P4 + NaOH + H2O——> PH3 + Na2HPO3
Balance given equation by oxidation no. Method

Answers

Answer 1

Answer:

P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3

Explanation:

Answer 2

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.

A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.

Chemical equations must be balanced, which means that the atom types and numbers on both sides of the reaction arrow must match. Coefficients are the values added in front of formulas to balance equations; they multiply each atom in a formula.

Here the given equation is balanced as:

P₄ + 4NaOH + 2H₂O——> 2PH₃ + 2Na₂HPO₃

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Related Questions

Why is iodine always Used in a solution containing excess I2

Answers

Answer:

If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.

Iodine always used in a solution excess KI is given to aid in the solubilization of free iodine, which would be insoluble in clean water during normal circumstances.

What is Iodine?

Iodine is a kind of element which are mainly used in iodometry titration. It can be represented by I.

What is solution?

A solution would be a homogenous mixture of two components, usually a solute as well as a solvent.

Iodimetry would be a technique that uses a standard iodine solution as a titrant for such an oxidizable analyte. When an excessive amount of iodide is used to decrease a chemical while somehow producing iodine.

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Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?

Answers

Answer:

Explanation: hell noo

Emily must notify the Instructor of the Lab/Classroom.

Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)

Answers

Answer:

3.6124 m/kg

Explanation:

Molality is calculated as moles of solute (mol) divided by kilogram of solvent (kg). Here, we can find these numbers by using the 35.4%, which gives us  35.4 g of H3PO4 and 100 g of solution to work with.

To go from grams to moles for the phosphoric acid, you need to find the molar mass of the compound or element and divide the grams of the compound or element by that molar mass.

Here, the molar mass for phosphoric acid is 97.9952 g/mol. The equation would look like this:

35.4 g x 1 mol / 97.9952 g = 0.3612422 mol

Next, the 100 g of solvent can easily be converted to 0.1 kg of solvent.

To find the molality, divide the moles of solute and kilograms of solution.

0.3612422 mol / 0.1 kg = 3.6124 m/kg

What must happen for ice to melt at a given pressure?
A. The average kinetic energy of the water molecules must decrease.
B. Thermal energy must be transferred to the ice from its
surroundings.
C. The orderliness of the water molecules must decrease.
D. Thermal energy must be transferred from the ice to its
surroundings.

Answers

Answer:

D

Explanation:

thermal energy must be transferred from the ice to it's surroundings

Thermal energy is the heat and energy present in the system. The thermal energy must be dissipated from ice to the surroundings to melt and produce liquid. Thus, option D is correct.

What is thermal energy?

Thermal energy is present in any substance in the form of energy and heat that depends on kinetic energy, orderliness, randomness, temperature, etc. It is passed from a substance to the surrounding at a lesser temperature.

The ice can melt into a liquid when it loses its thermal energy and heat to the surrounding with increased kinetic energy and releases the temperature to the area with a temperature less than the ice.

Therefore, the heat from ice will get dissipated to the outer environment to melt.

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The drugs Prilosec and Nexium both contain the same active ingredient. Nexium contains a single enantiomer, but Prilosec is a racemic mixture. Which of the following is probably true regarding 20 mg doses of the two different drugs?

a. both drugs will be equally effective
b. both drugs can be prepared using the same synthetic procedure
c. Nexium will be more effective than Prilosec
d. Prilosec will be more effective than Nexium

Answers

Answer:

both drugs will be equally effective

Explanation:

A racemic mixture is a substance that contains a 50/50 mixture of the (+) and (-) enantiomers of an optically active compound.

It is important to note that even if a drug occurs as a racemic mixture, only the biologically active enantiomer will interact with the substrate on which the drug acts. The other enantiomer present is just irrelevant. Similarly, its presence does not affect the biological activity of the active enantiomer.

Hence, both Prilosec and Nexium are both equally effective.

Please help me with this ASAP i I will give you Brainliest

Answers

I am not sure about the question

identify the organ system pictured below and state two functions of this system in the body​

Answers

Answer:

skeletal system

Explanation:

to create and fliter blood and provide frame-work to the human body and support

You are an intermediate product of an industrial process which intends to separate iron from its ore. A well known iron ore is hematite. Which of these ores does not contain iron?
Goethite
Malachite
Siderite
Limonite

Answers

Answer:

Malachite

Explanation:

Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!

Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 9.32 percent of its original value

Answers

Answer:

t(9.32% remaining) = 203 yrs (3 sig. figs.)

Explanation:

All radioactive decay follows a 1st order decay profile. This is defined by the expression ...

A =A₀e^-k·t

A = final activity = 9.32%

A₀ = initial activity = 100%

e = base of natural logs

k = rate constant = 0.693/t(1/2) = (0.693/30.2) yrs⁻¹ = 0.023 yrs⁻¹

t = time of decay = ln(A/A₀)/-k = ln(9.32%/100%)/-0.023 yrs⁻¹

 = 203.286637 yrs (calc. ans.)

 ≅ 203 yrs (3 sig. figs.)

For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase in GPS of the system, decrease S, or leave S unchanged. If you don’t have enough information to decide, check the “not enough information“ button in the last column. Note for advanced students: you may assume ideal gas and ideal solution behavior.

Answers

Answer:

For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column


15. Triglycerides, waxes, and steroids are all ___ lipids because they contain only carbon, hydrogen, and oxygen


A. simple
B. methyl esters
C. complex
D. long-chain compounds

Answers

the answer to this question is C

Answer:

A. simple

Explanation:

A 15.0 mL urine from a dehydrated patient has a density of 1.019g/mL. What is the mass of the sample, reported in mg?

Answers

Answer:

Mass of sample in mg = 15,285 mg

Explanation:

Given:

Volume of urine sample = 15 ml

Density of sample = 1.019 g/ml

FInd:

Mass of sample in mg

Computation:

Mass = density x volume

Mass of sample in mg = Volume of urine sample x Density of sample

Mass of sample in mg = 1.019 x 15

Mass of sample in mg = 15.285 gram

Mass of sample in mg = 15.285 x 1,000

Mass of sample in mg = 15,285 mg

Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
Volume of unknown weak acid used : 20.00 mL Total volume of 0.20 M NaOH required to reach the equivalence point: 18.50 mL Initial pH of the weak acid 2.87

Answers

Answer:

Concentration: 0.185M HX

Ka = 9.836x10⁻⁶

pKa = 5.01

Explanation:

A weak acid, HX, reacts with NaOH as follows:

HX + NaOH → NaX + H2O

Where 1 mole of HX reacts with 1 mole of NaOH

To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).

18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX

In 20.0mL = 0.0200L =

0.00370 moles HX / 0.0200L = 0.185M HX

The equilibrium of HX is:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

And Ka is defined as:

Ka = [H⁺] [X⁻] / [HX]

Where [H⁺] = [X⁻] because comes from the same equilibrium

As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M

Replacing:

Ka = [H⁺] [H⁺] / [HX]

Ka = [1.349x10⁻³M]² / [0.185M]

Ka = 9.836x10⁻⁶

pKa = -log Ka

pKa = 5.01

The sp of strontium carbonate, SrCO3, is 5.60×10−10 . Calculate the solubility of this compound in g/L.

Answers

Answer:

3.50 × 10⁻³ g/L

Explanation:

Step 1: Make an ICE chart for the solution of SrCO₃

"S" represents the molar solubility.

         SrCO₃(s) ⇄ Sr²⁺(aq) + CO₃²⁻(aq)

I                             0               0

C                           +S              +S

E                             S               S

The solubility product constant (Ksp) is:

Ksp = [Sr²⁺] [CO₃²⁻] = S²

S = √Ksp = √5.60 × 10⁻¹⁰ = 2.37 × 10⁻⁵ M

Step 2: Convert "S" to g/L

The molar mass of SrCO₃ is 147.63 g/mol.

2.37 × 10⁻⁵ mol/L × 147.63 g/mol = 3.50 × 10⁻³ g/L

Calculate the number of representative particles of 0.0391 mol Neon gas.


i need help ASAP !

Answers

Answer:

2.35 × 10²² particles

Explanation:

To get the number of particles in a substance, we multiply the number of moles (n) of that substance by Avogadro's number (nA).

That is, we say;

number of atoms = n × 6.02 × 10²³

In this question, Neon gas is said to have 0.0391 moles. The number of atoms in that field.

number of particles = 0.0391 × 6.02 × 10²³

number of particles = 0.235 × 10²³

number of particles = 2.35 × 10²² particles

Express as ordinary numbers.
3 x 10^0 =

Answers

Answer:

the answer is 3

Explanation:

hope this works

Over time, rocks break down into sediment by wind, water, ice, and/or gravity. This process is commonly referred to as
chemical change

Answers

Answer:

Explanation:

Chemical change

A transition metal in the fourth period from the following list : Cu, O , Pr, Ag

Answers

Answer:

Cu

Explanation:

Groups 3 - 12 (or groups IIA - IIB) of the periodic table contain transition elements. Transaction elements start from period four (4) of the periodic table. The phrase alludes to the fact that the d sublevel is filling at a lower main energy level than the s sublevel that came before it.

The transition elements' arrangement is inverted from the fill order, with the 4 s filled prior to the actual 3 d begins. The transition elements are commonly referred to as transition metals since they are all metals. They are less reactive than the metals in Groups 1 and 2 and have normal metallic characteristics.

From the options given Cu is the only transition metal in the fourth period on the periodic table.

What is erosion?
A) Weathered materials staying in one place
B) The movement of weathered materials by wind, water or ice
C) New materials on a land form

Answers

the process of eroding or being eroded by wind, water, or other natural agents.

I hope this helps!

Answer:

B. The movement of weathered materials by wind, water or ice.

Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN

Answers

Answer:

CH3CH2CH3

Explanation:

Dipole moment is the measure of the polarity of a chemical bond. It is the extent of charge separation in a molecule.

Dipole moment is the product of the magnitude of charge and the distance separating the charges from each other.

The molecule having the lowest dipole moment among the options is the molecule that has the least polarity. The least polar molecule among the options is CH3CH2CH3, it has no polar bonds in its structure.

We have that for the Question "Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN "

it can be said that

[tex]CH_3CH_2CH_3 have the lowest dipole moment[/tex]

 From the question we are given

CH3CH2CH3

CH3OCH3

CH3CHO

CH3OH

CH3CN

Generally alkanes have the lowest dipole moment, they have C-H bond which are non polar.

Therefore,

[tex]CH_3CH_2CH_3[/tex] have the lowest dipole moment

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What volume in mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr?

Answers

Answer: A volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

Explanation:

Given: Moles = 0.0130 mol

Molarity = 0.220 M

Molarity is the number of moles of solute present in liter of a solution.

[tex]Molarity = \frac{moles}{volume (in L)}[/tex]

Substitute the values into above formula as follows.

[tex]Molarity = \frac{moles}{volume (in L)}\\0.220 M = \frac{0.0130 mol}{Volume (in L)}\\Volume (in L) = 0.059 L[/tex]

As 1 L = 1000 mL

So, 0.059 L = 59 mL

Thus, we can conclude that a volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

How much energy does an X-ray with an 8 nm (8 x 10-9m) wavelength have?
A. 1.99 x 10-25 J
B. 3.33 x 1016 J
C. 2.48 x 10-17 j
D. 8.28 x 10-26 J

Answers

Answer:

it would be option C

Explanation:

Speed of light = 3×10^8m/s

Planck's constant = 6.626×10^-34 Js

Wavelength = 8 x 10^-9 m

Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9

Energy = [19.878×10^(8-34)] / 8 x 10^-9

Energy = 2.48475 × 10^(-26+9)

Energy = 2.48×10^-17 J

A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this bubble?

Answers

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:

P = 2.4 atmV = 250 mL ⇒ 250 / 1000 = 0.250 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 15 °C ⇒ 15 + 273 = 288 K

We input the given data:

2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And solve for n:

n = 0.025 mol

Finally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:

0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates

Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction. 2 NaN3(s) --> 2 Na(s) 3 N2(g) What mass in grams of NaN3(s) must be reacted in order to inflate an air bag to 79.5 L at STP

Answers

Answer:

154 g

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

79.5 L × 1 mol/22.4 L = 3.55 mol

Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.

Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.37 mol × 65.01 g/mol = 154 g

1. Determine the volume of SO2 (at STP) formed from the reaction of 96.7 mol FeS2 and 55.0 L of O2 at 358 K and 1.20 atm.
4 FeS2(s) + 11O2(g)  2Fe2O3(s) + 8SO2(g)

Answers

Answer:

40.0L of SO2 are produced

Explanation:

To solve this question we need to find the moles of O2 using PV = nRT in order to find the moles. Thus, we can find the limiting reactant and the moles (And volume) of SO2 produced as follows:

Moles O2:

n = PV/RT

n = 1.20atm*55.0L / 0.082atmL/molK*358K

n = 2.25 moles of O2.

Clearly, limiting reactant is O2.

The moles of SO2 produced are:

2.25 moles of O2 * (8mol SO2 / 11mol O2) = 1.6351 moles SO2

Volume SO2:

V = nRT/P

V = 1.6351 moles SO2*0.082atmL/molK*358K / 1.20atm

V = 40.0L of SO2 are produced

Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2and 0.229 gof H2O and 0.407g of SO2are obtained.
Calculate its empirical formula.

Answers

Answer:

The empirical formula is, C4H4S

Explanation:

Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles

Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g

Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles

Mass of hydrogen = 0.025 moles × 1 = 0.025 g

Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles

Mass of sulphur= 0.0064 moles ×32 = 0.2 g

Now we obtain the mole ratios by dividing through by the lowest ratio.

C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles

C4H4S

What is the molar mass of Na2SO4?
O A. 142.04 g/mol
O B. 71.05 g/mol
O c. 238.22 g/mol
O D. 94.04 g/mol

Answers

I believe its D due to my thinking

Answer: A. 142.04 g/mol

Explanation:


1. Complete the following chart for the following atoms:
Element
Mass
number
Number of
electrons
Number of
neutrons
Atomic
Number
(number of
protons)
Potassium
16
56
26
What is the atomic symbol (the nuclide) for the isotope with 15 protons and 16
neutrons? Your answer must be in the form shown:
AX
You must show the correct numbers for A and Z
and have the correct symbol (Z). (3 points)

Answers

Explanation:

If there are 15 protons, 15 nuclear particles of unit positive charge, then

Z

=

15

. Now

Z

the atomic number

, and you look at your copy of the Periodic Table, and you find that for

Z

=

15

, the element phosphorus is specified.

But we are not finished. Along with the 15 defining protons, there are also 16 neutrally charged, massive nuclear particles, 16 neutrons, and the protons and neutrons together determine the atomic mass. The isotope is thus

31

P

, which is almost 100% abundant, and an important nucleus for

NMR spectroscopy.

An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
How many milliliters of this suspension should be given to an infant weighing 13 lb.

Answers

Answer:

0.8853 mL

Explanation:

First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:

13 lb * [tex]\frac{0.454kg}{1lb}[/tex] = 5.902 kg

Then we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:

15 mg/kg * 5.902 kg = 88.53 mg

Finally we calculate the required mL of suspension, using its concentration:

88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL

Name the parts of an electromagnet

Answers

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

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In team dynamics, process losses are best described as: Question 1 options: resources expended towards team development and maintenance. information lost due to imperfect communication among team members. knowledge lost when tacit knowledge is converted to structural knowledge. productivity losses that occur when individual members need to learn a new task. knowledge lost when a team member leaves the organization. The number of boxes in Warehouse "A" currently totaling 476 is increasing at a rate of 4 boxes per day. The number of boxes in Warehouse "B" currently totaling 986 is decreasing at a rate of 6 boxes per day. In how many days will these two warehouses contain the same number of boxes Explain how specialized structures found in multiflora rose support its reproduction and spreading/dispersal throughout ecosystems in the United States. Use evidence and scientific reasoning to support your response. What did FDR accuse the Sixty Families of?A. Stealing from the governmentB. Sabotaging the 1938 electionsC. Being IsolationistD. Being undemocratic During receiving of a food order, you notice a bag of rice with signs that the bag has been wet. What do you do? I will give BRAINLIEST to the correct answerFind the measure of angle 5 The lever of a car lift has an area of 0.2 meters squared, and the area of the lift under the car is 8meters squared. If you push with a force of 3 newtons, how much force will be applied to thecar? does anyone understand this or can anyone explain what i need to do please ?? theres no instructions Which statement best sums up the U.S. Government's attitude toward big businessin the 1920s? Find the Value of X (in this picture) A regular polygon of (2A+ 1) sides has 140as the size of each interior angle. Find A A primary function of the promotional mix is to Multiple Choice explain how to use a product. persuade consumers to try a product. inform customers of complementary offerings. inform customers of pricing changes. point out flaws in competitors' products. 3. Find the value of:a) 9b) 15c) (0.2)d) (0.7) 3- Reglas para hablar gestos, entorna-cin, ritmopausas que se debentomar en cuenta enmomento de desarrollar un debate.publico al How did Caesar change the Roman Senate?a) He increased its membership by adding members who were loyal to him.b) He loosened its membership requirements so more people could run for election.c) He gave the people of the nation more representation than people from conquered lands.d) He created new rules that made representation more equal between patricians and plebeians. Solve the following system by graphing and identify the point of intersection -2x - y=-12 2x-3y=4 (v) A carA car is pulled with a force of 60.N at angle of 30 ron, thehorizontal. Find the vertical and horizontal components of the appliedforce. PLEASE PLEASE I RLY NEED HELP ...... ....... . .. . . . . . . . . .... . . . Pick three Enlightenment thinkers and explain how they inspired Americas founders. The following expressions are factorizations of 60. Which is the prime factorization? Los principales accionistas de la empresa global zafiro S.A. estn interesado en una empresa que representa una importante competencia. Entre los datos de la empresa tiene los siguientes: la planta opera a nivel que oscila entre 80 y 100% de su capacidad. Cuando su nivel de actividad es de 80% los costos variables de fabricacin totalizan $180,000,000. A su nivel normal de 90% de la empresa utiliza 40,500 horas de mano de obra directa y tiene costos de fabricacin totales de $371,500,000. Determina los costos de fabricacin finos y variables al 80 y 100% de su capacidad