Answer:
Discriminant is -740, the equation will have two complex solutions
Step-by-step explanation:
I substituted the variables into the discriminant (b^2-4ac) and then multiplied everything out, then subtracted. Since the discriminate comes out to a negative number (-740), it will have two complex solutions
Write the following expression in standard place-value form.
Answer:
3408
Step-by-step explanation:
describe the transformation of the equation below from the parent function of y=|x| y=|x-4| left 4, right 4, up 4, down4
Answer:
The transformation is right 4
Step-by-step explanation:
Since the transformation occurred inside the absolute value function, this means there will be a horizontal shift. Therefore, the transformation is right 4.
Observe the graph to view the transformation.
I need help anyone please
Answer:
Base: 7
Height:10
BH divided by two so
7 times 10 = 70 divided by two 35
Base: 7 yd
Height: 10 yd
Area: 35 square yd
([tex]A=\frac{h_{b}b }{2}[/tex] = [tex]\frac{10*7}{2}[/tex] = 35)
hope this helps....
Suppose that you have a square pyramid like the one pictured. Which plane section will produce a triangle?
A)
A cut parallel to the vertical axis, but off the vertical axis
B)
A cross section cut parallel with the bottom
C)
A cut parallel to the vertical axis, directly through the vertical axis
D)
Cutting off one of the bottom corners
Answer:
A
Step-by-step explanation:
What is the 8th term of a(n)=6•3^(n-1)
Answer:
13122
Step-by-step explanation:
a(n) = 6 * 3^(n -1)
a(8) = 6* 3^7
3^7 = 2187
a(8) =6 * 2187
a(8) = 13122
Select the correct answer. Simplify. V75 options: A. 3v5 B. 15v5 C. 25v3 D. 5v3
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
prove triangle ACD and BCE are congruent
Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
[tex]AC=BC[/tex] (Given)
[tex]AC\cong BC[/tex]
[tex]\angle C\cong m\angle C[/tex] (Common angle)
[tex]CD=CE[/tex] (Given)
[tex]CD\cong CE[/tex]
In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
[tex]\Delta ACD\cong \Delta BCE[/tex] (SAS congruence postulate)
Hence proved.
Answer:
Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD
Given AB=AC∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)
Given BE=CDThen BE−DE=CD−DE
ORBC=CE......................................(2)
In ΔABD and ΔACE
∠ABD=∠ACE ( From 1)
BC=CE (from 2)
AB=AC ( GIven)
∴ΔABD≅ΔACE
So AD=AE [henceproved]
In ΔTUV, t = 7 inches, u = 9.4 inches and ∠V=18°. Find the area of ΔTUV, to the nearest 10th of a square inch.
Answer:
10 square inches
Step-by-step explanation:
that is the procedure above
Answer:
Area=10.167=10.2
Step-by-step explanation:
Area=1/2ab sin c
area= 1/2(7)(9.4)sin18
area = 10.167=10.2
this is for delta math
Identify the relationship between the graphs of these two equations. y = 5/6x + 5 y = 5/6x - 1
parallel
perpendicular
neither
Answer:
parallel
Step-by-step explanation:
the slope of each line is 5/6 which means the lines are parallel
Simplify (-k)^0
Help! Thank you. (:
Answer:
I think 1 is the correct answer
On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?
(2, 3)
(–2, 3)
(3, 2)
(3, –2)On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?
(2, 3)
(–2, 3)
(3, 2)
(3, –2)
Answer:
the coordinates of pre - image point H is (3,2)
Answer:
c time for learning
Step-by-step explanation:
The owner of a football team claims that the average attendance at games is over 74,900, and he is therefore justified in moving the team to a city with a larger stadium. An independent investigator will conduct a hypothesis test to determine whether his claim is accurate. This test is ________. Group of answer choices Two-sided Lower-tailed Upper-tailed
Answer:
Option c (Upper tailed) is the correct choice.
Step-by-step explanation:
Given that:
The average attendance is:
= 74,900
We will have to test:
⇒ [tex]H_0:\mu \leq \mu_0[/tex]
or,
[tex]H_0: \mu \leq 74,900[/tex]
Verses,
⇒ [tex]H_1: \mu> \mu_0[/tex]
or,
[tex]H_1: \mu >74,900[/tex]
The other given alternatives aren't connected to the given scenario. So the above is the correct one.
what pairs of degree measures NOT belong to the
group?
Answer:
B. 56° and 38°
Step-by-step explanation:
The sum of each of the two angles sums up to 90° ;
A.) 13° and 77°
Sum of A ; (13 + 77)° = 90°
B.) 56° + 38°
Sum = 56° + 38° = 94°
C) 37° and 53°
Sum = 37° + 53° = 90°
D.) 42° and 48°
Sum = 42° + 48° = 90°
Hence, the pair of degree measure which does not belong is B. 56° and 38°
Please help!!! Urgent ….
9514 1404 393
Answer:
ΔWZT ~ ΔWXY
Step-by-step explanation:
Angle XWY and angle ZWT are vertical angles, so congruent.
The sides on either side of those angles are proportional:
WZ/WX = WT/WY
11/22 = 10/20 = 1/2
so, we can claim similarity by the SAS Theorem.
ΔWZT ~ ΔWXY
Help me please hurry!!
Answer:
answer is 36 centimeter
Step-by-step explanation:
volume of a cylinder=πr^2h
1696=3.14*r^2*15
1696=47.1=r^2
1696-47.1=r^2
1648.9=r^2
[tex]\sqrt{1648.9}[/tex] =r
40.60 =r
here according to the question and option given 40.60 is closest to 36 centimeters.so answer is option d.
Select the correct answer.
The y-Intercept of the parent quartic function, f(x) = 24
is translated 3 units to the right and 1 unit down. Which equation represents this
transformation?
OA. g() = (x – 3)4 - 1
OB. g(t) = (x + 3)4 - 1
OC. g(t) = (x - 1)* + 3
OD. g() = (x + 1)4 + 3
Using translation concepts, it is found that the equation that represents this transformation is given by:
A. [tex]g(x) = (x - 3)^4 - 1[/tex]
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
In this problem, the parent function is given by:
[tex]f(x) = x^4[/tex].
Then:
The function is shifted 3 units right, hence x -> x - 3.The function is shifted 1 unit down, hence f(x) -> f(x) - 1.Hence, the equation that represents the transformation is given by:
[tex]g(x) = (x - 3)^4 - 1[/tex]
Which means that option A is correct.
More can be learned about translation concepts at https://brainly.com/question/4521517
#SPJ1
What is the probability of tossing a penny and landing on heads 3 times in a row
Answer:
Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.
Which of the following ordered pairs is a solution to the equation 4x+6y=12? Select all that apply. Select all that apply: (−3,4) (1,3) (−6,6) (−13,10) (0,2)
Two circles are concentric if they have the same center.
On a coordinate plane, a circle has center (4, 6) and has a radius of 2 units.
Which equation represents a circle that is concentric with the circle shown but has a radius that is twice as large?
9514 1404 393
Answer:
(b) (x – 4)^2 + (y – 6)^2 = 16
Step-by-step explanation:
The equation for a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
You want the equation for a circle with center (4, 6) and radius 4. That equation is ...
(x -4)^2 +(y -6)^2 = 16
Answer:
B; (x – 4)2 + (y – 6)2 = 16
Step-by-step explanation:
correct on edge
Which choice shows (40+10)+30 correctly rewritten using the associative property and then correctly simplified?
40 + (10 + 30) = 40 + 40 = 80
40 + 30 + 10 = 70 + 10 = 80
40 + (10 +30) = 50 + 30 =80
(10 +40) + 30 = 50 + 30 =80
What is the equation of the line that passes through (-3,-1) and has a slope of
2/5. Put your answer in slope intercept
Answer:
y = 2/5x + 1/5
Step-by-step explanation:
First, plug in the slope.
y = mx+b
y = 2/5x + b
Then, plug in the point given, in order to find b.
-1 = 2/5(-3) + b
-1 = -6/5 + b
1/5 = b
So the final equation is:
y = 2/5x + 1/5
What should my answer be?
Anybody mind giving me the answer? Im struggling to get it rn
Answer:
nnn bjbjjjjjnn
Step-by-step explanation:
Answer:
c. 108
Step-by-step explanation:
do 12×12 and get 144 then do 6×6 to get 36 then do 144-36 and you get 108. hope this helps mate.
(4-i)-(3-i) in standard form
Answer:
ifeywifheb
Step-by-step explanation:
hkefewib
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4 = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm^3 and the pressure is 80 kPa and is decreasing at a rate of 10 kPa/min. At what rate is the volume increasing at this instant?
Answer:
The volume increases at 35.71cm^3/min
Step-by-step explanation:
Given
[tex]PV^{1.4} = C[/tex]
[tex]V = 400cm^3[/tex]
[tex]P =80kPa[/tex]
[tex]\frac{dP}{dt} =-10kPa/min[/tex]
Required
Rate at which volume increases
[tex]PV^{1.4} = C[/tex] [tex]V = 400cm^3[/tex] [tex]P =80kPa[/tex]
Differentiate: [tex]PV^{1.4} = C[/tex]
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]
By differentiating C, we have:
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]
Rewrite as:
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]
Solve for [tex]\frac{dV}{dt}[/tex]
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]
[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]
Substitute values
[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]
[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]
[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]
[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]
I need help solving for x
Answer:
x = 25
Step-by-step explanation:
Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is
[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )
24x = 600 ( divide both sides by 24 )
x = 25
If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,
find f(x) – g(x).
Answer: x^2 - 4x + 3
Answer:
f(x) – g(x) = x^2 - 4x + 3
Step-by-step explanation:
f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,
f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)
Distribute the minus sign
f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2
Combine like terms
f(x) – g(x) = x^2 - 4x + 3
Plz help me solve this algebra problem
Answer:
Exact Form:
x = 2 √ 2 − 1 3 , − 2 √ 2 − 1 3
Decimal Form:
x = 2.49509379 , − 3.16176045
Step-by-step explanation:
Simplify the decimals as needed
ON
16
aset
3rd
test
MATHEMATICS
Direction : Assemor all question, Tome and Shoul Work
1) A) use the newerberline (6) to find the finishing points for
these infegers
a)- 5110
Answer:
what????????????????????
WILL GIVE BRAINLIST! PUT THESE NUMBERS ON THE PLOT
Answer:
"fair" srry im only in 8th so im d.u.m
Step-by-step explanation:
