People's movements between places is called

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the given angle, we know the opposite side and want to know the adjacent side. Therefore, we should use the tangent function.

tan(54) = 16/BC

BC = 16/tan(54)

BC = 11.62 units

Hope this helps!

Answer:

Slope = 5

Step-by-step explanation:

To find the slope of a line perpendicular to a given line, take the opposite reciprocal of the given line's slope.

Ex. -1/5 ⇒ 5

Opposite = opposite sign (- ⇒ +)

Reciprocal = numerator and denominator flipped (1/5 ⇒ 5/1 = 5)

Answer:

You'd think its 34% but apparently it's 16%.

I hope this is right. If its not then it must be 34%.

(A) -- or maybe (B). 80% confident it is A.

ED2021

Answer:

Quadratic

Step-by-step explanation:

Answer:

Linear

Step-by-step explanation:

for every one unit increase in x, there is a 3 unit increase in y

The slope of the plot line would be 3

The y intercept of the plot line would be -1

y = 3x - 1

Answer:

1)17

2)33

3)9

4)27

5)1252

6)50

Step-by-step explanation:

9514 1404 393

Answer:

  is a polynomial

Step-by-step explanation:

The expression is a sum of products.

Each product involves a numerical value and a product of variables to positive integer powers.

These meet the requirements for an expression to be a polynomial, so ...

  the given expression is a polynomial

Answer:

There are four ways to represent an inequality: Equation notation, set notation, interval notation, and solution graph.

Answer:

Option C. √280

Step-by-step explanation:

From the question given above, the following data were obtained

MN = 19

ML = 9

LN =?

We can obtain the value of LN by using the pythagoras theory as illustrated:

M ² = ML² + LN²

19² = 9² + LN²

361 = 81 + LN²

Collect like terms

361 – 81 = LN²

280 = LN²

Take the square root of both side

LN = √280

Therefore, the length of LN is √280

This requires finding the number of small sweaters the company made last week

Number of small sweaters the company produced last week is 372

Total sweaters made = 1,612

Let

Small sweaters = 3x

Medium sweaters = x

Large sweaters = 3(3x) = 9x

Total = small + medium + large

1,612 = 3x + x + 9x

1612 = 13x

Divide by 13

x = 1612/13

Medium sweaters = x = 124

Small sweaters = 3x

= 3(124)

= 372

Read more:

https://brainly.com/question/24326559

y + z + r + x = 360

2x + 3x + 4x + x = 360

10x = 360

x = 360/10

x = 36

Now

x = 36

y = 72

z = 108

r = 144

Answered by Gauthmath must click thanks and mark brainliest

Answer:

It's a decimal, so it's around 6.771cm

Step-by-step explanation:

First, divide 144cm² by pi, or 3.14. Then find the square root of the answer, giving you the radius. The formula for the area of a circle is pi x radius squared, so to find out the radius you just use this formula in reverse.

If I messed up or didn't make my explanation clear, please comment.

Answer:

radius is [tex]\frac{12}{\sqrt{\pi } }[/tex] = 6.77 cm

Step-by-step explanation:

we know,

[tex]\pi[/tex] × r² = Area

⇒ [tex]\pi[/tex] × r² = 144

⇒ r² =[tex]\frac{144}{\pi}[/tex]

⇒ r= [tex]\frac{12}{\sqrt{\pi } }[/tex]

∴ r= [tex]\frac{12}{\sqrt{\pi } }[/tex]

pls mark this as the braniliest

Let it be x

Using basic proportionality theorem

[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{14}{7}[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{10}=2[/tex]

[tex]\\ \sf\longmapsto x=10(2)[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

use x^2 when x=0 because the restriction for it is "use x if x is less than or equal to 1"

when x = 0, (0)^2 will make f(x) = 0

the graph of f(x) will just be a dot at 0

Answer: Distance = √145

Concept:

Here, we need to know the concept of the distance formula.    

The distance formula is the formula, which is used to find the distance between any two points.

If you are still confused, please refer to the attachment below for a clear version of the formula.

Solve:

Given information

(x₁, y₁) = (4, -9)

(x₂, y₂) = (5, 3)

Given formula

[tex]Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substitute values into the formula

[tex]Distance = \sqrt{(5-4)^2+(3+9)^2}[/tex]

Simplify values in the parentheses

[tex]Distance = \sqrt{(1)^2+(12)^2}[/tex]

Simplify exponents

[tex]Distance = \sqrt{1+144}[/tex]

Simplify by addition

[tex]Distance = \sqrt{145}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

[tex]\boxed {\boxed {\sf \sqrt {145} \ or \ 12.04}}[/tex]

Step-by-step explanation:

The distance between 2 points is calculated using the following formula.

[tex]d= \sqrt {(x_2-x_1)^2+(y_2-y_1)^2)[/tex]

In this formula, (x₁, y₁) and (x₂, y₂) are the coordinates of the two points.

We know the two points are (4, -9) and (5,3). If we match the values of the points and the coordinating variable, we see that:

Substitute the values into the formula.

[tex]d= \sqrt { ( 5 -4)^2 + ( 3 --9)^2[/tex]

Solve inside the parentheses.

[tex]d= \sqrt {(1)^2 + (12)^2}[/tex]

Solve the exponents.

[tex]d= \sqrt{ 1+144}[/tex]

Add.

[tex]d= \sqrt{145[/tex]

Take the square root.

[tex]d=12.04159458[/tex]

Let's round to the nearest hundredth. The 1 in the thousandth place tells us to leave the 4 in the hundredth place.

[tex]d \approx 12.04[/tex]

The distance between the 2 points is √145 or approximately 12.04.

Answer:

Reflection

Step-by-step explanation:

It is the opposite of the first,...

13x - 4[x + (3 - x)] =

= 13x - 4(x + 3 - x) =

= 13x - 4 · 3 = 13x - 12

C.

Answer:

13x -12

Step-by-step explanation:

13 x - 4[ x + (3 - x )].

Combine like terms inside the brackets

13 x - 4[ 3 -0x]

13x - 4[3]

Multiply

13x -12

Answer:

Megan’s at 2.5 inches per week

Answer:

a. 1.44

Step-by-step explanation:

We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.

At the null hypothesis, it is tested if the proportion is of at most 40%, that is:

[tex]H_0: p \leq 0.4[/tex]

At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:

[tex]H_1: p > 0.4[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that [tex]p = 0.4, \sigma = \sqrt{0.4*0.6}[/tex]

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.

This means that:

[tex]n = 200, X = \frac{90}{200} = 0.45[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}[/tex]

[tex]z = 1.44[/tex]

Thus the correct answer is given by option a.

Answer:

A: The distribution is skewed to the left.

Step-by-step explanation:

Skewness:

If the distribution has a long left tail, it is skewed to the left.

If it has a long right tail, it is skewed to the right.

Otherwise, it is approximately symmetrical.

In this question:

Lots of values on the start(left), few on the end(right), so it is skewed to the left, and the correct answer is given by option a.

Answer:

x= (2+ √ 34) /5 , (2- √ 34) /5

decimal form= 1.566

Step-by-step explanation:

That's a question about quadratic function.

Any quadratic function can be represented by the following form:

[tex]\boxed{f(x)=ax^2+bx+c}[/tex]

Example:

[tex]f(x)= -3x^2-9x+57[/tex] is a function where [tex]a=-3[/tex], [tex]b=-9[/tex] and [tex]c=57[/tex].

