please help.
find the missing side or angle and each problem .
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Answer:

27405

Step-by-step explanation:

There are 6 different variants available for each croissant. There are 26 croissants in all out of which 1 is plain. We use combination and permutation technique to identify different ways to choose croissant.

[5 + 26 - 1 ] 26 = 30C26 = 27405.

Answer:

Step-by-step explana

540

Carlene's employer's contribution to the 401(k) was of $3,200., using proportions.

A proportion is a fraction of a total amount, and this fraction is combined with basic arithmetic operations, especially multiplication and division, to find the desired measures in the context of a problem.

The proportion of her salary that she contributed to the 401(k) plan is of:

4000/40000 = 0.1.

The first 6% of her salary is:

0.06 x 40000 = $2,400.

Hence her employee contributed $2,400 relative to the first 6% of her salary.

For the 4% between 6% and 10%, the employee contributed 50% of her contributions, hence:

0.5 x (4000 - 2400) = 0.5 x 1600 = $800.

Hence the total contribution by the employee is of:

2400 + 800 = $3,200.

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Answer:

100

Step-by-step explanation:

if every 1/100 is 1 tuna can you need to multiply the amount of tuna to make a tuna can so it will be 1 so times 100

Yeahhhh I ain't dat smart

But that's why I got BRAINLY...

Anyways your welcome

Hope u have a good day

Answer:

3

Step-by-step explanation:

We know that the sum of the angles of a triangle is 180

Assume that the angles are equal

x+x+x = 180

3x= 180

x = 180/3 =60

All three angles are less than 90 which makes them acute so we know that we can have 3 acute angles

9514 1404 393

Answer:

  13

Step-by-step explanation:

152AB1 is not a square in hexadecimal, so we assume A and B are supposed to represent single digits in decimal.

If A=B=0, √152001 ≈ 389.9

If A=B=9, √152991 ≈ 391.1

The least significant digit of 152AB1 being non-zero, we know it is not the square of 390. Hence, it must be the square of 391.

For 152AB1 to be a perfect square, we must have ...

  152AB1 = 391² = 152881

The sum of the digits of the square root is 3+9+1 = 13.

Answer:

2+6=8

Step-by-step explanation:

Start at 2

Then since we are adding 6 move 6 units to the right

Answer: 64000000

Explanation: Why are you named as my ALT-

Answer:

0

Step-by-step explanation:

Let n be the first term of this sequence and d the difference between two consecutive terms.

Following the arithmetic sequence formula,

The equation for the 3rd term:

n + 2d = 5

and the equation for the 8th term:

n + 7d = -20

We should start by finding d by subtracting the second equation from the first.

n + 2d - (n + 7d) = 5 - (-20)

-5d = 25

d = -5

We can then find the 1st term by plugging this number into the first equation.

n + 2 * -5 = 5

n - 10 = 5

n = 15

Now, using once again the arithmetic sequence formula, find the equation for the fourth term.

n + (4 - 1)*d

Plug in the values we found previously and solve:

15 + (4 - 1)*-5

= 15 + 3*-5

= 15 + (-15)

= 0

The 4th term is 0.

Remember that this problem is asking for the product of the 4th term and the 2015th term, and anything times zero equals to zero, so we don't even need to solve for the 2015th term!

Therefore, the answer to this problem is 0.

The product of the 4th and 2015th terms is 0 if the third term of an arithmetic sequence is 5 and the eighth term is -20.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have:

The third term of an arithmetic sequence is 5 and the eighth term is -20

a + 2d = 5

a + 7d = -20

After solving the equations:

a = 15

d = -5

4th term = 15 + 3(-5) = 0

2015th term = 15 + 2014(-5) = -10055

The product of the 4th and 2015th terms = 0(-10055) = 0

Thus, the product of the 4th and 2015th terms is 0 if the third term of an arithmetic sequence is 5 and the eighth term is -20.

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Answer:

The lower bound of the 99% confidence interval for the gift basket's average shipping weight is of 49.34 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 70 - 1 = 69

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 69 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.649

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.649\frac{8.4}{\sqrt{70}} = 2.66[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 52 - 2.66 = 49.34

The lower bound of the 99% confidence interval for the gift basket's average shipping weight is of 49.34 ounces.

