of hydrogen in large scale in the sun ?​

Answers

hydrogen is essential to nuclear fusion. hydrogen is the fuel the sun burns. we don't have to burn solar energy, so there's no smoke and pollution

Answer:

Hydrogen fusion reaction is the one which provides so much light and heat (in short, energy) which escapes into space and spread. If Hydrogen on sun ends, It will lose its warmth (and may be soon become a planet, but will surely be a dead star).

Explanation:

Answer from Gauth math

Fertilization, Fruit and Seed Formation x3 3. a. name the two processes that lead to seed formation in flowering

Answers

Answer:

Pollination, the transfer of pollen from flower-to-flower in angiosperms or cone ... In angiosperms, the process of seed development begins with double ...

Missing: x3 ‎| Must include: x3

A small group of mice are released on an island without mice but with abundant food for mice and no predators. After the population size stabilizes for several years, a hurricane drastically reduces it. We can now say that:________.
A) the biotic potential of the population has been reduced.
B) its new population size is a result of density-dependent regulation.
C) its new population size is a result of density-independent regulation.
D) it can now act as a sink metapopulation.

Answers

The correct answer is option C) The new mice population size is a result of density-independent regulation.

The carrying capacity might be affected by different factors, known as limiting factors, which might be a result of the population density (for example, competition) or might be density-independent. This last case refers to dense-independent factors, and among these, we can mention human impact or natural disasters (fires, volcanic eruption, flooding). Natural disaster causes damages in an ecosystem, reducing the available resources such as food or shelter, and consequently decreases the number of individuals. Natural disasters reduce the carrying capacity of the environment

In the exposed example, mice got to stabilize on the island. The population had enough food and no predators. But the occurrense of the huricane reduced drastically the population size. This is an example of a natural dissaster acting as a limiting dense-independent factor affecting the population size.

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i need help in biology questions please G10?

Answers

Answer:

ok where is it

we can help only if there is something attached

Attach the picture or something so we could respond

What else is produced during the replacement reaction of silver nitrate and potassium sulfate?

2AgNO3 + K2SO4 Ag2SO4 + ________

KNO3
2KNO3
K2
2AgNO3

Answers

Answer:

2KNO3

Explanation:

Pls mark it brainliest

hope it helps u

Answer:

The answer is B.) 2KNO3

Explanation:

Ecosystems rely on interdependence between species to keep balance. Which of the following is a threat to a stable
ecosystem?
A. Loss of biodiversity
B. High biodiversity
C. Low biodiversity
D. Increase in biodiversity

Answers

Answer:

loss of biodiversity

Explanation:

Biodiversity- refers to the variety of life on Earth at all its levels, from genes to ecosystems, and can encompass the evolutionary, ecological, and cultural processes that sustain life.

loss in biodiversity affect food chains greatly

thanks

hope it helps

H. pylori cannot grow in other microenvironments of the human body because the conditions are unsuitable for its growth, but other species require different conditions.

a. True
b. False

Answers

Answer:

it should be an true statement

QUESTION 11 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Using the allele's frequencies experimentally derived, calculate the frequency of the H4/H5 genotype that would be expected if the class were a population in Hardy-Weinberg equilibrium. 1. 0.28 2. 0.51 3. 0.19 4. 0.72 5. 0.14 6. 0.24 7. 0.41 QUESTION 12 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Using the genotype frequencies derived assuming that the class were a population in Hardy-Weinberg equilibrium, calculate the number of H4/H4 individuals that would be expected in the class (rounded numbers). 1. 19 2. 57 3. 72 4. 147 5. 171 6. 120 7. 96 QUESTION 13 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium and comparing the observed and the expected number of individuals for the three genotypes, calculate the value of the Chi-square statistic 1. 2.69 2. 0.05 3. 28.67 4. 14.59 5. 0.50 6. 22.31 7. 3.84 QUESTION 14 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium, which is the (correct) null hypothesis tested by Chi-square? 1. The whole class represents a population that is in Hardy-Weinberg equilibrium 2. The whole class represents a population that may not be in Hardy-Weinberg equilibrium 3. The whole class represents a population that is not in Hardy-Weinberg equilibrium 4. The whole class represents a population that may be in Hardy-Weinberg equilibrium QUESTION 15 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium and calculating the Chi-square statistic, do you reject or fail to reject the null-hypothesis? 1. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis. 2. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom, I conclude that P>0.05. Hence, I fail to reject the null hypothesis. 3. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I reject the null hypothesis. 4. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I fail to reject the null hypothesis.

Answers

According to Hardy-Weinberg, when a population is in equilibrium, it will have the same allelic frequencies generation after generation, meaning that they are stable, they are not evolving.

When any evolutive force is acting on the population, this equilibrium breacks, and allelic and genotypic frequencies change through generations, differing from the expected ones.  

A) Option 7 is the correct answer ⇒ 0.41

B) Option 6 is the correct answer ⇒ 120

C) Option 7 is the correct answer ⇒ 3.84

D) Option 1 is the correct answer ⇒ The class represents a population that is in H-W equilibrium

E) Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

-------------------------------------------

Allelic frequencies in a locus are represented as p and q, referring to the

allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (H0m0zyg0us  dominant), 2pq (H3ter0zygous), (H0m0zyg0us recessive). Populations in H-W equilibrium will get the same

allelic frequencies generation after generation.

