Please help me with this question and please show me step by step and the frmula used.

Please Help Me With This Question And Please Show Me Step By Step And The Frmula Used.

Answers

Answer 1

By interpretating the graph of a quadratic equation, the initial height of the ball is equal to 5 feet above ground.

How to determine the initial height of the ball

In this problem we must determine the initial height of the ball according to a graph, whose form resembles quadratic equations. Graphically speaking, the initial height is the y-coordinate of the y-intercept. First, the coordinates of the y-intercept of the equation are:

(t, h) = (0 s, 5 ft)

Second, the final height of the ball is equal to:

h = 5 ft

To learn more on quadratic equations: https://brainly.com/question/29011747

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Related Questions

can someone help answer this and explain how you did it

Answers

Answer:

  2

Step-by-step explanation:

You want the slope of segment DC given points A, B, C, D are collinear and the rise between B and A is 2 units, while the run is 1 unit.

Slope of a line

The slope of a line is the same everywhere on the line. It is the same for segment DC as for segment BA on the same line.

  slope = rise/run = 2/1 = 2

The slope of DC is 2.

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Answer:  SLOPE of DC    =    2

        Thanks for reposting the pertinent question:

        Therefore the SLOPE of DC:

         DC  =   2

Step-by-step explanation:  Cheers to the person who has explained and answered the question correctly as well.Make a Plan:  FORMULA FOR SLOPE OF A LINE:   m = rise/run =  y1  - y2 / x2 - x1

        POINTS:  D, C, B, and A  are COLLINEAR

Now, We can FIND That:

       SLOPE of:  DC  is  Equal (=)  To the SLOPE  of: AB

So, Now, The SLOPE of AB:

       AB  =   2/1   =  2

Now, we conclude that:

       Therefore the SLOPE of DC:

       DC  =   2

I hope this helps you!

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