Please help me with this problem

Please Help Me With This Problem

Answers

Answer 1

Answer:

2nd one, 3rd one and last one


Related Questions

The nth term for the question

Answers

Answer:

Step-by-step explanation:

1) nth therm = dn + (a - d)

-10n + (11+10)

-10n + 21

t11 = -110 + 21 = -89

2) nth therm = 3n + (-66 - 3)

3n - 69

t16 = 48 - 69 = -21

what is the value of m in the equation 1/5m - 2/3y = 30 when y = 15

Answers

Answer:

200

Step-by-step explanation:

1/5m-2/3y=30

1/5m-2/3(15)=30

1/5m-30/3=30

1/5m-10=30

1/5m=30+10

1/5m=40

m=40/(1/5)

m=(40/1)(5/1)

m=200/1

m=200

find the area of the triangle

Answers

The area of the triangle is 253.5 yd^2


If 9^x = 81, then 3(3^x) =

A) 27
B) 3
C) 9
D) 81
E) 243

Answers

Answer:

A) 27

Step-by-step explanation:

[tex]9^{x}[/tex] = 81

x = 2

3([tex]3^{2}[/tex]) = 3(9) = 27

Write an equation for a quadratic function in factored form with
zeros at x = -4 and x = 0 that passes through the point (-3,6).

Answers

Answer:

[tex]f(x)=-2x(x+4)[/tex]

Step-by-step explanation:

We want to find the equation of a quadratic function in factored form with zeros at x = -4 and x = 0 that passes through the point (-3, 6).

The factored form of a quadratic is given by:

[tex]f(x)=a(x-p)(x-q)[/tex]

Where p and q are the zeros and a is the leading coefficient.

Since we have zeros at x = -4 and x = 0, let p = -4 and q = 0. Substitute:

[tex]f(x)=a(x-(-4))(x-0)[/tex]

Simplify:

[tex]f(x)=ax(x+4)[/tex]

And since we know that the function passes through the point (-3, 6), f(x) = 6 when x = -3. Thus:

[tex](6)=a(-3)(-3+4)[/tex]

Simplify:

[tex]6=a(-3)(1)[/tex]

Thus:

[tex]-3a=6\Rightarrow a=-2[/tex]

So, our quadratic function is:

[tex]f(x)=-2x(x+4)[/tex]

Solve for x. Round to the nearest tenth, if necessary.

Answers

Cos(o)= ads
CoS61X
5.5=* (Cos (60)
11.344
-
X= 5.5

COSC61)
The answer is in the picture

It has been reported that the average credit card debt for college seniors is $3262. The student senate at a large university feels that their seniors have a debt much less than this, so it conducts a study of 50 randomly selected seniors and finds that the average debt is $2995, and the population standard deviation is $1100. At α = 0.05, is the student senate correct? a) State the hypotheses and identify the claim with the correct hypothesis

Answers

Answer:

Following are the solution to the given point:

Step-by-step explanation:

The formulated null hypothesis would be that the reported average do not differ significantly

[tex]H_o : \mu = \$3262\\\\H_a : \mu < \$3262 \ \text{(One tailed test)}[/tex]

Someone tell me where everyone is going right please !!

Answers

9514 1404 393

Explanation:

The problem statement tells you the meaning of t. It is minutes after Riko leaves. 0 ≤ t < 52.5 is the answer to the question regarding the interval Riko is behind Yuto. It means Riko is behind Yuto for 52.5 minutes after she leaves their house.

t will not be negative because time moves forward. Here, we're only counting time after Riko leaves the house. A negative value for t would refer to a time before Riko leaves the house, which is irrelevant in this problem.*

_____

* One might argue that Riko is behind Yuto for all values of time after Yuto leaves the house, which would be for -21 < t < 52.5. The concept of "behind Yuto" has no meaning except in that interval.

Answer:

again again again hello or merhaba(hello)

speed = path / time

so we can say this;

speed × time = path

note;

two speeds in different directions add up

and

two speeds in the same direction subtract

our speeds are in the same direction so we subtract

0.35 - 0.25 = 0.10 speed

and our path is 5.25 miles because there are 5.25 miles between Yuto and Rico

when will they be in the same place now?

Let's solve with the formul;

speed × time = path

0.10 × time = 5.25 miles

in this equation we find the time 52.5 minutes

After 52.5 minutes they will be in the same place but before 52.5 minutes Riko will be behind Yuto

When Riko was behind Yuto;

0≤ t ≤ 52,5 ( this is our equation of time)

now the second question?

Why can't t be less than 0?

because time cannot take a negative value, as soon as they start moving, time passes and this cannot take a negative value

GOOD LUCK :D

Step-by-step explanation:

greetings from Turkey (≧▽≦)

Carina spent a total of $5.27 buying a pineapple for $3.40 and some tomatoes that were on sale for $0.85 per pound ​

Answers

what's the whole question??

Express tan J as a fraction in simplest terms​

Answers

Answer:

SOH-CAH-TOA

tan = opposite/adjacent

tan J = 15/20 = 3/4

Step-by-step explanation:

If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expression in the parabola's equation?

Answers

Answer:

[tex]y=a(x-h)^{2} +k[/tex]

[tex](x,y)=(-3,14)[/tex]

[tex](h,k)=(-4,6)[/tex]

[tex]14=a(-3-(-4))^{2})+6[/tex]

[tex]14=a(-3+4)^{2} +6[/tex]

[tex]14=a(1)^{2} +6,-6[/tex]

[tex]8=a[/tex]

[tex]ANSWER:8[/tex]

--------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

The measurement of the angle K is 3x - 42, and it is obtuse. Find the restriction(s) on the values of x.

Answers

Answer:

x = 44° and 74°: x cannot be less than 44°, x cannot be greater than 74°.

Step-by-step explanation:

Obtuse angles are greater than 90° but less than 180°.

We can first solve for the lower bound of x.

[tex]3x-42=90[/tex][tex]3x=132\\[/tex][tex]x=44[/tex]°

Thus the lower bound restriction of x is 44°

We can now solve for the upper bound of x.

[tex]3x-42=180[/tex][tex]3x=222[/tex][tex]x=74[/tex]°

Thus the upper bound restriction of x is 74°

Helpppp please
Find the volume of this object.
Use 3 for pi

Answers

Answer:

The sphere

[tex]v=\frac{4}{3} \pi r^{3}=\frac{4}{3}*3.14 *2^{3}=\frac{4*3.14*8}{3}=\frac{100.48}{3}=33.493[/tex]

The cylinder

[tex]v=\pi r^{2} h=3.14*(\frac{4}{2} )^{2}*3=3.14*2^{2}*3=9.42*4=37.68[/tex]

Add those two volumes together:

[tex]33.493 + 37.68 = 71.173 in^{3}[/tex]

SOMEONE PLEASE HELP ME! IM SO CONFUSED, NEED THIS VERY BADLY!

Answers

Answer:

115°

Step-by-step explanation:

in a parallelogram vertically opposite angles are equal.

m∠MNK=m∠KLM=115°

the temperature of a city was 26 degrees celsius on Monday the temperature rise by 2 degrees celsius on everyday upto thrusday and fell by 5 degree Celsius on Friday what was the temperature of the city on Friday​

Answers

Answer: 29 degrees Celsius

Step-by-step explanation:

On Monday, Tuesday, Wednesday, and Thursday, the temperature increased by 2 degrees for a total increase of 8 degrees. Then, on Friday, the temperature decreased by 5 degrees. Since 8 - 5 = 3, the total temperature change is +3 degrees, so the answer is 26 + 3 = 29 degrees

Which correlation is most likely a causation?



the positive correlation between the sales of apples and sales of oranges at a farmer’s market

the positive correlation between the number of crimes in a city and the number of cars in the city

the positive correlation between the height of a person and the number of times a person bumps their head on a low ceiling

the positive correlation between the number of socks and number of shoes in a home

Answers

Answer:

The positive correlation between the number of socks and the number of shoes in home

Step-by-step explanation:

Nah i just get an example so that i can get clue,if my answer is wrong sorry in advanced

Can someone help with this

Answers

answer:

85

explanation:
too long

Using the digits 0, 1, 2, ...8, 9, determine how many 4-digit numbers can be constructed according to the following criteria.
The number must be odd and greater than 6,000; digits may be repeated.
The number of 4-digit numbers that can be constructed is

Answers

Answer:

2000

Step-by-step explanation:

Since the number must be odd, it can have either 1, 3, 5, 7 or 9 in its one's place.

With a 4-digit number starting with 6, any of these digits can be in the one's place and it will still be greater than 6,000.

For the one's place, since we can choose from 5 digits, we have ⁵P₁. In the thousands place, we have one digit which is 6. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively.

So, the total number of 4 digit odd numbers greater than 6000 starting with 6 are 1 × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 1 × 10 × 10 × 5 = 500 numbers.

For the thousands place, we are left with the digits 7, 8 and 9. So, to arrange these 3 digits in the thousands place, we have ³P₁. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively. For the one's place, since we can choose from 5 digits, we have ⁵P₁.

So, the total number of 4 digit odd numbers greater than 6000 starting with 7, 8 or 9 are  ³P₁ × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 3 × 10 × 10 × 5 = 1500 numbers.

So, the total number of 4-digit numbers greater than 6000 that can be constructed is 500 + 1500 = 2000 numbers.

find the area of the shape below​

Answers

Answer:

34?

Step-by-step explanation:

I think 34 because 3×3 is equal to 9. 5×5 is equal to 25. If you add 9+25, you would get 34.

Answer:

24 cm²

Step-by-step explanation:

the area = ½× (3+3) × (5+3)

= ½× 6×8

= 3×8

= 24 cm²

Leon needs to save more than $350 to buy a new bike. He has $130 saved so far, and he plans to save $20 each week until he has enough. The inequality below represents x, the number of weeks he must save to have the extra money needed.

Answers

Answer:

11 weeks

Step-by-step explanation:

350=X*20+130

220=X*20

11=x

solve for y
[tex]2y - 3 = \sqrt{ {3y}^{2} - 10y + 12} [/tex]
absurd answers will be reported!!​

Answers

Answer:

y = 3

Step-by-step explanation:

2y - 3 = [tex]\sqrt{3y^2-10y+12}[/tex]

square both sides to remove sqrt bracket

(2y - 3)^2 = ( [tex]\sqrt{3y^2-10y+12}[/tex] )^2

simplify both sides

(2y - 3)(2y - 3) = [tex]3y^2[/tex] - 10y + 12

[tex]4y^2[/tex] - 12y + 9 = [tex]3y^2[/tex] - 10y + 12

bring all value to left side

[tex]y^2[/tex] - 2y - 3 = 0

factor

(y - 3)(y + 1)

solve for y

y = 3, y = -1

When plugged back into the equation, only y = 3 is true

Answer:

y = 3

Step-by-step explanation :

[tex]2y - 3 = \sqrt{ 3y² - 10y + 12} [/tex]

Swap the sides both of the equation.

[tex]\sqrt{ 3y² - 10y + 12} = 2y - 3 [/tex]

To remove the brackets of equations square both side and simplify .

3y² - 10y + 12 = 4y² - 12y + 9

Move the expression to left-hand side and change its sign.

3y² - 10y + 12 - 4y² + 12y - 9 = 0

collect like terms

3y² - 4y² - 10y + 12y + 12 - 9 = 0

-y² + 2y + 3 = 0

Change the sign of expression. because it helps to solve.

y² - 2y - 3 = 0

Splits the term -2y

y² + y -3y - 3 = 0

Factor out y from the first pair and -3 from second pair of expression.

y ( y + 1 ) - 3 ( y + 1) = 0

Factor out y + 1 from the expression.

( y + 1 ) ( y - 3 ). = 0

When product and factors equals 0. at least one factor is 0.

y + 1 =0

y - 3 = 0

Solve for y

y = -1 and y = 3

If we plug the 3 as y in the expression we find that y = 3 is the true solution of this expression.

This equation has one solution which is y = 3.

According to class 8 please solve

Answers

Answer:

i) 4x

ii) Father's age = 3(x + 10)

Son's age = x + 10

iii) 4x + 10 = 3(x + 10)

iv) Present age of the son = x = 20

Present age of the father = 4x = 4(20)

= 80

Step-by-step explanation:

Present age of the son = x

Present age of the father = 4x

Age of the son in 10 years = x + 10

Age of the father in 10 years = 3(x + 10)

4x + 10 = 3(x + 10)

4x + 10 = 3x + 30

4x - 3x = 30 - 10

x = 20

Given f(x) = 1 - 2x with the range {-3, -5, -7 }, find the domain.

Answers

Answer:

{2,3,4}

Step-by-step explanation:

The range are simply the f(x) values

The range are the x values

To get the x values, we simply get x from each f(x)

So we have;

1-2x = -3

1+ 3 = 2x

2x = 4

x = 4/2

x = 2

Secondly;

1-2x = -5

1 + 5 = 2x

2x = 6

x = 6/2

x = 3

lastly;

1-2x = -7

1 + 7 = 2x

2x = 8

x = 8/2

x = 4

So the domain values are;

{2,3,4}

calculate the exact value of 1 1/3- 3 5/6+ 5 1/9​

Answers

[tex]\displaystyle\bf 1\frac{1}{3} -3\frac{5}{6} +5\frac{1}{9} =5+1-3+\frac{1^{/6}}{3} +\frac{1^{/2}}{9} -\frac{5^{/3}}{6}\\\\\\\ =3+\frac{6+2-15}{18} =3-\frac{7}{18}=\boxed{2\frac{11}{18} }[/tex]

. Out of 140 students, 50 passed in English and 20 passed in both Nepali and English. The number of students who passed in Nepali is twice the number of students who passed in English. Using a Venn-diagram, find the number of students who passed in Nepali only and who didn't pass in both subjects. ​

Answers

Answer:

80 ;

10

Step-by-step explanation:

Given :

Total number of students = μ = 140

Let :

Number of students who passed in English = E

Number of students who passed in Nepali = N

n(NnE) = 20

n(E) only = n(E) - n(NnE) = 50 - 20 = 30

Students who passed English only = 30

Number of students who passed in Nepali is twice the number who passed in English

n(N) = 2 * n(E) = 2 * 50 = 100

Number of students who passed in Nepali only

n(N) only = n(N) - n(NnE) = 100 - 20 = 80

Students who passed Nepali only = 80

The number who didn't pass both subjects :

μ - (English only + Nepali only + English and Nepali)

140 - (30 + 80 + 20)

140 - 130

= 10

I don’t know how to do this can someone help?

Answers

Answer:

Why your question is not visible

Your photo is black screen

Step-by-step explanation:

Please Mark me brainliest

Use the elimination method to solve the system of equations.

A. (1.5,-8)

B. (-6,-13)

C. (0,0)

D. (4.5,-6)

Answers

Answer:

(4.5,-6)

Step-by-step explanation:

[tex]2x-3y = 27\\4x+3y = 0[/tex]

6x = 27

x = 27/6=4.5

9-3y = 27

-3y = 18

y = -6

Can anyone help with this

Answers

Step-by-step explanation:

I solved it in the diagram

a) y=4.9x

b)y=63.7

c)x=13

Can someone help me with this math homework please!

Answers

Answer:

11.2

Step-by-step explanation:

[tex]p =\frac{160.16}{14.3}=\frac{160.16*10}{14.3*10}\\\\p = \frac{1601.6}{143}\\\\[/tex]

p = 11.2

Answer:

The person above me is correct I just did the work and I got the same answer as them :)

Step-by-step explanation:

HURRY NEED ASAP TRYNA FINISH SUMMER SCHOOL LOL, I WILL MARK BRAINLIEST :)) PICTURE IS THERE FOR U

Answers

Answer:

B.

Step-by-step explanation:

Since the numbers in the root is all the same, lets say [tex]\sqrt{2}[/tex] is a variable.

7x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex]

Group with like terms:

7x[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]

Combine like terms:

8x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]

There you have it! Since all the square roots are the same thing, we can treat them like variables.

the answer is B..................

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