By interpretating the graph of a quadratic equation, the initial height of the ball is equal to 5 feet above ground.
How to determine the initial height of the ball
In this problem we must determine the initial height of the ball according to a graph, whose form resembles quadratic equations. Graphically speaking, the initial height is the y-coordinate of the y-intercept. First, the coordinates of the y-intercept of the equation are:
(t, h) = (0 s, 5 ft)
Second, the final height of the ball is equal to:
h = 5 ft
To learn more on quadratic equations: https://brainly.com/question/29011747
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can someone help answer this and explain how you did it
Answer:
2
Step-by-step explanation:
You want the slope of segment DC given points A, B, C, D are collinear and the rise between B and A is 2 units, while the run is 1 unit.
Slope of a lineThe slope of a line is the same everywhere on the line. It is the same for segment DC as for segment BA on the same line.
slope = rise/run = 2/1 = 2
The slope of DC is 2.
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Thanks for reposting the pertinent question:
Therefore the SLOPE of DC:
DC = 2
Step-by-step explanation: Cheers to the person who has explained and answered the question correctly as well.Make a Plan: FORMULA FOR SLOPE OF A LINE: m = rise/run = y1 - y2 / x2 - x1POINTS: D, C, B, and A are COLLINEAR
Now, We can FIND That:SLOPE of: DC is Equal (=) To the SLOPE of: AB
So, Now, The SLOPE of AB:AB = 2/1 = 2
Now, we conclude that:Therefore the SLOPE of DC:
DC = 2
I hope this helps you!