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Answer:

a=1

b=-5

c=6

Step-by-step explanation:

ax^2+bx+c=0

Is the formula used for this question.

The given function is the same as y = 1x^2 + (-5x) + 6

Compare it to the form y = ax^2+bx+c, and we have the following:

a = 1

b = -5

c = 6

Answer:

1 hour

Step-by-step explanation:

hope it helps ....

Answer:

prime number between 1 to7

The description of set P is the set of prime numbers less than or equal to 7 and the rule is {x | x is a prime number less than or equal to 7}

The set P is given as:

P = {2,3,5,7}

Note that the numbers are prime numbers.

This means that the description of set P is the set of prime numbers less than or equal to 7

The rule form of the set would be:

P = {x | x is a prime number less than or equal to 7}

Read more about sets at:

https://brainly.com/question/1563195

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Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3.

Answer:

-3,4 are the TWO integers whos product is -12 and whose sum is 1.

Step-by-step explanation:

-3×4=12

-3+4=1

Answer:

Not sure but I think it might be A

Step-by-step explanation:

Took the test

Answer:

12,-2

Step-by-step explanation:

Answer:

41

Step-by-step explanation:

Answer:

rs. 81

Step-by-step explanation:

given,

mp. = 1620

sp. = 1539

now,

discount = mp - s.p = 1620 - 1539 = 81

Answer:

% change in perimeter = 43. 44 %

% change in area = 16 %

Step-by-step explanation:

initial perimeter of the rectangle = 2(2p + p)

= 6p

initial area of the rectangle = 2p × p

= 2p²

therefore,

= 2p + 0.8p = 2.8 p

= p - 0.4p

= 0.6 p

= 3.4 p

= 1.68 p²

% change in perimeter

[tex] = \frac{6p - 3.4p}{6p} \times 100 \\ = \frac{2.6p}{6p} \times 100 \\ = 43.33\%[/tex]

% change in area

[tex] \frac{2 {p}^{2} - 1.68 {p}^{2} }{2 {p}^{2} } \times 100 \\ = \frac{0.32}{2} \times 100 \\ = 16\%[/tex]

Answer:

[tex]x=6[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]\displaystyle \log_6(2x-6)+\log_6x=2[/tex]

Recall the property:

[tex]\displaystyle \log_bx+\log_by=\log_b(xy)[/tex]

Hence:

[tex]\log_6(x(2x-6))=2[/tex]

Next, recall that by the definition of logarithms:

[tex]\displaystyle \log_b(a)=c\text{ if and only if } b^c=a[/tex]

Therefore:

[tex]6^2=x(2x-6)[/tex]

Solve for x. Simplify and distribute:

[tex]36=2x^2-6x[/tex]

We can divide both sides by two:

[tex]x^2-3x=18[/tex]

Subtract 18 from both sides:

[tex]x^2-3x-18=0[/tex]

Factor:

[tex](x-6)(x+3)=0[/tex]

Zero Product Property:

[tex]x-6=0\text{ or } x+3=0[/tex]

Solve for each case. Hence:

[tex]x=6\text{ or } x=-3[/tex]

Next, we must check the solutions for extraneous solutions. To do so, we can simply substitute the solutions back into the original equations and examine its validity.

Checking x = 6:

[tex]\displaystyle \begin{aligned} \log_{6}(2(6)-6)+\log_{6}6&\stackrel{?}{=} 2 \\ \\ \log_6(12-6)+(1)&\stackrel{?}{=}2 \\ \\ \log_6(6)+1&\stackrel{?}{=}2 \\ \\ 1+1=2&\stackrel{\checkmark}{=}2\end{aligned}[/tex]

Hence, x = 6 is indeed a solution.

Checking x = -3:

[tex]\displaystyle\begin{aligned} \log_6(2(-3)-6) + \underbrace{\log_6-3}_{\text{und.}} &\stackrel{?}{=} 2\\ \\ \end{aligned}[/tex]

Since the second term is undefined, x = -3 is not a solution.

Therefore, our only solution is x = 6.

Answer:

x = 6

Step-by-step explanation:

The given logarithmic equation is ,

[tex]\implies log_{6}(2x - 6) + log_{6}x = 2[/tex]

We can notice that the bases of both logarithm is same . So we can use a property of log as ,

[tex]\bf \to log_a b + log_a c = log_a {( ac)} [/tex]

So we can simplify the LHS and write it as ,

[tex]\implies log_{6} \{ x ( 2x - 6 )\} = 2 [/tex]

Now simplify out x(2x - 6 ) . We get ,

[tex]\implies log_6 ( 2x^2 - 6x ) = 2 [/tex]

Again , we know that ,

[tex]\bf \to log_a b = c , a^c = b [/tex]

Using this we have ,

[tex]\implies 2x^2 - 6x = 6^2 \\\\\implies 2x^2 - 6x -36 = 0 [/tex]

Now simplify the quadratic equation ,

[tex]\implies x^2 - 3x - 18 = 0 \\\\\implies x^2 -6x + 3x -18=0\\\\\implies x( x -6) +3( x - 6 ) = 0 \\\\\implies (x-6)(x+3) = 0 \\\\\implies x = 6 , -3 [/tex]

Since logarithms are not defined for negative numbers or zero , therefore ,

[tex]\implies 2x - 6 > 0 \\\\\implies x > 3 [/tex]

Therefore the equation is not defined at x = -3 . Hence the possible value of x is 6 .

[tex]\implies \underline{\underline{ x \quad = \quad 6 }}[/tex]

Answer:

1/3 fraction of whole paint is used by mark

Step-by-step explanation:

Mark used  1/2 out of 3/2 cans.

[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]

Answer:

Step-by-step explanation:

Use the formulas that allow us to find the point that divides the segment into a ratio which is

[tex]x=\frac{bx_1+ax_2}{a+b}[/tex]  and  [tex]y=\frac{by_1+ay_2}{a+b}[/tex] where a is 1 (comes from the ratio) and b is 3 (comes from the ratio as well). Filling in:

[tex]x=\frac{3(9)+1(6)}{1+3}=\frac{27+6}{4}=\frac{33}{4}[/tex] and then y:

[tex]y=\frac{3(-1)+1(-10)}{1+3}=\frac{-3-10}{4}=-\frac{13}{4}[/tex] so the coordinates in question are

[tex](\frac{33}{4},-\frac{13}{4})[/tex]

Answer:

Step-by-step explanation:

the answer would be (7,-7)

Answer:

Dilated pupils

Long periods of wakefulness

Loss of appetite

Overconfidence

Over-excitement

Paranoia

Runny nose or frequent sniffles

White powder around nostrils

Legal issues

Missing or being late to work

Financial problems

Mood swings

Irritability

Depression

Answer:

1

Step-by-step explanation:

64+32 =96 that'd how I got the answer

Answer:

[tex]{ \tt{8(2v + 8) = 96}} \\ { \tt{2v + 8 = 12}} \\ { \tt{2v = 4}} \\ { \bf{v = 2}}[/tex]

9514 1404 393

Answer:

  3.31227766..., irrational

Step-by-step explanation:

  3/20 +√10 = 0.15 + 3.16227766017...

The root of 10 is irrational, so adding that to a rational number will give an irrational sum.

The sum is about 3.31227766017..., an irrational number.

