Page 69 Section Review 3-1,3-) When an acrobat reaches the equilibrium position, the net force acting along the direction of motion is zero. Why does the acrobat swing past the equilibrium position?
According to the 1st law of motion (the law of inertia), the acrobat past the equilibrium position because he/she is initially in motion.
(or it gains momentum as approaching to equilibrium position and pass there with that momentum)
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Related Questions
9. What is the mass of a sky diver falling at a velocity of 52 m/s who has a kinetic energy of
97344 Joules?
Answers
Answer: m = 72 kg
Explanation:
A potato falling vertically downward is struck by a dart that is traveling vertically upward, as shown above. The dart and potato then collide, stick together, and continue moving after the collision.The weight of the dart is W. Which of the following claims best describes the magnitude of the net force on the dart immediately before, during, and immediately after the collision with the potato?
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Option B is Correct
The velocity of the center of mass remains constant before the collision, when they collide there is a slight decrease in kinetic energy of the system since the collision is inelastic, resulting in a slight decrease of velocity, afterwards the velocity is constant again.
Velocity is the directional velocity of a moving object, observed from a given frame of reference and indicating the rate of change of position measured at a given time reference (eg 60 km/h northward). Velocity is a fundamental concept in kinematics, a branch of classical mechanics that describes the motion of bodies.
Velocity is a physical vector quantity. Both magnitude and direction are required to define it. The scalar absolute value (magnitude) of velocity is called velocity, and its magnitude is a consistent derived unit measured in the SI (metric) system as meters per second (m/s or m⋅s−1). For example, " meters/second" is a scalar, but "5 meters/second east" is a vector. An object is said to be accelerating if its velocity, direction, or both change.
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A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits into two parts with masses of 0.01 kg and 0.09 kg, respectively. Immediately after the separation, the 0.01 kg part moves horizontally due east. Air resistance is negligible. True statements about the 0.09 kg part include which of the following? I. It could move north immediately after the spring is released. II. It takes longer to reach the ground than does the 0.01 kg part. III. It strikes the ground closer to the launch point than does the 0.01 kg part. (A) I only (B) III only (C) I and II only (D) II and III only (E) I, II, and III
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Air resistance is hardly noticeable. true regarding the 0.09-kilogram component. This causes 0.01kg to land farther from the launch site than 0.09kg did.
0.09kg will move to the west due to momentum conservation (opposite of 0.01 kg). Additionally, since both are at the same height above the ground, it will take them equal amounts of time to descend to the ground.
Allowing v to be the speed of 0.01 kg, which means that the speed of 0.09kg will be smaller than 0.01 kg,
0.01v - (0.09)V = 0
V = 0.01 v/ 0.09 = 0.111v
The speed of 0.09 kg = 0.111v
The speed of 0.09 kg is less than 0.01kg.
Because of this, 0.01kg hits the ground farther from the launch point than 0.09kg did.
The amount of resistance in an electrical circuit represents the resistance to current flow. The Greek letter omega (), which represents resistance, represents ohms. German physicist Georg Simon Ohm (1784–1854), who investigated the connection between voltage, current, and resistance, is the name given to the unit of resistance known as an ohm.
Resistance measurements are typically performed in order to evaluate the health of a component or a circuit.
Current flow is inversely correlated with resistance. Conductor damage from corrosion or burning could be one of several potential causes if it is extremely high.
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Given that A + B = 0, (a) how does the magnitude of B compare with the magnitude of A? (b) How does the direction of B compare with the direction of A?
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If A + B = 0, then the magnitude of B is equal to the magnitude of A. This is because the magnitude of a vector is simply its size or length, and if two vectors add up to zero, then their magnitudes must be equal.
As for the direction of B, it is the opposite of the direction of A. This is because if two vectors are equal in magnitude and opposite in direction, their sum will be zero. For example, if A is a vector pointing to the right and B is a vector pointing to the left, their sum will be zero. Similarly, if A is a vector pointing upwards and B is a vector pointing downwards, their sum will also be zero.
In summary, if A + B = 0, then the magnitude of B is equal to the magnitude of A, and the direction of B is opposite to the direction of A.
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Which of the following is an important difference between the infinite square-well potential and the finite square-well potential?a. The number of energy levels is limited in the infinite square-well potential but not limited in the finite square-well potential.b. The infinite square-well potential utilizes Schrödinger's equation to describe particle motion while the finite square-well potential does not.c. The energy levels are quantized only in the finite square-well potential.d. Particles can exist in classically forbidden regions outside the finite square-well potential.e. Only the energy levels in the finite square-well potential depend on Planck's constant.
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Particles can exist in classically forbidden regions outside the finite square-well potential.
The correct option is D.
What if Planck's constant was zero?In the absence of quantum effects, everything would be continuous, smooth, and completely predictable in the Newtonian sense. However, we may not be here to get bored with this if Planck's constant were 0.
What use does Planck's constant serve?At the atomic scale, the behavior of both particles and waves is described by Planck's constant. One of the factors that led to the creation of quantum mechanics is Planck's constant. It was a surprise when those boundaries also turned to represent the limits where known rules of physics applied since the Planck scaled was developed as an universal set of units.
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A disk of mass M is spinning freely at 4.91 rad/s when a second identical disk, initially not spinning, is dropped onto it so that their axes coincide. In a short time the two disks are corotating.
(a) What is the angular speed of the new system (in rad/s)? rad/s
(b) If a third such disk is dropped on the first two, find the final angular speed of the system (in rad/s). rad/s
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(a) The angular speed of the new system is 2.455 rad/s.
(b) The angular speed of the new system is 1.64 rad/s.
(a) The Angular Momentum Conservation Principle is observed since there are no outside forces acting on either disk.The fact that the axes of rotation of each disk coincide allows for the principle to be reduced to its scalar version. The ratio of the inertial moment to the angular speed determines the angular momentum's size. The moment of inertia doubles and the angular speed is cut in half as soon as both disks start to revolve.
It is given by, I ω₀ = 2* I * ωf
Where,
I - Moment of inertia of a disk, measured in kilogram-square meter
ω₀ - Initial angular speed, measured in radians per second
ωf - Final angular speed, measured in radians per second
The expression for relating final angular speed to initial angular speed is,
ωf = 1/2 * ω₀
Given that, ω₀ = 4.91 rad/s
The new system's angular speed is,
ωf = 1/2 * 4.91 = 2.455 rad/s
(b) If third such disk is dropped on the first two, the expression on angular velocity becomes,
I ω₀ = 3* I * ωf
ωf = 1/3* ω₀ = 1/3* 4.91 = 1.64 rad/s.
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X ft See the framing plan above. If the image doesn't display, click this link or this link. Assume that There are two girders and 5 beams Each beam spans between two girders (i.e., from grid line 1 to 3) There are four columns (at A/1, A/3, E/1 and E/3) What is the tributary area for a rim joist? (Although not explicitly shown, assume that there are joists directly above the girders. The dimensions of the building are as follows: X = 96 ft . Y = 36 ft A B © D (E) Girder 1 Joist EQ. (2 Y ft EQ Girder EQ. EQ. EQ EQ. X ft
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There are two girders and 5 beams Each beam spans between two girders. The tributary area of rim joist is 864ft²
Length of the rim joist = Y ft = 36ft
Length of each bay out of 4 = X/4 = 96/4 = 24ft
Tributary width of rim joist is half on each bay to its side
Tw = 24/2 + 24/2 = 24
Tributary area Ta = tw × length
Ta = 24 × 36 = 864ft²
The floor or roof area (in plan) that results in loading on a certain structural element is known as the tributary area. In each direction, name the adjacent column.
the distance between the two, measured.
multiplying by two the distance
From here, create a perpendicular line.
Repeat until a bounding polygon appears for each gridline that is close by.
A beam's tributary area is equal to its length times the addition of half its space to each adjacent girder.
The square footage of the deck surface area supported by one post is known as the tributary area. Depending on how the deck is set up, this can differ for each post.
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During the heating season, a damper in the bypass duct is closed to prevent air from passing through the humidifier. Electronic humidistats are equipped with solid-state sensors in place of a hygroscopic element. Evaporative humidifiers contain an element that is kept damp. False
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This statement is False because Solid-state sensors are used in place of a water - absorbing element in electronic humidistats. A damper in the bypassed duct is closed during the summer period to stop airflow.
What is hygroscopic and example?Hygroscopy - A material is said to be hygroscopic if it has the capacity to adsorb and retain water or water from its immediate surroundings. Examples include ethanol, glycerin, concentrated sulfuric acid, honey, silica gel, and methanol.
How hydroscopic is water?Around the soil particles, some water in the soil creates an incredibly thin, firmly held layer. It's referred to as hydroscopic water. A little amount of water in the soil is chemically linked to soil components in the soil. We refer to it as mixed water.
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A roller coaster starts from rest at point A. If you ignore friction and take the zero of potential energy to be at C, A) the kinetic energy of the coaster at D will be equal to its potential energy at A. B) the kinetic energy of the coaster at E will be equal to its potential energy at C. C) the kinetic energy of the coaster at C will be equal to its potential energy at A. D) the kinetic energy of the coaster at B will be equal to its potential energy at C E) None of these is correct. 13. Two objects are sliding at the same speed across a wooden surface. The coefficient of kinetic friction between the first object and the surface is twice that between the second object and the surface. The distance traveled by the first object before it stops is S. The distance traveled by the second object is A) impossible to determine without knowing the masses involved. B) 28 C) S/2 D) S E) 4S 14. A person of weight w is in an upward-moving elevator when the cable suddenly breaks. What is the person's weight measured in the elevator immediately after the elevator starts to fall? A) w B) greater than w C) less than w D) 9.81w E) zero A force F produces an acceleration a on an object of mass m. A force 3F is exerted on a second object, and an acceleration 8a results. What is the mass of the second object? A) 3m B) 9m C) 24m D) (3/8)m E) (8/3)m 15.
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A roller coaster starts from rest at point is option C) the kinetic energy of the coaster at C will be equal to its potential energy at A.
Since Two objects are sliding at the same speed across a wooden surface. The distance traveled by the second object is option B) 2S
A person's weight measured in the elevator immediately after the elevator starts to fall is option E) zero A force F produces an acceleration a on an object of mass m.
The mass of the second object is option D) (3/8)m.
What happens when kinetic energy is equal to potential energy?The amount of kinetic energy change and the amount of potential energy change are identical in all physical processes that take place in closed systems. When the kinetic energy rises, the potential energy falls, and vice versa.
Wave speed is the number of meters a wave travels in a second, or the distance a wave travels in a particular amount of time. Equation Speed = Wavelength x Frequency describes how wave speed relates to wave wavelength and wave frequency.
Therefore, When wavelength and frequency are known potential energy stored energy that depends on the relative positions of different components of a system may be utilized to compute wave speed—this equation can be used to determine wave speed. When stretched or squeezed, a spring has higher potential energy.
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for a severe supercell ts to form over the great plains, one would expect the 5,000 agl wind to be group of answer choices 360/10 kt 200/15 240/90 190/45
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Note that for a severe supercell ts to form over the great plains, one would expect the 5,000 AGL wind to be 190/45kts (Option D)
What is a supercell?A supercell thunderstorm is distinguished by the presence of a mesocyclone, which is a deep, continually revolving updraft. As a result, these storms are sometimes known as spinning thunderstorms.
Supercells are storms that have updrafts that spin along a vertical axis and are generally but not always thunderstorms. This rotation is caused by shear in the environmental wind field (a change in wind direction and/or speed with height) that surrounds the storm as it grows.
Supercell thunderstorms are intense, long-lived storms that are characterized by strong wind shear and rotational dynamics.
The wind shear, or the change in wind speed and direction with height, is a key factor in the development and maintenance of supercell thunderstorms.
Note that AGL means Above Ground Level; while
KTS means Knots. Knots are a unit measurement of speed. I nautical mile is usually equated to one knot.