Answer:

35

Step-by-step explanation:

7-7(-4)

Using PEMDAS

Multiply first

7 +28

Then add

35

Answer:

x=1

Step-by-step explanation:

5x+37=-6(1-8x)

Distribute

5x+37 = -6 +48x

Subtract 5x from each side

5x+37 -5x = -6+48x-5x

37 = -6+43x

Add 6 to each side

37+6 = -6+43x+6

43 = 43x

Divide by 43

43/43 = 43x/43

1 =x

Answer:

x=1

Step-by-step explanation:

5x+37=-6(1-8×)

5x+37=-6(-7)

5x+37=6 x 7

5x+37= 42

5x+37-37=42-37

5x=5

5x/5 = 5/5

x = 1

Hope it Helps !!

Answer:

5x3 y(5xy-4)

5x3y ×1xy

5x4y2

Answer:

[tex]5 {x}^{3} y[/tex]

step by step

[tex]5 {x}^{3} y(2x + 3y - 4) \\ = 10 {x}^{3}y + 15 {x}^{3} y + 20 {x}^{3} y \\ = 5 {x}^{3} y[/tex]

Answer:

I dont know the question

Step-by-step explanation:

Answer:

arithmetic

hyj

bhhm

bm.hg

hgjm

hgjgshmih

mhh

jhuu

Answer:

see below

Step-by-step explanation:

0 = x^2 + 6x – 10

Add 10 to each side

10 = x^2-6x

Take the coefficient of x

-6

Divide by 2

-6/2 =-3

Square it

(-3)^2 =9

Add 9 to each side

10+9 = x^2-6x+9

We use -3 for the square term

19 = (x-3)^2

Take the square root of each side

±sqrt(19) = x-3

Add 3 to each side

3±sqrt(19) = x

Answer:

-2,-6,-10

Step-by-step explanation:

Answer:

option b

Step-by-step explanation:

both are rectangles and similar measures  

Yes, because both figures are rectangles and all rectangles are similar

The rectangle EFGH is a result of the dilation of rectangle ABCD

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the first rectangle be represented as ABCD

Now , the rectangle is dilated by a scale factor k

And , the transformed rectangle is given by EFGH

where the center of origin is the scale factor of dilation

Now , the ratios of the sides of the rectangles will be similar

So , the rectangles ABCD and EFGH are similar

Hence , the dilated rectangle is EFGH

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Answer:

[tex]d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} } \\\\=\sqrt{(4-(-1))^{2}+(7-9)^{2} } \\\\=\sqrt{(5)^{2}+(-2)^{2}} \\\\=\sqrt{25+4} \\\\=\sqrt{29}[/tex]

Answer:

I have to go get my car from the doctor office today

Answer:

[tex]269 \frac{1}{4} [/tex]

Step-by-step explanation:

the solution is found above in the diagram.

Answer:

Y = (x + 1)^2 - 4

where is

look the Diagram when the line arrow cross to x line got -4 it's mean left side is Negative and reach to y diagram within 1 on positive to below

so the right answer is = Y = (x+1)^2 - 4

////////////////////////

Let X(s) and Y(s) denote the Laplace transforms of x(t) and y(t), respectively. Then taking the transform of both sides of both equations gives

LT[dx/dt + 5x + dy/dt] = LT[1]

==>   s X(s) - x (0) + 5 X(s) + s Y(s) - y (0) = 1/s

==>   s X(s) + 5 X(s) + s Y(s) = 1/s

==>   (s + 5) X(s) + s Y(s) = 1/s

LT[dx/dt - x + dy/dt - y] = LT[exp(t )]

==>   s X(s) - x (0) - X(s) + s Y(s) - y (0) - Y(s) = 1/(s - 1)

==>   s X(s) - X(s) + s Y(s) - Y(s) = 1/(s - 1)

==>   (s - 1) X(s) + (s - 1) Y(s) = 1/(s - 1)

Solve for X(s) and Y(s). Using elimination, you would get

X(s) = (1 - 2s) / (5s (s - 1)²)