Answer:

A

Step-by-step explanation:

Answer:

x = 38°

y = 90°

Step-by-step explanation:

x is an inscribed angle, so, 78/2=39

y is an inscribed angle of which connects two endpoints of the diameter, so y = 90°

Answered by GAUTHMATH

Answer:

Step-by-step explanation:

B/c  the bigger triangle is a copy of the smaller we can say

8[tex]\sqrt{3}[/tex] / 12  = x / 8[tex]\sqrt{3}[/tex]

then, solve for x

8[tex]\sqrt{3}[/tex](8[tex]\sqrt{3}[/tex]/12) = x

(64 *3) 12 = x

192 /12 = x

16 = x

nice,  the first answer looks good , then :P

Answer:

16

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

that is √ 14 which is 27 ×>44.2177

Answer:

in jh ynhtym

hunt ghb JBL iggmmjuu ki ju nu j

Answer:

x = 7

Step-by-step explanation:

x + 5 = 12

Subtract 5 from both sides

5 - 5 cancels out

12 - 5 = 7

We're left with x = 7

Answer:

x = 63.9

Step-by-step explanation:

We have:

[tex]\frac{QR}{sin35}[/tex] = [tex]\frac{78}{sin90}[/tex]

=> QR × sin90 = 78 × sin35

=> QR × sin90 = 44.7

=> QR = 44.7

But, we also have: [tex]x^{2}[/tex] + [tex]QR^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] + [tex]44.7^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] = 6084 - 1998.09

=> [tex]x^{2}[/tex] = 4085.91

=> x = [tex]\sqrt{4085.91}[/tex] = 63.9211.. = 63.9

<3 Have a nice day!!

Answer:

1  4/5

Step-by-step explanation:

3/4 ÷ 5 /12

Copy dot flip

3/4 * 12/5

Rewriting

3/5 * 12/4

3/5 * 3

9/5

1 4/5

Answer:

3

Step-by-step explanation:

Let's find the first term in terms of p.

So an arithmetic sequence is a linear relation.

That means it will have the same slope no matter the pair of points used. We are given the slope, the common difference, is 2. We are going to use point (9, 3+3p) and (1, t(1)) along with m=2 to find t(1).

[t(1)-(3+3p)]/[1-9]=2

Simplify denominator

[t(1)-(3+3p)]/[-8]=2

Multiply both sides by -8

t(1)-(3+3p)=-16

Add (3+3p) on both sides

t(1)=-16+3+3p

Combine like terms

t(1)=-13+3p

This means we can find the next term by adding 2 this.

t(2)=-11+3p

Let's find the next term by adding 2 this.

t(3)=-9+3p

Finally we can find the 4th term by adding 2 to this

t(4)=-7+3p

We are given the sum of the first 4 terms is 2p-10. So we can write:

-13+3p+-11+3p+-9+3p+-7+3p=2p-10

Combine like terms on left

12p-40=2p-10

Subtract 2p on both sides

10p-40=-10

Add 40 on both sides

10p=30

Divide both sides by 10

p=3.

-----------------

Checking:

t(1)=-13+3p=-13+3(3)=-13+9=-4

t(2)=-11+3p=-11+3(3)=-11+9=-2

t(3)=-9+3p=-9+3(3)=-9+9=0

t(4)=-7+3p=-7+3(3)=-7+9=2

----sum of the first 4 is -4

And 2p-10 at p=3 gives 2(3)-10=6-10=-4

So this part checks out

In general, the pattern that those 4 terms I wrote out follow t(n)=(-13-2)+2n+3p. I know this because the 0th term would have been (-13-2)+3p and this part goes up by 2 each time. The plus 3p part doesn't change.

Anyways t(9)=(-13-2)+2(9)+3p=-15+18+3p=3+3p. And this part looks good too.

Step-by-step explanation:

w = 34° (alternate interior angles)

x = 34° (vertically opposite angles)

y = 101°

z = 79° (corresponding angles)

Answer:

to get the slope. take the change of y axis value divide by the change of x axis value

Answer:

x^4+4x^3+6x^2+7x+2

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

Hello,

we are going to use the theorem of the bissectrice. (if this word is good in english)

[tex]\dfrac{KL}{LM} =\dfrac{KN}{NM} \\\\\dfrac{8}{x} =\dfrac{14}{20-x} \\\\8(20-x)=14x\\\\160-8x=14x\\\\22x=160\\\\x=\frac{160}{22} \\\\x=\frac{80}{11} \\\\\\x=7.\overline{27}[/tex]

Answer:

Step-by-step explanation: