Part 1: Parallel & Skew Lines & Planes
1.) Name a segment skew to line AB.
2.) Name a segment parallel to line AD.
3.) Name a plane parallel to plane DCH.
4.) Name a plane that is NOT parallel to plane EFG.

No cup of ketchup remains.

Brown Sugar =1/4 C

Cider Vinegar = 1/2 C

Ground Cumin = 1tsp

Ketchup           = 2/3 C

Pepper             = 1tsp

Total Quantity of Ketchup =9 cups

1 batch of barbecue sauce =2/3 Cup

x batch of barbecue sauce =9 Cups

x batch of barbecue sauce = 9 Cups *1 batch of barbecue sauce

                                                               2/3 Cup

x batch of barbecue sauce =13[tex]\frac{1}2}[/tex] batches

we know that;

1 batch of barbecue sauce =2/3 Cup

Therefore,

The total number of ketchup Cups used = Total  batch of barbecue sauce *quantity for1 batch of barbecue sauce

               =       13[tex]\frac{1}2}[/tex] batches * 2/3 Cup

The total number of ketchup Cups used =  9 Cups  

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The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .

The charge at which anything happens is referred to as the velocity at which it happens.

The required details for mean rate :

(a) H0: µ = 21.62

Ha: µ ≠ 21.62

(b) t = -1.231

p-value = 0.2253

(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.

(d) H0: µ = 21.62

Ha: µ ≠ 21.62

t = -1.231

check statistic ≥ 2.020

Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.

The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.

The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.

The crucial values for t at this level of significance are t=2.019.

Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.

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A student can take one of each subject in 40 different ways as calculated using the properties of permutation and combination..

So there are four separate math classes, five different science courses, and two different history courses.

There are now 4 ways to complete a math course.

There are 5 different ways to take science courses.

There are two ways to take a history course.

Total ways are now calculated as the product of the potential ways for each course, which equals 4 × 5 x 2 or 40 ways.

As a result, there are 40 possible combinations for three subjects.

In mathematics, a permutation of a set is, if the set also has an ordered structure, the rearranging of its members into a sequence or linear order. The technique of altering an ordered set's linear order is known as permutation.

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Answer:

y=-2x+2: second graph

y=-2x-5: third graph

y= 3/2x+5: first graph

Step-by-step explanation:

we can just look at the y intercept since each equation has different ones

The graphs are left to right so I’ll call it by 1st graph 2nd graph and last graph

y=mx+b is slope intercept formula where big y intercept

The first equation b or the y intercept is 2 and the only graph where the Line intersects with the y axis at 2 is the second one

The second equation has a y intercept of -5 so the last graph is the only one that line intersects with the y axis at -5

the last equation has a y intercept of 5 so the first graph is the only one where the line intersects with 5

Hopes this helps please mark brainliest

The had to wait for the second flight for 40 mins.

We know that sometimes when a person is travelling there may be need to have a flight that connects a person from one place to another and at times you would have to wait for a connecting flight and this wait would add to the total time that is required for the journey.

Now we are told in the question that it takes 8 hours and 5 minutes to travel from Hong Kong to Dubai and that they left Dubai at 2250 hrs but landed in Hong King at  1405 hrs. The time in between must be;  2250 hrs - 1405 hrs = 8: 45 hrs thus the time of waiting is 40 minutes.

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T statistics are more unpredictable than z scores since they employ sample variance rather than population variance.

Thus, because the t statistic employs the sample variance rather than the population variance, it is more volatile than z scores.

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1) missing number is 7 (answer #2)

Each circles' numbers add up to 20. (the first one is 1 + 9 + 10, the second is 5 + 4 + 11.)

20 minus 10 minus 3 is 7, so that's the missing number.

2) missing number is 3 (answer #4)

This one's similar to the previous question. Each square's numbers have a sum of 10, this time. (First square is 2 + 7 + 1 + 0, second is 4 + 3 + 1 + 2.)

10 minus 6 minus 1 minus 0 is the same as 10 minus 7. This equals 3- so there's the number that's missing!

Hopefully this helps!

5) <OSL

Vertical pair angles are equal angles formed by intersecting lines

6) <MSN (or <LOS)

Supplementary angles are angles that add up to 180 degrees

Rosie's statement about expecting a total of about 175 points over 100 turns is accurate.

Based on the expected value, Rosie's statement is correct.

The expected value, denoted as E(X), represents the average or mean value of a random variable, in this case, the sum of points in a given turn when rolling the five dice.

Tom's statement, "A player will most likely get 17.5 points in any given roll," is not accurate. The expected value of 17.5 points does not necessarily mean that a player is most likely to get exactly 17.5 points in any single roll. Instead, it indicates that over many rolls, the average value of points earned in a turn is 17.5 points.

On the other hand, Rosie's statement, "Over 100 turns, we can expect a total of about 175 points," is correct. Since the expected value is 17.5 points per turn, over 100 turns, we can expect the total sum of points to be approximately 100 turns × 17.5 points/turn = 1750 points.

In summary, the expected value of 17.5 points represents the average outcome over multiple rolls, and based on this value, Rosie's statement about expecting a total of about 175 points over 100 turns is accurate.

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The complete question:

Tom and Rosie are designing a game. In each turn, a player rolls five 6-sided dice and adds the numbers showing on each face to determine how many points they get that turn. For example, the lowest number of points in a given turn is 1+1+1+1+1=5 points, and the highest is 6+6+6+6+6=30 points.

They let X represent the sum in a given turn, and they find the expected value of X is E(X) = 17.5 points.

Tom says, "A player will most likely get 17.5 points in any given roll."

Rosie says, "Over 100 turns, we can expect a total of about 175 points."

Whose statement is correct based on the expected value?

The system of equation 2x + 6y = 10 , x = 8 - 3y has no solution.

System of equation can be solved using different method such as substitution method, elimination method and graphical method.

Let's use substitution method to solve the system of equation as follows:

2x + 6y = 10

x = 8 - 3y

substitute equation(ii) in equation(i)

2(8 - 3y) + 6y = 10

16 - 6y + 6y = 10

16 + 0 = 10

Therefore, the equation has no solution.

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The length of Rocky Mountain Juniper tree will be 1.269 feet.

What is Proportional?

Any relationship that is always in the same ratio and quantity which vary directly with each other is called the proportional.

Given that;

A tour guide for Yellowstone National Park is 5.1 feet tall and casts a shadow of 81.6 inches.

Now,

Let the height of Rocky Mountain Juniper tree = x feet

And, A tour guide for Yellowstone National Park is 5.1 feet tall and casts a shadow of 81.6 inches.

So, The height of a Rocky Mountain Juniper tree be if at the same time of day it casts a shadow of 20.3 feet will be find as;

⇒ 5.1 / 81.6 = x / 20.3

Solve for x as;

⇒ 5.1 × 20.3 / 81.6 = x

⇒ 103.53 / 81.6 = x

⇒ x = 1.269 feet

Thus, The length of Rocky Mountain Juniper tree will be 1.269 feet.

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The 95% confidence interval for the population mean SAT score is given as follows:

(1340, 1460).

The confidence interval is calculated using the t-distribution, as the standard deviation for the population is not known, only for the sample.

The bounds are obtained according to the equation defined as follows:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which the variables of the equation are presented as follows:

In the context of this problem, the values of these parameters are given as follows:

[tex]\overline{x} = 1400, n = 64, s = 240[/tex]

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 64 - 1 = 63 df, is t = 1.998.

Then the lower bound of the interval is of:

1400 - 1.998 x 240/sqrt(64) = 1340.

The upper bound of the interval is of:

1400 + 1.998 x 240/sqrt(64) = 1460.

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Answer:

A

Step-by-step explanation:

Eliminate B and C because they don't pass through (0,1).

Eliminate D because it doesn't decrease quickly enough.

Answer: No solution

Step-by-step explanation:

3y - x = (3 * 2 - 18) = 6 - 18 = -12

3y - x = -12

x - 3y = 12

since parallel lines, by definition, have NO point of intersection, there is no solution.

Answer:

98.6

Step-by-step explanation:

in photo!!

Answer:

6115

Explanation:

[tex]70000(1-0.15)^{15} \approx 6115[/tex]

Answer:

6115

Explanation:

[tex]70000(1-0.15)^{15} \approx 6115[/tex]

The total change in the stock market from the beginning of the day to the end of the day is 89.75

A fraction is written in the form of a numerator and a denominator where the denominator is greater than the numerator.

Example: 1/2, 1/3 is a fraction.

We have,

At the beginning of the day, the stock market goes up 30 1/2 points.

At the end of the day, the stock market goes down 120 1/4 points.

The total change in the stock market from the beginning of the day to the end of the day.

= 120(1/4) - 30(1/2)

= 481/4 - 61/2

= 120.25 - 30.5

= 89.75

Thus,

The total change in the stock market from the beginning of the day to the end of the day is 89.75

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Answer:

the remaining mass is 7.3 g

Step-by-step explanation:

a=30g

t=200 years

h=98 years

f(98)=a([tex](\frac{1}{2})^ \frac{t}{h}[/tex]

f(98)=30([tex](\frac{1}{2})^ \frac{200}{98}[/tex]

f(98)=7.3

The statement if true, for 95% of the samples from the population, the confidence interval we compute will contain the true mean.

In the given question we have to check whether the given statement is TRUE or FALSE.

The given statement is:

For 95% of the samples from the population, the confidence interval we compute will contain the true mean.

Because the underlying approach succeeds on 95% of random samples, we have a 95% confidence that this confidence interval contains the population mean.

Approximately 95% of the estimated intervals will contain the actual value of the population mean if samples are taken frequently and 95% confidence intervals are generated.

So the given statement is true.

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If x and y are independent variables such that x has uniform distribution (0,1) and y has exponential distribution means 1 then e (X+Y) is 3/2, E(XY) is 1/2, E (x-y)2 is 4/3 and E x2 e24 is -1/3

[tex]2^{2}[/tex][tex]e^{ty}[/tex]x ≈ u (0,1) > Independent

y ≈ exp (1) > Independent

E (x) = 0+1/2 = 1/2

v (x) = [tex][1- 0 ] ^{2}[/tex] / 12 = 1/12

E [tex]x^{2}[/tex] = v (x) + [tex][ E x]^{2}[/tex]

       = 1/12 + 1/4 = 1+3/12 = 4/12 = 1/3

E (y) = 1  v(y)=1  E [tex]y^{2}[/tex]= 1+1= 2

E[tex]e^{ty}[/tex] = [tex]\int\limits^_0[/tex][tex]e^{ty}[/tex][tex]e^{-y} dy[/tex]

E[tex]e^{ty}[/tex]  = [tex]\int\limits^_0[/tex][tex]e^{-y} (1-t)[/tex] dy

a : E (x+y) = E (x) + E(y)

       E (x+y) = 1/2+1 = 3/2

b: E (xy) = E (x) E(y) = 1/2 x 1 = 1/2

c: E [tex][x-y]^2[/tex] = E ([tex]x^{2}[/tex]-2xy+ [tex]y^{2}[/tex]

   = E [tex]x^{2}[/tex] - 2 Exy + E [tex]y^{2}[/tex]

  =  1/3 - 2 x 1/2 + 2

   = 1/3 + 1 = 4/3

d. E [tex]x^{2}[/tex] [tex]e^{24}[/tex]

   E ([tex]x^{2}[/tex] ) E [tex]e^{24}[/tex] = 1/3 x -1 = - 1/3

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The expression of the radius is √3v/πx

The equation of the volume is given as

v = 1/3πr²x

Where

r= radius

x = height

So, we have

v = 1/3πr²x

Multiply both sides of the equation by 3

This gives

3v = πr²x

Divide both sides of the equation by πx

So, we have the following representation

3v/πx = r²

Take the square root of both sides

r = √3v/πx

Hence, the radius expression is √3v/πx

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[tex]Answer:\ f^{-1}(x)=\boxed{6^{-x}}[/tex]

Step-by-step explanation:

[tex]\displaystyle\\f(x)=6^x\\\\f^{-1}(x)=(6^x)^{-1}\\\\f^{-1}(x)=\frac{1}{6^x} \\\\f^{-1}(x)=6^{-x}[/tex]

Answer:

Step-by-step explanation:

First of all let's look at the side lengths of both figures.

Let's see how the corresponding sides relate:-

[tex]\sf 6*\cfrac{1}{3} =3[/tex]

[tex]\sf 3*\cfrac{1}{3} =1[/tex]

We can see that all sides scale by the same factor of 1/3.

Therefore, YES A is a scaled copy of Figure B.

______________________

Hope this helps!

Have a great day!

The graph of the line that represents the given equation, 3x - 4y = 8, is shown below

From the question, we are to graph the line that represents the given equation.

The given equation is

3x - 4y = 8

To graph the line, we will determine x-intercept and y intercept of the line.

The x-intercept in the point where y equals zero on the line

and

The y-intercept in the point where x equals zero on the line

Determining the x-intercept

3x - 4y = 8

Set y = 0

3x - 4(0) = 8

3x = 8

x = 8/3

The x-intercept is (8/3, 0)

Determining the y-intercept

3x - 4y = 8

Set x = 0

3(0) - 4y = 8

-4y = 8

y = 8/-4

y = -2

The y-intercept is (0, -2)

Using the x-intercept and y-intercept, the graph of the line is shown below

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The Java code that follows inserts the code into the main function so that the result may be obtained. It incorporated the appropriate questions related to pet so that users could choose the data they should fill in.

Proper class naming and naming practises provide the following advantages:

Even if you aren't the person who developed it or if it was written a long time ago, you know what to anticipate from a specific class without looking at code or documentation.

A codebase is simple to find and traverse.

Speaking with your team about issues or improvements is simpler.

It facilitates newbie onboarding and reduces confusion.

A correctly utilised MVP with a defined name standard is generally a nice illustration of working name expectations. You would anticipate that a class named UseCase/Interactor would provide business logic.

How to solve?

import java.util.Scanner;

public class PetInformation {

 public static void main(String[] args) {

      Scanner scnr = new Scanner(System.in);

      String petName, dogName;

      String dogBreed = "null";

      int petAge, dogAge;

      Pet myPet = new Pet();

      System.out.println("Enter Pet Name:");

      petName = scnr.nextLine();

      System.out.println("Enter Pet Age:");

      petAge = scnr.nextInt();

      Dog myDog = new Dog();

      System.out.println("Enter Dog Name:");

      dogName = scnr.next();

      System.out.println("Enter Dog Age:");

      dogAge = scnr.nextInt();

      scnr.nextLine();

      System.out.println("Enter Dog Breed:");

      dogBreed = scnr.nextLine();

      System.out.println(" ");

      myPet.setName(petName);

      myPet.setAge(petAge);

      myPet.printInfo();

      myDog.setName(dogName);

      myDog.setAge(dogAge);

      myDog.setBreed(dogBreed);

      myDog.printInfo();

      System.out.println(" Breed: " + myDog.getBreed());

  }

}

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