please help, thank you:))

Answer:

0.03

Explanation:

22.8 g Ba(OH)2 (1 mol Ba (OH)2/ 171.34 g) = 0.133 mol Ba (OH)2

77.2 g H2O (1 mol H2O/18 g) = 4.29 mol H2O

X= molar fraction= mol Ba(OH)2/ mol total

X= 0.133/ (0.133+4.29) = 0.03

0.03 is the mole fraction of [tex]Ba(OH)_2[/tex] in an aqueous solution that contains 22.8% [tex]Ba(OH)_2[/tex] by mass.

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Moles of [tex]Ba(OH)_2[/tex]

Moles = [tex]\frac{mass}{molar \;mass}[/tex]

Moles = [tex]\frac{22.8 g Ba(OH)_2}{171.34 g}[/tex]

= 0.133 mol [tex]Ba (OH)_2[/tex]

Moles of [tex]H_2O[/tex]

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{77.2 g H_2O}{18 g}[/tex]

= 4.29 mol [tex]H_2O[/tex]

The mole fraction of [tex]Ba(OH)_2[/tex]

[tex]\frac{mol Ba(OH)_2}{total \;mol}[/tex]

= 0.03

0.03 is the mole fraction of [tex]Ba(OH)_2[/tex] in an aqueous solution that contains 22.8% [tex]Ba(OH)_2[/tex] by mass.

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sound energy, kinetic energy,

i cant think of any more but hope this helps

Answer:

Mechanical to kinetic to sound to heat

Explanation:

Remember that all types of energy transformation end in heat

Answer:

unbalanced

Explanation:

Cl and H have an extra atom

- Hope that helps! Please let me know if you need further explanation.

Answer:

In chemistry, neutralization or neutralisation is a chemical reaction in which acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in the solution.

Explanation:

Answer:

jeez thats some calculus stuff right there im pretty sure its b

Explanation:

Answer:

answer: A. all of the living organisms in a specific place at a specific time

Explanation:

A landslide can be defined as a mass movement of material (e.g., rocks), which moves down a steep slope. A geologist is an expert that studies SLOW-MOVING landslides on a geological scale.

Landslides can occur suddenly or more slowly over long periods of time.

On a geological scale, landslides occur slowly so they are imperceptible to humans.

A geologist is a professional who investigates landslides on a geological scale, which is coarse on a human time-frame.

In conclusion, a geologist is a professional who investigates SLOW-MOVING landslides on a geological scale.

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Answer:

Gas is more open particles

Explanation: gas can flow

Answer:

55×10^-26 J

Explanation:

We can calculate the energy of the wave from

E= hc/λ

Where

h= Planks constant = 6.6×10^-34 Is

c= speed of light = 3×10^8 ms-1

λ= wavelength of the wave = 0.36 metres

Recall that cell phone use radio waves which belong to the electromagnetic spectrum hence it must possess the speed of light.

E= 6.6×10^-34 × 3×10^8/ 0.36

E= 55×10^-26 J

Hence the energy possessed by 0.36 meters wavelength radio waves is 55×10^-26 J

Answer:

A. compound (NaCl)

B. element (note: it should be Ar. AR is not an element or compound.)

c. compound (CH4)

d. element (O2)

e. element (Cl)

Explanation:

Element is single and by its self. A compound is multiple elements put together.

Answer: 16700 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed = ?

m = mass of sand = 2 kg

c = heat capacity = [tex]835J/kg^0C[/tex]

Initial temperature  = [tex]T_i[/tex] = [tex]40^0C[/tex]

Final temperature= [tex]T_f[/tex]  = [tex]50^0C[/tex]

Change in temperature ,[tex]\Delta T=T_f-T_i=(50-40)^0C=10^0C[/tex]

Putting in the values, we get:

[tex]Q=2kg\times 835J/kg^0C\times 10^0C[/tex]

[tex]Q=16700J[/tex]

16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C

Answer:

b

Explanation:

Answer:

True!

Explanation:

Fossil fuels are carbon based compounds present deep in the earth left millions of years ago.

hope it helps!

Answer:

A continuous spectrum is a record formed by collecting light of all frequencies traveling through space together. ... A line spectrum is a record formed by collecting light emitted from excited atoms whose electrons are falling back down to lower energy states.

Explanation:

Answer:

Cirrus

Cirrus cloudsCirrus clouds are delicate, feathery clouds that are made mostly of ice crystals. Their wispy shape comes from wind currents which twist and spread the ice crystals into strands.

Cirrostratus

Cirrostratus cloudsCirrostratus clouds are thin, white clouds that cover the whole sky like a veil. These clouds are most commonly seen in the winter, and can cause the appearance of a halo around the sun or the moon.

Cirrocumulus

Cirrocumulus cloudsCirrocumulus clouds are thin, sometimes patchy, sheet-like clouds. They sometimes look like they’re full of ripples or are made of small grains.

Mid-level Clouds (6,500-23,000 feet)

Altocumulus

Altocumulus cloudsAltocumulus clouds have several patchy white or gray layers, and seem to be made up of many small rows of fluffy ripples. They are lower than cirrus clouds, but still quite high. They are made of liquid water, but they don’t often produce rain.

Altostratus

Altostratus cloudsAltostratus clouds are gray or blue-gray mid-level clouds composed of ice crystals and water droplets. The clouds usually cover the entire sky.

Nimbostratus

Nimbostratus cloudsNimbostratus clouds are dark, gray clouds that seem to fade into falling rain or snow. They are so thick that they often blot out the sunlight.

Low Clouds (less than 6,500 feet)

Cumulus

Cumulus cloudsCumulus clouds look like fluffy, white cotton balls in the sky. They are beautiful in sunsets, and their varying sizes and shapes can make them fun to observe!

Stratus

Stratus cloudsStratus cloud often look like thin, white sheets covering the whole sky. Since they are so thin, they seldom produce much rain or snow. Sometimes, in the mountains or hills, these clouds appear to be fog.

Cumulonimbus

Cumulonimbus cloudCumulonimbus clouds grow on hot days when warm, wet air rises very high into the sky. From far away, they look like huge mountains or towers.

Stratocumulus

Stratocumulus cloudStratocumulus clouds are patchy gray or white clouds that often have a dark honeycomb-like appearance.

Special Clouds

Contrails

(Photo of white streaks of contrails in the sky) Contrails are made by high-flying jet airplanes. They are still clouds, though, because they are made of water droplets condensed from the water vapor in the exhaust of the jet engines.

Weather prediction: Contrails can provide information about the layers of moisture in the sky.

Mammatus clouds

Mammatus cloudsMammatus clouds are actually altocumulus, cirrus, cumulonimbus, or other types of clouds that have these pouch-like shapes hanging out of the bottom. The pouches are created when cold air within the cloud sinks down toward the Earth.

Orographic clouds

Orographic cloudsOrographic clouds get their shape from mountains or hills that force the air to move over or around them. They can also be formed by sea breezes and often appear as lines where two air masses meet.

Lenticular clouds

Lenticular clouds are shaped like lenses or almonds or...flying saucers! They may get their shape from hilly terrain or just the way the air is rising over flat terrain.

(Hope this helps) Sky

Answer:

Q= 29.2 J

Explanation:

22°C=295K

37°C=310K

Q= mC dT

Q= (15.0 g) *(0.130 J/g-K)* (310 K-295K)

Q= 29.2 J

29.2 J is required to raise the temperature of 15.0 g of lead from 22.0 °C to 37.0 °C.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given data:

22°C=295K

37°C=310K

Applying specific heat capacity formula:

Q= mC dT

Putting all the values in the formula:

Q= (15.0 g)  X (0.130 J/g-K) X (310 K-295K)

Q= 29.2 J

Hence, 29.2 J is required to raise the temperature of 15.0 g of lead from 22.0 °C to 37.0 °C.

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Answer:

Gamma Rays.

Explanation:

Gamma-ray photons have the highest energy in the EMR spectrum and their waves have the shortest wavelength.

Answer:

1) Sound waves are stores as electrical signal in the digital recording.

2) the electrical signal of the digital recording is transcribed and sent to the voice coils.

3) the voice coil changes this electrical signal into varying magnetic fields.

4) The magnetic field pushes and pulls the diaphragm of the speakers.

5) the pushing and pulling of the diaphragm generates sound waves in the speaker.

Answer:

hydrogen

Explanation:

Answer:

V = 513.36m/s

Explanation:

Temperature (T) = 25°C = (25 + 273.15) = 298.15K

Speed (V) = 1.92*10³m/s

According to kinetic theory of gases, the speed (v) of a molecule is

V= √(3RT / M)

V = speed or velocity

R = ideal gas constant = 0.082J/mol.K

T = temperature of the gas

M = molar mass

Molar mass of hydrogen molecule = 2.0g/mol

Molar mass of Nitrogen molecule = (2×14.0) = 28.0g/mol

Since they're in the same temperature

V1 / V2 = √(M2 / M1)

1.92×10³ / V2 = √(28 / 2)

1.92×10³ / V2 = √(14)

1.92*10³ / V2 = 3.74

1.92*10³ = 3.74V2

V2 = 1920 / 3.74

V2 = 513.36m/s

The velocity of Nitrogen molecule is 513.36m/s

Answer:

Explanation:

mostly empty space

Answer:

Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefore only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.

Explanation:

Answer: C

# The main reason why the reaction above can not be balanced is:

   This chemical reaction SO2 + H2O -> H2SO2 is not correctly written.

    It must be: SO2 + H2O -> H2SO3

Explanation:

Note 1:

H2SO2 can be produced by the other chemical reaction:

2H2O + SCl2 -> 2HCl + H2SO2

....

Note 2: Answer A is false

As you can see in the reaction  SO2 + H2O -> H2SO3, the oxygen atoms are in two molecules on one side, but one in the other - However, this reaction is written correctly.

Note 3: Answer D is false

Of course the Sulfur atom must be placed in different places: in reactant and product molecules.

Note 4: Answer B is false

There are different kinds of chemical reactions, and this is normal that there are more molecules on one side than on the other.

The answer is C

The correct way to balance the reaction, would be to write it as SO2 + H2O →  H2SO3

Answer A is incorrect.

The oxygen atoms in the reaction SO2 + H2O -> H2SO3 are in two compounds on one end but on the other, it is in just one.

Answer D is wrong.

The sulfur atom has to be in the reactants and the products.

Answer B is not correct.

There are many types of chemical reactions . One side commonly has more atoms than the other.

Proper lane placement can include positioning your car 36 inches from the right or left line. Therefore, option B is correct.

Using different lane positions to make adjustments for potential problems and create larger space between car and problem situations. Lane position is the placement of car in the center, on the right, or on the left of a lane.  The width of a lane is twelve feet on most highways or streets.

There are three main positions are lane position 1 is center of lane, lane position 2 is left side, and lane position 3 is right side. Position 2 is left side of lane is for car.

Position 3 is a vehicle placement to the right when a restriction to path of travel or your line of sight occurs. Proper lane placement can include positioning your car 36 inches from the right or left line.

Thus, option B is correct.

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Answer:

the number of orange candies divided by total number of candies

the mass of orange candies divided by total mass of candies

Explanation:

The two correct options that are appropriate to describe the concentration of orange candies would be the number of orange candies divided by total number of candies and the mass of orange candies divided by total mass of candies.

The concentration of a substance can be described as the fraction of that substance in a particular mix of substances.

In term of number, the concentration of a substance in a mix of substances can be expressed as the number of that substance divided by the total number of substances in the mix.

In term of mass, the concentration of a substance in a mix of substances can be expressed as the mass of that substance divided by the total mass of the mix.

Answer:

A, B, E

Explanation:

edge

Answer:

A. 82.2g of KClO3

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3

C. Formula equation:

2KCl + 3O2 —> 2KClO3

Explanation:

The balanced equation for the reaction. This is given below:

2KCl + 3O2 —> 2KClO3

Next, we shall determine the masses of KCl and O2 that reacted and the mass of KClO3 produced from the balanced equation. This is illustrated below:

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Summary:

From the balanced equation above:

149g of KCl reacted.

96g of O2 reacted.

245g of KCl were produced.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

149g of KCl reacted with 96g of O2.

Therefore, 50g of KCl will react with = (50 x 96)/149 = 32.21g of O2.

Since a lesser mass of O2 ( i.e 32.21g) than what was given (i.e 50g) is needed to react completely with 50g of KCl, therefore, KCl is the limiting reactant and O2 is the excess reactant.

A. Determination of the mass of KClO3 produced from the reaction.

In this case the limiting reactant will be used.

From the balanced equation above,

149g of KCl reacted To produce 245g of KClO3.

Therefore, 50g of KCl will react to produce = (50 x 245)/149 = 82.2g of KClO3.

Therefore, 82.2g of KClO3 is produced from the reaction.

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3.

C. Formula equation:

2KCl + 3O2 —> 2KClO3

The mass of [tex]\rm KClO_3[/tex] produced has been 82.1085 g.

The word equation for the reaction has been: 50 gram potassium chloride reacts with 50 g oxygen to give 82.1085 g potassium chlorate.

The formula equation has been, [tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex].

The balanced chemical equation for the reaction has been given as:

[tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex]

From the balanced chemical equation, 2 moles of KCl reacts with 3 moles of oxygen to give 2 moles of [tex]\rm KClO_3[/tex].

The moles of reactants have been given as:

[tex]\rm Moles=\dfrac{mass}{molar\;mass}[/tex]

The moles of 50 g KCl has been given as:

[tex]\rm Moles\;KCl=\dfrac{50}{74.55} \\Moles\;KCl=0.67\;mol[/tex]

The moles of KCl available has been 0.67 mol.

The moles of 50 g [tex]\rm O_2[/tex] has been given as:

[tex]\rm Moles\;O_2=\dfrac{50}{32}\\Moles\;O_2=1.5625\;mol[/tex]

The moles of 50 g [tex]\rm O_2[/tex] has been 1.5625 mol.

From the balanced equation, for 2 moles KCl, 3 moles oxygen has been required. For 0.67 mol KCl, oxygen required has been:

[tex]\rm 2\;mole\;KCl=3\;moles\;O_2\\0.67\;mol\;KCl=\dfrac{3}{2}\;\times\;0.67\;mol\;O_2\\0.67\;mol\;KCl=1.005\;mol\;O_2[/tex]

The available moles of oxygen has been 1.5625 mol. Thus, oxygen has been excess reactant and KCl has been limiting reactant.

The moles of [tex]\rm KClO_3[/tex] produced has been given as:

[tex]\rm 2\;mol\;KCl=2\;mol\;KClO_3\\0.67\;mol\;KCl=\dfrac{2}{2}\;\times\;0.67\;mol\;KClO_3\\0.67\;mol\;KCl=0.67\;mol\;KClO_3[/tex]

The moles of [tex]\rm KClO_3[/tex] produced has been 0.67 mol.

The mass of [tex]\rm KClO_3[/tex] produced has been:

[tex]\rm Mass=Moles\;\times\;molar\;mass\\Mass\;KCl=0.67\;\times\;122.55\;\\Mass\;of\;KCl=82.1085\;g[/tex]

The mass of [tex]\rm KClO_3[/tex] produced has been 82.1085 g.

The word equation for the reaction has been:

50 gram potassium chloride reacts with 50 g oxygen to give 82.1085 g potassium chlorate.

The formula equation has been, [tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex].

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