Please help i don't get it.
Which image matches the Topographic Map Shown?
Also, please explain how your answer is the correct answer. Why is your answer correct?

Answer:

4200 J/°C/kg

Explanation:

The formula for heat transfer is given by :

Q= m*c*ΔT  where;

Q= heat transferred = 6930 J

m=mass of the liquid = 0.330 kg

c= specific heat capacity=?

ΔT = 25-20 = 5.0°C

Applying the values in the formula as;

Q= m*c*ΔT

6930 = 0.330 * c * 5

6930 = 1.65 c

6930/1.65 = c

4200 = c

c= 4200 J/°C/kg

Answer: macroscopic outputs

Explanation:

When fireworks explode, sound and light are produced. These are examples of macroscopic outputs. Because, explosion from fireworks is an exothermic process which releases massive heat energy to the surroundings.

Exothermic reaction are those which evolve heat energy to the surroundings.  The change in enthalpy of the reaction is negative here. Whereas, in an endothermic reaction energy is absorbed by the reactants.

Exothermic reactions sometimes results in massive explosion. The heat energy released to the surroundings from the fire works is macroscopic level.

The small scale process or quantity that cannot be measured using normal scales are called microscopic units. Therefore, the sound, light, and heat from the explosion all are macroscopic outputs.

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The thing same about a particle as gas, liquid, or solid is its chemical composition.

Matter exists in three different states: solid, liquid, and gas. By examining the configuration of their particles, it is possible to understand why they have various qualities. Theoretically, at this temperature, particles move slowly and have the least amount of energy.

Phase refers to the material's actual state. To pay attention to is the word physical. Only physical means can change the state of matter. You can make a physical change if energy is added (by raising the temperature) or subtracted (by freezing things).

The chemical composition of matter same about a particle as gas, liquid or solid.

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Answer:

option 2

Explanation:

you are very welcom

Answer:

weight at height = 100 N .

Explanation:

The problem relates to variation of weight  due to change in height .

Let g₀ and g₁ be acceleration due to gravity , m is mass of the object .

At the surface :

Applying Newton's law of gravitation

mg₀ = G Mm / R²

At height h from centre

mg₁ = G Mm /h²

Given mg₀ = 400 N

400 = G Mm / R²

400 = G Mm / (6400 x 10³ )²

G Mm = 400 x (6400 x 10³ )²

At height h from centre

mg₁ =  400 x (6400 x 10³ )²/ ( 2 x 6400 x 10³)²

= 400 / 4

= 100 N .

weight at height = 100 N

Answer:

The planets spun in epicycles.

Explanation:

The planets were not simply attached to a mystical sphere (“deferent”) but they were actually attached to a mini-sphere (“epicycle”) which rotated on the larger one.

Answer:A

Explanation:

Answer:

Fscos63

Explanation:

Given that a horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Taking the moment from the pivot point P, that means the moment at point p = 0

Then, if we consider the weight mg of the pole, according to the principle of equilibrium : sum of the upward forces equal to the sum of the downward forces.

Therefore, mg = Fsinø ....... (1)

Also, taking moment at point P

Let the length of the pole = s

The length of the weight of the pole = 1/2 S

Fscosø = mgs/2

The distance s will cancel out

2Fcosø = mg ...... (3)

Substitute mg in equation 1 into equation 3

2fcosø = fsinø

F will cancel out

Tanø = 2

Ø = tan^-1(2)

Ø = 63.4 degree

The moment of force F about pivot point P will be

Moment = force × distance

Moment = Fcos63 × S

Moment = Fscos63

Answer:

Gravity is an ever present force, and therefore acceleration is guaranteed to happen at every single one of those points (and in fact, everywhere in the universe).

On top of that, friction will be present in all four spots (friction with the rails, with the air, with the axles, etc.), and friction is a perfectly acceptable force that will cause acceleration, slowing the roller coaster down.

So the correct answer is every single point, regardless of what answer the teacher expects.

The object will be moving faster if the acceleration and velocity are pointing in the same direction. The object will also slow down if the acceleration is pointing in the opposite direction as the velocity.

When an object's speed, direction of motion, or both change, it accelerates. Even while it may appear to be virtually immediate in some circumstances, such as when a golf ball is struck by a club or during car collisions, changes in an object's speed are always continuous.

Since gravity is a constant force, acceleration will unavoidably occur at each of those locations and throughout the whole universe.

Therefore, In addition, there will be friction at all four locations—friction with the axles, the air, the rails, etc.—and friction is a completely normal force that will accelerate the roller coaster, slowing it down.

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Answer:

the answer is T!!

!!!!!!!!

Answer:

true

Explanation:

hope this helps

Answer:

d = 4[m]

Explanation:

Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.

[tex]T=F*d[/tex]

where:

T = torque [N*m]

F = force [N]

d = distance [m]

Now replacing in the equation above.

[tex]84=21*d\\\\d= 4[m][/tex]

Answer:

I guess that the atoms are:

Protons:     6     8    5    2    12    12

Neutrons:  8     8     5   3     13    14

Now, two atoms are isotopes if they share the same number of protons (so both atoms are the same element) but they have a different number of neutrons.

From the given options, the only two that have the same number of protons but a different number of neutrons are:

Protons 12, neutrons 13

and

Protons 12, neutrons 14.

These two are isiotopes.

Answer:

Im not fully corrrect but I would say C

Explanation:

Answer:

52.802

Explanation:

"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.

The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.

Explanation:

five significant of 52.8015=52.801 ..

Answer:

1.8 m/s

Explanation:

Step one:

given data

m1= 2kg

u1= 5m/s

m2= 5kg

u2= 1m/s

v1= 3m/s

From

m1u1+m2u2= m1v1+m2v2

substitute

2*5+5*1 = 2*3+5*v2

10+5= 6+5v2

15-6= 5v2

9= 5v2

divide both side by 5

v2= 9/5

v2= 1.8 m/s

Answer:

The initial velocity is 89.16m/s

Attached is the solution

Explanation:

Answer:

Inside a femur bone found in the woods,

saliva of gum

Answer:

(a) the total momentum of the system before the collision = -2m kg.m/s.

(b) the total momentum of the system after the collision = -2m kg.m/s.

(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)

Explanation:

Given;

mass of Puck 1 , = m

mass of Puck 2, = m (since they have the same mass m)

initial velocity of Puck 1, u₁ = 10 m/s to the left

initial velocity of Puck 2, u₂  = 8 m/s to the right

Let the rightward direction be positive direction

Let the leftward direction be negative direction

(a) the total momentum of the system before the collision;

P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)

P₁ = (-mu₁) + mu₂

P₁ = mu₂ - mu₁

P₁ = m(u₂ - u₁)

P₁  = m(8 - 10)

P₁  = -2m kg.m/s

(b) the total momentum of the system after the collision;

Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.

Thus, the total momentum of the system after the collision is -2m kg.m/s.

(c) puck 1's velocity after the collision in component form

[tex]v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s[/tex]

Answer: work

Explanation:

When Jerome swings on a rope and hence this leads to the transfer of energy from the gravitational potential energy to a kinetic energy, this implies that work is being done.

For work to be done, it simply means that one has to transfer energy from one particular form to another form. In this case, the energy was transferred from the gravitational potential energy to a kinetic energy.

Answer:

work

Explanation:

Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

       Mass  = density x volume

Volume of petrol  = 4.2m³

Density of petrol  = 0.3kgm⁻³  

       Mass of petrol  = 4.2 x 0.3  = 1.26kg

So;

      We can now find the volume of the alcohol

 Volume of alcohol = [tex]\frac{mass}{density}[/tex]  

Mass of alcohol  = 1.26kg

Density of alcohol  = 0.4kgm⁻³  

  Volume of alcohol  = [tex]\frac{1.26}{0.4}[/tex]   = 3.15m³

Explanation:

what is time in this question

Velocity of sound travels faster in solids than in liquids, and faster in liquids than in gases because "the density of solids is higher than that of liquids, meaning that the particles are closer together."

Answer:

Explanation:

Due to the fact that sound is caused by vibrations, it's more noticeable in liquid because the vibrations may cause ripples in the liquid

Answer:

I believe you are correct but we just started this unit

Explanation:

Answer:

Ffriction = 217.7[N]

Explanation:

First, we must find the mass of the box, we must remember that the weight is defined as the product of the mass by acceleration.

[tex]w=m*g[/tex]

where:

w = weight [N] (units of Newtons)

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]1300=m*9.81\\m=132.51[kg][/tex]

Now we must use Newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F sum of forces

m = mass = 132.51[kg]

a = acceleration = 1.3[m/s²]

We must know that the forces that act are the horizontal force that moves the box and the friction force in the negative direction that acts against the movement.

Now replacing:

[tex]390-f_{friction}=132.51*1.3\\390-172.26=f_{friction}\\f_{friction}=217.7[N][/tex]

Answer:

C M (change in T) = heat absorbed      thermal equation for heat gained

C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K     specific heat

Note: 1 gm =.001 kg

So C = .004184J / gm * deg K

Also, 1 J = .239 cal   so in conventional terms

C = .001 cal / gm deg K     (very low, water would be 1 cal / gm deg C

0.184[tex]m^{3}[/tex] is the answer for Acellus students!

Answer:

0.35

Explanation:

According to Newton's second law;

\sum Fx = ma

Fm - Ff =ma

Fm is the moving force = Wsin theta

Fm = 4(9.8)sin55

Fm = 32.1N

Ff is the frictional force = nmgcos theta

Ff = n(4)(9.8)cos55

Ff = 22.48n

Acceleration a = 6.0m/s²

Substitute the given values into the formula and get the coefficient of friction

32.11-23.48n = 4(6)

32.11-24= 23.48n

8.11 = 23.48

n = 8.11/23.48

n = 0.35

Hence the coefficient of friction is 0.35

Answer:

11.025m

Explanation:

In this question there is no vertical velocity,

t= 1.5s

Height of platform=h

From Newton equation

s = ut + 1/2gt^2

But there is no vertical velocity,

Hence,

Then u=0

h = 0 + 1/2 x 9.8 x (1.5)^2

h = 11.025m

Answer:

0

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

 Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.