Please help this is due at 11:59 and im really stuck.

Answers

Answer 1
has form - last two
can be put in form - none
other - first four
Answer 2

9514 1404 393

Answer:

  B B C C A A

Step-by-step explanation:

If we number the equations 1 to 6 left to right, then we have ...

B - can be put (y = 2x)B - can be put (y = (1/9)x)C - other, not a proportional relationshipC - other, y = 5/x, an inversely proportional relationshipA - has the form, k = 0.04A - has the form, k = -11

Related Questions

What is the following product?
(V12+ V6 (16-V10
6-12-2130+6-2V15
-2 དུ་
6V3-615
31/7- V22+2/3-4
2V3+6-2V15

Answers

Answer:

The answer is A: 6√2 - 2√30 + 6 - 2√15

Believe me it right.

What two things have to be true in order to use the Zero Product Property?

A: Both sides of the equations must be zero.

B: One side of the equation must be a factored polynomial, and the other side must be -1.

C: One side of the equation must be a factored polynomial, and the other side must be 1.

D: One side of the equation must be a factored polynomial, and the other side must be zero.

Wrong answers will be reported. Thanks!

Answers

Answer:

D - One side is a factored polynomial and the other side is 0.

A - Incorrect; If each side is 0, the equation would be equal since 0 = 0.

B - Incorrect; It cannot be -1 because the property states Zero product which means 0 should be the product.

C - Incorrect; It cannot be 1 because the property states Zero product which means 0 should be the product.

D - Correct; One side is 0, and the other is a factored polynomial, which correctly displays the correct definition of Zero Product Property.

Which of the SMART criteria are NOT met by this data analytics project goal (pay close attention to whether the options are words the SMART acronym stands for)?

Answers

Answer:

Specific

Step-by-step explanation:

The data analytics is defined as the study of analyzing the raw data and information so as to make a proper conclusion about the information. It is a process of inspecting, transforming, and  modelling the data with the intention of finding useful information and conclusions.

The acronym for S.M.A..R.T is Specific, Measurable, Attainable, Relevant and Time bounding.

The SMAR criteria which do not meet the data analytics project goal in the question is "Specific".

A jewelry box is in the shape of a rectangular prism with an area of 528 cubic inches. The length of the box is 12 inches and the height is 5 1/2 inches. What is the width of the jewelry box? A=LxWxH

please help. :)​

Answers

the height is 8 i believe

how to construct angle 30°​

Answers

Answer:

Angle ABC = 30°

Step-by-step explanation:

Construct a ray AB, horizontally.Take a compass, keep the pointy edge on the origin of the ray and make an arc passing through AB.Mark the point where the arc cuts AB as XPlace the pointy edge of the compass on X, draw another arc through the existing arc.Mark the point where on arc cuts the other arc as Y.Now from the origin of AB through the point Y draw a straight line.The angle thus formed is 60°.Now make arcs keeping the compass on X and Y.Mark the point where these two arcs meet as Z.Now from the origin of AB through the point Z draw a straight line.The angle formed in this process is a 30°.

pls help me in this question it is really needed

Answers

Answer:

6 1/8 ×10 2/7= 60

60÷2 1/3= 30

The answer:

30

Which value of a in the exponential function below would cause the function to stretch?
f(x) = (1)
O 0.3
O 0.9
O 1.0
O 1.5

Answers

Answer:

1.5

Step-by-step explanation:

Took the test already.

The value of a for which the exponential function below would cause the function to stretch is a > 1 Or 1.5.

What are some rules for function transformations?

Suppose we have a function f(x).

f(x) ± d = Vertical upshift/downshift by d units (x, y ±d).

f(x ± c) = Horizontal left/right shift by c units (x - + c, y).

(a)f(x) = Vertical stretch for a > 0, vertical shrink a < 0. (x, ay).

f(bx) = Horizonatal compression b > 0, horizontal stretch for b < 0. (bx , y).

f(-x) = Reflection over y axis, (-x, y).

-f(x) = Reflection over x-axis, (x, -y).

We know an exponential function f(x) = [tex]e^x[/tex].

Now if we multiply f(x) by some number 'a' which is greater than 1 let it be g(x) = [tex]ae^x[/tex] the function would stretch horizontally for a > 1.

learn more about function transformations here :

https://brainly.com/question/13810353

#SPJ6

Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?

y – 12 = –5(x + 2)
y – 12 = 2(x + 2)
y + 12 = 2(x – 2)
y + 12 = –5(x – 2)

Answers

Answer:

the answer is A y  −  12  =  − 5 ( x + 2 )

Step-by-step explanation:

y − 12 = ( − 5 x + 2 ) ⋅ ( x + 2 )

to get this answer you can plug it into point slope equation:

y-y1=m(x+x1)

plug in the given information:

-y and x will stay the same

-y1 will be 12 and x1 will be -2 (remember the given point -2,12)

-m will be the slope given from the y intercept equation

I hope this helps~

Answer:

a

Step-by-step explanation:

Let (-5, 2) be a point on the terminal side of 0.
Find the exact values of coso , csco, and tano.

Answers

Answer:

Following are the response to this questions:

Step-by-step explanation:

Please find the graph file in the attachment.

Given:

P=2

B=-5

H=?

[tex]H=\sqrt{P^2+B^2}[/tex]

    [tex]=\sqrt{2^2+(-5)^2}\\\\=\sqrt{4+25}\\\\=\sqrt{29}\\\\[/tex]

Using formula:

[tex]\to \ cosec \theta \ or\ \ csco \theta =\frac{H}{P}\\\\\to \cos \theta=\frac{B}{H}\\\\\to \tan \theta=\frac{p}{B}\\\\[/tex]

So,

[tex]\to \ cosec \theta \ or\ \ csco \theta =\frac{\sqrt{29}}{2}\\\\\to \cos \theta=\frac{-5}{\sqrt{29}} =\frac{-5}{\sqrt{29}}\times \frac{\sqrt{29}}{\sqrt{29}}=-\frac{5\sqrt{29}}{29}\\\\\to \tan \theta=\frac{2}{-5}= -\frac{2}{5}\\\\[/tex]

Giving BrainleYst. Which Inequality is graphed on the coordinate plane?
O A. y<-2x-1
OB. y>-2x-1
OC. ys-2x-1
OD. y2-2x - 1

Answers

Answer:

A. y<-2x-1

Step-by-step explanation:

not C or D because it is a dashed line meaning the linear equation will either have the symbol ≥ or ≤.

when y is less than, you shade below

thus, the answer is A

A punch contains cranberry juice and ginger ale in the ratio 5:3. If you require 32 L
of punch for a party, how many litres of cranberry juice and how many litres of ginger
ale are required?

Answers

you must add
6
litres of cranberry juice
Explanation:
"A fruit punch recipe calls for 3 parts of apple juice to 4 parts of cranberry juice"
Meaning: For every 3 litres of apple juice, you must add 4 litres of cranberry juice. That means if you add 6 litres of apple juice, then you must add 8 litres of cranberry juice
Now, if you add 4.5 litres of apple juice, you can think of it this way
3
apple juice
:
4
cranberry juice

4.5
apple juice
:
x
cranberry juice
x
=
4.5
×
4
3

x
=
18
3

x
=
6
Therefore, you must add
6
litres of cranberry juice
Answer link

Shwetank Mauria
Jul 25, 2018
6
liter of cranberry juice.
Explanation:
As
3
parts of apple juice are added to
4
parts of cranberry juice
and
4.5
liter of apple juice means each of three parts are
4.5
3
=
1.5
liter
and one needs
4
parts of cranberry juice i.e.
4
×
1.5
liter or
6
liter of cranberry juice.

A certain cosine function has an amplitude of 7. Which function rule could model this situation?

Answers

Answer:

y = 7cos bx

Step-by-step explanation:

For a cosine function without pahse shift and vertical shift, but with amplitude given, it will also have period and thus , the formula for the cosine function is;

y = Acos bx

Where;

A is the amplitude

Period = 2π/b

Now, we are told that the amplitude is 7. Thus;

y = 7cos bx

21-B Book Street Books sells about 700700 books each month. The pie chart displays the most popular book categories, by percentage, each month. Find the number of romance books sold each month. Round your answer to the nearest integer.

Answers

Solution :

Given data :

Total number of books sold each month= 700

The charts in the display attached below shows the most popular books category by percentages.

Percentage of romance books sold each = 8.5%

Therefore, the number of romance books sold in each month is given by :

[tex]$=8.5 \% \text{ of }\ 700$[/tex]

[tex]$=\frac{8.5}{100}\times 700$[/tex]

= 59.5

≈ 60 books (rounding off)

You can use the fact that total amount is taken as 100%.

The number of romance books in the given Streets Books is 60

How to find the percentage from the total value?

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is [tex]\dfrac{a}{100} \times b[/tex]

How to find the number of Romance books if its given that it is 8.5% of the total books present in that book collection?

Since the total amount of books is 700, and its 8.5% books are romance books, thus we have:

[tex]\text{Number of Romance books} = \dfrac{700}{100} \times 8.5 = 59.5 \approx 60[/tex]

The number of romance books in the given Streets Books is 60

Learn more about percentage here:

https://brainly.com/question/11549320

Provided below are summary statistics for independent simple random samples from two populations. Use the pooled​ t-test and the pooled​ t-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval.
x1=21, s1=4, n1=12, x2=20, s2=3, n2=15
A. What are the correct hypotheses for a​ right-tailed test?
b. Compute the test statistic.
c. Determine the​ P-value.
B. The 90​% confidence interval is from ____to ____.

Answers

Answer:

(a) [tex]H_o:\mu_1 = \mu_2[/tex]     [tex]H_a:\mu_1 > \mu_2[/tex]

(b) [tex]t = 0.74[/tex]

(c) [tex]p =0.2331[/tex]

(d) [tex]CI = (-2.095,4.095)[/tex]

Step-by-step explanation:

Given

[tex]\bar x_1=21,\ s_1=4,\ n_1=12,\\ \bar x_2=20,\ s_2=3,\ n_2=15[/tex]

Solving (a): The hypotheses

The test is right-tailed, means that the alternate hypothesis will contain greater than sign.

So, we have:

[tex]H_o:\mu_1 = \mu_2[/tex]

[tex]H_a:\mu_1 > \mu_2[/tex]

Solving (b); The test statistic (t)

This is calculated as:

[tex]t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{n_1 + n_2 - 2} * (\frac{1}{n_1} + \frac{1}{n_2})}}[/tex]

So, we have:

[tex]t = \frac{21 - 20}{\sqrt{\frac{4^2(12 - 1) + 3^2(15 - 1)}{12 + 15 - 2} * (\frac{1}{12} + \frac{1}{15})}}[/tex]

[tex]t = \frac{1}{\sqrt{\frac{302}{25} * (0.15)}}[/tex]

[tex]t = \frac{1}{\sqrt{12.08 * 0.15}}[/tex]

[tex]t = \frac{1}{\sqrt{1.812}}[/tex]

[tex]t = \frac{1}{1.346}[/tex]

[tex]t = 0.74[/tex]

Solving (c): The P-value

First, we calculate the degrees of freedom

[tex]df = n_1 + n_2 -2[/tex]

[tex]df = 12+15 -2[/tex]

[tex]df = 25[/tex]

Using the t distribution, the p-value is:

[tex]p =TDIST(0.74,25)[/tex]

[tex]p =0.2331[/tex]

Solving (d): The 90% confidence interval

Calculate significance level

[tex]\alpha = 1 - CI[/tex]

[tex]\alpha = 1 - 90\%[/tex]

[tex]\alpha = 0.10[/tex]

Calculate the t value (t*)

[tex]t^* = (\alpha/2,df)[/tex]

[tex]t^* = (0.10/2,25)[/tex]

[tex]t^* = (0.05,25)[/tex]

[tex]t^* = 1.708[/tex]

The confidence interval is calculated using:

[tex]CI = (\bar x - \bar x_2) \± t^* *\sqrt{\frac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{n_1 + n_2 - 2} * (\frac{1}{n_1} + \frac{1}{n_2})}[/tex]

[tex]CI = (21 - 20) \± 1.708 *\sqrt{\frac{4^2(12 - 1) + 3^2(15 - 1)}{12 + 15 - 2} * (\frac{1}{12} + \frac{1}{15})}[/tex]

[tex]CI = 1 \± 1.708 *1.812[/tex]

[tex]CI = 1 \± 3.095[/tex]

Split

[tex]CI = 1 - 3.095 \ or\ 1 + 3.095[/tex]

[tex]CI = -2.095 \ or\ 4.095[/tex]

[tex]CI = (-2.095,4.095)[/tex]

4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto repair shop take per year. A previous study indicated thatthe standard deviation was2.2 days. a) How large a sample must be selected if thecompany wants to be 92% confident that the true mean differs from the sample mean by nomore than 1 day

Answers

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.92}{2} = 0.04[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.04 = 0.96[/tex], so Z = 1.88.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that [tex]\sigma = 2.2[/tex]

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = 1.88\frac{2.2}{\sqrt{n}}[/tex]

[tex]\sqrt{n} = 1.88*2.2[/tex]

[tex](\sqrt{n})^2 = (1.88*2.2)^2[/tex]

[tex]n = 17.1[/tex]

Rounding up:

A sample of 18 is required.

Find the sample size necessary to estimate the mean arrival delay time for all American Airlines flights from Dallas to Sacramento to within 6 minutes with 95% confidence. Based on a previous study, arrival delay times have a standard deviation of 39.6 minutes.

Answers

Answer:

The sample size necessary is of 168.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Based on a previous study, arrival delay times have a standard deviation of 39.6 minutes.

This means that [tex]\sigma = 39.6[/tex]

Find the sample size necessary to estimate the mean arrival delay time for all American Airlines flights from Dallas to Sacramento to within 6 minutes with 95% confidence.

This is n for which M = 6. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]6 = 1.96\frac{39.6}{\sqrt{n}}[/tex]

[tex]6\sqrt{n} = 1.96*39.6[/tex]

[tex]\sqrt{n} = \frac{1.96*39.6}{6}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*39.6}{6})^2[/tex]

[tex]n = 167.34[/tex]

Rounding up:

The sample size necessary is of 168.

Area: Change in Dimensions
A rectangle FGHJ has a width of 3 inches and a length of 7 inches

Answers

Answer:

A) 21 in²

B) 42 in²

C) 84 in²

D) I) 4 in²

II) 8 in²

III) 16 in²

E) From our calculations, we can see that doubling one part of the dimensions gives an area that is twice the original one while doubling both dimensions gives an area that four times the original one.

Step-by-step explanation:

We are given dimensions of triangle as;

width; w = 3 inches

length; L = 7 inches

A) Area of triangle is;

A = Lw

A = 7 × 3

A = 21 in²

B) If we double the width, then area is;

A = 7 × (2 × 3)

A = 42 in²

Area is twice the original area

C) If we double the width and length, then we have;

Length = 7 × 2 = 14 in

Width = 3 × 2 = 6 in

Area = 14 × 6 = 84 in²

Area is four times the original one

D) Let's try a triangle with base 2 in and height 4 in.

I) formula for area of triangle is;

A = ½ × base × height

A = ½ × 2 × 4

A = 4 in²

II) If we double the width(base) , then area is;

A = ½ × 2 × 2 × 4

A = 8 in²

This is twice the original area.

III) If we double the width(base) and length(height), then we have;

A = ½ × 2 × 2 × 4 × 2

A = 16 in²

This is four times the original area

E) From our calculations, we can see that doubling one part of the dimensions gives an area that is twice the original one while doubling both dimensions gives an area that four times the original one.

Which of the following have both 2 and -5 as solutions?

X2+3x-10-0

X2-3x-10=0

X2+7x+10=0

X2-7x+10=0

Answers

Answer:

X^2 + 3x - 10=0

If three times a number added to 8 is divided by the number plus 7, the result is four thirds. Find the number.​

Answers

9514 1404 393

Answer:

  4/5

Step-by-step explanation:

The wording is ambiguous, as it often is when math expressions are described in English. We assume you intend ...

  [tex]\dfrac{3n+8}{n+7}=\dfrac{4}{3}\\\\3(3n+8)=4(n+7)\qquad\text{multiply by $3(n+7)$}\\\\9n+24=4n+28\qquad\text{eliminate parentheses}\\\\5n=4\qquad\text{subtract $4n+24$}\\\\\boxed{n=\dfrac{4}{5}}\qquad\text{divide by 5}[/tex]

The number is 4/5.

4. Consider the function g(x) = 2x^2 - 4x+3 on the interval [-1, 2]
A.) Does Rolle's Theorem apply to g(x) on the given interval? If so, find all numbers, s,
guaranteed to exist by Rolle's Theorem. If not, explain why not. (2 pts.)
b.) Does the Mean Value Theorem apply to g(x) on the given interval? If so, find all
numbers, a guaranteed to exist by the Mean Value Theorem. If not, explain why not.
(4 pts.)

Answers

Hi there!

A.) Begin by verifying that both endpoints have the same y-value:

g(-1) = 2(-1)² - 4(-1) + 3

Simplify:

g(-1) = 2 + 4 + 3 = 9

g(2) = 2(2)² - 4(2) + 3 = 8 - 8 + 3 = 3

Since the endpoints are not the same, Rolle's theorem does NOT apply.

B.)

Begin by ensuring that the function is continuous.

The function is a polynomial, so it satisfies the conditions of the function being BOTH continuous and differentiable on the given interval (All x-values do as well in this instance). We can proceed to find the values that satisfy the MVT:

[tex]f'(c) = \frac{f(a)-f(b)}{a-b}[/tex]

Begin by finding the average rate of change over the interval:

[tex]\frac{g(2) - g(-1)}{2-(-1)} = \frac{3 - 9 }{2-(-1)} = \frac{-6}{3} = -2[/tex]

Now, Find the derivative of the function:

g(x) = 2x² - 4x + 3

Apply power rule:

g'(x) = 4x - 4

Find the x value in which the derivative equals the AROC:

4x - 4 = -2

Add 4 to both sides:

4x = 2

Divide both sides by 4:

x = 1/2

A business rents in-line skates and bicycles to tourists on vacation. A pair of skates rents for $5 per day. A bicycle rents for $20 per day.
On a certain day, the owner of the business has 25 rentals and takes in $425.
Write a system of equation to represent this situation, then solve to find the number of each item rented.
Show both the equations and the solution.

Answers

Answer:

5x+20y=425

Step-by-step explanation:

Its 5 bucks for x pairs of skates

Its 20 dollars for y bikes

x+y rentals have to equal 25

all of this is equal to 425. All that is left to do is test with number until the statement is true.

try :

5(5)+(20)(20)=425

x + y do equal 25, and the total is equal to 425.

What is the simplified expression for the
expression below? 4(x+8)+5(x-3)

Answers

4(x+8)+5(x-3)
= 4x+32+5(x-3)
=4x+32+5x-15
=9x+17

Answer: 9x+17

A soft drink manufacturer wishes to know how many soft drinks adults drink each week. They want to construct a 95% confidence interval with an error of no more than 0.08. A consultant has informed them that a previous study found the mean to be 3.1 soft drinks per week and found the variance to be 0.49. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.

Answers

Answer:

The minimum sample size required to create the specified confidence interval is 295.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Variance of 0.49:

This means that [tex]\sigma = \sqrt{0.49} = 0.7[/tex]

They want to construct a 95% confidence interval with an error of no more than 0.08. What is the minimum sample size required to create the specified confidence interval?