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a package of mass m is released from rest at a warehouse loading dock and slides down the 2.0-m-high, frictionless chute to a waiting truck. unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m, from the bottom of the chute. (figure 1)
Part A
Suppose the packages stick together. What is their common speed after the collision? Express your answer to two significant figures and include the appropriate units. Part B
Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound? Express your answer to two significant figures and include the appropriate units.
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[tex]\frac{mv^{2} }{2}[/tex]their common speed after the collision is 2.1 m/s and
height the package of mass m rebound is 22cm using conservation of energy and conservation of momentum.
conservation of energy:
Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present. The law of energy conservation is adhered to by all energy forms.
conservation of momentum:
The product of an object's mass and velocity is that object's momentum. A vector quantity, that is. A fundamental tenet of physics is the conservation of momentum, which asserts that in the absence of an external force, the overall momentum of an isolated system remains constant. In other words, if no outside force influences the system, its total momentum is constant throughout every interaction. The vector sum of the individual momenta represents the total momentum.
Here, we first have to apply conservation of energy:
P.E = K.E
mgh = [tex]\frac{mv^{2} }{2}[/tex] (i)
mass cancels out
v = √2gh = √2×9.8×2 = 6.26099m/s
now applying the conservation of momentum. Since the package sticks after collision, we have for final momentum m = m1 + m2 and initially u2=0
m1u1 + m2u2 = (m1+m2)v
m*6.26099 = 3m*v
v = 2.1 m/s
now using eq (i) we have,
mgh = [tex]\frac{mv^{2} }{2}[/tex]
masses cancels out
h=22cm
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How do I calculate the force needed to lift an object of 15N at a constant speed of 2m/s?
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The force necessary to lift an object is the same as the force necessary to fight gravity.
We may calculate the gravitational force acting on the object using Newton's second law if we assume that the acceleration caused by gravity is 9.8ms2. By exerting force that is produced by the person's muscles, the weights are raised. It is therefore a muscular force. Lift can be in any direction with respect to gravity, contrary to the popular understanding of the word, which defines it with respect to the direction of flow rather than the direction of gravity. If the force on an object's bottom is greater than the force of gravity coming from above, lift will result. Lift must equal gravity for a height to be sustained.
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An oscillator creates periodic waves on two strings made ofthe same material. The tension is the same in both strings.If the strings have different thicknesses,which of the following parameters, if any, will be different in thetwo strings?Check all that apply.wave frequencywave speedwavelengthnone of the aboveIf the strings have the same thickness butdifferent lengths, which of the following parameters, if any, willbe different in the two strings?Check all that apply.wave frequencywave speedwavelengthnone of the above
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Wavelength of the following parameters, if any, will be different in the two strings.
What is wavelengths and frequency?The distance between two wave crests, which also applies to troughs, is known as the wavelength. Cycles per second (Hz), a unit of measurement for frequency, is the number of vibrations that pass through a certain space in a second (Hertz). The link between frequency and wavelength is discussed in this article.
Briefing:The formula for the wave's speed on the string is
[tex]$v=\sqrt{\frac{T}{\mu}}$[/tex]
Here, mu stands for mass per unit of length and T for string tension.
The mass per unit length varies depending on the thickness. As a result, the wave speed varies between the two strings.
The oscillator determines the frequency of the oscillations. As a result, using the same oscillator, the frequency is the same for the two strings.
In terms of frequency and speed,
f= γλ
λ= f/γ
The wavelength of the waves varies as the speeds vary since the frequency is constant.
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in the Pollowing figures the horizontal surface on which this block slides is frictionless . if the two Forces acting on
each have magnitude F= 30. №
10.kg What is the magnitude
of the resulting acceleration of the block
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The magnitude of the resulting acceleration of the block is 5.60 m/s.
What is Newton's second law?The product of the block's mass and acceleration is the net force acting on the block. Newton's second law of motion is what is known as this.
The following is the expression for Newton's second law:
F = ma
The net horizontal force acting on the block is as follows:
Fnet =F + FcosΘ
Here, F is the force acting on the block, and 8 is the angle at which the force is applied to the block.
Substitute 30Θ for 8 and 30 N for F.
Fnet =30 N + (30 N)cosΘ = 55.98 N
From Newton's second law, the expression for the force is.
Fnet = ma
Substitute 10.0 kg for m and 55.98 N for Fnet
55.98 N = (10 kg)a
a (55.98 N /10 kg)
a = 5.598 m/s2 a = 5.60 m/s
Therefore, the acceleration of the block is 15.60 m/s
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The question is incomplete. Your most probably complete question is given below: The figure is added.
A gymnast uses a flexible stick to jump over the bar. Which of the following
describes energy changes when he reaches the highest point of his jump?
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When the gymnast starts to jump his potential energy starts to convert to kinetic energy. But when he reaches the maximum height and stop there for seconds, potential energy regains. Thus, option C is correct.
What is potential energy?Potential energy of an object is the energy stored in it by virtue of its position. Potential energy increases with increases in mass and height which is clear from the equation for potential energy
p = mgh
Kinetic energy is generated by motion of the object. Thus, only a moving body attains a kinetic energy. Kinetic energy depends on the mass and velocity of the object.
Here, the gymnast gains a kinetic energy when he starts to jump from rest. But, when he reaches the maximum height where the speed slows down, his kinetic energy converts to potential energy. Thus, option C is correct.
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Your question is incomplete. But your complete question probably was:
A gymnast uses a flexible stick to jump over the bar. Which of the following
describes energy changes when he reaches the highest point of his jump?
A) kinetic- potential- potential
B) kinetic- potential- kinetic
C) potential - kinetic – potential
D) potential- potential- kinetic
a hippo's body is 4.0 m long with front and rear feet located as in (figure 1). the hippo carries 60% of its weight on its front feet. Figure <1 of 1 Part A How far from its tail is the hippo's center of gravity? Express your answer with the appropriate units. S → ? de Value Units Submit Request Answer Provide Feedback Beview 1 Constants
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The hippo's center of gravity is d = 158m.
Calculation:
from the given figure-
weight of front = 0.60w
weight of back = 0.40 W
By Balancing the forces.
0.60 [1.8+ 0.5-d] -[0.4(α-0.5)]=0
= 1.08 +0.3 - 0.60d - 0.4d +0.2 = 0
d = 158m
A force is a push or pulls on an object caused by its interaction with another object. Whenever there is an interaction between two objects, there is a force acting on each object. When the interaction stops, there is no force on the two objects.
There are four fundamental forces gravity electromagnetic force weak nuclear force, and strong nuclear force. Of these four forces, the mighty nuclear force is the most powerful. From this, we can conclude that whenever the direction of force is in the direction of motion the velocity of the object increases, and when it is opposite to the direction of motion the velocity decreases.
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Does the Foucault pendulum rotate at the poles because they are considered to be the axes of rotation of earth? Why doesn’t the pendulum move at the equator?
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Due to the pendulum's sluggish swing, which gave the impression of changing direction as the Earth moved away, the Foucault Pendulum demonstrated that the Earth rotates.
Foucault understood that his pendulum would swing more slowly the longer the thread was linked to the weight.
If he used a very heavy weight and the string above to a nearly frictionless pin, the pendulum would swing so slowly that it would seem to shift direction as the Earth moved away.
Foucault's pendulum revolves at the same speed as the Earth's rotation when they align at the poles. These axes are perpendicular to each other everywhere on the equator, therefore the pendulum is completely unaffected by the Earth's spin.
The first scientific proof of the Earth's rotation on its axis was the rotation of the plane of swing of Foucault's pendulums. There is relative motion between them as the Earth spins beneath a Foucault pendulum that swings back and forth in a plane.
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five coins are stacked in the smooth plastic container. if each coin weighs 0.0235 lb, determine the normal reactions of the bottom coin on the container at points a and b.
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The smooth plastic jar has five pennies placed inside of it. The normal reactions of the bottom coin on the container at locations a and b will be 0.0705 lb and 0.1175 lb respectively if each coin weighs 0.0235 lb.
What does normal force mean?A contact force, the normal force is often referred to as the normal reaction force. On two surfaces that are not attached to one another, a normal force cannot be applied.
What normal force is present during deceleration?The body's weight determines the usual deceleration force. A body's position relative to the ground tells us when it is about to fall. The normal force is the portion of a force that is perpendicular to any contact surface.
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a cellist tunes the c-string of her instrument to a fundamental frequency of 65.4 hz. the vibrating portion of the string is 0.615 m long and has a mass of 14.8 g .
Answers
(A) With 268.94 N tension must she stretch it.
26% increase in tension is needed to increase the frequency from 65.4 Hz to 73.4 Hz, corresponding to a rise in pitch from C to D.
Part (A)
Fundamental frequency =f0= 65.4 Hz.
The length of the vibrating portion of the string = l = 0.615 m
Mass= m = 14.8 g
We know, [tex]f_0 = \frac{v}{2l}[/tex]
So, the value of v will be 65.4*2*0.615 = 80.442 m/s
As, We know,
[tex]T=\frac{v^2}{\frac{m}{l}}[/tex]
So, the value of tension will be: [tex]\frac{80.442^2}{\frac{14.8}{0.615}}=\frac{6470.91}{24.06}=268.94\:N[/tex]
Part (B)
Fundamental frequency =f0= 73.4 Hz.
The length of the vibrating portion of the string = l = 0.615 m
Mass= m = 14.8 g
We know, [tex]f_0 = \frac{v}{2l}[/tex]
So, the value of v will be 73.4*2*0.615 = 90.282 m/s
As, We know,
[tex]T=\frac{v^2}{\frac{m}{l}}[/tex]
So, the value of tension will be: [tex]\frac{90.282^2}{\frac{14.8}{0.615}}=\frac{8150.8395}{24.06}=338.77\:N[/tex]
So, the percentage increase in tension will be [tex]\frac{338.77-268.94}{268.94}\times 100\%=25.96\% \approx 26\%[/tex]
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The complete question should be:
a cellist tunes the c-string of her instrument to a fundamental frequency of 65.4 hz. the vibrating portion of the string is 0.615 m long and has a mass of 14.8 g .
Part A: With what tension must she stretch it?
Part B
What percent increase in tension is needed to increase the frequency from 65.4 Hz to 73.4 Hz, corresponding to a rise in pitch from C to D?
A single loop of copper wire lying flat in a plane, has an area of 7.80 cm^2 and a resistance of 2.70 Ω A uniform magnetic field points perpendicular to the plane of the loop. The field initially has a magnitude of 0.500 T, and the magnitude increases linearly to 3.50 T in a time of 1.10 s. What is the induced current (in mA) in the loop of wire over this time?
Answers
The induced current in the loop of the copper wire is found to be 7.85 mA.
The single loop of the copper wire is lying in flat plane and the magnetic field is pointing perpendicular to the plane of the loop. The area of the loop is given to be 7.8cm²
The magnetic field initially has a magnitude of 0.500 Tesla and it finally increases manner to grow to a magnitude of 3.50 Tesla in a time 1.10 seconds.
The induced EMF in the circuit will be given by the relation,
E = A∆B/∆T
Where,
B is magnetic field,
A is the area and T is the time taken.
Putting all the values,
E = 0.00078×(3.5-0.5)/1.1
E = 21.2mV.
The resistance in the copper loop is given to be 2.7 ohm.
Now, the induced current in the circuit will be given by the relation,
I = E/R
Putting all the values
I = 21.2/2.7
I = 7.85 mA.
So, the induced current in the wire is 7.85 milliamps.
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A 1000-kilogram space vehicle travels at 5 meters per second along the level road. The magnitude of the normal force acting on the vehicle is approximately A) 1000N B) 5000N C) 10000N D) 50000N
Answers
Answer:
C = 10000N
Explanation:
On a level surface, with no other force acting on the vehicle,
|Normal force| = |Weight|,
Weight = mass * acceleration due to gravity
= 1000 kg * 9.8 m/s^2 or N/kg
= 9800 N
--> 10000 N rounded to one significant digit
a) Calculate the ratios of longitudinal modulus of the composite to the matrix modulus for glass/epoxy and carbon /epoxy composites with 10% and 50% fibers by volume. Elastic modules of glass fibers, carbon fibers and epoxy resin are 70, 350, and 3.5 GPa, respectively.
b) Discuss what is the effect of the fibers in the elastic modulus of the composite in the longitudinal direction (2-3 phrases.)