The sum of the allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

 p the dominant allelic frequency,

 q the recessive allelic frequency,

 p² the h0m0zyg0us dominant genotypic frequency

 q² the h0m0zyg0us recessive genotypic frequency

 2pq the h3ter0zyg0us genotypic frequency

 

Situation: Through PCR, we have determined the PER3 genotypes for a class of students as follows:

 H4/H4 = 125 individuals;

 H4/H5 = 85 individuals;

 H5/H5=24 individuals.

⇒ Total number of individuals= 125 + 85 + 24 = 234

⇒ Genotypic frequencies, F(xx):

 F(H4/H4) = 125/234 =0.534

 F(H4/H5) = 85/234 = 0.363

 F(H5/H5) = 24/234 = 0.102

⇒ Allelic frequencies, f(x):

 f(H4) = p = F(H4/H4) + 1/2 F(H4/H5) = 0.534 + 0.363/2 = 0.534 + 0.182 = 0.716

 f(H5) = q = F(H5/H5) + 1/2 F(H4/H5) = 0.102 + 0.363/2 = 0.102 + 0.182 = 0.284

Questions:

A)  According to the theoreticall frame, we know that 2pq is the h3ter0zygous genotypic frequency. So,  

F(H4/H5) = 2pq = 2 x 0.716 x 0.284 = 0.408 ≅ 0.41 ⇒ Option 7 is the correct answer.

-------------------------------------------------------------------------------------------------------------

B)  According to the theoreticall frame, we know that p² is the h0m0zyg0us genotypic frequency. So,

p = 0.716

p² = 0.5126 ≅ 0.513 ⇒ This is the genotypic frequency.

To calculate the number of individuals carrying this genotype, we need to multiply it by the total number of

individuals.

H4/H4 individuals = p² x total number of individuals = 0.513 x 234 = 120

Option 6 is the correct answer.

-----------------------------------------------------------------------------------------------------------

C)  Up to here we know that 2pq = 0.41 and p² = 0.513

Now we need to calculate q ²

q = 0.284, then q² = 0.284² = 0.08

These are the expected frequencies if the population was in H-W equilibrium.

The expected number of individuals with each genotype are:

 H4/H4 = 0.513 x 234 = 120 individuals

 H4/H5 = 0.41 x 234 = 96 individuals

 H5/H5= 0.08 x 234 = 18 individuals

The observed number of individuals with each genotype are:

 H4/H4 = 125 individuals

 H4/H5 = 85 individuals

 H5/H5=24 individuals

X² = ∑ (Observed - Expected)²/Expected)

X² = ((125-120)²/120) + ((85 - 96)²/96) + ((24-18)²/18)

X² = 0.21 + 1.26 + 2 =

X² = 3.47

The clossest option is option 7 = 3.84. The difference might be related to decimals and rounding.

-------------------------------------------------------------------------------------------------------------

D)  The correct answer is  1 ⇒ The whole class represents a population that is in Hardy-Weinberg equilibrium

The null hypothesis always predict that populations are in H-W equilibrium.

-----------------------------------------------------------------------------------------------------------

E)  

 X² = 3.47

 Freedom degrees = n - 1 = 3 - 1 = 2

 Table p value: 7.82

 Significance level, 5% = 0.05

 Table value/Critical value = 5.991

5.991 > 0.347

Meaning that the difference between the observed individuals and the expected individuals is statistically  significant. Not probably to have differe by random chances. There is enough evidence to reject the null

hypothesis.

Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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During the performance of the simple staining procedure, you failed to heat fix your E-coli smear preparation. Upon microscopic examination , how would you expect this slide to differ from the correctly prepared slides ?

Answers

OMG I'm a business study Student so I really don't know about this stuff

For every 100ml of deoxygenated blood delivers approximately _____ml of CO2 to the alveoli.​

Answers

Answer:

For every 100ml of deoxygenated blood delivers approximately __4___ml of CO2 to the alveoli.

Answer:

4ml

Explanation:

For every 100ml of deoxygenated blood delivers approximately 4 ml of CO2 to the alveoli.

Hope it is helpful....

In New York, the worst-hit state, a total of 350,121 cases have been confirmed and 28,232 deaths have been reported. There are now 29 states with tens of thousands of cases, and more than 50,000 in New York, New Jersey, Massachusetts, Illinois, California, Pennsylvania and Michigan

Answers

Answer:

Thats true

Explanation:

A large section of tropical rainforest is cleared to build roads for mining. Select the least likely outcome of this habitat fragmentation from the options below. a.) Species that require open grazing areas may not survive. b.) Species will quickly adapt and re-populate the area. c.) The environment on the habitat edges will support different plants and animals. d.) Subpopulations of species may emerge.

Answers

Answer:

B

Explanation:

B - Species, especially ones with small niches, that looses their niches will likely die out or move to another location. Roads Will, in general, also disrupt the ecosystem (or the remains of it) and its inhabitants, which might lead to migration once again. That would be my reasoning at least. (:

what is the definition of wildlife?

Answers

Answer:

wild animals collectively; the native fauna (and sometimes flora) of a region.

Explanation:

I hope this helped :)

Animals living in their natural habitat and not within the possession or control of humans.


What component of Earth's atmosphere exists entirely as a result of photosynthesis?
oxygen pas
n mas
O water vapor
O nitrogen gas
O carbon dioxide gas

Answers

Answer:

Explanation:

Carbon dioxide

The last one is correct
Hope its help for your questions
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