The minimum sample size is n for which M = 0.08. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.08 = 1.96\frac{0.7}{\sqrt{n}}[/tex]

[tex]0.08\sqrt{n} = 1.96*0.7[/tex]

[tex]\sqrt{n} = \frac{1.96*0.7}{0.08}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*0.7}{0.08})^2[/tex]

[tex]n = 294.1[/tex]

Rounding up:

The minimum sample size required to create the specified confidence interval is 295.

The regression analysis can be summarized as follows: Multiple Choice No significant relationship exists between the variables. A significant negative relationship exists between the variables. For every unit increase in x, y decreases by 12.8094. A significant positive relationship exists between the variables

Answers

Answer:

A significant negative relationship exists between the variables

Step-by-step explanation:

Base on the information given in the question which goes thus : For every unit increase in x, y decreases by 12.8094. The value 12.8094 is the slope which is the rate of change in y variable per unit change in the independent variable. The sign or nature of the slope Coefficient gives an hint about the relationship between the x and y variables. The slope Coefficient in this case is negative and thus we'll have a negative relationship between the x and y variables (an increase in x leads to a corresponding decrease in y). This is a negative association.

Let f(x) = 5 + 12x − x^3. Find (a) the x- coordinate of all inflection points, (b)
the open intervals on which f is concave up, (c) the open intervals on which
f is concave down.

Answers

Answer:

A) x = 0.

B) f is concave up for (-∞, 0).

C) f is concave down for (0, ∞).

Step-by-step explanation:

We are given the function:

[tex]f(x)=5+12x-x^3[/tex]

A)

We want to find the x-coordinates of all inflection points.

Recall that inflections points (may) occur when the second derivative equals zero. Hence, find the second derivative. The first derivative is given by:

[tex]f'(x) = 12-3x^2[/tex]

And the second:

[tex]f''(x) = -6x[/tex]

Set the second derivative equal to zero:

[tex]0=-6x[/tex]

And solve for x. Hence:

[tex]x=0[/tex]

We must test the solution. In order for it to be an inflection point, the second derivative must change signs before and after. Testing x = -1:

[tex]f''(-1) = 6>0[/tex]

And testing x = 1:

[tex]f''(1) = -6<0[/tex]

Since the signs change for x = 0, x = 0 is indeed an inflection point.

B)

Recall that f is concave up when f''(x) is positive, and f is concave down when f''(x) is negative.

From the testing in Part A, we know that f''(x) is positive for all values less than zero. Hence, f is concave up for all values less than zero. Our interval is:

[tex](-\infty, 0)[/tex]

C)

From Part A, we know that f''(x) is negative for all values greater than zero. So, f is concave down for that interval:

[tex](0, \infty)[/tex]

In factons you divide the numerator and the whole number .. then denominator

Correct?

Answers

Answer:

Step-by-step explanation:

yes

A research team is testing a product that will minimize wrinkles among older adults. Volunteers in the age group of 40 to 45 are included in the research. The research team gives a cream to be applied on the face to one group and a placebo cream to the other group.

Answers

What is the question?

A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns​ shown, making the​ one-day sale price of the ski set ​$324. Find the original selling price of the ski set.

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Answer:

$520.632

Step-by-step explanation:

520 and some change

You want to walk from home to a clothing store that is 1/4 miles away you stop for a rest after 1/8 miles how much farther do you have to walk

Answers

Answer:

1/8

Step-by-step explanation:

Answer: 1/8

Step-by-step explanation:

1/8 + 1/8 = 2/8 = 1/4

The population of the world in 1987 was 5 billion and the annual growth rate was estimated at 2 percent per year. Assuming that the world population follows an exponential growth model, find the projected world population in 2015

Answers

Answer:

The projected world population in 2015 was 8,705,121,030 people.

Step-by-step explanation:

Given that the population of the world in 1987 was 5 billion and the annual growth rate was estimated at 2 percent per year, assuming that the world population follows an exponential growth model, to find the projected world population in 2015 the following calculation must be performed :

5,000,000,000 x 1.02 ^ (2015-1987) = X

5,000,000,000 x 1.02 ^ 28 = X

5,000,000,000 x 1.741024 = X

8,705,121,030 = X

Therefore, the projected world population in 2015 was 8,705,121,030 people.

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