Answers
carbon fibers and epoxy resin have respective tensile strengths of 70, 350, and 3.5 GPa. According to these estimates, fibers are particularly effective at increasing the composite modulus in the longitudinal direction.
(a) [tex]V_{f}[/tex]=[tex]A_{f} /A_{c}[/tex] ,[tex]V_{m} =A_{m}/A_{c}[/tex]
The elastic modulus of the composite is given by
E[tex]_{c}[/tex]=[tex]E_{f} V_{f} +E_{m} V_{m}[/tex]
E[tex]_{c}[/tex]/E[tex]_{m}[/tex]=([tex]E_{f} /E_{m}[/tex] - 1) [tex]V_{f}[/tex]+1
the calculation will give the following result
System([tex]E_{f} /E_{m}[/tex]) [tex]V_{f}[/tex]=10% [tex]V_{f}[/tex]=50%
Glass – epoxy(20) 2.9 10.5
Carbon epoxy (100) 10.9 50.5
(b) 50 It has been found that as the volume fraction of fiber grows by a factor of 5, the ratio (E[tex]_{c}[/tex]/E[tex]_{m}[/tex]) similarly increases by a corresponding amount (3.62 for glass epoxy and 4:63 for carbon epoxy )
Additionally, as the fiber modulus increases by a factor of 5, the ratio of (E[tex]_{c}[/tex]/E[tex]_{m}[/tex]) increases by a comparable factor (3.7 at [tex]V_{f}[/tex]=10% and 4.81 at [tex]V_{f}[/tex] =50%). These calculations demonstrate that fibers are particularly successful in raising the composite modulus in the longitudinal direction.
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A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As observed by a person standing on the ground and viewing the plane as in the figure below, which of the paths 1-5 would the bowling ball most closely follow as it falls to the ground.a. 10
b. 2
c. 4
d. 45
Answers
4th paths out of 1 - 5 would the bowling ball most closely follow as it falls to the ground
The bowling ball moves due to the resultant force of the vertical and horizontal direction.
What is resultant force ?The overall force operating on the item or body as well as the direction in which the body is moving are referred to as the resultant force. When the object is stationary or moving at the same speed as it, there is no consequent force.
The outcome is what is produced when vectors are added together. The biggest (maximum) consequent when adding two vectors is equal to their sum when forces are acting in the same direction.
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A penguin slides on ice.
A. Newton's First Law of Motion
B. Newton's Second Law of Motion
C. Newton's Third Law of Motion
Answers
Answer:
Newton's first law: An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force.
find the degeneracy of the second, third, fourth, and fifth levels for the threedimensional cubical box.
Answers
The degeneracies of the first, fourth and fifth energy levels for the three dimensionsal cubical box are 1, 3 and 1.
Calculation :
Given Data
A three-dimensional cubic box with
lx=ly=lz=Li.
For a 3D cubic box, the energy of the particle in a box is having a formula given below,
E3D=h²8m(n²x/l²x+n²y/l²y+n²z/l²z)
Given,
lx=ly=lz=Li, put in the above equation, we get,
E3D=h²/8m(n²x/L²+n²y/L²+n²z/L²)
E3D=h²/8mL²(n²x+n²y+n²z)
Now, for the First energy level, the energy will be,
E3D=h²/8mL²(1²+1²+1²)
E3D=3h²/8mL²
The degeneracy is equal to 1 because nx=ny=nz=1.
Now, for the Fourth energy level, the energy will be,
E3D=h²/8mL²(1²+1²+3²)
E3D=h²/8mL²(1+1+9)
E3D=11h²8mL²
The degeneracy is equal to 3 because, nx=1,ny=1,nz=3,nx=1,ny=3,nz=1 and nx=3,ny=1,nz=1.
Now, for the Fifth energy level, the energy will be,
E3D=h²/8mL²(2²+2²+2²)
E3D=h²/8mL²(4+4+4)
E3D=12h²/8mL²
The degeneracy is equal to 1 because nx=2,ny=2,nz=2.
Therefore, the degeneracies of the first, fourth and fifth energy levels are 1, 3 and 1.
Energy levels are degenerate if they correspond to two or more different measurable states of a quantum system. Conversely, two or more distinct states of a quantum mechanical system are said to be degenerate if they have the same energy value when measured. The number of different states corresponding to a particular energy level is called the degeneracy of the level.
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A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm are 160 cm apart. A 2.5 cm-tall object is 60 cm in front of the converging lens.
Calculate the image position. cm in front of the second lens.
Calculate the image height.
Answers
1.25 cm is the height of the image. 160 cm separates a converging lens with such a 40 cm focal length from a diverging lens with the a -40 cm focal length. The converging lens is 60 cm away from a 2.5 cm tall item.
What does a converging or diverging lens mean?A lens that conforms a parallel source beam of light is known as a converging lens. One kind of converging lens is a double convex lens. Converging Lens A lens that separates a parallel light beam is known as a diverging lens. Diverging lenses include those that are double concave.
For the diverging lens, this image height corresponds to object height. We obtain h ′D=(20cm40cm)(5.0cm)=1.25cm again for diverging lens as a result.
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- A basketball strikes the rim of the basket. Explain each force in the force pair.
Answers
A basketball experiences four forces as it soars through the air. The ball is being pulled down to the Earth by gravity, being propelled upward by buoyancy, and slowed down due to the drag force created by the air it collides with.
What is force ?A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
For instance, a basketball will strike the ground hard when it is dribbled. The ground's force on the ball is balanced by this force of the ball on the ground. The ball is sent upwards by the second force since it acts in the opposite direction. There are numerous characteristics of motion that depend on this interaction.
Thus, A basketball experiences four forces as it soars through the air.
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A wire is formed into a circle having a diameter of 20.0 cm and placed in a uniform magnetic field of 2.50 mT. The wire carries a current of 5.00 A.
(a) Find the maximum torque on the wire.
_____ µN·m
(b) Find the range of potential energies of the wire-field system for different orientations of the circle.
minimum
_____µJ
maximum
_____ µJ
Answers
The maximum torque on the wire is 392.3 µN·m and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)
Torque: Torque is a measure of the force that can cause an object to rotate about an axis. It is a vector quantity.
Given that,
diameter D=20cm
Radius r =10cm
magnetic field B =2.5mT
current I=5A
Torque= n×B
=nBsinФ
torque=nB= NIAB
= 1×5×π×[tex]10^{2}[/tex]×[tex]10^{-4}[/tex]×2.5×[tex]10^{-3}[/tex]
= 39.23×[tex]10^{-5}[/tex]
= 392.3µN·m
minimum potential energy= -nB= -392.3µN·m
maximum potential energy =+nB= +392.3µN·m
Therefore the maximum torque on the wire is 392.3 µN·m when is placed in an uniform magnetic field of 2.50mT and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)
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which of the following vectors best describes the path of the airplane? question 6 options: none of these
Answers
The following vectors best describes the path of the airplane Aniseed of the as plan is 528 [tex]\mathrm{mi} / \mathrm{hr}[/tex]
What is airplane?
A fixed-wing aircraft that is pushed forward by the thrust of a jet engine, propeller, or rocket engine is known as an aeroplane or aeroplane. There are many different sizes, forms, and wing arrangements for airplanes.
[tex]\text { bearing } 25^{\circ} \text { west of north }[/tex]
[tex]\text { Since } \quad 90^{\circ}+25^{\circ}=115^{\circ}[/tex]
[tex]\text { so path of the airplane is }[/tex]
[tex]\left.v=528 \cos \left(i 15^{\circ}\right) i+528 \sin \left(115^{\circ}\right)\right][/tex]
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what is the amplitude and period of this wave? I WILL MARK BRAINLIEST!
Answers
Answer:
amplitude:1m
period:10s
Explanation:
