Please help solve this

Answer:

Literally do a^2+b^2=x^2 and solve for x

Answer:

Yes. A linear pair forms a straight angle which contains 180º, so you have 2 angles whose measures add to 180, which means they are supplementary.

Answer:

4350 in^2

Step-by-step explanation:

hope this helps :)

Answer:

remember that you start in the [ ] and work your way out

Step-by-step explanation:

Answer:

a) I think its 2n+1

c) I think its 6n+3

d) I think its 7n-4

Answer:

I'm currently having the same lesson.

Exponential form:

5⁶ = 15,625

The number next to the "log" symbol is the base, which is positioned down. Next to the base of the exponent is the result of the exponent.

The number after the equal sign is the exponent.

Check the image for better clarification.

Step-by-step explanation:

Answer: [tex]5^{6} =15625[/tex]

Step-by-step explanation:  

Answer:27.1c

Step-by-step explanation:

18.6 + 8.5 =27.1

Answer:

27.1

Step-by-step explanation:

Answer:

x1 = t, x2 = -t and x3 = 0

Step-by-step explanation:

Given the system of equation

x1 + x2 + x3 = 0 .... 1

x1 + x2 + 9x3 = 0 .... 2

Subtract both equation

x3 - 9x3 = 0

-8x3 = 0

x3 = 0

Substitute x3 = 0 into equation 1

x1 + x2 + 0 = 0

x1+x2 = 0

x1 = -x2

Let t = x1

t = -x2

x2 = -t

Hence x1 = t, x2 = -t and x3 = 0

Question seems incomplete but will be explained with assumptions

Answer and explanation:

If for example, a car travels 30 km per hour, then it would travel 60km in 2 hours and 90km in 3 hours and so on

We can apply the formula for distance as such:

Distance(d)= Speed(s) × time(t)

d=st

Where d is distance travelled say 60km

S is speed= 30km/hr

Time = 2 hrs

Also to calculate speed when distance and time is given, we can make speed the subject of the formula:

s=d/t

To calculate time when distance and speed are given, we can make time the subject of the formula:

t=d/s

Answer:

22 * n + 4

Step-by-step explanation:

Answer:

[tex]\frac{7x}{x^2 - 10x + 21} / \frac{x + 7}{7}[/tex]

Step-by-step explanation:

Given

See attachment

To answer this question, we start by equating the denominators of each option to 0; then, solve for x

(a):

[tex]\frac{7x}{x^2 - 10x + 21} / \frac{x + 7}{7}[/tex]

This gives

[tex]\frac{7x}{x^2 - 10x + 21} * \frac{7}{x + 7}[/tex]

Set the denominator to 0

[tex](x^2 - 10x + 21)(x + 7) = 0[/tex]

Solve for x

[tex](x^2 - 7x - 3x + 21)(x + 7) = 0[/tex]

Factorize:

[tex](x(x - 7) - 3(x - 7))(x + 7) = 0[/tex]

[tex](x - 7)(x - 3)(x + 7) = 0[/tex]

This implies that:

[tex]x = 7\ or\ x = 3\ or\ x = -7[/tex]

From above, one of the values of x is 7.

This implies that x = 7 is an excluded value for this quotient.

Other options do not need to be checked, since there is only one answer.

Answer:

A

Step-by-step explanation:

Answer:

$625

Step-by-step explanation:

If Todd has to pay $14,000 in tuition for his school each year and uses $6,500 in financial aid each year all for 2 years, the money he needs to save can be modeled by:

2(-$14000 + $6500) + 2(12x) = 0.

x is the minimum amount of money he needs to save in order to cover this expense without debt.

Thus 2(-$14000 + $6500) + 2(12x) = 0 →

2(-$7500) + 24x = 0 → -$15000 + 24x = 0 →

24x = $15000 → x = $625

Answer:

$625

Step-by-step explanation:

If Todd has to pay $14,000 in tuition for his school each year and uses $6,500 in financial aid each year all for 2 years, the money he needs to save can be modeled by:

2(-$14000 + $6500) + 2(12x) = 0.

x is the minimum amount of money he needs to save in order to cover this expense without debt.

Thus 2(-$14000 + $6500) + 2(12x) = 0 →

2(-$7500) + 24x = 0 → -$15000 + 24x = 0 →

24x = $15000 → x = $625

Answer:

Step-by-step explanation:

4(y-3) = 4y - 4·3 = 4y - 12

The equivalent value of the expression is A = 4y - 12

Given data ,

Let the equation be represented as A

Now , the value of A is

A = 4 ( y - 3)

On simplifying the equation , we get

A = 4 ( y - 3 )

So , the left hand side of the equation is equated to the right hand side by the value of A = 4 ( y - 3 )

Opening the parenthesis on both sides , we get

A = 4 ( y - 3 )

Using the distributive property , we get

A = 4 ( y ) - 4 ( 3 )

On further simplification , we get

A = 4y - 12

Taking the common factor as 4 , we get

A = 4 ( y - 3 ) = 4y - 12

Therefore , the value of A = 4y - 12

Hence , the expression is A = 4y - 12

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Answer:

a)   [tex]S=50[/tex]

    [tex]P(X)=0.02[/tex]

b)  [tex]P(W,M,C)=8*10^-^6[/tex]

c)  [tex]P(W_2_3)=1.18*10^-^3[/tex]

Step-by-step explanation:

From the question we are told that

Sample space S=50

Sample size n=30

a)Generally the sample space S is

[tex]S=50[/tex]

The probability measure is given as

[tex]P(X)=\frac{1}{50}[/tex]

[tex]P(X)=0.02[/tex]

b)

Generally the probability that  the class hangs Wisconsin’s flag on Monday, Michigan’s flag on Tuesday, and California’s flag on Wednesday is mathematically given as

Probability of each one being hanged is

[tex]P(X)=\frac{1}{50}[/tex]

Therefore

[tex]P(W,M,C)=\frac{1}{50} *\frac{1}{50}* \frac{1}{50}[/tex]

[tex]P(W,M,C)=\frac{1}{125000}[/tex]

[tex]P(W,M,C)=8*10^-^6[/tex]

c)Generally the probability that Wisconsin’s flag will be hung at least two of the three days is mathematically given as

Probability of two days hung +Probability of three days hung

Therefore

[tex]P(W_2_3)=^3C_2 (1/50) * (1/50) * (49/50) +^3C_3 (1/50) * (1/50) *(1/50)[/tex]

[tex]P(W_2_3)=148 / 125000[/tex]

[tex]P(W_2_3)=1.18*10^-^3[/tex]

Answer:

y=15x+35

Step-by-step explanation:

15 every month and 35 for instant charge

Answer:

-5+7

=2

-5+-7

=-12

Step-by-step explanation:

It is the same thing with adding its opposite(aka change its sign so addition is being imply)

Answer:39

Step-by-step explanation:

If you add 28+11 you get 39 making 39-11=28

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

Answer:

37.50÷75=0.5 so first you are dividing bcus u need to find what percentage she has saved.

Answer:

O.5 because u need to divide and give me brainlessly plz

Step-by-step explanation:

Answer:

[tex]xy-4y+2x-8 = (y + 2)(x-4)[/tex]

Step-by-step explanation:

Given

[tex]xy-4y+2x-8[/tex]

Required

Factor the expression

[tex]xy-4y+2x-8[/tex]

Group the expression

[tex](xy-4y)+(2x-8)[/tex]

Factor each group

[tex]y(x-4)+2(x-4)[/tex]

This gives:

[tex](y + 2)(x-4)[/tex]

Hence:

[tex]xy-4y+2x-8 = (y + 2)(x-4)[/tex]

Answer:

Step-by-step explanation:

just add 36 and 3

Answer:

The 95% confidence interval for the mean installation time is between 40.775 minutes and 43.225 minutes. This means that for all instalations, in different computers, we are 95% sure that the mean time for installation will be in this interval.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96*\frac{5}{\sqrt{64}} = 1.225[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.225 = 40.775 minutes

The upper end of the interval is the sample mean added to M. So it is 42 + 1.225 = 43.225 minutes

The 95% confidence interval for the mean installation time is between 40.775 minutes and 43.225 minutes. This means that for all instalations, in different computers, we are 95% sure that the mean time for installation will be in this interval.

The 95% confidence interval for the mean installation time is (40.775, 43.225) and this can be determined by using the formula of margin of error.

Given :

The following steps can be used in order to determine the 95% confidence interval for the mean installation time:

Step 1 - The formula of margin of error can be used in order to determine the 95% confidence interval.

[tex]M = z \times \dfrac{\sigma}{\sqrt{n} }[/tex]

where z is the z-score, [tex]\sigma[/tex] is the standard deviation, and the sample size is n.

Step 2 - Now, substitute the values of z, [tex]\sigma[/tex], and n in the above formula.

[tex]M = 1.96 \times \dfrac{5}{\sqrt{64} }[/tex]

[tex]M = 1.225[/tex]

Step 3 - So, the 95% confidence interval is given by (M - [tex]\mu[/tex], M + [tex]\mu[/tex]) that is (40.775, 43.225).

The 95% confidence interval for the mean installation time is (40.775, 43.225).

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Answer:

3/24 + 4/24 = 7/24

Step-by-step explanation:

Find a common denominator then multiply the numerator by how many times you multiplied the denominator and add them to get your answer and you may simplify.

Answer:

C. x = 8 is a solution, but x = 6 is not

Step-by-step explanation:

12 + 6 = 18

12 + 8 = 20

20 - 12 = 8

Answer:

its 180

Step-by-step explanation:

Answer:

450

Step-by-step explanation:

15x30=450

Answer:

a) A  (-2,-2)  →A¹ (  2, 2)

   B (-5,-2)  →B¹ (5 , 2)

   C (-3,-4) →C¹ ( 3 ,4))

b)

A (-2,-2)  → A¹(  -2, 2)

B (-5,-2)  →B¹ (-5 , 2)

C (-3,-4) →C¹ ( -3 ,4))

c)

A (-2,-2)  → A¹(  -2, 2)

B (-5,-2)  →B¹ (-2 , 5)

C (-3,-4) →C¹ ( -4 ,3))

Step-by-step explanation:

a) Given the (-2,-2) is rotation 180° of counter clock wise then the transformed

to A (-2,-2)  → A¹(  2, 2)

   B (-5,-2)  →B¹ (5 , 2)

   C (-3,-4) →C¹ ( 3 ,4))

b)

Reflection about the x-axis

( x, y) → (  x, -y)

A (-2,-2)  → A¹(  -2, 2)

B (-5,-2)  →B¹ (-5 , 2)

C (-3,-4) →C¹ ( -3 ,4))

c)

( x, y) → (  y, -x)

Given (x, y) is rotation 90° of  clock wise about the origin then the transformed to

A (-2,-2)  → A¹(  -2, 2)

B (-5,-2)  →B¹ (-2 , 5)

C (-3,-4) →C¹ ( -4 ,3))