Okay, in our problem, we need to find the value of x when [tex]f(x)=0[/tex]. That's mean that the result of our function is equal to zero. Therefore, we have the quadratic equation below:

[tex]x^2+4x-5=0[/tex]

To solve a quadratic equation, we use the Bhaskara's formula. Do you remember the value of a, b and c? They going to be important right now. This is the Bhaskara's formula:

[tex]\boxed{x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} }[/tex]

So, let's see the values of a, b and c in our equation and apply them in the Bhaskara's formula:

In [tex]x^2+4x-5=0[/tex] equation, [tex]a=1[/tex], [tex]b=4[/tex] and [tex]c=-5[/tex]. Let's replace those values:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-4\pm \sqrt{4^2-4\times1\times(-5)} }{2\cdot1}[/tex]

[tex]x=\frac{-4\pm \sqrt{16-(-20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{16 + 20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{36} }{2}[/tex]

[tex]x=\frac{-4\pm 6 }{2}[/tex]

From now, we have two possibilities:

To add:

[tex]x_1 = \frac{-4+6}{2} \\x_1=\frac{2}{2} \\x_1=1[/tex]

To subtract:

[tex]x_2=\frac{-4-6}{2} \\x_2=\frac{-10}{2} \\x_2=-5[/tex]

Therefore, the result of our problem is: [tex]x_1 = 1[/tex] and [tex]x_2=-5[/tex].

I hope I've helped. ^^

Enjoy your studies.  \o/

Let a, b, and c be vectors each starting at the origin and terminating at the points (x, x + 1), (x + 2, x + 3), and (x + 3, 2x + 4), respectively.

Then the vectors a - b, a - c, and b - c are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.

If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:

(a - b) • (a - c) = 0

or

(a - b) • (b - c) = 0

or

(a - c) • (b - c) = 0

We have

a - b = (x, x + 1) - (x + 2, x + 3) = (-2, -2)

a - c = (x, x + 1) - (x + 3, 2x + 4) = (-3, -x - 3)

b - c = (x + 2, x + 3) - (x + 3, 2x + 4) = (-1, -x - 1)

Case 1: If (a - b) • (a - c) = 0, then

(-2, -2) • (-3, -x - 3) = (-2)×(-3) + (-2)×(-x - 3) = 2x + 12 = 0   ==>   x = -6

which would make a - c = (-3, 3) and b - c = (-1, 5), and their dot product is not zero. Then the triangles vertices are at the points (-6, -5), (-4, -3), and (-3, -8).

Case 2: If (a - b) • (b - c) = 0, then

(-2, -2) • (-1, -x - 1) = (-2)×(-1) + (-2)×(-x - 1) = 2x + 4 = 0   ==>   x = -2

which would make a - c = (-3, -1) and b = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).

Case 3: If (a - c) • (b - c) = 0, then

(-3, -x - 3) • (-1, -x - 1) = (-3)×(-1) + (-x - 3)×(-x - 1) = x ² + 4x + 6 = 0

but the solutions to x here are non-real, so we throw out this case.

So there are two possible values of x that make a right triangle, x = -6 and x = -2.

Answer:

[tex]x ^{m - 3} \div x^{m - 4} \\ \frac{ {x}^{m - 3} }{ {x}^{m - 4} } \\ \frac{ {x}^{m - 3 - m + 4} }{x} \\ \frac{ {x}^{1} }{x} \\ x \: and \: x \: will \: cancel \: each \: other \: hence \: answer \: will \: be \: 1[/tex]

Answer:

x = 4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Pytago:

x[tex]x^{2} +7^{2} = 9^{2} \\\\x = \sqrt{9^{2} - 7^{2} } x = 4\sqrt{2}[/tex]

Answer:

Not very sure what you mean,

But in the provided set, 8 is the greatest number, and 1 is the smallest.

Hope this helps!!

9514 1404 393

Answer:

  y < 3x -4

Step-by-step explanation:

The boundary line has a slope (rise/run) of 3/1 = 3. It has a y-intercept of -4. The shaded area is below the line and the solution does not include the line. The relevant inequality can be written ...

  y < 3x -4