Las dos líneas más largas del terreno de juego se denominarán líneas de banda. Las dos más cortas se llamarán líneas de meta. El terreno de juego será rectangular y la longitud de las líneas de banda deberá ser mayor que las de las líneas de meta. La longitud de la línea de banda debe tener como mínimo 90 metros y como máximo 120 metros. La anchura de la línea de meta debe de tener como mínimo 45 metros y como máximo de 90 metros. Todas las líneas del terreno de juego deberán se líneas continuas y tener la misma anchura, como máximo 12 cm., menos las líneas de meta que deben tener la misma anchura que los postes y larguero de la portería. Todas las líneas que delimitan al campo forma parte del terreno de juego. El terreno de juego puede ser de tierra, césped natural ó césped artificial de color verde según las normas del reglamento de la competición. El terreno de juego está dividido en dos partes iguales por una línea que unirá los puntos medios de las dos líneas de banda. El centro del campo estará marcado con un punto situado en la mitad de la línea media que divide las dos partes iguales del campo, tomando este punto como centro, haremos circulo de un radio de 9,15 metros. También se puede poner un banderín en cada extremo de la línea de media, a una distancia mínima de 1 m al exterior de la línea de banda.
what are 2 ways elastic energy affects us as humans
Answer:
The coil spring of a wind-up clock.
An archer's stretched bow.
Explanation:
A dog runs 20 m east and then 35 m west in 12 seconds.
What is the dog speed? What is the dogs velocity?
Answer: Dog's speed = (20 + 35) /12 = 4.583 m/s
Dog's velocity = (20-35)/12 = -1.25 m/s
Explanation: Speed is a scalar quantity so we don't care about direction which means we add the magnitude of both the directions i.e. east and west.
About the velocity, it's a vector quantity. So, we must be very careful with the directions and signs. In cartesian coordinates system, we generally take the right side of origin as the positive x-axis and the left side of origin as the negative x-axis. So, considering the same fact, we consider east as positive side and west as the negative side.
Therefore, when we add 20m + (-35m), we get = -15m and you already have the time period of 12 s.
The speed of sound in air is about 330m/s. How long will it take to travel 1km answer in seconds to one decimal point
Answer:
3.03
Explanation:
time=distance/speed
1km=1000m
1000÷330
=3.030
what is the relationship between the variables on this graph? The temperature does not have an effect on flow time. As the temperature increases, the flow time increases. As the temperature increases, the flow time decreases.
Answer: As the temperature increases, the flow time increases.
Explanation: i took the test
The relationship between the variables on this graph is that As the temperature increases, the flow time increases, therefore the correct answer is option B.
What is the kelvin scale of temperature?It is a scale of temperature used to measure the temperature, the kelvin scale of temperature is also known as the absolute scale of temperature.
The Standard International unit of thermodynamic temperature is the kelvin, often known less frequently as the degree Kelvin. The formal definition of one kelvin is 1/273.16 of the thermodynamic temperature of pure water's triple point.
As shown in the graph as the temperature increase across the X axis the flow time is increasing as well, these two variables are directly proportional to each other.
Thus, The graph shows a link between the variables, showing that when the temperature rises, flow time also rises, hence option B is the proper response.
Learn more about the kelvin scale of temperature from here,
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Using the graph above determine the change in velocity between 0.0 s and 4.0 s.
- 1.0 m/s
1.0 m/s
-8.0 m/s
- 16 m/s
help me please i dont understand
Answer:
0.58
Explanation:
Sinẞ = opposite ÷ hypotenuse
Sinẞ = 5 ÷ 8.6
Sinẞ = 0.5814
Sinẞ ≈ 0.58
Answer: 0.58
Explanation:
hope this helps
Fun Fact: Peanuts aren’t technically nuts
calculate the frequency and time period of sound wave of 35 m wave length propagating at a speed of 3500m/s
Answer:
Frequency = 100 Hz
Time period = 0.01 sec
Explanation:
f= 3500/35 = 100
T = 1/f = .01
