please help me with this on the image

9514 1404 393

Answer:

  373 miles

Step-by-step explanation:

The difference in latitude is ...

  39.1° -33.7° = 5.4° = 0.54°(π/180°) radians = 0.03π radians

The arc length is given by ...

  s = rθ, where θ is the angle in radians

The length of the arc along the longitude line is ...

  s = (3960 mi)(0.03π) ≈ 373 mi

The distance from Atlanta to Cincinnati is about 373 miles.

Answer:

y=(3/7)*x+52/7

Step-by-step explanation:

The slope of the line will be (3/7). The equation of line will be y=(3/7)*x+52/7

Answer:

Step-by-step explanation:

Answer:

D. x = -2y + 4

Step-by-step explanation:

4x + 8y = 16

Solve for x

Our objective here is to isolate x ( in other words we want to get x by itself ) using inverse operations.

So let's begin

4x + 8y = 16

First we want to get rid of 8y

Notice how 8y is being added to 4x

Well we can get rid of it by applying it's inverse operation. The opposite of addition is subtraction. So to get rid of 8y we would simply subtract 8y.

Important note! Whatever we do to one side we must do to the other

So we would subtract 8y from both sides

4x + 8y - 8y = 16 - 8y

The 8y on the left hand side cancels out and the 8y on the right side stays as it is as you can't subtract 8y from 16

We then have 4x = 16 - 8y

Next we want to get rid of 4 from 4x.

4x is the same as 4*x which is multiplication

The inverse of multiplication is division so to get rid of the 4 we divide both sides by 4

4x/4 = (16-8y)/4

4x/4 = x

16-8y/4 ( simply divide 16 by 4 and -8y by 4 )

16-8y/4 = 4 - 2y

We're left with x = 4 - 2y which can also be written as x = -2y + 4

Answer:

-6

Step-by-step explanation:

Answer:

[tex]24 + x = 13 \\ x = 13 - 24 \\ x = - 11 \\ thank \: you[/tex]

Answer:

85

Step-by-step explanation:

Given that :

Mean height , μ = 166

Standard deviation, σ = 8

Sample size, n = 1000

Using the Zscore formula :

Zscore = (x - μ) / σ

x = 177

Z = (177 - 166) / 8

Z = 1.375

P(Z > 1.375) = 0.084566(Area to the right of Z)

P(Z > 1.375) * n

0.084566 * 1000 = 84.566 = 85 soldiers

Answer: 7 / 50

Step-by-step explanation:

Given

0.14

Convert to 100-denominator fraction

= 14 ÷ 100

= 14/100

Divide both numerator and denominator by 2

=(14 ÷ 2) / (100 ÷ 2)

=7 / 50

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Step 1:  Complete the first equation

0.01 is a hundredth, therefore if we have 1.86 then we have 186 hundredths.

Step 2:  Complete the second equation

1.86 / 2 = 0.93

0.01 is a hundredth, therefore if we have 0.93 then we have 93 hundredths.

Step 3:  Complete the third equation

1.86 / 2 = 0.93

Cells are the basic building blocks of living things. The human body is composed of trillions of cells, all with their own specialised function. Cells are the basic structures of all living organisms.

Cells provide structure for the body, take in nutrients from food and carry out important functions.

HAVE A GREAT DAY :)

9514 1404 393

Answer:

  (x, y) = (4, -4)

Step-by-step explanation:

A graphing calculator makes graphing very easy. The attachment shows the solution to be (x, y) = (4, -4).

__

The equations are in slope-intercept form, so it is convenient to start from the y-intercept and use the slope (rise/run) to find additional points on the line.

The first line can be drawn by staring at (0, -2) and moving down 1 grid unit for each 2 to the right.

The second line can be drawn by starting at (0, 2) and moving down 3 grid units for each 2 to the right.

The point of intersection of the lines, (4, -4), is the solution to the system of equations.

Answer:

The sample proportion of students who prefer vanilla ice cream is 0.56.

Step-by-step explanation:

Sample proportion of students who prefer vanilla ice cream:

Sample of 375 students.

Of those, 210 said they prefer vanilla ice cream.

The proportion is:

[tex]p = \frac{210}{375} = 0.56[/tex]

The sample proportion of students who prefer vanilla ice cream is 0.56.

Answer:

3

Step-by-step explanation:

Please Mark me brainliest

Answer:

aren't one of the numbers in the equations supposed to be negative?

Answer:

See below

Step-by-step explanation:

we want to prove that A.M, G.M. and H.M between any two unequal positive numbers satisfy the following relations.

well, to do so let the two unequal positive numbers be [tex]\text{$x_1$ and $x_2$}[/tex] where:

the AM,GM and HM of [tex]x_1[/tex] and[tex] x_2[/tex] is given by the following table:

[tex]\begin{array}{ |c |c|c | } \hline AM& GM& HM\\ \hline \dfrac{x_{1} + x_{2}}{2} & \sqrt{x_{1} x_{2}} & \dfrac{2}{ \frac{1}{x_{1} } + \frac{1}{x_{2}} } \\ \hline\end{array}[/tex]

[tex] \displaystyle \rm AM \times HM = \frac{x_{1} + x_{2}}{2} \times \frac{2}{ \frac{1}{x_{1} } + \frac{1}{x_{2}} } [/tex]

simplify addition:

[tex] \displaystyle \frac{x_{1} + x_{2}}{2} \times \frac{2}{ \dfrac{x_{1} + x_{2}}{x_{1} x_{2}} } [/tex]

reduce fraction:

[tex] \displaystyle x_{1} + x_{2} \times \frac{1}{ \dfrac{x_{1} + x_{2}}{x_{1} x_{2}} } [/tex]

simplify complex fraction:

[tex] \displaystyle x_{1} + x_{2} \times \frac{x_{1} x_{2}}{x_{1} + x_{2}} [/tex]

reduce fraction:

[tex] \displaystyle x_{1} x_{2}[/tex]

rewrite:

[tex] \displaystyle (\sqrt{x_{1} x_{2}} {)}^{2} [/tex]

[tex] \displaystyle AM \times HM = (GM{)}^{2} [/tex]

hence, PROVEN

[tex] \displaystyle x_{1} > x_{2}[/tex]

square root both sides:

[tex] \displaystyle \sqrt{x_{1} }> \sqrt{ x_{2}}[/tex]

isolate right hand side expression to left hand side and change its sign:

[tex]\displaystyle\sqrt{x_{1} } - \sqrt{ x_{2}} > 0[/tex]

square both sides:

[tex]\displaystyle(\sqrt{x_{1} } - \sqrt{ x_{2}} {)}^{2} > 0[/tex]

expand using (a-b)²=a²-2ab+b²:

[tex]\displaystyle x_{1} -2\sqrt{x_{1} }\sqrt{ x_{2}} + x_{2} > 0[/tex]

move -2√x_1√x_2 to right hand side and change its sign:

[tex]\displaystyle x_{1} + x_{2} > 2 \sqrt{x_{1} } \sqrt{ x_{2}}[/tex]

divide both sides by 2:

[tex]\displaystyle \frac{x_{1} + x_{2}}{2} > \sqrt{x_{1} x_{2}}[/tex]

[tex]\displaystyle \boxed{ AM>GM}[/tex]

again,

[tex]\displaystyle \bigg( \frac{1}{\sqrt{x_{1} }} - \frac{1}{\sqrt{ x_{2}}} { \bigg)}^{2} > 0[/tex]

expand:

[tex]\displaystyle \frac{1}{x_{1}} - \frac{2}{\sqrt{x_{1} x_{2}} } + \frac{1}{x_{2} }> 0[/tex]

move the middle expression to right hand side and change its sign:

[tex]\displaystyle \frac{1}{x_{1}} + \frac{1}{x_{2} }> \frac{2}{\sqrt{x_{1} x_{2}} }[/tex]

[tex]\displaystyle \frac{\frac{1}{x_{1}} + \frac{1}{x_{2} }}{2}> \frac{1}{\sqrt{x_{1} x_{2}} }[/tex]

[tex]\displaystyle \rm \frac{1}{ HM} > \frac{1}{GM} [/tex]

cross multiplication:

[tex]\displaystyle \rm \boxed{ GM >HM}[/tex]

hence,

[tex]\displaystyle \rm A.M>G.M>H.M[/tex]

PROVEN

Answer:

please tell me the complete question

Answer:

Speed of car = 49 mph (Approx.)

Step-by-step explanation:

Given:

Length of skid marked = 115 ft

Formula for skid mark = S = √21d

Where d = Length of skid marked

Find:

Speed of car

Computation:

Speed of car = √21d

Speed of car = √21(115)

Speed of car = √2,415

Speed of car = 49.1426

Speed of car = 49 mph (Approx.)

Answer:

y=105

Step-by-step explanation:

82+75+x=180

157+x=180

x=23

82+23=y

105=y

Answer:

C

Step-by-step explanation:

sin(theta)=7/8, theta=arcsin(7/8)=61

Answer:

If we put x=17/4

f(4×17/4-15)=8×17/4-27

f(2x=34-27

f(x)=7.

Hope i helped you.

Answer:

πr

Step-by-step explanation:

radius = r/2

so circumference = 2π(r/2)

= 2πr/2

= πr

Answer:

The answer is B which is C=2πr

Step-by-step explanation:

i just did it

Answer:

Step-by-step explanation:

In order to find out how long it takes for the rocket to hit the ground, we only need set that position equation equal to 0 (that's how high something is off the ground when it is sitting ON the ground) and factor to solve for t:

[tex]0=-4.9t^2+112t+395[/tex]

Factor that however you are factoring in class to get

t = -3.1 seconds and t = 25.9 seconds.

Since time can NEVER be negative, it takes the rocket approximately 26 seconds to hit the ground.

9514 1404 393

Answer:

  117.9°

Step-by-step explanation:

Solving the Law of Cosines equation for C, we get ...

  C = arccos((a² +b² -c²)/(2ab))

Filling in the values from the figure, we find the angle X to be ...

  X = arccos((y² +z² -x²)/(2yz)) = arccos((55² +50² -90²)/(2·55·50))

  X = arccos(-2575/5500) ≈ 117.9°

Answer:

The value of the test statistic is 59.75.

Step-by-step explanation:

The test statistic for the population standard deviation is:

[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]

In which n is the sample size, [tex]\sigma_0[/tex] is the value tested and s is the sample standard deviation.

A sample of 45 bottles of soft drink showed a variance of 1.1 in their contents.

This means that [tex]n = 45, s^2 = 1.1[/tex]

The process engineer wants to determine whether or not the standard deviation of the population is significantly different from 0.9 ounces.

0.9 is the value tested, so [tex]\sigma_0 = 0.9, \sigma_0^2 = 0.81[/tex]

What is the value of the test statistic

[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]

[tex]\chi^2 = \frac{44}{0.81}1.1 = 59.75[/tex]

The value of the test statistic is 59.75.

Answer:

8x-21

----------------------

(2x-7)(2x+7)

Step-by-step explanation:

7                       4

-----------   + ------------

4x^2 -49    2x+7

Factor  ( notice that it is the difference of squares)

7                       4

-----------   + ------------

(2x)^2 - 7^2    2x+7

7                       4

-----------       + ------------

(2x-7)(2x+7)    2x+7

Get a common denominator

7                       4(2x-7)

-----------       + ------------

(2x-7)(2x+7)    (2x-7)(2x+7)

Combine

7 +4(2x-7)

----------------------

(2x-7)(2x+7)  

7 +8x-28

----------------------

(2x-7)(2x+7)  

8x-21

----------------------

(2x-7)(2x+7)  

Answer:

(8x - 21) / (2x + 7)(2x - 7)

Step-by-step explanation:

7 / (4x^2 - 49)+ 4 / (2x + 7)

= 7 / (2x + 7)(2x - 7) + 4 / (2x + 7)

LCM = (2x + 7)(2x - 7)   so we have

(7 + 4(2x - 7) / (2x + 7)(2x - 7)

=   (8x - 21) / (2x + 7)(2x - 7).

Answer:

√3/3

Step-by-step explanation:

To obtain Tan θ ;

From trigonometry, tan θ = sin θ / cosθ

Given the paired value : (√3/2, 1/2)

The (cosine, sine ) pair ;

Tan θ = sin (1/2) / cos (√3/2)

Tan θ = (1/2 ÷ √3 / 2) = 1 / 2 * 2 / √3 = 2 / 2√3 = 1 / √3

Tan θ = 1 / √3

Rationlaizing the denominator :

1/√3 * √3/ √3 = √3/√9 = √3/3

Answer:

43

Step-by-step explanation:

1 , 4 , 7 , 10

→ Find the difference between each term

4 - 1 = 3, 7 - 4 = 3 and 10 - 7 = 3

→ Put this into the nth term format

3n + x

→ Write the 3 times tables above the sequence and find what you need to take away from the times tables to get to the sequence

3 , 6 , 9 , 12

1 , 4 , 7 , 10

→ Minus 2

3n - 2

→ Substitute 15 as n

3 × 15 - 2 = 43

Answer and Step-by-step explanation:

When multiplying exponents:

- Product of Powers: When the base of the exponents are the same, and the bases are being multiplied to each other, the exponents are added together.

Example: [tex]a^x + a^y = a^{x+y}[/tex]

- Different bases Same Exponents: When the bases of the exponents are different, but the exponents are the same, the bases multiply together (within a parenthesis) with the exponent on the parenthesis.

Example: [tex]a^x*b^x = (a*b)^x[/tex]

- Quotient of Powers: When the base of the exponents are the same, and they are being divided by each other, the exponents will subtract from each other.

Example: [tex]\frac{a^x}{a^y}= a^{x-y}[/tex]

- Power of a Power: When a base has an exponent, and that entire term has and exponent, the exponents multiply together.

Example: [tex](a^x)^y = a^{x*y}[/tex]

- Power of a Product: The opposite of Different bases Same Exponents. Distribute the exponent onto the different bases.

Example: [tex](ab)^x = a^x*b^x[/tex]

- Power of a Quotient: The opposite of Quotient of Powers. Distribute the exponent to the dividing bases.

Example: [tex](\frac{a}{b} )^x = \frac{a^x}{b^x}[/tex]

- Zero Power: Any number raised to the 0 power equals 1.

Example: [tex]a^0 = 1\\999999^0=1[/tex]

- Negative Exponent: Any number raised by a negative number goes to the denominator of a fraction (if not already in the denominator), and vise versa (goes to the numerator if not already in the numerator).

Example: [tex]a^-2 = \frac{1}{a^2} \\\\\frac{1}{b^-3} = b^3[/tex]

- Power of One: Any number raised to the power of 1 is the same number.

Example: [tex]a^1 = a\\\\999^1 = 999[/tex]

I hope this helps!

#teamtrees #PAW (Plant And Water)