Please Help Me!!! (WORTH 60 POINTS) Will Give Extra points out

Please Help Me!!! (WORTH 60 POINTS) Will Give Extra Points Out

Answers

Answer 1
Answer:

O C.

Step-by-step explanation:

To find a missing side length, use Pythagorean Theorem:

a^2 + b^2 = c^2 where a = 5 b = x and c = 6

5^2 + x^2 = 6^2

25 + x^2 = 36

x^2 = 36 - 25

x^2 = 11

x = 3.3

The value of x is sqrt rt 11

Answer 2

Answer:

√11 cm

Step-by-step explanation:

Pythagorean Thereom

a^2 + b^2= c^2

x^2 +5^2=6^2

x^2 + 25 = 36

subtract 25 from both sides

x^2=11

do the square root

x = √11


Related Questions

Write the point-slope form of an equation of the line through the points (-1, 4) and (-2, 2).

Answers

Answer:

Point-slope form: y-4=2(x+1)

Slope intercept form: y=2x+6

I hope this helps!

Answer:

[tex]y-4=2(x+1)[/tex]

Step-by-step explanation:

Point-slope form is equal to

[tex]y-y_1=m(x-x_1)[/tex]

where y and y1 are the known y coordinates of two points on the line, and x and x1 are the known x coordinates of two points on the line. All we need now is m, which is the slope:

[tex]4-2=m(-1-(-2))[/tex]

We can simplify negative one minus negative two as positive 1.

[tex]4-2=m(1)[/tex]

4 minus 2 is 2, so m times 1 is 2. That means m is 2.

Now, we have the slope, so we can convert to point-slope form using one of the two points. Let's use (-1, 4). We can plug those values in for x1 and y1:

[tex]y-4=2(x+1)[/tex]

A line passes through the point (-4, -6) and has a slop of 5. Write an equation for this line.

Answers

The answer is y=5x+14 where 5 is the slope and 14 is the value of b in equation y=mx+c

In the diagram below, circle O has a radius of 10. If the measure of arc AB is 72°, find the area of shaded sector AOB, in terms of π. Show all your work that leads to the final answer.

Answers

Answer:

62.8

Step-by-step explanation:

Area of sector=(pi*r^2)*(theta/360)

Area of sector=(pi*100)*(72/360)=62.8

The area of the shaded sector AOB in terms of π is 20π units squared.

How to find area of a sector?

The area of a sector can be described as follows;

area of sector = ∅ / 360 × πr²

where

r = radius of the circle

Therefore,

r = 10 units

∅ = 72°

Hence,

area of the sector = 72° / 360° × π10²

area of the sector = 7200 / 360 π

area of the sector = 20π units²

learn more on sector here: https://brainly.com/question/24351015

#SPJ2

5. Given a test in which there is overlap of the test results for diseased and non-diseased individuals (e.g., normal individuals are found who have test results ranging in value from 8 to 15, and diseased individuals are found who have test results ranging in value from 12 to 25, so that in the range of values 12 to 15 there are both normal and diseased individuals), if the current cutoff value lies in the range of this overlap and you move the cutoff value toward the normal population (lower numbers in this example), the true negative numbers will _____________________ . (5 points)

Answers

Answer:

True negative numbers are considered as diseased individual. So, the true negative numbers will increase

Step-by-step explanation:

True negative numbers are considered as diseased individual. So, the true negative numbers will increase.

The automatic opening device of a military cargo parachute has been designed to open when the parachute is 185 m above the ground. Suppose opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m. Equipment damage will occur if the parachute opens at an altitude of less than 100 m. What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes

Answers

Answer:

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

Step-by-step explanation:

For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.

To find the probability of damage on a parachute, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability of a parachute having damage.

The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that [tex]\mu = 185, \sigma = 32[/tex]

Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of  Z when X = 100. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 185}{32}[/tex]

[tex]Z = -2.66[/tex]

[tex]Z = -2.66[/tex] has a p-value of 0.0039.

What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?

0.0039 probability of a parachute having damage, which means that [tex]p = 0.0039[/tex]

5 parachutes, which means that [tex]n = 5[/tex]

This probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807[/tex]

Then

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193[/tex]

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

PLEASE gelp me with this, gelp me please oh please gelp me!

