please help me with this!!!!!

Answer:

A: 42

Step-by-step explanation: 10.5x4=42

Answer:

your answer is A 42

Step-by-step explanation:

make me brainliest

Answer:

The amount paid as VAT is $ 12800.

Step-by-step explanation:

Sales = $ 80,000

VAT = 16 %

The amount of VAT paid to the government is

= 16 % of $ 80,000

= 0.16 x $ 80,000

= $ 12800

The amount paid as VAT is $ 12800.

Answer: 52x+4

Step-by-step explanation: Do 16(2x-1)+4(5x+5) and get 52x+4.

Answer:

what do you mean for this question. What do you need help on?

Answer:

If I understand this right, the answer is $48.00

Step-by-step explanation:

If they pay $1.50 three times a month just times $1.50 by 12 because there are 12 days in a month, then you get 16, then you times 16 by 3 and you get 48.

(I hope this is right lol)

Answer:

$54.00

Step-by-step explanation:

3 transactions × $1.50 per transaction = $4.50 per month

$4.50 × 12 months in a year = $54.00

Answer:

relation only

Step-by-step explanation:

The vertical line will be relation only.

Function is a type of relation, or rule, that maps one input to specific single output.

In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable.

In mathematics and the physical sciences, functions are indispensable for formulating physical relationships.

Noted that Linear function is a function whose graph is a straight line

We can conclude that  vertical line would be relation only.

Learn more about function here:

https://brainly.com/question/2253924

#SPJ3

Answer:

8 - 42x - 56y - 12xy

Step-by-step explanation:

Length = 4 - 7(3x + 4y)

= 4 - 21x - 28y

Width = 3x(-2y)

= -6xy

Perimeter of the rectangle = 2(length + width)

= 2{(4 - 21x - 28y) + ( -6xy)}

= 2(4 - 21x - 28y - 6xy)

= 8 - 42x - 56y - 12xy

Perimeter of the rectangle = 8 - 42x - 56y - 12xy

Answer:

He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots.

Step-by-step explanation:

He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots. The true factorized form of the fourth grade polynomial is:

[tex]r(x) = (x^{2}+1)\cdot (x^{2}-9)[/tex]

[tex]r(x) = (x- i)\cdot (x+i)\cdot (x+3)\cdot (x-3)[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{2.3(x - 2) = 15}[/tex]

[tex]\mathsf{2.3(x) + 2.3(-2) = 15}[/tex]

[tex]\mathsf{2.3x - 4.6 = 15}[/tex]

[tex]\large\textsf{ADD 4.6 to BOTH SIDES}[/tex]

[tex]\mathsf{2.3x - 4.6 + 4.6 = 15 + 4.6}[/tex]

[tex]\large\textsf{CANCEL out: -4.6 + 4.6 because it gives the number 0}[/tex]

[tex]\large\textsf{KEEP: 15 + 4.6 because that helps solve find the x-value}[/tex]

[tex]\mathsf{15 + 4.6 = \boxed{\bf 19.6}}[/tex]

[tex]\large\textsf{NEW EQUATION: 2.3x = 19.6}[/tex]

[tex]\large\textsf{DIVIDE 2.3 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{2.3x}{2.3}=\dfrac{19.6}{2.3}}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{\dfrac{2.3}{2.3}}\large\textsf{ because that gives you 1}[/tex]

[tex]\large\textsf{KEEP: }\mathsf{\dfrac{19.6}{2.3}}\large\textsf{ because that gives you the value of x}[/tex]

[tex]\mathsf{\dfrac{19.6}{2.3}= \boxed{\bf x}}[/tex]

[tex]\mathsf{\boxed{\bf x}=\dfrac{19.6}{2.3}}[/tex]

[tex]\boxed{\bf {x = 8.521739}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf x = 8.521739}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:) }[/tex]

Answer:

13[tex]\sqrt{22}[/tex] / 44

Step-by-step explanation:

cos A = 9/13

here adjacent = 9 and hypotenuse = 13  opposite = ?

using pythagoras theorem to find opposite

a^2 + b^2 = c^2

9^2 + b^2 = 13^2

81 + b^2 = 169

b^2 = 169 - 81

b^2 = 88

b = [tex]\sqrt{88}[/tex]

b =  [tex]2\sqrt{22}[/tex]

therefore opposite =  [tex]2\sqrt{22}[/tex]

cosec A = hypotenuse/opposite

= 13/[tex]2\sqrt{22}[/tex]

rationalizing the denominator

=13/ [tex]2\sqrt{22}[/tex]  *  [tex]2\sqrt{22}[/tex] /  [tex]2\sqrt{22}[/tex]

=13 *[tex]2\sqrt{22}[/tex] /( [tex]2\sqrt{22}[/tex] )^2

=26 [tex]\sqrt{22}[/tex] / 4*22

=26 [tex]\sqrt{22}[/tex] / 88

=13[tex]\sqrt{22}[/tex] / 44

Answer:

[tex]cosec A = \frac{13}{\sqrt{88}}[/tex]

   OR

[tex]cosec A = \frac{13 \sqrt{22}}{44}[/tex]

Step-by-step explanation:

Formulas used:

[tex]cos^2 A = 1 - sin^2 A\\\\cosec A = \frac{1}{sin A}[/tex]

Given :

  [tex]cos A = \frac{9}{13}[/tex]

Find cosec A

   [tex]sin ^2 A = 1 - cos^2 A[/tex]

              [tex]= 1 - (\frac{9}{13})^2\\\\= 1 - \frac{81}{169}\\\\=\frac{169 - 81}{169}\\\\=\frac{88}{169}[/tex]

 [tex]sin A = \sqrt{\frac{88}{169}} = \frac{\sqrt{88}}{13}[/tex]

Therefore,

         [tex]cosec A = \frac{1}{sin A} = \frac{1}{ \frac{\sqrt{88}}{13}} = \frac{13}{ \sqrt{88}}[/tex]

OR In a simplified form :

[tex]cosec A = \frac{13}{\sqrt{88}} \times \frac{\sqrt{88}}{\sqrt{88}} = \frac {13 \times \sqrt{4 \times 22}}{88} = \frac{13 \times 2 \sqrt{22}} {88} = \frac{13 \sqrt{22}}{44}[/tex]        

Answer:

16+5w/4

Step-by-step explanation:

Answer:

3.75

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

that's a very vague question

Answer:

∠ LHJ = 55°

Step-by-step explanation:

Consecutive angles in a parallelogram are supplementary, sum to 180° , so

∠ LHJ + ∠ KLH = 180° , that is

∠ LHJ + 125° = 180° ( subtract 125° from both sides )

∠ LHJ = 55°

Answer:

I think you mean significant figures

Step-by-step explanation:

Answer:

3  7/15

Step-by-step explanation:

1 4/5 + 2 2/3 - 16/15

9/5 + 8/3 - 16/15

27/15 + 40/15 - 16/15

52/15 = 3  7/15

Answer:

3 2/5

Step-by-step explanation:

STEP 1: Convert all fractions into improper fractions

9/5 + 8/3 - 16/15

Step 2: pass denominators

(9x3 + 8x5 - 16) / 15

=51/15

Step it into proper mixed number

3 2/5

Answer:

6 6 6 6 11

Step-by-step explanation:

The median is the middle number

the mode is the number of items, usually the number that are the same.

the mean is the average

the range is the number between the smallest and the largest.

So the information you have makes 4 of the 5 numbers the same.

The middle number is 6. This is an interesting fact because it means that 4 of the five numbers are 6

x 6 6 6 6  or  6 6 6 6 x  is what you know so far.

The range is a bit of a devil. And so is the mean. We need the mean to be related to  5*7 = 35. So the sum of the five numbers equals 35. The range would have to be 5, I think. (35 - 4*6) = 11

The difference between 11 and 6 = 5

So 11 works for everything but the range.

If the range must be ten, then x = 16 but then the mean = 8 and 7  is incorrect

So I can get 3 out of 4, but not them all.

The lower the frequency the least common the average.

There are two frequencies that are 1, which would be the least common.

The answer is C. 0.320-0.329 and 0.360 -0.369

Answer:

option C

Step-by-step explanation:

option c is contains the two batting averages which have a frequency of 1, this means that they both only occurred once which is the least amount of times any of the batting averages has occurred.

Answer:

v = 27,000 mm³

Step-by-step explanation:

v = s³

v = 30³

v = 27,000 mm³

Answer:

Part A

The volume of the triangular prism is 500 cm³

Part B

The total surface area of the prism is approximately 441.42 cm²

Step-by-step explanation:

The given details are;

The dimensions of the side length of the cube, s = 10 cm

The shape the cube was cut across to obtain = A prism

Part A

Whereby the prism obtained is a triangular prism, we have;

The cube can be cut in half to form a triangular prism

The volume of each triangular prism obtained = (1/2) × The volume of the cube

∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³

Part B

The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism

The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50

The square cross sectional area, A₂  = 10 × 10 = 100

The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2

The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃

∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42

The total surface area of the prism, A ≈ 441.42 cm²

[tex]f(x) = \log_b(x)[/tex] is a decreasing function when [tex]0 < b < 1[/tex]

This is because we can use the change of base formula to say

[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]

If b is between 0 and 1, not including either endpoint, notice how the log(b) term is negative.

For example, if b = 0.5, then log(b) = log(0.5) = -0.301 approximately. I'm using log base 10 to get log(0.5) = -0.301

So for b = 0.5, we have,

[tex]\log_{0.5}(x) = \frac{\log(x)}{\log(0.5)} \approx \frac{\log(x)}{-0.301} \approx -3.322\log(x)[/tex]

The log(x) part on its own is always increasing. The negative coefficient out front flips it to always decreasing.

By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex]decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D) #SPJ5

Logarithms are trascendent functions whose form is defined by the following expression:

[tex]\log _{b} x[/tex] such that [tex]x = b^{a}[/tex], where b > 0.

Where b is the base of the power.

Whose rules are described below:

By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex] is a decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D)

The statement is poorly formatted and reports several mistakes. Correct form is shown below:

For what values of b will [tex]F(x) = \log_{b} x[/tex] be a decreasing function?

A. b > 0

B. 0

C. b < 0

D. 0 < b < 1

To learn more on logarithms, we kindly invite to check this: https://brainly.com/question/20785664 #SPJ5

Answer:

See Explanation

Step-by-step explanation:

You posted an incomplete question with little and unclear details.

I will answer this question with a more complete version (see attachment)

Given that:

[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]

Required

The fraction that passed the test

Rearrange the score in ascending order:

[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

The total number of students is:

[tex]n =20[/tex]

Extract the students that passed (scored 70 and above)

[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

Their numbers are:

[tex]Passed: 14[/tex]

So, the fraction of those that passed is:

[tex]Fraction = \frac{Passed}{n}[/tex]

[tex]Fraction = \frac{14}{20}[/tex]

Reduce fraction

[tex]Fraction = \frac{7}{10}[/tex]

Answer:

to do this lets first solve this so

5*5*5*5=625

5^-3=0.008

0.008^2=0.000064

0.000064*625=0.4

so all equations that are equal to 0.4 are right which is C

Answer:

12

Step-by-step explanation:

Answer:

The answer is below

Step-by-step explanation:

The area of the wall is 84 ft².

The width of the wallpaper is 18 in.

1 ft. = 12 in

Hence; 18 in = 18 in * 1 ft. per 12 in = 1.5 ft

The length of the wallpaper is 33 ft.

Therefore, the area of the wallpaper = length * width = 1.5 ft. * 33 ft. = 49.5 ft². This means that each roll of wallpaper has an area of 49.5 ft²

Therefore, the minimum amount of rolls of wallpaper needed = area of wall / area of wallpaper

Amount of wallpaper = 84 ft² / 49.5 ft² = 1.7 rolls

Answer:

[tex]\theta = \frac{\pi}{6}[/tex]

Step-by-step explanation:

[tex]tan^ 2 \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) tan \theta + 1 = 0\\\\tan \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) +\frac{1}{ tan \theta } = 0\\\\[/tex]          [tex][ \ divide \ by \ tan \theta \ on \ both \ sides \ ][/tex]

[tex]tan\theta + \frac{1}{ tan \theta }- ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\\frac{tan^2 \theta + 1}{ tan \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\\frac{sec ^2 \theta}{ \frac{sin \theta }{cos \theta}} - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0[/tex]              [tex][ \tan ^ 2\theta + 1 = sec ^2 \theta \ , \ tan \theta = \frac{sin \theta }{cos \theta } \ ][/tex]

[tex]\frac{sec^2 \theta }{sin \theta \times sec \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]                  [tex][\ \frac{sin \theta }{cos \theta } = sin \theta \times sec \theta \ ][/tex]

[tex]\frac{sec \theta }{sin \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]

[tex]sec \theta \ cosec \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]              [tex][ \ \frac{1}{sin \theta } = cosec \theta \ , \ \frac{ sec \theta }{sin \theta } = sec \theta cosec \theta \ ][/tex]

[tex]sec \theta \ cosec \theta - \sqrt 3 - \frac{1}{\sqrt3}} = 0\\\\\frac{\sqrt 3\ sec \theta \ cosec \theta - 3 - 1}{\sqrt3} = 0\\\\\sqrt 3 sec \theta cosec \theta - 4 = 0\\\\[/tex]              

[tex]\sqrt3 \frac{1}{cos \theta } \frac{1}{sin \theta } - 4 = 0\\\\\frac{\sqrt3 - 4sin \theta cos \theta} { sin \theta cos \theta } = 0[/tex]                      

[tex]\sqrt 3 - 2sin 2\theta = 0[/tex]                                  [tex][ \ sin 2 \theta = 2 sin \theta cos \theta \ ][/tex]

[tex]2sin 2 \theta = \sqrt3\\\\sin 2 \theta = \frac{\sqrt3 }{2} \\\\2 \theta = sin^{-1} (\frac{\sqrt3}{2})\\\\2 \theta = 60^{ \circ} = \frac{ \pi}{3}\\\\\theta = \frac{\pi} {6}[/tex]