Answer:
Step-by-step explanation:
I did 70 jumping jacks in 1 minute.
Which is the dependent variable? Which is the independent variable?
Write an equation that represents the relationship between the time you spent doing the activity and the amount of the activity you completed.
Answer:
in jh ynhtym
hunt ghb JBL iggmmjuu ki ju nu j
Solve for x. Thank you
Answer:
Step-by-step explanation:
B/c the bigger triangle is a copy of the smaller we can say
8[tex]\sqrt{3}[/tex] / 12 = x / 8[tex]\sqrt{3}[/tex]
then, solve for x
8[tex]\sqrt{3}[/tex](8[tex]\sqrt{3}[/tex]/12) = x
(64 *3) 12 = x
192 /12 = x
16 = x
nice, the first answer looks good , then :P
Answer:
16
Step-by-step explanation:
Use the image below and find the missing angles
Step-by-step explanation:
w = 34° (alternate interior angles)
x = 34° (vertically opposite angles)
y = 101°
z = 79° (corresponding angles)
Find the TWO integers whos product is -12 and whose sum is 1
m
Answer:
[tex] \rm Numbers = 4 \ and \ -3.[/tex]
Step-by-step explanation:
Given :-
The sum of two numbers is 1 .
The product of the nos . is 12 .
And we need to find out the numbers. So let us take ,
First number be x
Second number be 1-x .
According to first condition :-
[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]
Hence the numbers are 4 and -3.
Answer:
-3,4 are the TWO integers whos product is -12 and whose sum is 1.
Step-by-step explanation:
-3×4=12
-3+4=1
pls help tysm will give brainliest!!
Answer:
% change in perimeter = 43. 44 %
% change in area = 16 %
Step-by-step explanation:
initial perimeter of the rectangle = 2(2p + p)
= 6p
initial area of the rectangle = 2p × p
= 2p²
25% is equal to 0.4therefore,
new length = 2p + (2p × 0.4)= 2p + 0.8p = 2.8 p
new breadth= p - 0.4p
= 0.6 p
new perimeter = 2 ( 2.8 p + 0.6p)= 3.4 p
new area = 2.8p × 0.6p= 1.68 p²
% change in perimeter
[tex] = \frac{6p - 3.4p}{6p} \times 100 \\ = \frac{2.6p}{6p} \times 100 \\ = 43.33\%[/tex]
% change in area
[tex] \frac{2 {p}^{2} - 1.68 {p}^{2} }{2 {p}^{2} } \times 100 \\ = \frac{0.32}{2} \times 100 \\ = 16\%[/tex]
Find the coordinates of P so that P partitions segment AB in the part-to-whole ratio of 1 to 3 with A(6, -10) and B(9, -1).
Answer:
Step-by-step explanation:
Use the formulas that allow us to find the point that divides the segment into a ratio which is
[tex]x=\frac{bx_1+ax_2}{a+b}[/tex] and [tex]y=\frac{by_1+ay_2}{a+b}[/tex] where a is 1 (comes from the ratio) and b is 3 (comes from the ratio as well). Filling in:
[tex]x=\frac{3(9)+1(6)}{1+3}=\frac{27+6}{4}=\frac{33}{4}[/tex] and then y:
[tex]y=\frac{3(-1)+1(-10)}{1+3}=\frac{-3-10}{4}=-\frac{13}{4}[/tex] so the coordinates in question are
[tex](\frac{33}{4},-\frac{13}{4})[/tex]
Answer:
Step-by-step explanation:
the answer would be (7,-7)
Find x from this triangle
Hello,
we are going to use the theorem of the bissectrice. (if this word is good in english)
[tex]\dfrac{KL}{LM} =\dfrac{KN}{NM} \\\\\dfrac{8}{x} =\dfrac{14}{20-x} \\\\8(20-x)=14x\\\\160-8x=14x\\\\22x=160\\\\x=\frac{160}{22} \\\\x=\frac{80}{11} \\\\\\x=7.\overline{27}[/tex]
Mark had 3/2 cans of paint and used 1/2 cans for his room. What fraction of the paint did he use
Help I’m slowww
Answer:
1/3 fraction of whole paint is used by mark
Step-by-step explanation:
Mark used 1/2 out of 3/2 cans.
[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]
P=(2,3,5,7) Express it in description method and in rule method.
Answer:
prime number between 1 to7
The description of set P is the set of prime numbers less than or equal to 7 and the rule is {x | x is a prime number less than or equal to 7}
How to describe the set of P?The set P is given as:
P = {2,3,5,7}
Note that the numbers are prime numbers.
This means that the description of set P is the set of prime numbers less than or equal to 7
The rule form of the set would be:
P = {x | x is a prime number less than or equal to 7}
Read more about sets at:
https://brainly.com/question/1563195
#SPJ2
The time spent by Nadia to answer the geography quiz is 30 minutes more than the time spent to answer the history quiz. What is the total time that Nadia took to answer both quizzes?
Answer:
1 hour
Step-by-step explanation:
hope it helps ....
What is the sum and classification of StartFraction 3 Over 20 EndFraction + StartRoot 10 EndRoot?
3.31227766..., irrational
3.31227766..., rational
18.16227766..., irrational
18.16227766..., rational
9514 1404 393
Answer:
3.31227766..., irrational
Step-by-step explanation:
3/20 +√10 = 0.15 + 3.16227766017...
The root of 10 is irrational, so adding that to a rational number will give an irrational sum.
The sum is about 3.31227766017..., an irrational number.
Answer:
A
Step-by-step explanation:
pLZ HELPPPPPPPPPPPPPPPPPPPPPPPPP.
Answer:
x^4+4x^3+6x^2+7x+2
The 9th term of an arithmetic progression is 3+3p and the sum of the first four terms is 2p-10, where p is constant. Given that the common difference is 2, find the value of p.
Answer:
3
Step-by-step explanation:
Let's find the first term in terms of p.
So an arithmetic sequence is a linear relation.
That means it will have the same slope no matter the pair of points used. We are given the slope, the common difference, is 2. We are going to use point (9, 3+3p) and (1, t(1)) along with m=2 to find t(1).
[t(1)-(3+3p)]/[1-9]=2
Simplify denominator
[t(1)-(3+3p)]/[-8]=2
Multiply both sides by -8
t(1)-(3+3p)=-16
Add (3+3p) on both sides
t(1)=-16+3+3p
Combine like terms
t(1)=-13+3p
This means we can find the next term by adding 2 this.
t(2)=-11+3p
Let's find the next term by adding 2 this.
t(3)=-9+3p
Finally we can find the 4th term by adding 2 to this
t(4)=-7+3p
We are given the sum of the first 4 terms is 2p-10. So we can write:
-13+3p+-11+3p+-9+3p+-7+3p=2p-10
Combine like terms on left
12p-40=2p-10
Subtract 2p on both sides
10p-40=-10
Add 40 on both sides
10p=30
Divide both sides by 10
p=3.
-----------------
Checking:
t(1)=-13+3p=-13+3(3)=-13+9=-4
t(2)=-11+3p=-11+3(3)=-11+9=-2
t(3)=-9+3p=-9+3(3)=-9+9=0
t(4)=-7+3p=-7+3(3)=-7+9=2
----sum of the first 4 is -4
And 2p-10 at p=3 gives 2(3)-10=6-10=-4
So this part checks out
In general, the pattern that those 4 terms I wrote out follow t(n)=(-13-2)+2n+3p. I know this because the 0th term would have been (-13-2)+3p and this part goes up by 2 each time. The plus 3p part doesn't change.
Anyways t(9)=(-13-2)+2(9)+3p=-15+18+3p=3+3p. And this part looks good too.
solve the logarithmic equation
[tex] log_{6}(2x - 6) + log_{6}x = 2[/tex]
Answer:
[tex]x=6[/tex]
Step-by-step explanation:
We want to solve the equation:
[tex]\displaystyle \log_6(2x-6)+\log_6x=2[/tex]
Recall the property:
[tex]\displaystyle \log_bx+\log_by=\log_b(xy)[/tex]
Hence:
[tex]\log_6(x(2x-6))=2[/tex]
Next, recall that by the definition of logarithms:
[tex]\displaystyle \log_b(a)=c\text{ if and only if } b^c=a[/tex]
Therefore:
[tex]6^2=x(2x-6)[/tex]
Solve for x. Simplify and distribute:
[tex]36=2x^2-6x[/tex]
We can divide both sides by two:
[tex]x^2-3x=18[/tex]
Subtract 18 from both sides:
[tex]x^2-3x-18=0[/tex]
Factor:
[tex](x-6)(x+3)=0[/tex]
Zero Product Property:
[tex]x-6=0\text{ or } x+3=0[/tex]
Solve for each case. Hence:
[tex]x=6\text{ or } x=-3[/tex]
Next, we must check the solutions for extraneous solutions. To do so, we can simply substitute the solutions back into the original equations and examine its validity.
Checking x = 6:
[tex]\displaystyle \begin{aligned} \log_{6}(2(6)-6)+\log_{6}6&\stackrel{?}{=} 2 \\ \\ \log_6(12-6)+(1)&\stackrel{?}{=}2 \\ \\ \log_6(6)+1&\stackrel{?}{=}2 \\ \\ 1+1=2&\stackrel{\checkmark}{=}2\end{aligned}[/tex]
Hence, x = 6 is indeed a solution.
Checking x = -3:
[tex]\displaystyle\begin{aligned} \log_6(2(-3)-6) + \underbrace{\log_6-3}_{\text{und.}} &\stackrel{?}{=} 2\\ \\ \end{aligned}[/tex]
Since the second term is undefined, x = -3 is not a solution.
Therefore, our only solution is x = 6.
Answer:
x = 6
Step-by-step explanation:
The given logarithmic equation is ,
[tex]\implies log_{6}(2x - 6) + log_{6}x = 2[/tex]
We can notice that the bases of both logarithm is same . So we can use a property of log as ,
[tex]\bf \to log_a b + log_a c = log_a {( ac)} [/tex]
So we can simplify the LHS and write it as ,
[tex]\implies log_{6} \{ x ( 2x - 6 )\} = 2 [/tex]
Now simplify out x(2x - 6 ) . We get ,
[tex]\implies log_6 ( 2x^2 - 6x ) = 2 [/tex]
Again , we know that ,
[tex]\bf \to log_a b = c , a^c = b [/tex]
Using this we have ,
[tex]\implies 2x^2 - 6x = 6^2 \\\\\implies 2x^2 - 6x -36 = 0 [/tex]
Now simplify the quadratic equation ,
[tex]\implies x^2 - 3x - 18 = 0 \\\\\implies x^2 -6x + 3x -18=0\\\\\implies x( x -6) +3( x - 6 ) = 0 \\\\\implies (x-6)(x+3) = 0 \\\\\implies x = 6 , -3 [/tex]
Since logarithms are not defined for negative numbers or zero , therefore ,
[tex]\implies 2x - 6 > 0 \\\\\implies x > 3 [/tex]
Therefore the equation is not defined at x = -3 . Hence the possible value of x is 6 .
[tex]\implies \underline{\underline{ x \quad = \quad 6 }}[/tex]
6. Don Juan compro un terreno con las dimensiones que se muestran en la figura el cual se va acondicionar para realizar eventos sociales, por lo que desea instalar césped en la region sombreada. ¿Cuantos metros cuadrados de césped requiere? Considera rt=3.14 16 m O 50 24 m2 0 205 76 m2 256 00 m2 0 5504 m2
Answer:
Not sure but I think it might be A
Step-by-step explanation:
Took the test
Consider the quadratic function f(x) = x2 - 5x + 6.
What are the values of the coefficients and constant in the function?
а
b
c
Answer:
a=1
b=-5
c=6
Step-by-step explanation:
ax^2+bx+c=0
Is the formula used for this question.
The given function is the same as y = 1x^2 + (-5x) + 6
Compare it to the form y = ax^2+bx+c, and we have the following:
a = 1
b = -5
c = 6
Solve for x. Round to the nearest tenth, if necessary.
Answer:
x = 63.9
Step-by-step explanation:
We have:
[tex]\frac{QR}{sin35}[/tex] = [tex]\frac{78}{sin90}[/tex]
=> QR × sin90 = 78 × sin35
=> QR × sin90 = 44.7
=> QR = 44.7
But, we also have: [tex]x^{2}[/tex] + [tex]QR^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] + [tex]44.7^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] = 6084 - 1998.09
=> [tex]x^{2}[/tex] = 4085.91
=> x = [tex]\sqrt{4085.91}[/tex] = 63.9211.. = 63.9
<3 Have a nice day!!
What is the answer of this question?
Answer:
2 ( Option A )
Step-by-step explanation:
The given integral to us is ,
[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]
Here 5 is a constant so it can come out . So that,
[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]
Now we can write √x as ,
[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]
Simplify ,
[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]
By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,
[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]
On simplifying we will get ,
[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]
I do not understand any of this
Answer:
to get the slope. take the change of y axis value divide by the change of x axis value
Solve |x - 5| = 7 ......
Answer:
12,-2
Step-by-step explanation:
given circle o, what are the values of x and y?
Answer:
x = 38°
y = 90°
Step-by-step explanation:
x is an inscribed angle, so, 78/2=39
y is an inscribed angle of which connects two endpoints of the diameter, so y = 90°
Answered by GAUTHMATH
What is the answer to this
Answer:
Step-by-step explanation:
An auto transport truck holds 12 cars. A car dealer plans to bring in 1,006 new cars in June and July. If an auto transport truck is filled for each delivery, except for the last one, how many full truckloads are needed and how many cars will be in the last truck?
Express each of the following negative angles as its equivalent positive angle between 0°and360°
+120°
Answer:
Dilated pupils
Long periods of wakefulness
Loss of appetite
Overconfidence
Over-excitement
Paranoia
Runny nose or frequent sniffles
White powder around nostrils
Legal issues
Missing or being late to work
Financial problems
Mood swings
Irritability
Depression
what is the mesure of DBC?
Answer:
41
Step-by-step explanation:
Solve the following equa
8 (2v + 8) = 96
оа
v = 2
ii need help
Answer:
1
Step-by-step explanation:
64+32 =96 that'd how I got the answer
Answer:
[tex]{ \tt{8(2v + 8) = 96}} \\ { \tt{2v + 8 = 12}} \\ { \tt{2v = 4}} \\ { \bf{v = 2}}[/tex]
solve the equation x + 5 = 12
Answer:
x = 7
Step-by-step explanation:
x + 5 = 12
Subtract 5 from both sides
5 - 5 cancels out
12 - 5 = 7
We're left with x = 7
The marked price of a fan is Rs 1,620 and selling price is Rs 1,539. Find the discount amount.
Answer:
rs. 81
Step-by-step explanation:
given,
mp. = 1620
sp. = 1539
now,
discount = mp - s.p = 1620 - 1539 = 81
what is the quotient of 3/4 ÷ 5/12
Answer:
1 4/5
Step-by-step explanation:
3/4 ÷ 5 /12
Copy dot flip
3/4 * 12/5
Rewriting
3/5 * 12/4
3/5 * 3
9/5
1 4/5
Using trial and improvement, find the solution between 5 and 6 for the following equation:
x
2
=
27
Give your answer rounded to 1 DP.
Answer:
2
Step-by-step explanation:
that is √ 14 which is 27 ×>44.2177