Please help with this!!! 8 points!!!

Answer:

9 < x

6 - f

t × 6

1/2n

Step-by-step explanation:

Given expressions:

9 less than x

Less than (<)

9 less than x = 9 < x

6 minus f

Minus (-)

= 6 - f

t multiplied by 6

Multiplication (×)

= t × 6

one half of a number n

One half = 1/2

one half of a number n

= 1/2 × n

= 1/2n

= n/2

Answer:

Hope you find it helpful and usef

the answer is in the picture

Answer:

b ≈ 48.6°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin b = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{9}{12}[/tex] , then

b = [tex]sin^{-1}[/tex] ([tex]\frac{9}{12}[/tex] ) ≈ 48.6° ( to 1 dec. place )

Answer:

5 units!

Step-by-step explanation:

Because Rectangle Perimeter = 2(a+b)

a=2w-1, b=w

2(2w-1+w)=28

3w-1=14

3w=15

w=5

So the answer is 5! 5! 5! A!A!A!

Fighting!! o(≧o≦)o

Answer:

188 m

Step-by-step explanation:

[tex] \tan(12) = \frac{40}{x} \\ x = \frac{40}{ \tan(12) } \\ x = 188[/tex]

Answer:

I think that the other answer is WRONG

tan(12) = [tex]\frac{x}{40}[/tex]

x = tan(12)*40 = 8.5

Step-by-step explanation:

[tex]\frac{sin\left(78\right)}{40}=\frac{sin\left(12\right)}{x}[/tex] = 8.5

Answer:

Step-by-step explanation:

From the picture attached,

ΔDEF is a right triangle with two sides,

EF = 17 units

DF = 20 units

By applying Pythagoras theorem in the given triangle,

DE² = DF² + EF²

(20)² = DF² + (17)²

DF² = 400 - 289

DF = √111

Trigonometric ratios for the ∠F,

sin(F) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\text{sin}F=\frac{\sqrt{111}}{20}[/tex]

[tex]\text{cosF}=\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\text{cos}F=\frac{17}{20}[/tex]

[tex]\text{tan}F=\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

[tex]\text{tan}F=\frac{\sqrt{111}}{17}[/tex]

Choose the correct option.

Answer:

you need to solve for 'X'

mean 49 = 55 + 42 + 32 +48 + 55 + X

49 = (232+X) / 6

49 * 6 = 232 + X

294 = 232 + X

294 - 232 = X

62 = X

so therefore X is 62

Step-by-step explanation:

please give me a brainliest

Answer:

d. 20

Step-by-step explanation:

28 ÷ (100%+40%)

= 28 ÷ 140%

= 28 ÷ 1.4 = 20

Answer:

option d

Step-by-step explanation:

Let the number be x

40% of x = 0.40x

Increased by 40% = 28

That is ,

           x + 0.40x = 28

               1.40x = 28

                   [tex]x = \frac{28}{1.40}\\[/tex]

                  [tex]x = \frac{28 \times 100}{1.40 \times 100 } = \frac{28 \times 100}{140} =\frac{4 \times 100}{20} = 4 \times 5 = 20[/tex]

Therefore, the number is 20

Answer:

1: 16

2: 4940

3: 24

4: 25

5: 9

Step-by-step explanation:

A permutation is a method of calculating the number of possible outcomes. It follows the following general formula;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

There (n) is the number of objects, and (r) is the number of objects selected.

1. Arranging 4 pots with different plants in a row

In order to solve this, one needs two pieces of information, the number of objects, and the number of objects selected. One is given the number of objects; (4), but when the problem states "in a row" it never specifies how many plants are in a row. Thus, let one assume that a "row" can have an infinite amount of space, but in this case, only (4) space will be used. Therefore there are (4) objects with (4) objects selected. However, the drawback is that the combination formula doesn't work when the two parameters (n) and (r) are the same. Hence, to solve this special case, one simply multiplies the two numbers to get the answers:

[tex]n*r\\\\=4*4\\\\=16[/tex]

2. Forming a four-digit ATM pin

One is given that there are (4) digits in the ATM pin, this is the number of objects selected. One is also given that number of objects, there are (10) digits including (0). Set up the permutation and solve;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

[tex]_1_0P_4=\frac{10!}{(10-4)!}\\\\=\frac{10!}{6!}\\\\=\frac{10*9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}\\\\=10*9*8*7\\\\=4940[/tex]

3. Securing a motorcycle with a three-digit combination lock using the numbers (1), (2), (3), and (6).

There are (4) digits to choose from on the lock. But there are (3) numbers that can be selected.

[tex]_4P_3=\frac{4!}{(4-3)!}\\\\=\frac{4!}{1!}\\\\=\frac{4*3*2*1}{1}\\\\=4*3*2*1\\\\=24[/tex]

4. Displaying 3 identical small vases, 1 figure, and a photo frame in a row.

There are (5) objects, and (5) spaces (read problem (1) for an explanation for the objects being put in a row). Thus, this is a special case; multiply the two numbers to get the result;

[tex]n*r\\=5*5\\=25[/tex]

5. 3 girls sitting around a circular table

There are (3) subjects, and (3) spaces in this problem. Apply the same logic applies to a row in this problem. Therefore, this is another special case; multiply the two numbers to get the result;

[tex]n*r\\=3*3\\=9[/tex]

Answer:

2 i think it is

Step-by-step explanation:

ok so we see that TR is 17 units, so RV is the same amount

3x+2 so 3x=15 so divide both sides by 3 we get x=5

now we know x=5 4x+1=21 and 9x-4=41

*drops microphone*

Answer:

TR = 12

=> 3x + 2 =17

=> x = 5

We have QT = QV (because QTV is an isosceles triangle)

=> QT = 4x+1=4x5+1=21 units

We have TS = SV (because TSV is an isosceles triangle)

=>SV = 9x-4= 9x5-4=41 units

Answer:

Get all the values of the histogram and put them in order:

For example 2,5,7,1,7,3  becomes 1,2,3,5,7,7 and then you get the middle number, which is in this case (3+5)/2=3.5

Then see which of the readings lie on 3.5.

Step-by-step explanation:

9514 1404 393

Explanation:

The histogram will have a count associated with each class. You may have to read the count from the vertical scale of the graph. If it is a histogram of relative frequencies, each class will have a fraction or percentage instead of a count.

Find the total of all counts. Determine what half that number is. If the total is odd, then round up to the nearest integer. This is the index number of the median value.

Add up the counts in the classes starting at one side of the graph, working toward the other side. (Left-to-right is the usual direction for doing this.) When you find the class that increases the total to a value equal or greater than the index number, this is the class that contains the median.

__

If the histogram is a relative frequency histogram, the class that brings the total to 50% is the one containing the median.

__

There may be cases where the total count is even, and the total of all of the classes up to a point is exactly equal to the index number you're looking for. In that case, the median is between that class and the next. Here's an example:

  class 1: count 3

  class 2: count 5

  class 3: count 4

  class 4: count 4

Total count: 3+5+4+4 = 16. Median index = 16/2 = 8

Total of classes 1 and 2 = 3+5 = 8. This means exactly half of the represented values are in class 2 or below, and half are in class 3 or above. If you had access to the actual data values, you would find the median as the average of the 8th and 9th data values (when they are sorted into increasing order). Here, the median might be estimated as the value halfway between the upper bound of class 2 and the lower bound of class 3.

__

2nd example

Consider the same histogram as above, but with a count of 3 in class 4. This brings the total count to 15, and the index of the median is 15/2 = 7.5, rounds to 8. Again, the 8th data value (median) is in class 2. There is no ambiguity in this case.

Answer:

-27/7

Step-by-step explanation:

put x into the equation

Answer:

B. 13.95 meters

Step-by-step explanation:

The question is just asking you to talk the amount of time taken, and divide it in half.

d= 0.5(27.9)

Answer:

y=n^2+3n+4

Step-by-step explanation:

Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

Subtracting 4 on both sides gives: 4=a+b

(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

If a+b=4 and a=1, then b=3. Because 3+1=4.

So the equation is y=1n^2+3n+4 or y=n^2+3n+4.

Answer:

The median is 9

Step-by-step explanation:

The median is the number in the middle. The middle of this is 8 and 10, so you plus them and divide by to 2, then it gives 9, so the median is 9.

Answer:

6.5

Step-by-step explanation:

We need to solve out for x , the given Equation is ,

[tex]: \implies[/tex] x - 3x + 2 = -11

[tex]: \implies[/tex] -2x = -11 -2

[tex]: \implies[/tex] -2x = -13

[tex]: \implies[/tex] x = -13/-2

[tex]: \implies[/tex] x = 6.5

Answer:

x = 6.5

Step-by-step explanation:

[tex]x - 3x + 2 = - 11 \\ - 2x + 2 = - 11 \\ - 2x = - 11 - 2 \\ \frac{ - 2x}{ - 2} = \frac{ - 13}{ - 2} \\ x = + 6.5 [/tex]

Answer:

1

Step-by-step explanation:

Let the number be n.

We are given:

n/12=q1+(7/12) where q1 is the quotient

n/6=q2+(?/6) where q2 is the quotient and ? is the remainder value we are trying to find.

? must be a integer between 0 and 5, inclusive. A remainder cannot be bigger than or equal to the divisor.

Let's rewrite the first equations

Multiply equation 1 on both sides by 2:

n/6=2q1+7/6

Remainder cannot be 7.

Rewrite again.

6 goes into 7 1 time with remainder 1.

n/6=2q1+(1+1/6)

n/6=(2q1+1)+1/6

So q2=2q1+1 and the remainder is 1 when dividing n by 6.

For fun. What is a number n with such conditions on it?

So what number has remainder 7 when divided by 12 and a remainder 1 when divided by 6.

n=12q1+7

n=6q2+1

If q1=1, we find a number right away that works.

19/12=1+7/12

19/6=3+1/6

Answer:

75 in^2

Step-by-step explanation:

The surface area is the sum of the areas

Area of the square:

A = s^2 = 5^2 =25

Area of one triangle

A = 1/2 bh = 1/2 (5)(5) = 25/2

There are 4 triangles

4* (26)/2 = 50

The sum is 25+50 = 75

Hi!

[tex]P_{\square}=5^2=25 \ in.^2\\\\P_{\triangle}=\frac{1}{2}\cdot5\cdot5=\frac{1}{2}\cdot25=12,5 \ in.^2\\\\P_c=25+4\cdot12,5=25+50=\boxed{75 \ in.^2}[/tex]

Answer:

hope this will help you more

Step-by-step explanation:

hope it is helpful to you

stay safe healthy and happy

Answer:

y=|x -3| -1

Step-by-step explanation:

Answer: 69, -69

Step-by-step explanation:

it is easy buddy not lies

Answer:

a) A shopkeeper marked the price of an article a certain percentage above the cost price and he allowed 16% discount to make 5% profit. If a customer paid Rs 9.492 with 13% VAT to buy the article, by what percent is the marked price above the cost of the price article? (I hope this helps)

Answer:

Option C.

Step-by-step explanation:

For a given set of N elements:

{x₁, x₂, ..., xₙ}

The mean is given by:

[tex]M = \frac{x_1 + x_2 + ... + x_n}{N}[/tex]

And the variance is given by:

[tex]v = \frac{(x_1 - M)^2 + (x_2 - M)^2 + ... + (x_n - M)^2}{N}[/tex]

Then for our set:

{70, 80 ,75, 75, 80}

We have 5 elements, then N = 5

The first thing we need to find is the mean.

[tex]M = \frac{70 + 80 + 75 + 75 + 80}{5} = 76[/tex]

Then the variance will be:

[tex]v = \frac{(70 - 76)^2 + (80 - 76)^2 + (75 - 76)^2 + (75 - 76)^2 + (80 - 76)^2}{5} = 14[/tex]

The correct option is C, 14.

Answer:

0.50=1.7. They do not equal each other

Step-by-step explanation:

Thats what I got from this question

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]0 \to[/tex] Correct

[tex]1 \to[/tex] Defective

Required

The probability that the next is defective

The question is incomplete because the list of bottles that came out is not given.

However, the formula to use is:

[tex]Pr = Num ber\ o f\ d e f e c t i v e \div T o t a l\ b o t t l e s[/tex]

Take for instance, the following outcomes:

[tex]0\ 1\ 0\ 0\ 0\ 1\ 0\ 0\ 1\ 1\ 0\ 0\ 0\ 1[/tex]

We have:

[tex]Total = 14[/tex]

[tex]D e f e ctive = 9[/tex] --- i.e. the number of 0's

So, the probability is:

[tex]Pr = 9 \div 14[/tex]

[tex]Pr = 0.643[/tex]

Answer:

1/20

Step-by-step explanation:

000000000000100000

It is asking the probability of a defective bottle

there is one defective bottle out of 20