simplify expresion 5x³y(2x+3y-4) =
Answer:
5x3 y(5xy-4)
5x3y ×1xy
5x4y2
Answer:
[tex]5 {x}^{3} y[/tex]
step by step
[tex]5 {x}^{3} y(2x + 3y - 4) \\ = 10 {x}^{3}y + 15 {x}^{3} y + 20 {x}^{3} y \\ = 5 {x}^{3} y[/tex]
I need help please help me
Answer:
Y = (x + 1)^2 - 4
where is
look the Diagram when the line arrow cross to x line got -4 it's mean left side is Negative and reach to y diagram within 1 on positive to below
so the right answer is = Y = (x+1)^2 - 4
My question is very simple and yes I'm saying all this bc I can't ask without 20 words- What is 400 cubed?
Answer: 64000000
Explanation: Why are you named as my ALT-
3/9 and 5/15 are they equivalent
Answer:
yes
Step-by-step explanation:
3/9 Divide the top and bottom by 3
1/3
5/15 Divide the top and bottom by 5
1/3
They are equal
How do you do 7-7(-4)
Answer:
35
Step-by-step explanation:
7-7(-4)
Using PEMDAS
Multiply first
7 +28
Then add
35
Derive
Somebody could help me?
check that
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For what value of w is4w = 2w - 8
Answer:
w =-4
Step-by-step explanation:
4w = 2w - 8
Subtract 2w from each side
4w-2w = 2w-2w - 8
2w = -8
Divide by 2
2w/2 = -8/2
w = -4
pls help me REALY unrgent
Answer:
[tex]269 \frac{1}{4} [/tex]
Step-by-step explanation:
the solution is found above in the diagram.
Suppose the shipping weight of your cheese shop's customized gift baskets is asymmetrically distributed with unknown mean and standard deviation. For a sample of 70 orders, the mean weight is 52 ounces and the standard deviation is 8.4 ounces. What is the lower bound of the 99 percent confidence interval for the gift basket's average shipping weight
Answer:
The lower bound of the 99% confidence interval for the gift basket's average shipping weight is of 49.34 ounces.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 70 - 1 = 69
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 69 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.649
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.649\frac{8.4}{\sqrt{70}} = 2.66[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 52 - 2.66 = 49.34
The lower bound of the 99% confidence interval for the gift basket's average shipping weight is of 49.34 ounces.
Use the Laplace transform to solve the given system of differential equations.
Let X(s) and Y(s) denote the Laplace transforms of x(t) and y(t), respectively. Then taking the transform of both sides of both equations gives
LT[dx/dt + 5x + dy/dt] = LT[1]
==> s X(s) - x (0) + 5 X(s) + s Y(s) - y (0) = 1/s
==> s X(s) + 5 X(s) + s Y(s) = 1/s
==> (s + 5) X(s) + s Y(s) = 1/s
LT[dx/dt - x + dy/dt - y] = LT[exp(t )]
==> s X(s) - x (0) - X(s) + s Y(s) - y (0) - Y(s) = 1/(s - 1)
==> s X(s) - X(s) + s Y(s) - Y(s) = 1/(s - 1)
==> (s - 1) X(s) + (s - 1) Y(s) = 1/(s - 1)
Solve for X(s) and Y(s). Using elimination, you would get
X(s) = (1 - 2s) / (5s (s - 1)²)
Y(s) = (7s - 1) / (5s (s - 1)²)
Now take the inverse transforms of each. Start by getting the partial fraction decompositions:
(1 - 2s) / (5s (s - 1)²) = 1/5 (a/s + b/(s - 1) + c/(s - 1)²)
-2s + 1 = a (s - 1)² + bs (s - 1) + cs
-2s + 1 = (a + b) s ² + (-2a - b + c) s + a
==> a + b = 0, -2a - b + c = -10, a = 5
==> a = 1, b = -1, c = -1
==> X(s) = 1/5 (1/s - 1/(s - 1) - 1/(s - 1)²)
Similarly, you would find
Y(s) = -1/5 (1/s - 1/(s - 1) - 6/(s - 1)²)
Now for the inverse transforms:
LT⁻¹ [1/s] = 1
LT⁻¹ [1/(s - 1)] = exp(t )
LT⁻¹ [1/(s - 1)²] = t exp(t )
Putting everything together, we have
LT⁻¹ [X(s)] = x(t) = 1/5 - 1/5 exp(t ) - 1/5 t exp(t )
and
LT⁻¹ [Y(s)] = y(t) = -1/5 + 1/5 exp(t ) + 6/5 t exp(t )
Class A has 9 pupils and class B has 24 pupils.
Both classes sit the same maths test.
The mean score for class A is 40.
The mean score for class B is 20.
What is the mean score (rounded to 2 DP) in the maths test across both classes?
Answer:
mean ≈ 25.45
Step-by-step explanation:
mean is calculated as
mean = [tex]\frac{sum}{count}[/tex]
We require the sum for both classes
class A
mean = [tex]\frac{sum}{9}[/tex] = 40 ( multiply both sides by 9 )
sum = 9 × 40 = 360
class B
mean = [tex]\frac{sum}{24}[/tex] = 20 ( multiply both sides by 24
sum = 24 × 20 = 480
Total sum for both classes = 360 + 480 = 840 , then mean for both classes is
mean = [tex]\frac{840}{33}[/tex] ≈ 25.45 ( to 2 dec. places )
What is the answercto this equation? 5x+37=-6(1-8×)
Answer:
x=1
Step-by-step explanation:
5x+37=-6(1-8x)
Distribute
5x+37 = -6 +48x
Subtract 5x from each side
5x+37 -5x = -6+48x-5x
37 = -6+43x
Add 6 to each side
37+6 = -6+43x+6
43 = 43x
Divide by 43
43/43 = 43x/43
1 =x
Answer:
x=1
Step-by-step explanation:
5x+37=-6(1-8×)
5x+37=-6(-7)
5x+37=6 x 7
5x+37= 42
5x+37-37=42-37
5x=5
5x/5 = 5/5
x = 1
Hope it Helps !!
PLZZZZZ HURRY WILL GIVE BRAINLIEST!!!!
Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the origin? Why or why not?
Yes, because corresponding sides are parallel and have lengths in the ratio Four-thirds
Yes, because both figures are rectangles and all rectangles are similar.
No, because the center of dilation is not at (0, 0).
No, because corresponding sides have different slopes.
Answer:
option b
Step-by-step explanation:
both are rectangles and similar measures
Yes, because both figures are rectangles and all rectangles are similar
The rectangle EFGH is a result of the dilation of rectangle ABCD
What is Dilation?Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent
Given data ,
Let the first rectangle be represented as ABCD
Now , the rectangle is dilated by a scale factor k
And , the transformed rectangle is given by EFGH
where the center of origin is the scale factor of dilation
Now , the ratios of the sides of the rectangles will be similar
So , the rectangles ABCD and EFGH are similar
Hence , the dilated rectangle is EFGH
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What is the next step in solving 0 = x2 + 6x – 10 by completing the square, after you cut 6 in half?
Answer:
see below
Step-by-step explanation:
0 = x^2 + 6x – 10
Add 10 to each side
10 = x^2-6x
Take the coefficient of x
-6
Divide by 2
-6/2 =-3
Square it
(-3)^2 =9
Add 9 to each side
10+9 = x^2-6x+9
We use -3 for the square term
19 = (x-3)^2
Take the square root of each side
±sqrt(19) = x-3
Add 3 to each side
3±sqrt(19) = x
For the first 6% of Carlene's salary, her employer matches 100% of her 401(k) contributions, and from 6% to 12%, Carlene's employer matches 50% of her 401(k) contributions. Carlene's salary is $40,000, and last year, she contributed $4000 to her 401(k) plan. What was her employer's contribution to the 401(k)?
Carlene's employer's contribution to the 401(k) was of $3,200., using proportions.
What is a proportion?A proportion is a fraction of a total amount, and this fraction is combined with basic arithmetic operations, especially multiplication and division, to find the desired measures in the context of a problem.
The proportion of her salary that she contributed to the 401(k) plan is of:
4000/40000 = 0.1.
The first 6% of her salary is:
0.06 x 40000 = $2,400.
Hence her employee contributed $2,400 relative to the first 6% of her salary.
For the 4% between 6% and 10%, the employee contributed 50% of her contributions, hence:
0.5 x (4000 - 2400) = 0.5 x 1600 = $800.
Hence the total contribution by the employee is of:
2400 + 800 = $3,200.
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What is the greatest number of acute angles that a triangle can contain?
A.3
B.1
C.0
D.2
Answer:
3
Step-by-step explanation:
We know that the sum of the angles of a triangle is 180
Assume that the angles are equal
x+x+x = 180
3x= 180
x = 180/3 =60
All three angles are less than 90 which makes them acute so we know that we can have 3 acute angles
Henry wants to buy a new table saw for his carpentry shop. he saved $360 which is 2/3 of the price of the saw.how much does the table saw cost?
Answer:
Step-by-step explana
540
What are the solutions to the equation?
x3 – 6x2 – 9x + 54 = 0
Answer:
x = -3 or x = 3 or x = 6
Step-by-step explanation:
x3 – 6x2 – 9x + 54 = 0
There is no common factor to factor out. There are 4 terms. We try factoring by grouping. Factor a common factor out of the first two terms. Factor a common factor out of the last two terms.
x^2(x - 6) - 9(x - 6) = 0
x - 6 is a common factor, so we factor it out.
(x^2 - 9)(x - 6) = 0
x^2 - 9 is the difference of 2 squares, so we factor it.
(x + 3)(x - 3)(x - 6) = 0
x + 3 = 0 or x - 3 = 0 or x - 6 = 0
x = -3 or x = 3 or x = 6
Answer:
x=6 x=3 x=-3
Step-by-step explanation:
x^3 – 6x^2 – 9x + 54 = 0
Factor by grouping
x^3 – 6x^2 – 9x + 54 = 0
x^2(x-6) -9(x-6 ) =0
Factor out x-6
(x-6)(x^2 -9) =0
Notice x^2 -9 is the difference of squares
(x-6)(x-3)(x+3) = 0
Using the zero product property
x-6 =0 x-3 =0 x+3 =0
x=6 x=3 x=-3
How much money should
Answer:
I dont know the question
Step-by-step explanation:
it’s question number 3 and i know the answer but i need someone to explain to me how to get the answer the answer is B. pls can hurry i need the explanation soon
Answer:
2+6=8
Step-by-step explanation:
Start at 2
Then since we are adding 6 move 6 units to the right
Suppose $1,000 was deposited into an account compounded quarterly that grew to $1,490 at rate of 6%. How long did it take for this to occur?
Answer:
A (1 + i)^n = 1490 time for amount to reach 1490
(1 + i)^n = 1.49 since A = $1000
n log (1 + .06/4) = log 1.49 take log of both sides at 1.5% per quarter
n = log (1.49) / log 1.015 = 26.78 periods or 6.695 years
(compare to 6.843 years compounded annually)
[tex]t = ln(A/P) / n[ln(1 + r/n)]\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.06/4)] )\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.015)] )\\t = 6.7 years[/tex]
It would take around 6 years 8 months to get $1,490 from $1,000 at 6%.
I hope I've helped! :)
A croissant shop has plain croissants, cherry croissants, chocolate croissants, almond croissants, apple croissants, and broccoli croissants. How many ways are there to choose 26 croissants with at least one plain croissant, at least two cherry croissants, at least three chocolate croissants, at least one almond croissant, at least two apple croissants, and no more than three broccoli croissants
Answer:
27405
Step-by-step explanation:
There are 6 different variants available for each croissant. There are 26 croissants in all out of which 1 is plain. We use combination and permutation technique to identify different ways to choose croissant.
[5 + 26 - 1 ] 26 = 30C26 = 27405.
If the integer $152AB1$ is a perfect square, what is the sum of the digits of its square root?
9514 1404 393
Answer:
13
Step-by-step explanation:
152AB1 is not a square in hexadecimal, so we assume A and B are supposed to represent single digits in decimal.
If A=B=0, √152001 ≈ 389.9
If A=B=9, √152991 ≈ 391.1
The least significant digit of 152AB1 being non-zero, we know it is not the square of 390. Hence, it must be the square of 391.
For 152AB1 to be a perfect square, we must have ...
152AB1 = 391² = 152881
The sum of the digits of the square root is 3+9+1 = 13.
Find the next three terms of the sequence: 10, 6, 2, .
Answer:
-2,-6,-10
Step-by-step explanation:
What is the distance between U(-1,9) and V(4,7)leave answer in radical form
Answer:
[tex]d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} } \\\\=\sqrt{(4-(-1))^{2}+(7-9)^{2} } \\\\=\sqrt{(5)^{2}+(-2)^{2}} \\\\=\sqrt{25+4} \\\\=\sqrt{29}[/tex]
Will give brainliest answer
Yeahhhh I ain't dat smart
But that's why I got BRAINLY...
Anyways your welcome
Hope u have a good day
The third term of an arithmetic sequence is $5$ and the eighth term is $-20$. What is the product of the 4th and 2015th terms?
Answer:
0
Step-by-step explanation:
Let n be the first term of this sequence and d the difference between two consecutive terms.
Following the arithmetic sequence formula,
The equation for the 3rd term:
n + 2d = 5
and the equation for the 8th term:
n + 7d = -20
We should start by finding d by subtracting the second equation from the first.
n + 2d - (n + 7d) = 5 - (-20)
-5d = 25
d = -5
We can then find the 1st term by plugging this number into the first equation.
n + 2 * -5 = 5
n - 10 = 5
n = 15
Now, using once again the arithmetic sequence formula, find the equation for the fourth term.
n + (4 - 1)*d
Plug in the values we found previously and solve:
15 + (4 - 1)*-5
= 15 + 3*-5
= 15 + (-15)
= 0
The 4th term is 0.
Remember that this problem is asking for the product of the 4th term and the 2015th term, and anything times zero equals to zero, so we don't even need to solve for the 2015th term!
Therefore, the answer to this problem is 0.
The product of the 4th and 2015th terms is 0 if the third term of an arithmetic sequence is 5 and the eighth term is -20.
What is a sequence?It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
We have:
The third term of an arithmetic sequence is 5 and the eighth term is -20
a + 2d = 5
a + 7d = -20
After solving the equations:
a = 15
d = -5
4th term = 15 + 3(-5) = 0
2015th term = 15 + 2014(-5) = -10055
The product of the 4th and 2015th terms = 0(-10055) = 0
Thus, the product of the 4th and 2015th terms is 0 if the third term of an arithmetic sequence is 5 and the eighth term is -20.
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What is the difference between the temperature - 7 Celsius and - 12 Celsius on a scatter diagram
Answer:
I have to go get my car from the doctor office today
John caught a gigantic tuna fish. Every 1/100 of it could fill up a can of tuna fish. How many cans of tuna fish can it make?
Answer:
100
Step-by-step explanation:
if every 1/100 is 1 tuna can you need to multiply the amount of tuna to make a tuna can so it will be 1 so times 100
determine the values of X which the sequence
[tex]log3. \: log {3}^{3}. \: log {3}^{x} [/tex]
is (I) arithmetic (II) geometric
Answer:
arithmetic
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