Answer:
48
Step-by-step explanation:
16×3=48
therefore the answer is forty eight
A bag contains 4 red marbles, 3 blue marbles, and 7 green marbles. If a marble is randomly selected from the bag, find
the probability that a blue marble will be drawn.
a. 1
1
7
C.
b.
1
d.
3
11
14
Please select the best answer from the choices provided
B
оооо
Answer:
3/14
Step-by-step explanation:
Probability = # of favorable outcomes / # of possible outcomes
Favorable outcomes = we want to find the probability of pulling a blue marble. There are 3 blue marbles so 3 is the number of favorable outcomes
Possible outcomes: to find the number of possible outcomes we simply find the total number of marbles
3 + 7 + 4 which equals 14
So possible outcomes = 14
We now plug in the values into the probability formula
The probability of pulling a blue marble is 3/14
Answer:
3/14
Step-by-step explanation:
you add the red marbles, blue marbles, and green marbles together, which equal 14. Out of the 14, there are only 3 blue marbles so it would be 3/14.
According to a bridal magazine, the average cost of a wedding reception for an American wedding is $8213. Assume that the average is based on a random sample of 450 weddings and that the standard deviation is $2185.a. What is the point estimate of the corresponding population mean
Answer:
Point estimate of the corresponding population mean = $8,213
Step-by-step explanation:
Given:
Average cost of a wedding reception (x) = $8,213
Total number of sample (n) = 450
Standard deviation = $2185
Find:
Point estimate of the corresponding population mean
Computation:
Average cost of a wedding reception (x) = Point estimate of the corresponding population mean
Point estimate of the corresponding population mean = $8,213
Encuentra el resultado de la ecuación mediante la formula general
Step-by-step explanation:
de hecho, la respuesta está en la imagen de arriba
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y2(y2 − 4) = x2(x2 − 5) (0, −2) (devil's curve)
Answer:
Step-by-step explanation:
Given that:
[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]
at point (0, -2)
[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]
Taking the differential from the equation above with respect to x;
[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]
Collect like terms
[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
Hence, the slope of the tangent line m can be said to be:
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
At point (0,-2)
[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]
[tex]\dfrac{dy}{dx}= 0[/tex]
m = 0
So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:
(y - y₁ = m(x - x₁))
y + 2 = 0(x - 0)
y + 2 = 0
y = -2
PLEASE HELP! I really need to get this right
Answer:
27.3
Step-by-step explanation:
27.3
Answer:
Plays a musical instrument
Top left
Plays a sport: 0.46
Plays a musical instrument
Top right
Does not Play a sport: 0.54
Does not play a musical instrument
Bottom Left
Plays a sport: 0.73
Does not play a musical instrument
Bottom right
Does not Play a sport: 0.27
Step-by-step explanation:
I hope this helps you! :D
It take 6 Pounds of flour to make 36 cakes. How much flour is needed to make 9 cakes?
Answer:
54 pounds
Step-by-step explanation:
To find out how much flour is needed to make 9 cakes, we first need to find out how much much flour is needed to make 1 cake. For that, we need to divide 6 by 36. That will give you 6. Now that we know how much flour is needed to make 1 cake, we will just have to multiply 6 by 9 to find out how much flour is needed to make 9 cakes. That will give you 54 pounds, which is your final answer.
SOMEONE HELP ME PLEASE
find the real fifth root of -32
Answer: -2
This is because (-2)^5 = -32. Applying the fifth root to both sides lets us say [tex]-2 = \sqrt[5]{-32}[/tex]
There are four other roots but they are complex. Effectively, we are solving the equation [tex]x^5 + 32 = 0[/tex]
Question 16 of 20
If a study estimated that 22% of students ride their bikes to school, and the
error range is +2%, what percentage of students might actually ride their bikes
to school?
O A. 22% -24%
O B. 2% - 22%
O C. 20% - 22%
ОО
D. 20% - 24%
SUBMIT
PREVIOUS
Answer:
D) 20%-24%
Step-by-step explanation:
The margin of error is ±2%, which means that the true proportion it can be 2% above the average proportion or 2% below the average proportion. Therefore, the percentage of students that might actually ride their bikes to school is 20%-24%.
Answer: A. 22%-24%
Step-by-step explanation: There's a +2% error range, so you just add 2% to the existing percentage to get your range of 22% (the original percentage) through 24% (the percentage you get after adding 2%)
If anyone can do this for me step by step i will give you 30 points please help me out
Answer:
after 10 months
Step-by-step explanation:
Let x be the number of months and y be the amount they still owe.
Sin Ian borrows $1000 from his parents, then the y-intercept b= 1000 since he owes $1000 when x = 0. He pays them back $60 each month The slope is then m = -60 . Substituting in b = 1000 and m = -60 into the slope-intercept form of a line then gives y= mx + b=-60x +1000.
Sin Ken borrows $600 from his parents, then the y-intercept b = 600 since he owes $600 When x= 0. He pays them back $20 per month so the amount he owes decreases $20 each month. The slope is then m = -20 . Substituting in
b= 600 and m = -20 into the slope-intercept form then gives y = mx +b = -20x + 600.
They will owe the same amount when they have the same y-coordinate. Therefore -60x+ 1000= y= -20x+600. Solve this equation for x:
-60x+ 1000 = -20x+ 600
1000 = 40x+ 600
400 = 40x
10=x
They will then owe the same amount after 10 months.
Sum of 5x^2+2x and 4-x^2
Answer:
4x^2 + 2x + 4
Step-by-step explanation:
5x^2 + 2x + 4 - x^2
4x^2 + 2x + 4
Answer:
2(2x^2 + x + 2)
Step-by-step explanation:
5x^2+2x + 4-x^2
Re arrange so like terms are next to each other
Keep the same symbol that is at the front of the term when moving it
5x^2 - x^2 + 2x + 4
We will just do the first part first
5x^2 - x^2
5x^2 - 1x^2 (is the same thing as above)
So because they are like terms (are both x^2)
We can just minus 1 from 5
5-1=4
So 4x^2
Now the equation is
4x^2 + 2x + 4
This is as small as it gets but you can also bring it to this
4, 2 and 4 all are divisible by 2 so
2(2x^2 + x + 2)
X Y
-10 2
-15 3
-25 5
Determine whether y varies directly with x. If so, find the constant of variation and write the equation
Answer:
x = -5y
Step-by-step explanation:
x = ay
-10 = 2a
a = -5
x = ay
-15 = 3a
a = -5
x = ay
-25 = 5a
a = -5
Find the surface area of each solid figure
Answer:
First find the SA of the triangular figure
4 x 3 = 12 cm^2 (the triangles on the sides)
2 x 3 = 6 cm^2 (the back square)
2 x 5 = 10 cm^2 (the slanted square)
*I'm not sure if this question includes the bottom of the triangle but here it is anyways
4 x 2 = 8 cm^2
Including the bottom the SA of the triangular figure is:
12 + 6 + 10 + 8 = 36 cm^2
Find the SA of the rectangular shape
4 x 2 = 8 cm^2 (the bottom square)
2 x 6 = 12 x 2 = 24 cm^2 (the sides)
4 x 6 = 24 x 2 = 48 cm^2 (the front and back)
Add them up
8 + 24 + 48 = 80 cm^2
If you wanted to find the SA of the whole figure it would be:
12 + 6 + 10 + 8 + 24 + 48 = 108 cm^2
Hope this helps!
Solve for X in the triangle. Round your answer to the nearest tenth
Answer:
[tex]\displaystyle x \approx 9.9[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityTrigonometry
[Right Triangles Only] SOHCAHTOA[Right Triangles Only] sinθ = opposite over hypotenuseStep-by-step explanation:
Step 1: Define
Identify variables
Angle θ = 64°
Opposite Leg = x
Hypotenuse = 11
Step 2: Solve for x
Substitute in variables [sine]: [tex]\displaystyle sin(64^\circ) = \frac{x}{11}[/tex][Multiplication Property of Equality] Multiply 11 on both sides: [tex]\displaystyle 11sin(64^\circ) = x[/tex]Rewrite: [tex]\displaystyle x = 11sin(64^\circ)[/tex]Evaluate: [tex]\displaystyle x = 9.88673[/tex]Round: [tex]\displaystyle x \approx 9.9[/tex]Consider the expression 25 – 10 ÷ 2 + 3.
Part A
Which shows a way to rewrite the expression using parentheses so that the expression equals 23?
Select all that apply.
A. (25 – 10) ÷ 2 + 3 = 23
B. 25 – 10 ÷ (2 + 3) = 23
C. (25 – 10) ÷ (2 + 3) = 23
D. 25 – (10 ÷ 2) + 3 = 23
Part B
Which shows a way to rewrite the expression using parentheses so that the expression equals 3?
A. (25 – 10) ÷ 2 + 3 = 3
B. 25 – 10 ÷ (2 + 3) = 3
C. (25 – 10) ÷ (2 + 3) = 3
D. 25 – (10 ÷ 2) + 3 = 3
Given:
The expression is:
[tex]25-10\div 2+3[/tex]
To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,
[tex](25-10)\div 2+3=15\div 2+3[/tex]
[tex](25-10)\div 2+3=7.5+3[/tex] [Using BODMAS]
[tex](25-10)\div 2+3=10.5[/tex]
In option B,
[tex]25-10\div (2+3)=25-10\div 5[/tex]
[tex]25-10\div (2+3)=25-2[/tex] [Using BODMAS]
[tex]25-10\div (2+3)=23[/tex]
In option C,
[tex](25-10)\div (2+3)=15\div 5[/tex]
[tex](25-10)\div (2+3)=3[/tex]
In option D,
[tex]25-(10\div 2)+3=25-5+3[/tex]
[tex]25-(10\div 2)+3=28-5[/tex] [Using BODMAS]
[tex]25-(10\div 2)+3=23[/tex]
After the calculation, we have [tex]25-10\div (2+3)=23[/tex] and [tex]25-(10\div 2)+3=23[/tex].
Therefore, the correct options are B and D.
Part B: From part A, it is clear that
[tex](25-10)\div (2+3)=3[/tex]
Therefore, the correct option is C.
To find the constant vector C, we use the given initial condition v(0) = k, we also know that at t = 0, the general equation for v() i:s Comparing both equations for V(0) and solving for C, we have C = k. Substituting it back into the general equation, we have
V(t) = 4ti + 5tj + c = ______.
Answer:
4ti + 5tj + k
Step-by-step explanation:
Initial condition V(0) = k
at t = 0
general equation for v(t )
V(0) = 0i + 0j + c = k
when we compare V(0) and solve for c , c = k
back to general equation
V(t) = 4ti + 5tj + c = 4ti + 5tj + k
Which state ment is true regarding the graphed function
F(4)= g(4)
F(4)= g(-2)
F(2)= g(-2)
F(-2)= g(-2)
Answer:
F(-2)= g(-2)
Step-by-step explanation:
F(-2)= g(-2), both function have the same points of intersect.
Enlarge the triangle by scale factor 3
Answer:
The triangle will triple in size.
The number of adults who attend a music festival, measured in hundreds of people, is represented by the function a(d)=−0.3d2+3d+10, where d is the number of days since the festival opened.
The number of teenagers who attend the same music festival, measured in hundreds of people, is represented by the function t(d)=−0.2d2+4d+12, where d is the number of days since the festival opened.
What function, f(d) , can be used to determine how many more teenagers than adults attend the festival on any day?
f(d)=−0.1d2+d+22
f(d)=0.1d2+d+2
f(d)=−0.1d2+7d+2
f(d)=0.1d2+7d+2
Answer:
f(d)=0.1d^2+d+2
Step-by-step explanation:
t(d)=−0.2d2+4d+12
a(d)=−0.3d2+3d+10
how many more teenagers than adults attend the festival on any day?
==>
f(d) = t(d) - a(d)
=0.1d^2+d+2
GIVING BRAINLIEST!!!!!!
Answer:
B-2
Step-by-step explanation:
To find the constant of dilation take the lead of EF and divide it by the length of AB to get (6/3)=2
Prove the formula that:
((∃x)(F(x)∧S(x))→(∀y)(M(y)→W(y)))∧((∃y)(M(y)∧¬W(y)))
⇒(∀x)(F(x)→¬S(x))
Step-by-step explanation:
Given: [∀x(L(x) → A(x))] →
[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for
arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof
technique.
Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
We need to show that the above expression is unsatisfiable (False).
¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))
∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))
E.I with respect to x,
(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a
(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))
E.I with respect to y,
(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b
U.I with respect to y,
(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b
Since P ∧ Q is P, drop L(a) from the above expression.
(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b
Apply distribution
(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))
Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to
(L(b) ∧ H(a, b) ∧ ¬A(b))
U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace
¬A(b) in the above expression with ¬L(b). Thus, we get,
(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.
This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows
from the premise.
15
What is the zero of the function represented by this graph?
Use the graph to answer the question.
What is [tex]\frac{AD}{AB}[/tex] in simplest form?
A. [tex]\frac{10}{3}[/tex]
B. [tex]\frac{1}{3}[/tex]
C. [tex]\frac{17}{5}[/tex]
D. 3
Answer:
D. 3
Step-by-step explanation:
Distance between A and D = AD = 9 units
Distance between A and B = AB = 3 units
[tex] \frac{AD}{AB} = \frac{9}{3} [/tex]
Simplify by dividing
[tex] \frac{AD}{AB} = \frac{3}{1} [/tex]
[tex] \frac{AD}{AB} = 3 [/tex]
The answer is 3
What is the awnsers helppppp
Answer: 0.77
Step-by-step explanation:
Answer:
0.23
Step-by-step explanation:
the chart adds up to 1 as a whole so 23% chose football and there is a 23% chance the next person will also choose football.
Find all real zeros of the function y = -7x + 8
9514 1404 393
Answer:
x = 8/7
Step-by-step explanation:
The only real zero of this linear function is the value of x that makes y=0:
0 = -7x +8
7x = 8 . . . . . . add 7x
x = 8/7 . . . . . .divide by 7
PLEASE HELP!!!
WILL MARK BRAINLIEST!!!
If the diameter of the circle shown below is 6ft and 0 is a right angle, what is the length of segment AB to the nearest foot?
Multiple choice!
Thank you!
Answer:
how old are you gghhjjzetstu9u
Answer:
4 ft
Step-by-step explanation:
let's find radius first
radius=diameter/2
=6/2
=3 ft
radii=3 ft
Now by using pythagoras theorem
a^2 + b^2 = c^2
3^2 + 3^2 =AB^2
9+9=AB^2
18=AB^2
[tex]\sqrt{18}[/tex] AB
4.24 =AB
4 ft =AB (after converting to nearest foot)
How do I solve this math problem? The answer is: x = a^2/a-3
Answer:
I love algebra anyways
the ans is in the picture with the steps
(hope it helps can i plz have brainlist :D hehe)
Step-by-step explanation:
Bill can hit a bucket of 323 golf balls in 17 hours.
How many golf balls can Bill hit in 23 hours?
Find z such that 97.5% of the standard normal curve lies to the left of z. (Enter a number. Round your answer to two decimal places.)
Answer:
z=1.96
Step-by-step explanation:
Using normal distribution table or technology, 97.5% corresponds to z=1.959964, generally denoted z=1.96, or 1.96 standard deviations above the mean.
(above value obtained from R)
Find the equation of a line with a slope of −1/2 that passes through the point −4, 10
Answer:
y - 10 = -1/2(x + 4)
General Formulas and Concepts:
Algebra I
Coordinates (x, y)
Point-Slope Form: y - y₁ = m(x - x₁)
x₁ - x coordinate y₁ - y coordinate m - slopeStep-by-step explanation:
Step 1: Define
Identify variables
m = -1/2
Point (-4, 10) → x₁ = -4, y₁ = 10
Step 2: Find
Substitute in variables [Point-Slope Form]: y - 10 = -1/2(x - -4)Simplify: y - 10 = -1/2(x + 4)Answer: [tex]y=-\frac{1}{2} x+8[/tex]
Step-by-step explanation:
An equation of a line can be in slope intercept form which is y=mx+b
m is the slope, b is the y intercept, x it the x coordinate, and y is the y coordinate. Since we know the slope is -1/2 and we know a x coordinate is -4 and a y coordinate is 10 we can sub them in and solve for the value of b.
[tex]y=mx+b\\10=(-\frac{1}{2})(-4)+b\\10=2+b\\10-2=2+b-2\\8=b[/tex]
The value of b is 8. We can now sub it in for our equation of the line. This time with x and y as variables.
y=-1/2x+8
PLEASE HELP ME I HAVE TO PASS THIS TEST
30 POINTS
Answer:
Hi, there the answer is
These are the equations with exactly one solution
-5x + 12 = –12x – 12
-5x + 12 = 5x + 12
-5x + 12 = 5x – 5
Hope This Helps :)
Step-by-step explanation:
First degree equations
A first degree equation has the form
ax + b = 0
There are some special cases where the equation can have one, infinitely many or no solution
If , the equation has exactly one solution
If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0
If a=0 and the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.
We have been given some equations, we only need to put them in standard form
-5x + 12 = –12x – 12
Rearranging
7x + 24 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = 5x + 12
Rearranging
-10x + 0 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = 5x – 5
Rearranging
-10x + 17 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = -5x – 12
Rearranging
0x + 24 = 0
It has no solution, no matter what the value of x is, it's impossible that 24=0
Answer: These are the equations with exactly one solution
-5x + 12 = –12x – 12
-5x + 12 = 5x + 12
-5x + 12 = 5x – 5