please help it’s easy i’ll give u brainilest <33

Answer:

Option D

Step-by-step explanation:

y = 2(3)^x is the example of exponential equation.

Answer:

[tex]f(n) = \frac{32}{3}(\frac{3}{2})^n[/tex]

Step-by-step explanation:

Given

[tex]r = \frac{3}{2}[/tex]

[tex]f(5) = 81[/tex]

Required

The geometric sequence

A geometric sequence is represented as:

[tex]f(n) = ar^{n-1}[/tex]

Replace n with 5

[tex]f(5) = ar^{5-1}[/tex]

[tex]f(5) = ar^4[/tex]

Substitute values for f(5) and r

[tex]81 = a* (\frac{3}{2})^4[/tex]

Open bracket

[tex]81 = a* \frac{81}{16}[/tex]

Make a the subject

[tex]a = \frac{81 * 16}{81}[/tex]

[tex]a = 16[/tex]

So, the explicit function is:

[tex]f(n) = ar^{n-1}[/tex]

[tex]f(n) = 16 * (\frac{3}{2})^{n-1}[/tex]

Split

[tex]f(n) = 16 * (\frac{3}{2})^n \div (\frac{3}{2})[/tex]

Convert to multiplication

[tex]f(n) = 16 * (\frac{3}{2})^n * \frac{2}{3}[/tex]

[tex]f(n) = \frac{32}{3}(\frac{3}{2})^n[/tex]

Answer:

f(x) = 16*(3/2)^(x-1)

Step-by-step explanation:

right on edge

Answer:

2x(2x+11)

Step-by-step explanation:

4x^2 +22x

Factor out 2x

2x*2x +2x*11

2x(2x+11)

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

Answer:

Velocity in still air: 760 mi/ hr

Velocity against the wind: 210 mi/ hr

Step-by-step explanation:

Given

See attachment for complete question

Required

The rate in still air

The rate of the wind

From the question, the velocity (v) against the wind is:

[tex]v =\frac{distance}{time}[/tex]

[tex]v =\frac{3040}{4}[/tex]

[tex]v_1 =760mi/hr[/tex]

The velocity with the wind is:

[tex]v_2 = \frac{8260}{7}[/tex]

[tex]v_2 = 1180mi/hr[/tex]

Let:

[tex]x \to[/tex] velocity in still air

[tex]y \to[/tex] velocity of the wind

So, we have:

[tex]x - y = 760[/tex]

[tex]x + y = 1180[/tex]

Add both equations

[tex]x + x -y + y = 760 + 1180[/tex]

[tex]2x = 1940[/tex]

Divide by 2

[tex]x = 970[/tex]

Substitute [tex]x = 970[/tex] in [tex]x - y = 760[/tex]

[tex]970 - y= 760[/tex]

Make y the subject

[tex]y = 970 - 760[/tex]

[tex]y = 210[/tex]

Hello!

What is the function rule the line?

f(x) = 2/3x - 2

Good luck! :)

Answer:

(5, -6)

Step-by-step explanation:

The solution is where the lines cross.

Answer:

(5,-6)

Step-by-step explanation:

The solution to the system is where the two graphs intersect.

The graphs intersect at (5,-6)

Answer:

x = 10

Step-by-step explanation:

If n // m , then angle 6  and angle 7 are co interior angles and they are supplementary.

∠6 + ∠7 = 180

140 + x +30 = 180

       x + 170 = 180

               x = 180 - 170

x = 10

Answer:

where is the question oooo

Answer:

MBC=FTTHSGUSJHHUYYVSVHEJSJEVEJDJDHB=**?!1235849

Step-by-step explanation:

M is dead so B is going to collect money. thanks for the update and for some of my friends and for some reason and t and I will get you the information you requested and for your and your and I have a lot going to get you a copy of my CV and I have to be there by and pick it up tomorrow if the update I was just going to text you but the information I need to text me if the is no longer a part y to be y to be y to text or to be there by and pick up tomorrow at noon so we will be able or to be y be able or willing and for the first week of my e to text you and I hope to hear back from the guy I was telling you but you are not a good time to text or to be there by to pick up tomorrow if the update and the update I was just wondering if everything goes well and that the information you have a good ii

Hermes is incorrect. The opposite of 9 is -9 if Hermes says that the opposite of 9 is 9 since each number is 9 units from zero on the number line.

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

To find the same distance away from zero in the opposite direction to determine the opposite number.

The distance from zero in this situation is 9. nine times in the opposite direction from zero.

Thus, Hermes is incorrect. The opposite of 9 is -9 if Hermes says that the opposite of 9 is 9 since each number is 9 units from zero on the number line.

Learn more about the number line here:

brainly.com/question/13189025

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Answer:

50000000000000000000000000000*50000000000000000000000000000*50000000000000000000000000000=1.25e+86

Hope This Helps!!!

Answer:

35 miles

Step-by-step explanation:

You add up all of the miles on the chart to get 35 miles. Have a great day! I hope this helped.

Answer:

It's an identity

Step-by-step explanation:

The answer is an identity

I identity are composed by sin^2 and cos^2

Tan^2 can be simplified into those two sin n cos

Answer:

The quantity of natural numbers between [tex]a^{2}[/tex] and [tex]c^{2}[/tex] is [tex]2\cdot (a + b) + 1[/tex].

Step-by-step explanation:

If [tex]a^{2}[/tex], [tex]b^{2}[/tex] and [tex]c^{2}[/tex] are consecutive perfect squares, then both [tex]a[/tex], [tex]b[/tex] and [tex]c[/tex] are natural numbers and we have the following quantities of natural numbers:

Between [tex]b^{2}[/tex] and [tex]c^{2}[/tex]:

[tex]c^{2} = (b+1)^{2}[/tex]

[tex]c^{2} = b^{2}+2\cdot b + 1[/tex]

[tex]c^{2}-b^{2} = 2\cdot b + 1[/tex]

And the quantity of natural numbers between [tex]b^{2}[/tex] and [tex]c^{2}[/tex] is:

[tex]c^{2}-b^{2}-1 = 2\cdot b[/tex]

Between [tex]a^{2}[/tex] and [tex]b^{2}[/tex]:

[tex]b^{2} = (a + 1)^{2}[/tex]

[tex]b^{2} = a^{2} +2\cdot a + 1[/tex]

[tex]b^{2}-a^{2} = 2\cdot a + 1[/tex]

And the quantity of natural numbers between [tex]a^{2}[/tex] and [tex]b^{2}[/tex] is:

[tex]b^{2}-a^{2}-1 = 2\cdot a[/tex]

And the quantity of natural numbers between [tex]a^{2}[/tex] and [tex]c^{2}[/tex] is:

[tex]Diff = 2\cdot a + 2\cdot b + 1[/tex]

Please observe that the component +1 represents the natural number [tex]b^{2}[/tex]

Answer:

The time is 13.7 years.

Step-by-step explanation:

principal, P = 28000

Rate of interest , R = 4 % annually

Amount, A = 48000

Let the time is t.

Use the formula of the compound interest.

[tex]A = P\times \left ( 1+\frac{r}{100} \right )^t\\\\48000 = 28000\times \left ( 1+\frac{4}{100} \right )^t\\\\1.71 = 1.04^t\\\\log 1.71 = t log 1.04\\\\t =\frac{0.233}{0.017}\\\\t = 13.7 years[/tex]

Answer:

4x²+2x-2

Step-by-step explanation:

x²-3x+7

+

3x²+5x-9

Answer:

4x² + 2x - 2

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

x² - 3x + 7 + 3x² + 5x - 9

Step 2: Simplify

Answer:

she can buy 0 to 12 bags but no more

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

x = 1

y = 4

x + 2y = 1 + 8 = 9

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

9

Step-by-step explanation:

x + 2y

subtitute:

1 + 2(4)

simplify:

1 + 8 = 9

Answer:

44.4

Step-by-step explanation:

Sin=opposite/hypotenuse

Sin40=x/69

x=69sin40

x=44.4 rounded from 44.352

Answer:

x = (4,0)

y = (0,-4)

Step-by-step explanation:

x - y = 4

(0) - y = 4

-(-y) = -(4)

y = -4

x - (0) = 4

x = 4

x = (4,0)

y = (0,-4)

Answer:

x = 4 . 0

y = 0 . -4)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The scale factor is the ratio of corresponding sides, image to original, so

scale factor = [tex]\frac{XY}{AB}[/tex] = [tex]\frac{9}{45}[/tex] = [tex]\frac{1}{5}[/tex] → C

The scale factor will be equal to 1 / 5. the correct option is C.

The scale factor is defined as the proportion of the new image's size to that of the previous image. Dilation is the process of increasing the size of an object while maintaining its shape. Depending on the scale factor, the object's size can be increased or decreased.

In the given image all the angles are the same and the sides are dilated so the scale factor will be calculated as below,

Scale factor = Original size / dilated size

Scale factor = XY / AB

Scale factor = 9 / 45

Scale factor = 1 / 5

Therefore, the scale factor will be equal to 1 / 5. the correct option is C.

To know more about scale factors follow

https://brainly.com/question/25722260

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Answer:

34

Step-by-step explanation:

Answer:

[tex]110 in^{2}[/tex]

Step-by-step explanation:

[tex]===========================================[/tex]

Formulas:

Area of a rectangle/square:

[tex]A=lw[/tex]

[tex]===========================================[/tex]

Squares(2):

5*5=25

Multiply by 2

50 in.

Rectangles(4):

5*3=15

Multiply by 4.

60 in.

Total:

Add.

50+60= 110 in2

I hope this helps!

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope. This is a quadratic so the slope is not something that is constant like it is in a line. Here you have the x coordinates of 1 and 5; each one of these x coordinates has a y coordinate that goes with it. If we draw a line from one of these coordinates to another,  that line will have a slope. That is the slope we are trying to find. Thus, we need the y coordinates that go with each of these x coordinates. To do that, plug x into the equation and do the math to find y:

Let's start with x = 1.

f(1) = [tex]17-(1)^2[/tex] so

f(1) = 16 and the coordinate is (1, 16).

f(5) = [tex]17-(5)^2[/tex] so

f(5) = -8 and the coordinate is (5, -8). Now we apply the slope formula:

[tex]m=\frac{-8-16}{5-1}=\frac{-24}{4}=-6[/tex] So the answer is -6.

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]f(x) = \frac{2x + 3}{4x + 5} \\[/tex]

For [tex]f(-9)[/tex], put "[tex]-9[/tex]" for every value of "[tex]x[/tex]".

[tex]↬f( - 9) = \frac{2( - 9) + 3}{4( - 9) + 5}\\ [/tex]

[tex]↬ f(-9) = \frac{ - 18 + 3}{ - 36 + 5} \\[/tex]

[tex]↬ f(-9) = \frac{ - 15}{ - 31}\\ [/tex]

[tex]↬ f(-9)= \frac{15}{31}\\ [/tex]

[tex] ↬f(-9)= 0.48\\ [/tex]

[tex]\bold{ \green{ \star{ \red{Mystique35}}}}⋆[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{f(x) = \dfrac{2x + 3}{4x + 5}}[/tex]

[tex]\mathsf{y = \dfrac{ 2x + 3}{4x + 5}}[/tex]

[tex]\mathsf{y = \dfrac{2(-9) + 3}{4(-9) + 5}}[/tex]

[tex]\mathsf{2(-9)}[/tex]

[tex]\mathsf{\bf = -18}[/tex]

[tex]\mathsf{y = \dfrac{-18 + 3} {4(-9) + 5}}[/tex]

[tex]\mathsf{-18 + 3}\\\mathsf{= \bf -15}[/tex]

[tex]\mathsf{y = \dfrac{ -15} {4(-9) + 5}}[/tex]

[tex]\mathsf{4(-9)}\\\mathsf{\bf = -36}[/tex]

[tex]\mathsf{y = \dfrac{-15}{-36 + 5}}[/tex]

[tex]\mathsf{-36 + 5}\\\mathsf{= \bf-31}[/tex]

[tex]\mathsf{y = \dfrac{-15}{ -31}\rightarrow\boxed{\bf \dfrac{15}{31}}}[/tex]

[tex]\boxed{\boxed{\huge\text{Answer: } \boxed{\bf f(-9) = \dfrac{15}{31}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

Profit obtained by X =  Rs. 2,976.64

Profit obtained by Y = Rs. 2,545.58

Profit obtained by Z = Rs. 2,777.78

Step-by-step explanation:

Total capital for the first 6 months = Rs 5000 + Rs.4500 + Rs.6500 = Rs. 16,000

Total capital for the next 3 months = Rs. 16,000+ Rs 5000 = Rs. 21,000

Total capital for the last 3 months of the year = Rs. 21,000 + (Rs 4500 * 2) = Rs. 30,000

Share of profit of each partner is the sum of all the ratios of his capital to total capital of the business at each point in time multiply by the ratio of the numbers of months covered by each capital to 12 months and then multiply by RS.8300.

Profit obtained by X = ((Rs 5000 / 16,000) * (6 / 12) * Rs. 8300) +  ((Rs 10,000 / 21,000) * (3 / 12) * Rs. 8300) + ((Rs 10,000 / 30,000) * (3 / 12) * Rs. 8300) =  Rs. 2,976.64

Profit obtained by Y = ((Rs 4500 / 16,000) * (6 / 12) * Rs. 8300) +  ((Rs 4500 / 21,000) * (3 / 12) * Rs. 8300) + ((Rs 13,500 / 30,000) * (3 / 12) * Rs. 8300) = Rs. 2,545.58

Profit obtained by Z = ((Rs 6500 / 16,000) * (6 / 12) * Rs. 8300) +  ((Rs 6500 / 21,000) * (3 / 12) * Rs. 8300) + ((Rs 6,500 / 30,000) * (3 / 12) * Rs. 8300) = Rs. 2,777.78

Confirmation of total profit shared = Rs. 2,976.64 + = Rs. 2,545.58 + Rs. 2,777.78 = Rs. 8,300