Answer:
% of unoccupied seats = 63.2 %
Step-by-step explanation:
Total seats = 80, 000
VIP seats = 12 % of 80, 000
[tex]= \frac{12}{100} \times 80000\\\\= 9600[/tex]
General Seats = 39040
Remaining seats = 80000 - 9600 - 39040 = 50, 560
Percentage of un-occupied seats,
[tex]= \frac{50560}{80000} \times 100 = 63.2 \%[/tex]
Answer:
THE NUMBER OF SEATS OCCUPIED BY VIPS=80000×12/100
=9600
occupied seats=9600+39040
=48640
number of unoccupied seats=80000-48640
=31360
percentage of unoccupied seats=31360/80000×100%
=39.2%
Order the side lengths
Answer:
Step-by-step explanation:
First fill in the missing angles of each triangle:
angle IJK = 180-47-51 = 82°
angle KJL = 180 - 63 - 57 = 60°
Within EACH triangle, the side length is proportional to the opposite angle.
Therefore for triangle IJK,
JK < JL < IK
and for triangle JKL
JL < KL <JK
so combining (chaining) the two inequalities,
JL < LK <JK < JL < IK
Answer:
Step-by-step explanation:
first lets find angle J in triangle IJK
for angle J
47 + 51 + angle J =180 degree (sum of interior angle of a triangle )
98 + angle J =180
angle J =180 - 98
angle J =82 degree
Now lets find angle J in triangle JKL
for angle J
57 + 63 + angle J =180 degree (being sum of interior angle of the triangle)
120 + angle J =180
angle J = 180 - 120
angle J =60 degree
now lets place the angle from samllest to largest
angle I = 41 degree
angle K = 51 degree
angle K of JKL triangle = 57 degree
angle J of JKL triangle = 60 degree
angle L =63 degree
angle J of IJK triangle = 80 degree
Side opposite to the smallest angle is smallest in sides and side opposite to the longest angle is largest in side.So,
side opposite to angle I is JK
side opposite to angle K is IJ
side opposite to angle K of JKL triangle is JL.
side opposite to angle J of JKL triangle is LK.
side opposite to angle L is JK.
side opposite to angle J of IJK triangle is IK.
therefore required answer is
JK , IJ , JL , LK , JK , IK
Plz help me solve this algebra
Answer:
[tex]x=5, \\x=-1[/tex]
Step-by-step explanation:
Given [tex](x-2)^2=9[/tex], to solve for [tex]x[/tex], our goal is to isolate [tex]x[/tex].
Take the square root of both sides:
[tex]x-2=\pm\sqrt{9},\\x-2=\pm 3[/tex](recall that [tex]3^2=(-3)^2=9[/tex]).
Therefore, we have two cases:
[tex]\begin{cases}x-2=3,x=\boxed{5} \\x-2=-3, x=\boxed{-1}\end{cases}[/tex]
what's the value of 2
[tex]2\pi[/tex]
3. Two dice are rolled. What’s the conditional probability that both dice are 5’s if it’s known that the sum of points is divisible by 5?
Answer:
[tex]Pr =\frac{1}{3}[/tex]
Step-by-step explanation:
Given
[tex]S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)[/tex]
[tex](3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)[/tex]
[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}[/tex] --- sample space
First, list out all outcomes whose sum is divisible by 5
[tex]A = \{(4,6), (5,5),(6,4)\}[/tex]
So, we have:
[tex]n(A) = 3[/tex]
Next, list out all outcomes that has an outcome of 5 in both rolls
[tex]B = \{(5,5)\}[/tex]
[tex]n(B) =1[/tex]
The required conditional probability is:
[tex]Pr =\frac{n(B)}{n(A)}[/tex]
[tex]Pr =\frac{1}{3}[/tex]
solve for this square.
Answer:
a2
b4
c16 brainliest plzz
Answer:
a) SV = 2
The line that is SV actually is not the full slash. It is halfway, and we know that half of four would be two.
b) RT = 4
This time RT is a full line going all the way down. So it would be 4.
c) p = a + b + c
The lengths are all the same because we calculated in the first question that two is half of four. So the base, height, and hypotenuse are the same, 2.
2 + 2 + 2 = 6
So the perimeter of the triangle RVS is 6.
What is the value of the following function when x = 0?
y
5
(x)
4
3
2
1
V 2
-54 -3
3
4
х
5
Answer:
y=-2 when x=0
Step-by-step explanation:
The value of the function f(x), When x = 0 is y = - 2.
What is a polynomial?A polynomial is an algebraic expression.
A polynomial of degree n in variable x can be written as,
a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² +...+ aₙ.
What is a graph?The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.
These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.
From the graph of the function, it intersects the x-axis at two distinct places
so it is a polynomial of degree two.
Let the given function be f(x).
By observing the graph of the function f(x), When x = 0, f(x) = - 2.
Or y = - 2.
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please help me find the area
Answer:
320 square feet.
Step-by-step explanation:
For the moment, let's put the square back in place. That would make the length 16 + 8 = 24 and the width 16.
L = 24
W = 16
Area = L * W
Area = 24 * 16
Area = 384
Now the next step is to take out the square. It is 8 * 8 = 64
The area of the figure = 384 - 64 = 320 square feet, and that's the answer.
Answer:
320 in^2
Step-by-step explanation:
we need to find the area of this figure
Firstly divide above picture in two parts
1st figure = (16*16)in.
2nd figure = (8*8)in.
Area of 1st figure = 16*16 = 256 in^2
Area of 2nd figure = 8*8 = 64 in^2
Area of whole figure = ( 256 + 64 )in^2
= 320 in^2
Kayla wants to fence in a rectangular dog pen that is 30 ft by 40 ft How would you use wha
you know about geometry to help her ensure that she has truly built a rectangular pen?
Answer:
Kindly check explanation
Step-by-step explanation:
Given the dimension of the dog pen = 30 ft by 40 ft.
Using the knowledge of geometry, that know that a rectangle has been built, the area of the pen should be :
Area of rectangle = Length * width
Area = 40 * 30
Area = 1200 ft²
Perimeter of rectangle = 2(Length + width)
Perimeter = 2(40 + 30)
Perimeter = 2(70)
Perimeter = 140 feets
Hence, area of the pen should be 1200 ft² and its perimeter or fencing should measure 140 feets
Alex wants to arrange chairs in such a way that the number of chairs in a row is equal to the number of columns. He has ordered 5100 tables.
a)How many more tables needed to arrange in such a way that he planned? Justify your answer
2)How many chairs can he remove to arrange in a way that he wants? Justify your answer.
Answer:
84
59
Step-by-step explanation:
In other to have the same number of chayes in both rows and columns ;
If the Number of chairs per row = x ; then number of chairs per column = x
Then the total number of chairs needed = x * x = x²
Hence, if there are 5100 chairs ;
Number of chairs needed more ;
Take the square root of 5100 ;the round to the next whole number :
B.) For number of chairs to be removed ;
Take the square root of 5100 and round down to the whole number.
Hence,
A.) = √5100 = 71.414 = 72
72² - 5100 = 84
B.) 5100 = 71.414 = 71
5100 - 71² =
Jayden earned $74.00 for 8 hours of work.
How much did he earn per hour?
Answer:
Jayden earns $ 9.25 per hour.
Step-by-step explanation:
Time Earnings
8 74
1 x
[tex]\frac{8}{1} = \frac{74}{x}\\\\8 \times x = 74 \times 1\\\\x = \frac{74}{8} = \$ 9.25[/tex]
Answer:
9.25
Step-by-step explanation:
He earned 9.25 money per hour because you divide 74/8 and it will give you 9.25. If you wanna double-check you can multiply 9.25 times 8 and you'll get 74.
Suppose, as a rough estimate, we say that there are 20 distinct geons used for object recognition; and each geon can come in 5 classifiable qualitative sizes (tiny, small, moderate, large, huge); and a pair of geons can be placed in 10 distinct qualitative relations (geon A on top of geon B; geon A to upper left of geon B; geon A to the left of geon B; and so forth).How many distinct two-geon objects do we have in the space described above?
Answer:
49500
Step-by-step explanation:
According to the Question,
Given That, Suppose, as a rough estimate, we say that there are 20 distinct geons used for object recognition, and each geon can come in 5 classifiable qualitative sizes (tiny, small, moderate, large, huge). and a pair of geons can be placed in 10 distinct qualitative relations.We have, District geons = 20 , District Size = 5
So, The Number Of Ways A geon can be selected 20 x 5 = 100Now, We choose 2 geons From 100 Geons and arrange them in 10 district relations.
So, The number of district two-geon object= [tex]\left[\begin{array}{ccc}100\\2\end{array}\right] * 10[/tex]
= (100 × 99)/2 × 10
= 49.5×100×10 ⇒ 49500
Please help me on this question. Thanks
Answer:
E. p - 7 + 7 = 22 + 7
Step-by-step explanation:
p - 7 + 7 = 22 + 7 ( -7 + 7 = 0)
p = 22 + 7
p - 7 = 22//
Please help me solve this
Answer:
m1 = 107°
m2 = 73°
m3 = 107°
m1+m2+m3+m4 = 360°
107+73+107+73=360°
Pythagorean triples are super important to know. If the hypotenuse of a triangle is 15, what are its legs ( hint - use the three, four, five triple)
Answer:
9, 12
Step-by-step explanation:
Just multiply the 3,4,5 triple by 3 and u get 9, 12, 15
A manufacturer knows that their items have a lengths that are skewed right, with a mean of 10 inches, and standard deviation of 1.6 inches. If 39 items are chosen at random, what is the probability that their mean length is greater than 10.5 inches
Solution :
Given :
Mean, μ = 10 inches
Standard deviation, σ = 1.6 inches
Sample size is n = 39
Therefore,
[tex]$\mu_{\overline x}=\mu = 10$[/tex]
[tex]$\sigma_{\overline x}=\frac{\sigma}{\sqrt n } = \frac{1.6}{\sqrt{39}}$[/tex]
= 0.25
[tex]$P (\overline X > 10.5 ) = P\left( \frac{\overline X - \mu_{\overline x}}{\sigma_{\overline x}} > \frac{10.5 - 10}{0.25} \right)$[/tex]
= P( Z >2)
= 1 - P(Z < 2)
= 1 - 0.97225 (from standard normal table)
= 0.0277
Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Excel File: data10-03.xlsx Enter negative values as negative numbers. a. What is the value of the test statistic? (to 2 decimals) b. What is the -value? (to 4 decimals) c. With , what is your hypothesis testing conclusion? - Select your answer -
Answer:
[tex]z = -1.53[/tex] --- test statistic
[tex]p = 0.1260[/tex] --- p value
Conclusion: Fail to reject the null hypothesis.
Step-by-step explanation:
Given
[tex]n_1 = 80[/tex] [tex]\bar x_1= 104[/tex] [tex]\sigma_1 = 8.4[/tex]
[tex]n_2 = 70[/tex] [tex]\bar x_2 = 106[/tex] [tex]\sigma_2 = 7.6[/tex]
[tex]H_o: \mu_1 - \mu_2 = 0[/tex] --- Null hypothesis
[tex]H_a: \mu_1 - \mu_2 \ne 0[/tex] ---- Alternate hypothesis
[tex]\alpha = 0.05[/tex]
Solving (a): The test statistic
This is calculated as:
[tex]z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}[/tex]
So, we have:
[tex]z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}[/tex]
[tex]z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}[/tex]
[tex]z = \frac{-2}{\sqrt{0.8820 + 0.8251}}[/tex]
[tex]z = \frac{-2}{\sqrt{1.7071}}[/tex]
[tex]z = \frac{-2}{1.3066}[/tex]
[tex]z = -1.53[/tex]
Solving (b): The p value
This is calculated as:
[tex]p = 2 * P(Z < z)[/tex]
So, we have:
[tex]p = 2 * P(Z < -1.53)[/tex]
Look up the z probability in the z score table. So, the expression becomes
[tex]p = 2 * 0.0630[/tex]
[tex]p = 0.1260[/tex]
Solving (c): With [tex]\alpha = 0.05[/tex], what is the conclusion based on the p value
We have:
[tex]\alpha = 0.05[/tex]
In (b), we have:
[tex]p = 0.1260[/tex]
By comparison:
[tex]p > \alpha[/tex]
i.e.
[tex]0.1260 > 0.05[/tex]
So, we fail to reject the null hypothesis.
5/8
of a sum of money is $240. What is the value of the sum of money?
Answer:
The total amount is 384
Step-by-step explanation:
Let m = the amount of money
5/8 of the money is 240
5/8 * m = 240
Multiply each side by 8/5
8/5 * 5/8 * m = 8/5 * 240
m =384
The total amount is 384
in the number 32.8 which digit is in the ones place
help pls
Answer:
Step-by-step explanation:
the number 2 is in the ones place
its a pretty easy answer
If f(x) = 4x - 7 and g(x) = 2x + 4, evaluate fx) + g(x) for x = -3.
A-52
B --21
C-22
D-15
Answer:
Step-by-step explanation:
4(-3)-7+2(-3)+4
=-21
Suppose the ages at retirement for workers in the U.S. are normally distributed with an unknown population mean and standard deviation. If a random sample of 43 retirees is taken to estimate the mean retirement age, what t-score should be used to find a 80% confidence interval estimate for the population mean?
Answer: 1.302
Step-by-step explanation:
The sample used was 43 retirees, so n=43. To find the degrees of freedom:
df=n−1=43−1=42
The confidence level is given in the scenario: 80%. So,
α=1−CL=1−0.8=0.2
But we want to use the value for α2, which is 0.22=0.1. Using the table, we need to find the row for 42 degrees of freedom, and the column for t0.1. So, the t-score we would use to find the 80% confidence interval is 1.302.
We could also use a calculator and input 1−α2=0.9 and the degrees of freedom into invT, in which case we would enter invT(0.9,42).
The solution is: 1.302, is the t-score should be used to find a 80% confidence interval estimate for the population mean
What is the confidence interval?A confidence interval is a range of values, derived from a sample of data, that is likely to contain an unknown population parameter with a certain level of confidence.
here, we have,
The sample used was 43 retirees, so n=43.
To find the degrees of freedom:
df=n−1=43−1=42
The confidence level is given in the scenario: 80%. So,
α=1−CL=1−0.8=0.2
But we want to use the value for α2, which is 0.22=0.1. Using the table, we need to find the row for 42 degrees of freedom, and the column for t0.1. So, the t-score we would use to find the 80% confidence interval is 1.302.
We could also use a calculator and input 1−α2=0.9 and the degrees of freedom into invT, in which case we would enter invT(0.9,42).
Hence, The solution is: 1.302, is the t-score should be used to find a 80% confidence interval estimate for the population mean
To learn more about the confidence interval, visit:
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Help will give brailiest to first answer
question isn't loading
Step-by-step explanation:
Answer:
i think it is b but don't take my word
Step-by-step explanation:
3
What is
4
of 100 km?
0,75-100
Answer:
75 km.
Step-by-step explanation:
Fractions of a number
To get the fraction of a number, we multiply that number by the given fraction.
For example two-thirds of 60 is 2/3 × 60 = 2 × 20 = 40 and one-fifth of 100 is 1/5 × 100 = 100/5 = 20
Now, we are supposed to find a fraction of 100 km. Assume its three-quarters.
So, three-quarters of 100 km is 3/4 × 100 km = 3 × 100 km/4 = 3 × 25 km = 75 km
So, three-quarters of 100 km is 75 km.
does anyone know the answer to this question
Please guys help me fast!!!!!
Answer:
there 24 possible outcomes.
each color/letter on the spinner could coincide with each side of the dice, so there 4*6 possible outcomes
{A, 1},{A,2},{A,3},{A,4},{A,5},{A,6},{B,1},{B,2}, ...
Sample Space=S={A,B,C,D}
Hence
|S|=4
For Dice:-Sample Space=S={1,2,3,4,5,6}
Hence
|S|=6
help me find the volume (picture)
Answer:
18
Step-by-step explanation
IF YOU REALLY KNOW ABOUT THIS PLEASE HELP IT’S MY FINAL EXAM, leave it if you don’t..... The two triangles illustrated below are similar. What are the values of x and y?
Answer from A to D
Answer:
B
Step-by-step explanation:
the larger triangle is 4 times bigger.....so the measurements for the sides are multiplied by 4.
the shape however is the same ....so the internal angle will still be 83 degrees
When subtracting 1.578 from 127.3, the result on the calculator is 125.722. Round the answer to the appropriate precision based on the precision of the numbers in the subtraction column
Answer:
[tex]127.3 - 1.578 \approx 125.7[/tex]
Step-by-step explanation:
Given
[tex]127.3 - 1.578 = 125.722[/tex]
Required
Round to the precision of the 1.578
The number in the subtraction column is 1.578; so, the question implies that we round up 125.722 to the precision of 1.578
The precision of 1.578 is 4 (i.e. it has 4 digits). Hence, 125.722 will be approximated to 4 significant digits.
So, we have:
[tex]125.722 \approx = 125.7[/tex]
or
[tex]127.3 - 1.578 \approx 125.7[/tex]
If numbers collected from a survey are measurements, what are these measurements called before you perform any calculations?
Answer: raw data
Step-by-step explanation:
Raw data, is also referred to as the primary data, and it refers to the data that's collected from a source. It is a day that is yet to be processed. e.g the raw scores during examination can be considered to be raw data since it hasn't been processed yet to get further information.
Therefore, if the numbers collected from a survey are measurements, then the measurements before any calculation is performed is called raw data.
The number of accidents in a factory for each month is provided: Jan Feb Mar Apr May June July Aug Sep Oct Nov Dec 25 28 24 18 17 27 9 18 22 14 12 26 Which hypothesis test would be appropriate for determining whether some months have a greater number of accidents than others
Answer:
Chisquare goodness of fit test
Step-by-step explanation:
Given the data:
Jan Feb Mar Apr May June July Aug Sep Oct Nov Dec 25 28 24 18 17 27 9 18 22 14 12 26
The Chisquare goodness of fit test is used to test the relationship between the observed and theoretical or expected model data. Here, we make and assumption about the population using the sample distribution. For the goodness of fit test, there is only one observed variable, here it is the number of factory accident. The null hypothesis is of the claim that the number of factory accidents per month is the same for each month ;
Null hypothesis : Number of factory accident each month is the same ; while the alternative hypothesis is tests that some month gave greater number of accidents, that is ; the number of factory accidents is not the same for each month.
A service station charges $251 for four
new tires and installation. If the
installation portion of the bill is $84,
what is the price of one tire? Write and
solve an equation.
Answer:
$41.75
Step-by-step explanation:
$251-84=167
167 divided by 4 is $41.75
Hope this helps! :)