Answers

Answer:

V = 2143.57 cm^3

Step-by-step explanation:

The volume of a sphere is

V = 4/3 pi r^3

The diameter is 16 so the radius is 1/2 of the diameter or 8

V = 4/3 ( 3.14) (8)^3

V =2143.57333

Rounding to the nearest hundredth

V = 2143.57 cm^3

Answer:

2143.57 cm^3

Step-by-step explanation:

V = 4/3 * 3.14 * r^3

r = 1/2 * 16 = 8

So V = 4/3 * 3.14 * 8^3

= 2143.57 cm^3.

I need help really bad

Answers

Answer:

1 ???????

Step-by-step explanation:

HELP WILL GIVE BRAINLYIST

Answers

Answer:

The parent cubic function has been vertically stretched by a factor of 4.

Equation:G(x)= 4[tex]\sqrt[3]{x}[/tex]

Answer: Option B

OAmalOHopeO

The answer is option B

Tickets to a local movie were sold at $6.00 for adults and $4.50 for students. If 390 tickets were sold for a total of $2190.00, how many student tickets were sold

Answers

Answer: Therefore 100 student tickets were sold

Step-by-step explanation:

Let the number of student tickets be x

So adult tickets = 390 - x

ATQ

4.5(x) + 6(390-x) = 2190

4.5x + 2340 - 6x = 2190

-1.5x + 2340 = 2190

-1.5x = 2190-2340

-1.5x = -150

x = -150/-1.5

x = 100

Therefore 100 student tickets were sold

please click thanks and mark brainliest if you like :)


What is the inverse of the function a(x)=1/x-2

Answers

Answer:

x = 1/x - 2

Step-by-step explanation:

Power Function:
Consider the following graphs (1 and 2), and answer the questions FOR EACH GRAPH:

A) In what interval of the graph is it increasing, decreasing and constant? This answer must be justified by means of the definition
B) What is the domain and range?
C) Is it an odd or even function? This answer must be justified by means of the definition

Answers

Graph 1

Part (a)

The function is increasing when x > 0. The function is decreasing when x < 0.

The function is never constant

An increasing portion is when the graph goes uphill when moving left to right. A decreasing portion goes in the opposite direction: it goes downhill when moving left to right.

The reason why the function is never constant is because there aren't any flat horizontal sections. Such sections are when x changes but y does not. No such sections occur.

------------------------

Graph 1

Part (b)

Domain = set of all real numbers

Range = set of y values such that [tex]y \ge 0[/tex]

The domain is the set of all real numbers because we can plug in any value for x without any restriction. There are no division by zero errors to worry about, or square roots of negative numbers to worry about either.

The range is the set of nonnegative numbers as the graph indicates. The lowest y gets is y = 0.

------------------------

Graph 1

Part (c)

The function is even

The function f(x) = 1.6x^12 is an even function due to the even number exponent. For any polynomial, as long as the exponents are all even, then the function itself is even. If all the exponents were odd, then the function would be odd. This applies to polynomials only. A power function is a specific type of polynomial.

Note in the graph, we have y axis symmetry. The mirror line is vertical and placed along the y axis. This is a visual trait of any even function.

We could use algebra to show that f(-x) = f(x) like so

f(x) = 1.6x^12

f(-x) = 1.6(-x)^12

f(-x) = 1.6x^12

The third step is possible because (-x)^12 = x^12 for all real numbers x. It's similar to how (-x)^2 = x^2. You could think of it like (-1)^2 = (1)^2

============================================================

Graph 2

Part (a)

The function is decreasing when x < 0 and when x > 0

The function is never increasing

The function is never constant

In other words, the function is decreasing over the entire domain (see part b). The only time it's not decreasing is when x = 0.

The function is decreasing because the curve is going downhill when moving to the right. You can think of it like a roller coaster of sorts.

At no point of this curve goes uphill when moving to the right. Therefore, it is never increasing. The same idea applies to flat horizontal sections, so there are no constant intervals either.

------------------------

Graph 2

Part (b)

Domain: x is any real number but [tex]x \ne 0[/tex]

Range: y is any real number but [tex]y \ne 0[/tex]

Explanation: If we tried plugging x = 0 into the function, we get a division by zero error. This doesn't happen with any other number. Therefore, the set of allowed inputs is any number but 0.

The range is a similar story. There's no way to get y = 0 as an output.

If we plugged y = 0 into the equation, then we'd get this

y = 17x^(-3)

0 = 17/(x^3)

There's no way to have the right hand side turn into 0. The numerator is 17 and won't change. Only the denominator changes. We can't have the denominator be 0.  

------------------------

Graph 2

Part (c)

The function is odd

We can prove this by showing that f(-x) = -f(x)

f(x) = 17x^(-3)

f(-x) = 17(-x)^(-3)

f(-x) = 17* ( -(x)^(-3) )

f(-x) = -17x^(-3)

f(-x) = -f(x)

This is true for nearly all real numbers x, except we can't have x = 0.

Graphic 1:

(A) If f(x) = 1.6x ¹², then f '(x) = 19.2x ¹¹. Both f '(x) and x have the same sign, which means

• for -∞ < x < 0, we have f '(x) < 0, so that f(x) is decreasing on this interval

• for 0 < x < ∞, we have f '(x) > 0, so f(x) is increasing on this interval

f(x) is not constant anywhere on its domain.

(B) Speaking of domain, since f(x) is a polynomial (albeit only one term), it has

• a domain of all real numbers

• a range of {y ∈ ℝ : y = f(x) and y ≥ 0} (in other words, all real numbers y such that y = 1.6x ¹² and y is non-negative)

(C) This function is even, since

f(-x) = 1.6 (-x)¹² = (-1)¹² × 1.6x ¹² = 1.6x ¹² = f(x)

Graphic 2:

(A) Now if f(x) = 17/x ³, then f '(x) = -51/x ⁴. Because x ⁴ ≥ 0 for all x, this means f '(x) < 0 everywhere, except at x = 0. So f(x) is decreasing for (-∞ < x < 0) U (0 < x < ∞).

(B) f(x) has

• a domain of {x ∈ ℝ : x ≠ 0} (or all non-zero real numbers)

• a range of {y ∈ ℝ : y = f(x) and y ≠ 0} (also all non-zero reals)

(C) This function is odd:

f(-x) = 17/(-x)³ = 1/(-1)³ × 17/x ³ = -17/x ³ = -f(x)

Which equation is in standard form?
a. X +3= -5y
b. 5-y=x
c. y =3x + 6
d. -8x+ 3y = 12

Answers

选项 (d)

option (d)

!!!!!!!!!

if x and y are linear pair of angel then x +y=​

Answers

Answer: x + y = 180²

Step-by-step explanation:

A linear pair is a pair of adjacent, supplementary angles.

Adjacent means next to each other.

Supplementary means that the measures of the two angles add up to equal 180 degrees.

Therefore, by definition, if x and y are linear pairs of angles, then x + y = 180.

what are the factor of pair of number?

a.45 and 60

b.45 and 70

c.40 and 80

d.30 and 50

Answers

C…………………………x Mmmmmvvtvjvj I j I

Help plz last question

Answers

Answer:

224π in^2

Step-by-step explanation:

Just plug in the values,

Surface area=2πr(h+r) [Factoring]

r=7in

h=9in

2πr(h+r)=2π*7(9+7)=14π(16)=224π in^2

how many ways can this be done. if a committee of 5 people from 7 men and 8 women?​

Answers

Answer:

3003 ways

Step-by-step explanation:

(7+8)C5

= 15C5

= 15!/(5!10!)

= 3003

The length L of the base of a rectangle is 5 less than twice its height H. Write the algebraic expression to model the area of the rectangle.

Answers

Answer:

Area of rectangle = 2H² - 5H

Step-by-step explanation:

Let the length be L.Let the height be H.

Translating the word problem into an algebraic expression, we have;

Length =2H - 5

To write the algebraic expression to model the area of the rectangle;

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = L * H

Where;

L is the Length.H is the Height.

Substituting the values into the formula, we have;

Area of rectangle = (2H - 5)*H

Area of rectangle = 2H² - 5H

[tex]2i+3x=4-ix[/tex]

Show work.

No wrong answers or you will be reported. I will mark Brainliest! Thank you!

Answers

Answer:

Step-by-step explanation:

I am assuming i is the imaginary number:

Factor:

(3 + i)x - (4-2i) = 0.

In order for this to equal 0, x must be equal to 1-i.

I don't want to be reported to so take my word for it.

Also I plugged it into wolfram alpha so if it is wrong, blame the most powerful math equation solver available on the internet.

Using BTS he properties, find the unit's digit of the cube of each of the following numbers

If a ∥ b and b ⊥ y, then _____

Answers

Answer:

a ⊥ y

Step-by-step explanation:

since b is parallel to a & perpendicular to y , line y will eventually cut across line a at a 90 degree angle as well

Answer:

a ⊥ y

Step-by-step explanation:

Look at the image given below.

Find the missing segment in the image below

Answers

Answer:

x = 42

Step-by-step explanation:

24+8 = 32

[tex]\frac{x}{24}[/tex] = [tex]\frac{x+14}{32}[/tex]

32x = 24(x+14)

32x = 24x+336

8x = 336

x = 42

the value of 5/121^1/2​

Answers

Answer:

√5/121

Step-by-step explanation:

formula: a^½=√a

(⁵/¹²¹)^½=√⁵/¹²¹

I need help on this plzzz I and not the best at math ​

Answers

Answer:

See attachment for graph

Step-by-step explanation:

Given

[tex]f(x) = \left[\begin{array}{cc}-1&x<-1\\0&-1\le x \le -1\\1&x>1\end{array}\right[/tex]

Required

The graph of the step function

Before plotting the graph, it should be noted that:

[tex]\le[/tex] and [tex]\ge[/tex] use closed circle at its end

[tex]<[/tex] and [tex]>[/tex] use open circle at its end

So, we have:

[tex]f(x) = -1,\ \ \ \ x < -1[/tex]

The line stops at -1 with an open circle      

[tex]f(x) = 0,\ \ \ \ -1 \le x \le 1[/tex]

The line starts at - 1 and stops at -1 with a closed circle at both ends

[tex]f(x) = 1,\ \ \ \ x > 1[/tex]

The line starts at 1 with an open circle

The options are not complete, so I will plot the graph myself.

See attachment for graph

please help me with geometry

Answers

Answer:

x = 7

Explaination:

ABC = 40°

and BD bisects the angle so ABD = 20°

so 3x-1=20

solving for x gets us

x = 7

The measurements of a circular object are given in the ratio table.

a. Find the missing dimensions of other circular objects by completing the ratio table.

b. Graph the pairs of values.

Answers

Answer:

answer hajandtb Tj.yfs5bsyb

What is the distance between the following points?
WILL GIVE BRAINLIEST

Answers

Answer:

D.√85

Step-by-step explanation:

We can find the distance between two points using the distance between two points formula

Distance between two points formula:

d = √(x2 - x1)² + (y2 - y1)²

Where the x and y values are derived from the given points

We are given the two points (-2,7) and (7,9)

Using these points let's define the variables ( variables are x1, x2, y1, and y2)

Remember points are written as follows (x,y)

The x value of the first point is -2 so x1 = -2

The x value of the second point is 7 so x2 = 7

The y value of the first point is 7 so y1 = 7

The y value of the second point is 9 so y2 = 9

Now that we have defined each variable let's find the distance between the two points

We can do this by substituting the values into the formula

Formula: d = √(x2 - x1)² + (y2 - y1)²

Variables: x1 = -2, x2 = 7, y1 = 7, y2 = 9

Substitute values in formula

d = √(7 - (-2))² + (9 - 7)²

Evaluation:

The two negative signs cancel out on 7-(-2) and it changes to +7

d = √ (7+2)² + (9-7)²

Add 7+2 and subtract 9 and 7

d = √ (9)² + (2)²

Simplify exponents 9² = 81 and 2² = 4

We then have d = √ 81 + 4

Finally we add 81 and 4

We get that the distance between the two points is √85

a number has 7 at the tens place .there is zero in the thousand place. the number 5 is at the hundreds place .there is number 1at the ten thousand place..what is the number?​

Answers

10570 - ten thousand, five hundred and seventy

11 10 Find the area of the shaded region. Round your answer to the nearest tenth.​

Answers

the answer is 110 because 11 times 10 is 110

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is
multiplied by what factor to produce the radius of sphere B?
A.4/7
B.7/8
C.8/7
D.7/4

Answers

Answer:

B

Step-by-step explanation:

If the diameter of sphere B is 42, that means the radius is half, so it is 21.

The question is asking what multiplied by 24 is 21, or 21 divided by 24. 21/24 can be simplified to 7/8.

A cylinder with a base diameter of x units has a volume of excubic units.
Which statements about the cylinder are true,Select
two options.

1)The radius of the cylinder is 2x units.

2)The area of the cylinder's base is 1/4 piex^2square units.

3)The area of the cylinder's base is 1/2 piex^2 square units.

4)The height of the cylinder is 2x units.

5)The height of the cylinder is 4x units.

Answers

Answer:3 and 4

Step-by-step explanation:

Find the absolute extrema of the function over the region R. (In each case, R contains the boundaries.) Use a computer algebra system to confirm your results. (Order your answers from smallest to largest x, then from smallest to largest y.)
f(x, y) = x2 − 4xy + 5
R = {(x, y): 1 ≤ x ≤ 4, 0 ≤ y ≤ 2}

Answers

f(x, y) = x ² - 4xy + 5

has critical points where both partial derivatives vanish:

f/∂x = 2x - 4y = 0   ==>   x = 2y

f/∂y = -4x = 0   ==>   x = 0   ==>   y = 0

The origin does not lie in the region R, so we can ignore this point.

Now check the boundaries:

• x = 1   ==>   f (1, y) = 6 - 4y

Then

max{f (1, y) | 0 ≤ y ≤ 2} = 6 when y = 0

max{f (1, y) | 0 ≤ y ≤ 2} = -2 when y = 2

• x = 4   ==>   f (4, y) = 12 - 16y

Then

max{f (4, y) | 0 ≤ y ≤ 2} = 12 when y = 0

max{f (4, y) | 0 ≤ y ≤ 2} = -4 when y = 2

• y = 0   ==>   f (x, 0) = x ² + 5

Then

max{f (x, 0) | 1 ≤ x ≤ 4} = 21 when x = 4

min{f (x, 0) | 1 ≤ x ≤ 4} = 6 when x = 1

• y = 2   ==>   f (x, 2) = x ² - 8x + 5 = (x - 4)² - 11

Then

max{f (x, 2) | 1 ≤ x ≤ 4} = -2 when x = 1

min{f (x, 2) | 1 ≤ x ≤ 4} = -11 when x = 4

So to summarize, we found

max{f(x, y) | 1 ≤ x ≤ 4, 0 ≤ y ≤ 2} = 21 at (x, y) = (4, 0)

min{f(x, y) | 1 ≤ x ≤ 4, 0 ≤ y ≤ 2} = -11 at (x, y) = (4, 2)

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Yearly jackpot payments begin immediately (26 for Mega Millions and 30 for Powerball). Assume the lottery can invest at the given interest rate. Powerball: $360 million; 5.4% interest a. $188,347,953 b. $282,573,702 c. $185,870,742 d. $298,386,685 Question 3 of 10Select the action you would use to solve 3x = 12. Then select the propertythat justifies that actionSelect all that apply.A. Action: Add 3 to both sides.B. Action: Multiply both sides by 3.C. Action: Divide both sides by 3D. Property. Addition property of equalityE. Property: Multiplication property of equalityDF Property Division property of equality hlo guys please someone talk to me no one is talking with me worms move from computer to computer using wire true or false Arndt, Inc. reported the following for 2021 and 2022 ($ in millions): 2021 2022Revenues 888 980Expenses 760 800Pretax accounting income (income statement) 128 180 Taxable income (tax return) 116 200 Tax rate: 25% a. Expenses each year include $30 million from a two-year casualty insurance policy purchased in 2021 for $60 million. The cost is tax deductible in 2021. b. Expenses include $2 million insurance premiums each year for life insurance on key executives. c. Arndt sells one-year subscriptions to a weekly journal. Subscription sales collected and taxable in 2021 and 2022 were $33 million and $35 million, respectively. Subscriptions included in 2021 and 2022 financial reporting revenues were $25 million ($10 million collected in 2020 but not recognized as revenue until 2021) and $33 million, respectively. Hint. View this as two temporary differences-one reversing in 2021; one originating in 2021. d. 2021 expenses included a $14 million unrealized loss from reducing investments (classified as trading securities) to fair value. The investments were sold and the loss realized in 2022. e. During 2020, accounting income included an estimated loss of $6 million from having accrued a loss contingency. The loss was paid in 2021, at which time it is tax deductible. f. At January 1, 2021, Arndt had a deferred tax asset of $4 million and no deferred tax liability. Required: 1. Which of the five differences described in items a-e are temporary and which are permanent differences? 2. Prepare a schedule that reconciles the difference between pretax accounting income and taxable income. Using the schedule, prepare the necessary journal entry to record income taxes for 2022. 3. Prepare a schedule that reconciles the difference between pretax accounting income and taxable income. (Amounts to be deducted should be indicated with a minus sign.