Y(s) = (7s - 1) / (5s (s - 1)²)

Now take the inverse transforms of each. Start by getting the partial fraction decompositions:

(1 - 2s) / (5s (s - 1)²) = 1/5 (a/s + b/(s - 1) + c/(s - 1)²)

-2s + 1 = a (s - 1)² + bs (s - 1) + cs

-2s + 1 = (a + b) s ² + (-2a - b + c) s + a

==>   a + b = 0, -2a - b + c = -10, a = 5

==>   a = 1, b = -1, c = -1

==>   X(s) = 1/5 (1/s - 1/(s - 1) - 1/(s - 1)²)

Similarly, you would find

Y(s) = -1/5 (1/s - 1/(s - 1) - 6/(s - 1)²)

Now for the inverse transforms:

LT⁻¹ [1/s] = 1

LT⁻¹ [1/(s - 1)] = exp(t )

LT⁻¹ [1/(s - 1)²] = t exp(t )

Putting everything together, we have

LT⁻¹ [X(s)] = x(t) = 1/5 - 1/5 exp(t ) - 1/5 t exp(t )

and

LT⁻¹ [Y(s)] = y(t) = -1/5 + 1/5 exp(t ) + 6/5 t exp(t )

Answer:

mean ≈ 25.45

Step-by-step explanation:

mean is calculated as

mean = [tex]\frac{sum}{count}[/tex]

We require the sum for both classes

class A

mean = [tex]\frac{sum}{9}[/tex] = 40 ( multiply both sides by 9 )

sum = 9 × 40 = 360

class B

mean = [tex]\frac{sum}{24}[/tex] = 20 ( multiply both sides by 24

sum = 24 × 20 = 480

Total sum for both classes = 360 + 480 = 840 , then mean for both classes is

mean = [tex]\frac{840}{33}[/tex] ≈ 25.45 ( to 2 dec. places )

Answer:

A (1 + i)^n = 1490    time for amount to reach 1490

(1 + i)^n = 1.49    since A = $1000

n log (1 + .06/4) = log 1.49       take log of both sides at 1.5% per quarter

n = log (1.49) / log 1.015  = 26.78 periods or 6.695 years

(compare to 6.843 years compounded annually)

[tex]t = ln(A/P) / n[ln(1 + r/n)]\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.06/4)] )\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.015)] )\\t = 6.7 years[/tex]

It would take around 6 years 8 months to get $1,490 from $1,000 at 6%.

I hope I've helped! :)

Answer:

w =-4

Step-by-step explanation:

4w = 2w - 8

Subtract 2w from each side

4w-2w = 2w-2w - 8

2w = -8

Divide by 2

2w/2 = -8/2

w = -4

Answer:

x = -3  or x = 3  or x = 6

Step-by-step explanation:

x3 – 6x2 – 9x + 54 = 0

There is no common factor to factor out. There are 4 terms. We try factoring by grouping. Factor a common factor out of the first two terms. Factor a common factor out of the last two terms.

x^2(x - 6) - 9(x - 6) = 0

x - 6 is a common factor, so we factor it out.

(x^2 - 9)(x - 6) = 0

x^2 - 9 is the difference of 2 squares, so we factor it.

(x + 3)(x - 3)(x - 6) = 0

x + 3 = 0  or  x - 3 = 0  or x - 6 = 0

x = -3  or x = 3  or x = 6

Answer:

x=6     x=3   x=-3

Step-by-step explanation:

x^3 – 6x^2 – 9x + 54 = 0

Factor by grouping

x^3 – 6x^2     – 9x + 54 = 0

x^2(x-6)    -9(x-6 ) =0

Factor out x-6

(x-6)(x^2 -9) =0

Notice x^2 -9 is the difference of squares

(x-6)(x-3)(x+3) = 0

Using the zero product property

x-6 =0    x-3 =0   x+3 =0

x=6     x=3   x=-3

Answer:

yes

Step-by-step explanation:

3/9  Divide the top and bottom by 3

1/3

5/15 Divide the top and bottom by 5

1/3

They are equal