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Answer:

Nitrogen has 5 valence electrons

Explanation:

nitrogen has it's attoms form triple bonds which are very hard to break

so non-reactive

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Answer:

Vaporization

Since the question does not specify what molecule is being acted upon by the increment in temperature, I'll assume it's water.

When first taken out of the fridge, water is in the form of ice, and it has not been affected by a change in temperature yet, so it's at the origin.

(origin = ice)

As you raise the temperature, however, the ice starts to melt, and melting occur during phase 2. You have to keep the temperature constant for the process to properly occur.

(phase 2 = melting)

After it finishes melting, the ice is now in it's liquid state, which is water. The temperature continues to rise in order to proceed to the next phase.

(2nd slope = water)

Lastly, Water is being vaporized during phase 4. Notice, the temperature is kept constant in order to allow the process to properly occur.

(phase 4 = vaporization)

Answer:

noo

Explanation:

its basic

....................

Answer: acidic

Explanation:

Answer:

[tex]{ \bf{from \: ionic \: product \: of \: water : }} \\ { \boxed{ \tt{k _{w} = [H _{3} O {}^{ + } ][OH {}^{ - } ]}}} \\ \\ { \tt{1 \times {10}^{ - 14} = (1 \times {10}^{ - 5} ) [OH {}^{ - } ]}} \\ \\ { \tt{[OH {}^{ - } ] = 1 \times {10}^{ - 9} }} \: M[/tex]

A solution has an [H3O+] of 1 × 10−5 M the [OH−] of the solution will be 1 × 10−9 M and option C is correct.

The water is made up of H2O only and when the pH of it is 7 then the concentration of all the ions would be the same while dissociation the water will get dissociate into H+ ions and OH- ions.

The concentration of OH- ions will be

OH- = Kw {H3O+}

{H3O+} = 1 × 10−5 M.

Kw = 14

substituting the value in the equation,

OH = 14 { 1 × 10−5 M.}

OH = 1 × 10−9 M

Therefore, the solution has an [H3O+] of 1 × 10−5 M the [OH−] of the solution will be 1 × 10−9 M and option C is correct.

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Answer:

As organisms release energy during cellular respiration, carbon dioxide is produced from the carbon in energy storage molecules. ... Carbon dioxide in the biodome decreased because decomposers decreased which means there was a decrease in cellular respiration overall.

btw :

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Answer: The correct options are A and E

Explanation:

A chemical reaction is defined as the reaction in which two or more chemical substances react to form two or more different chemical substances.

A new substance (product) is formed in a chemical reaction when the bonds between the reactants are broken so that the new bonds between the products can be formed.

For a given chemical reaction:

[tex]HF+NaOH\rightarrow NaF+H_2O[/tex]

Here,

HF is a covalent compound as sharing of electrons take place between hydrogen and fluorine atom

NaOH is an ionic compound as a complete transfer of electrons occurs from sodium to hydroxide.

Thus, to form the products, an ionic bond between sodium and hydroxide must be broken coupled with a covalent bond between hydrogen and fluorine.

Hence, the correct options are A and E

Number of subatomic particles=35+36+35=106

Explanation:

Atomic number=35

Mass number=71

No. of proton p=35

No. of neutron n=71−35=36

No. of electron e=35

Explanation:

Fe- reducing agent (since it is oxidized to fe203)

v203- oxidizing agent(since it is reduced)

In the given reaction, Fe is the reducing agent and V is the oxidizing agent.

An atom or compound that loses its electrons to other substances in a reduction-oxidation reaction and gets oxidized to a higher valency state is called a reducing agent.

A reducing agent can be defined as one of the reactants of a redox reaction that reduces the other reactant by giving its electrons to the reactant. If the reducing agent can not give away its electrons to others in a reaction, then the reduction reaction cannot occur.

Given, the following chemical reaction:

2Fe + 3V₂O₃ → Fe₂O₃ + 6VO​

The V₂O₃ oxidation state of V:

2 x + 3(-2) = 0

2x = 6

x = + 3

The Fe₂O₃ oxidation state of Fe:

2 y + 3 (-2) = 0

2y = 6

y = + 3

The V acts as an oxidizing agent because it accepts one electron to change the oxidation state from +3 to +2.

Fe acts as a reducing agent because it gives out its electrons to change the oxidation state from 0 to +3.

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Answer:

The independent variable is the cause. Its value is independent of other variables in your study.

The dependent variable is the effect. Its value depends on changes in the independent variable.

Ex: The ice cube melts on the stove.

Dependent variable: Ice Cube

Independent variable: heat of stove

Answer:

In an experiment, the IV(independent variable) is a variable that is changed to see how it affects something else, and the DV (dependent variable)is a variable that is being measured/observed.

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REACTION TYPE:

Single displacement/Oxidation-reduction

(Hope this helped UwU)

Answer:

Synthesis reaction is the answer

32.7 g Zn

Explanation:

First convert the amount of gas into moles:

11.2 L H2 × (1 mol H2/22.4 L H2) = 0.500 mol H2

Then use the molar ratio to find the amount of zinc necessary to produce the amount of gas above:

0.500 mol H2 × (1 mol Zn/1 mol H2)

= 0.500 mol Zn

Now use the molar mass of zinc to find the number of grams of zinc for the reaction to occur:

0.500 mol Zn × (65.38 g Zn/1 mol Zn)

= 32.7 g Zn

Answer:

18.89 g of Al₂O₃.

Explanation:

The balanced equation for the reaction is given below:

4Al + 3O₂ —> 2Al₂O₃

Next, we shall determine the masses of Al and O₂ that reacted and the mass of Al₂O₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 4 × 27 = 108 g

Molar mass of O₂ = 16 × 2 = 32 g/mol

Mass of O₂ from the balanced = 3 × 32

= 96 g

Molar mass of Al₂O₃ = (27×2) + (16×3)

= 54 + 48

= 102 g/mol

Mass of Al₂O₃ from the balanced equation = 2 × 102 = 204 g

SUMMARY:

From the balanced equation above,

108 g of Al reacted with 96 g of O₂ to produce 204 g of Al₂O₃.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

108 g of Al reacted with 96 g of O₂.

Therefore, 10 g of Al will react with

= (10 × 96)/108 = 8.89 g of O₂.

From the calculation made above, we can see clearly that only 8.89 g out of 19 g of O₂ given, reacted completely with 10 g of Al.

Therefore, Al is the limiting reactant and O₂ is the excess reactant.

Finally, we shall determine the mass of aluminium oxide, Al₂O₃, produced from the reaction.

NOTE: in this case, the limiting reactant will be used because it will give the maximum mass of the aluminium oxide, Al₂O₃ as all of it is consumed in the reaction.

Al is the limiting reactant and the mass of aluminium oxide, Al₂O₃ produced can be obtained as follow:

From the balanced equation above,

108 g of Al reacted to produce 204 g of Al₂O₃.

Therefore, 10 g of Al will react to produce = (10 × 204)/108 = 18.89 g of Al₂O₃.

Thus, 18.89 g of Al₂O₃ were obtained from the reaction.

The statement which is an example of nuclear fission is that a large radioactive atom breaks into smaller atoms, producing nuclear energy.

Nuclear fission is a kind of radioactive decay reaction in which an unstable nuclei of an atom will split into smaller stable nuclei by the emission of lots of energy.

Hence in nuclear fission a large radioactive atom breaks into smaller atoms, producing nuclear energy.

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Answer:

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Answer:

C Fluorine

Explanation:

Answer:

200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water.

Explanation:

The solution is the result of the mixture between the solute, which is the substance that dissolves, and the solvent, which is the substance in which a solute dissolves. That is, a solution (or solution) is a mixture of two or more components, perfectly homogeneous since each component is intimately mixed with the other.

The concentration of solutions is the amount of solute contained in a given amount of solvent or solution. A unit of concentration is the percent weight to volume.

The percent weight to volume is the percentage ratio between the weight of the solute and the volume of the solution. It is calculated as:

[tex]Percent =\frac{mass of solute}{volume of solution} *100[/tex]

Mass is measured in grams, while volume is measured in mL.

In this case:

Replacing:

[tex]6=\frac{12 g}{volume of solution} *100[/tex]

Solving:

volume of solution*6= 12 g*100

[tex]volume of solution=\frac{12 g}{6} *100[/tex]

volume of solution= 200 mL

200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water

Answer:b

Explanation:

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the element X with the atomic number of 18 is Argon (Ar) while the next element (element Y) in the periodic table, with atomic number 19, is potassium (K).

Element X is found in the group zero (also called group 18 and elements found therewith are referred to as noble gases) of the periodic table while element Y is found in group 1 (elements found here are referred to as alkali metals).

Element X has a completely filled outermost shell while element Y has one electron in its outermost shell.

Element X is a metal while element Y is a nonmetal.

Answer:

C. All of the above

Explanation:

They all happen beyond critical point.

Explanation:

heat and pressure are two main forces that transform organic matter into fossil fuels

Answer:

Waves carry energy from one place to another.

Because waves carry energy,some waves are used for communication,eg radio and television waves and mobile telephone signals.

Explanation:

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that's my answer

correct me if im wrong

Based on the molarity of the solutions;

pH is the negative logarithm to base ten of the hydrogen ions concentration of a solution.

pOH is the negative logarithm to base ten of the hydroxide ions concentration.

Also;

For HCl:

pH = -log [H3O+]

pH =-log (0.200)

pH = 0.699

Then;

poH= 14-0.699

pOH = 13.301

For NaOH:

pOH= -log [OH-]

= -log (0.0143)

pOH = 1.845

Then;

pH= 14-poH

= 14- 1.845

pH = 12.16

For HNO3:

pH= -log[H3O+]

=-log(3.0)

= -0.4771

Then;

pOH = 14-9-0.4771

pOH = 14.4771

For [Ca(OH)2]

molarity = 0.0031M

2 moles of OH- are produced

[OH-]= 2 × 0.0031

[OH-] = 0.0062M

pOH = - log[OH-]

=-log(0.0062)

=-log(6.2x10-3)

=-(-2.21)

pOH = 2.21

Then;

pH =14-2.21

pH =11.79

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