Please help i need this answered!!

Michael is drawing a card from a standard 52-card deck, which includes 4 aces: the ace of clubs, the ace of diamonds, the ace of hearts, and the ace of spades. For each trial, he draws a card, records which cards he drew, and returns it to the deck. He draws an ace 240 times

Of the times he draws an ace, which of the following would be a good estimate for the number of times the ace drawn is the ace of hearts?

Answer:

Step-by-step explanation:

From the information:

Let consider the following variables,

assume p to be the number of times an ace was drawn,

also, q should be the number of aces  and r to be the number of outcomes.

Thus ;

[tex]\mathtt{r = \dfrac{p}{q}}[/tex]

where;

p = 240

q = 4

[tex]\mathtt{r = \dfrac{240}{4}}[/tex]

r = 60

It is literally unlikely that exactly 25% of the drawings are going to be the ace of hearts, therefore, the best answer will be 60 or the value closest to 60

Answer:

8 nickels

Step-by-step explanation:

Let n be the number of nickels.

4: (2+ 6 + 4 + n) = 1:5

4÷(12 + n) = 1÷5

4 x 5 = 1 x (12 + n)

20 = 12 + n

n = 8

Answer:

x=8

Step-by-step explanation:

4:3=x:6

Multiply the first set by 2

4*2 : 3*2

8:6

That means x =8

Answer:

B. The line of best fits shows a negative correlation between the number of months and the number of minutes

Step-by-step explanation:

In a scatter plot, when the data points are clustered along the line of best fit, it shows a trend, and it implies there's a correlation between the x-variable and the y-varisble.

Also, when the line of best fit slopes upward, from your left to your far right, it shows a positive correlation between the variables on the x-axis and y-axis.

On the other hand, if the line of best fit slopes downwards, from your left down to your right, this shows a negative correlation.

Thus, considering the line of best fit in the question, the line of best fit shows a negative correlation between the number of months and the number of minutes. The line of best fit slopes downwards, from your left to your right.

This shows that, as month number increases, number of minutes decreases.

Answer:

67°

Step-by-step explanation:

● cos<PQR = adjacent/hypotenus

● cos<PQR = 5/13

● cos< PQR = 0.384

Using a calculator:

● cos^-1(0.384) = 67°

● <PQR = 67°

Answer:

9hrs 11hrs 19hrs

Step-by-step explanation:

just took the quiz on edge 2020

Answer:

9 hours, 11 hours, 19 hours.

Greetings from Brasil...

It is said that polygons are similar, so we can use the expression of similarity.

BIG/small = BIG/small

35/14 = 25/X

X = 10

But the scale factor is questioned. Just use one of the expressions. We conclude that the largest is 2.5 times the value of the smallest

35/14 OR 40/16 OR 25/10

-----------------------------------------------------------

BIG/small = BIG/small

25/5 = 40/Y

Y = 8

25/5 OR 25/5 OR 40/8

times the value of the smallest

Answer:

[tex]a=-\frac{b}{2x}[/tex]

Step-by-step explanation:

The equation of a quadratic function is given as:

ax² + bx + c = 0

where a, b and c are the coefficient in the quadratic equation.

The axis of symmetry of the quadratic equation is given as:

[tex]x=-\frac{b}{2a}[/tex]

To get the equation for a, we have to make a the subject of formula:

[tex]x=-\frac{b}{2a}\\\\multiply\ both\ sides\ by \ 2a:\\\\x*2a=-\frac{b}{2a}*2a\\\\2ax=-b\\\\Divide\ through\ by\ 2a\\\\2ax/2a=-b/2a\\\\a=-\frac{b}{2x}[/tex]

The value of a when solved from x = -b/2a is;

a = -b/2x

We are given the formula for axis of symmetry of a quadratic equation to be;

x = -b/2a

Where;

a and b are coefficients in the quadratic equation

x represents the values along a vertical line on the coordinate plane.

Now, we want to solve for a which means we make it the subject of the equation;

Using multiplication property of equality, we multiply both sides by 2a to get;

2ax = -b

We now use division property of equality by dividing both sides by 2x to get;

a = -b/2x

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Answer:21

Step-by-step explanation:

50-32.5=17.5

17.5/0.8=21.875

Answer:

45 is the father's age

Step-by-step explanation:

Answer:

[tex]16x^{2} -42x+5[/tex]

Step-by-step explanation:

Sum of its zeroes=[tex]\alpha +\beta =\frac{21}{8} \\[/tex]

Product of its zeroes=[tex]\alpha \beta[/tex]=[tex]\frac{5}{16}[/tex]

Formula to form a quadratic polynomial:

[tex]p(x)=k[x^{2} -(\alpha +\beta )x+\alpha \beta ][/tex]

p(x)=[tex]k[x^{2} -(\frac{21}{8} )x+\frac{5}{16}][/tex]

p(x)=[tex]16[x^{2} -(\frac{21}{8} )x+\frac{5}{16}][/tex]

p(x)=[tex][16x^{2} -42x+5][/tex]

The quadratic polyniomial is [tex]16x^{2}-42x+5[/tex]

Answer:

a. [tex]\mathbf{P(Y \leq 60) = 0.3333}[/tex]

b. P(Y>50) = 0.8889

c. E(y) = 67.5 and  Standard deviation [tex]\sigma[/tex] = 12.99

Step-by-step explanation:

From the information given :

an automobile body paint shop, has determined that the painting time of automobiles is uniformly distributed and that the required time ranges between 45 minutes to [tex]1\frac{1}{2}[/tex]hours.

The objective is to determine  the probability that the painting time will be less than or equal to an hour?

since 60 minutes make an hour;

[tex]1\frac{1}{2}[/tex]hours = 60 +30 minutes = 90 minutes

Let Y be the painting time of the automobile; then,

the probability that  the painting time will be less than or equal to an hour ca be  computed as :

[tex]P(Y \leq 60) = \int ^{60}_{45} f(y) dy \\ \\ \\ P(Y \leq 60) = \int ^{60}_{45} \dfrac{1}{45} dy \\ \\ \\ P(Y \leq 60) = \dfrac{1}{45} \begin {pmatrix} x\end {pmatrix}^{60}_{45} \\ \\ \\ P(Y \leq 60) = \dfrac{60-45}{45 } \\ \\ \\ P(Y \leq 60) = \dfrac{15}{45} \\ \\ \\ P(Y \leq 60) = \dfrac{1}{3} \\ \\ \\ P(Y \leq 60) = 0.3333[/tex]

What is the probability that the painting time will be more than 50 minutes?

The probability that the painting will be more than 50 minutes is P(Y>50)

So;

[tex]P(Y>50) = \int \limits ^{90}_{50} f(y) dy[/tex]

[tex]P(Y>50) = \int \limits ^{90}_{50} \dfrac {1}{45} dy[/tex]

[tex]P(Y>50) = \dfrac{1}{45}[x]^{90}_{50}[/tex]

[tex]P(Y>50) = (\dfrac{90-50}{45})[/tex]

[tex]P(Y>50) = \dfrac{40}{45}[/tex]

P(Y>50) = 0.8889

Determine the expected painting time and its standard deviation.

Let consider E to be the expected painting time

Then :

[tex]E(y) = \int \limits ^{90}_{45} y f(y) dy \\ \\ \\ E(y) = \int \limits ^{90}_{45} y \dfrac{1}{45} dy \\ \\ \\ E(y) = \dfrac{1}{45} [\dfrac{y^2}{2}]^{90}_{45} \\ \\ \\ E(y) = \dfrac{1}{45}[\dfrac{(90^2-45^2)}{2}] \\ \\ \\ E(y) = \dfrac{1}{45} (\dfrac{6075}{2}) \\ \\ \\ E(y) = \dfrac{1}{45} \times 3037.8 \\ \\ \\ \mathbf{E(y) = 67.5}[/tex]

[tex]E(y^2) = \int \limits ^{90}_{45} y^2 f(y) dy \\ \\ \\ E(y^2) = \int \limits ^{90}_{45} y^2 \dfrac{1}{45} dy \\ \\ \\ E(y^2) = \dfrac{1}{45} [\dfrac{y^3}{3}]^{90}_{45} \\ \\ \\ E(y^2) = \dfrac{1}{45}[\dfrac{(90^3-45^3)}{3}] \\ \\ \\ E(y^2) = \dfrac{1}{45} (\dfrac{637875}{3}) \\ \\ \\ E(y^2) = \dfrac{1}{45} \times 2126.25 \\ \\ \\ \mathbf{E(y^2) = 4725}[/tex]

To determine the standard deviation, we need to first know what is the value of our variance,

So:

Variance [tex]\sigma^2[/tex] = E(x²) - [E(x)]²

Variance [tex]\sigma^2[/tex] = 4725 - (67.5)²

Variance [tex]\sigma^2[/tex] = 4725 - 4556.25

Variance [tex]\sigma^2[/tex] = 168.75

Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{variance}[/tex]

Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{168.75}[/tex]

Standard deviation [tex]\sigma[/tex] = 12.99

Answer:

[tex]W(t)=5(2^t)[/tex]

Step-by-step explanation:

Given that the Newly planted seedlings approximately double their weight every week and a seedling weighing 5 grams is planted at time t = 0 weeks. This represent an exponential function with an equation in the form:

[tex]W(t)=ab^t[/tex].

W(t) is the weight in t weeks, t is the weeks and a is the weight when t = 0. At t = 0, W = 5 g:

[tex]W(t)=ab^t\\W(0)=ab^0\\5=ab^0\\a=5[/tex]

Since the weight double every week, b = 2. The exponential function is given as:

[tex]W(t)=ab^t\\\\W(t)=5(2^t)[/tex]

Answer:

Step-by-step explanation:

Given the equation solved by Ernesto expressed as [tex]\sqrt{\dfrac{1}{2}w+8}=-2[/tex], the extraneous solution obtained by Ernesto is shown below;

[tex]\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8[/tex]

Hence, the extraneous solution that Ernesto obtained is w = -8

The point of intersection of the graph of y = (2/3)x and y = (-3/4)x is at point (0, 0).

An equation is an expression that shows the relationship between two or more numbers and variables.

The straight line passing through (0, 0) and (3, 2) have an equation of y = (2/3)x while the straight line passing through (0, 0) and (4, -3) have an equation of y = (-3/4)x

The point of intersection of the graph of y = (2/3)x and y = (-3/4)x is at point (0, 0).

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#SPJ1

Answer:

Relation (But not a function) Your welcome.

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

The easiest way to do this is to add the new members to the old and then divide by 11. Ignore the remainder.

13 + 52 = 65

65 / 11 = 5 with 10 left over. Ignore the 10. That's not a complete team.

The answer is 5

[tex]-\sqrt{-64}=-\sqrt{8^2\cdot (-1)}-8\sqrt{-1}=-8i[/tex]

Answer:

500,000 pages

Step-by-step explanation:

1 / 5000 = 100 / x

x = 5000(100)

x = 500,000

Answer:

1892705 pages of text.

Step-by-step explanation:

g=Gallon

L=Liters

P=Pages

1L=5000p

1g=3.78541L

100g·3.78541L=378.541L

378.541L·5000=1892705

Answer:

Daily pay= $18

5 days pay = $90

Step-by-step explanation:

Archer's daily pay =p

Pay for 5 days= 5p

Gas = 1/2 of 5p

= 1/2 × 5p

= 5p/2

Water = $5

Balance = $40

5p = 5/2p + 5 + 40

5p - 5/2p = 45

10p -5p /2 = 45

5/2p = 45

p= 45÷ 5/2

= 45 × 2/5

= 90/5

P= $18

5p= 5 × $18

=$90

The equation to determine Archer's daily pay is

5p = 5/2p + 5 + 40

Divide both sides by 5

p = 5/2p + 45 ÷ 5

= (5/2p + 45) / 5

p= (5/2p + 45) / 5

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

Answer:

1, 6, 15, 20, 15, 6, 1

Answer:

Step-by-step explanation:

[tex]-8+4x-12=-4\left(2x-8\right)\\\\\mathrm{Group\:like\:terms}\\\\\mathrm{Subtract\:the\:numbers:}\:-8-12=-20\\\\4x-20=-4\left(2x-8\right)\\\\\mathrm{Expand\:}-4\left(2x-8\right):\quad -8x+32\\4x-20=-8x+32\\\\\mathrm{Add\:}20\mathrm{\:to\:both\:sides}\\4x-20+20=-8x+32+20\\\\Simplify\\\\4x=-8x+52\\\\\mathrm{Add\:}8x\mathrm{\:to\:both\:sides}\\\\4x+8x=-8x+52+8x\\\\\mathrm{Simplify}\\\\12x=52\\\\\mathrm{Divide\:both\:sides\:by\:}12\\\\\frac{12x}{12}=\frac{52}{12}\\\\x=\frac{13}{3}[/tex]

Answer:

Step-by-step explanation:

-8+4x-12 =-8x+32

4x+8x=32+8+12

12x=52

x=52\12

x=41.3

Answer:

Domain is all real numbers, x ≠ -5

Range is all real numbers, y ≠ 0

Step-by-step explanation:

Answer:

3T=504

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

        ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                       PEACE!

Answer:

first number after the decimal point

Step-by-step explanation:

after the decimal point is the tenths, hundredths, and thousandths place.

0.1 - tenths

0.09 - hundredths

0.006 - thousandths

Answer:

x = (y + 26)/5

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out equation

y + 6 = 5(x - 4)

Step 2: Distribute

y + 6 = 5x - 20

Step 3: Isolate x

y + 26 = 5x

Step 4: Isolate variable x

(y + 26)/5 = x

Step 5: Rewrite

x = (y + 26)/5

Answer:

y = 5x - 26

Step-by-step explanation:

Since x is the independent variable, you have to solve for y.

y + 6 = 5(x-4)

Now distribute:

y + 6 = 5x - 20

subtract the 6 from both sides

y + 6 - 6 = 5x - 20 - 6

y = 5x - 26

Answer:

multiply length time width  

Answer:

93km/hr

Step-by-step explanation:

Using the formula Speed = Distance/Time. From the formula we can substitute for time as shown;

Time = Distance/Speed

Let the distance and speed  travelled by Mia be Dm ans Ds respectively

Distance travelled by Kirk be Km and and Ks respective.

Time taken be Mia to travel Tm = Dm/Sm

Time taken be Kirk to travel Tk = Dk/Sk

Since it takes the same length of time for both of them to travel, then Tm = Tk. Hence Dm/Sm = Dk/Sk

Given parameters

Dm = 558 kilometers

Dk = 522 kilometres

If Mia’s average driving speed is 6 kilometers per hour faster than Kirk’s, then Mia's driving speed Sm = 6 + Sk

Required

Mia’s average speed (Sm)

Since Dm/Sm = Dk/Sk

Substituting the given values to get Sk first we have;

558/6+Sk = 522/Sk

Cross multiply

558Sk = 522(6+Sk)

open the parenthesis

558Sk = 3132 + 522SK

558Sk-522Sk = 3312

36Sk =3132

Sk = 3132/36

Sk =87km/hr

SInce Sm = 6+Sk

Sm = 6+87

Sm = 93km/hr

Hence Mia's average speed is 93km/hr

Answer:

510 cm²

Step-by-step explanation:

To find how much construction paper is needed for the model, we calculate the total areas of each of its sides.

The area of the first triangular sides is A₁ = 15 cm × 5 cm = 75 cm²

The area of the second triangular sides is A₂ = 15 cm × 13 cm = 195 cm²

The area of the third triangular sides is A₃ = 15 cm × 12 cm = 180 cm²

The area of each triangular side is A₄ = 1/2 × 5 cm × 12 cm = 30 cm²

The area of the two triangular sides is A₅ = 2A₄ = 2 × 30 cm² = 60 cm²

The total surface area of a wedge of cheese is A = A₁ + A₂ + A₃ + A₅ = 75 cm² + 195 cm² + 180 cm² + 60 cm² = 510 cm²

So the amount of construction paper needed equals the total surface area of the wedge of cheese = 510 cm²

Answer:

510

Step-by-step explanation: