PLEASE HELPPP
A perfume bottle is in the shape of a cone. Its diameter is 13 centimeters and its height is 21 centimeters. What is the volume of the perfume bottle? Round to the nearest tenth.

Answer:

demographic

Step-by-step explanation:

That is the same as writing [tex]10\sqrt{30}[/tex]

======================================================

Explanation:

The diagram shows that

That must mean DC = AC-AD = 60-50 = 10

We'll use this to help find BD as shown below

AD/BD = BD/DC

AD*DC = BD*BD .... cross multiply

(BD)^2 = AD*DC

BD = sqrt(AD*DC) ..... geometric mean formula

BD = sqrt(50*10)

BD = sqrt(500)

----------------------

Now apply the pythagorean theorem to find AB. Focus on triangle ABD.

(AD)^2 + (BD)^2 = (AB)^2

(AB)^2 = (AD)^2 + (BD)^2

(AB)^2 = (50)^2 + (sqrt(500))^2

(AB)^2 = 2500 + 500

(AB)^2 = 3000

AB = sqrt(3000)

AB = sqrt(100*30)

AB = sqrt(100)*sqrt(30)

AB = 10*sqrt(30)

Answer:

The Answer to the Ultimate Question of Life, the Universe, and Everything is 42

Step-by-step explanation:

In this equation, the number 42 is called a minuend.

15 is a subtrahend because it is being subtracted from another number.

The number 27 would be called the difference.

Answer:

The answer is "Option B".

Step-by-step explanation:

Please find the complete question in the attached file.

The Horizontal stretch [tex]=(\frac{1}{6 \ x})\\\\[/tex]

Translation by 5 units right[tex]=( \frac{1}{6\ x})-5[/tex]

Answer:

its A i used his answer and got it wrong

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

Answer:

1866.11 m²

Step-by-step explanation:

Formula = 2πrh + 2πr²

Surface area = 2 * 3.14 * 9 * 24 + 2*3.14* 81 ≈ 1866.11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

midpoint= (x, y)

where x=(x1 + x2)/2

y=(y1 + y2)/2

x1=-3, x2=6, y1=5, y2=-11

so x=(-3 + 6)/2= 3/2

y=(5 + -11)/2= (5-11)/2= -6/2= -3

so mid point =(3/2, -3)

hope this helps

The exact value of cos(13π/8) is 1/2 [tex]\sqrt{2-\sqrt{2} }[/tex].

Trigonometriic ratios are the ratios of the sides of a right angled triangle. sin , cos, tan, sec, cosec, cot are some of the trigonometric ratios. Sin is the ratio of perpendicular and hypotenuse, cos is the ratio if base and hypotenuse, tan is the ratio of perpendicular and base, secant is the ratio of hypotenuse and base, cosecant is the ratio of hypotenuse and perpendicular, cot is the ratio of base and perpendicular.

We have to find the value of cos (13π/8).

We have to use formula which is following:

cos[tex]Θ[/tex]=[tex]\sqrt{1/2(1+cos 2Θ}[/tex]

=[tex]\sqrt{1/2(1+cos(2*13 π/8)}[/tex]   (π=[tex]π[/tex])

=[tex]\sqrt{1/2(1+cos(3 π+π/4)}[/tex]

=[tex]\sqrt{1/2(1-cos(π/4)}[/tex]

=[tex]\sqrt{1/2(1-1/\sqrt{2} }[/tex]

=[tex]\sqrt{\sqrt{2}-1/2\sqrt{2} }[/tex]

=1/2[tex]\sqrt{2-\sqrt{2} }[/tex]

Hence the value of cos (13π/8) is [tex]1/2\sqrt{2-\sqrt{2} }[/tex].

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Answer:

Step-by-step explanation:

Answer:

$1080

Step-by-step explanation:

I think I am not sure

Answer:

Step-by-step explanation:

The graph of f(x) = –x^2 + 5 is that of an upside-down parabola with vertex (0, 5) and x-intercepts (-√5, 0) and (+√5, 0).  Plot the vertex (0, 5) and then draw a smooth curve through it and through the x-intercepts.

The function f(x) = -x2+5 is thus represented by the quadratic functions in the first graph.

A quadratic function has the formula f(x) = ax2 + bx + c, with a, b, and c being integers and a not equal to zero.  Parabolas can have openings that are upward or downward, different "widths" or "steepnesses," but they all share the same fundamental "U" shape.

here calculation

The function provided is f(x) =  -x2+5

.... (1) (1)

We must locate the function's graph.

The quadratic function's vertex form is f(x)= a(x-h)2 + k.... (2)

When we compare (1) and (2), we obtain

h=0 , k=5

It denotes that the function's vertex is (0,5).

The values list is

x           y

-2            1

-1            4

0            5

1            4

2           1

Place all ordered pairings on a coordinate plane, and then use a free-hand curve to link them.

The function f(x) = -x2+5 is thus represented by the quadratic functions in the first graph.

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Answer:

−7.361097448

Step-by-step explanation:

Answer:

2821.51

73425.64

28124.24

4124.24

Step-by-step explanation:

Effective rate: .058/2 = .029

This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

[tex]175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511[/tex]

interested earned:

175000-2821.51*36= 73425.64

2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

[tex]400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24[/tex]

Interest earned: 28124-400*60=4124.24

Answer:

First problem: monthly payment $2741.99; interest earned $76,288.36

Second problem: amount in account $28,271.90; interest earned $4271.90

Step-by-step explanation:

First problem:

You open an account with a deposit. The deposit is the first monthly payment. This means that this is an annuity in which you pay at the beginning of the pay period. That makes it into an "annuity due."

[tex] A = \dfrac{F}{\frac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

where A = periodic payment,

F = future value

i = interest rate per compounding period, n = number of compounding periods

[tex]A = \dfrac{175000}{\frac{(1 + \frac{0.058}{2})^{2 \times 18} - 1}{\frac{0.058}{2}} \times (1 + \frac{0.058}{2})}[/tex]

[tex] A = 2741.99 [/tex]

Interest earned:

[tex] 2 \times 18 \times 2741.99 - 175000 = 76288.36 [/tex]

Second problem:

Once again, the account starts with a deposit of the monthly payment, so this is also an annuity due, meaning the payments occur at the beginning of each compounding period. Here, we are given the monthly payment, an d we need to find the future value.

[tex] F = A \times \dfrac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

[tex] F = 400 \times \dfrac{(1 + \frac{0.063}{12})^{5 \times 12} - 1}{\frac{0.063}{12}} \times (1 + \frac{0.063}{12})} [/tex]

[tex] F = 28271.90 [/tex]

The interest earned is:

[tex] 28271.90 - 12 \times 5 \times 400 = 4271.90 [/tex]

Answer:

[tex]x^2 + y^2 = 52[/tex]

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Equation of a circle:

The equation of a circle with center [tex](x_0,y_0)[/tex] and radius r has the following format:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

Center at the origin;

This means that [tex]x_0 = 0, y_0 = 0[/tex]

So

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

[tex](x - 0)^2 + (y - 0)^2 = r^2[/tex]

[tex]x^2 + y^2 = r^2[/tex]

Passes through (4, 6)

The radius is the distance from this point to the center. So

[tex]r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]r = \sqrt{(4-0)^2+(6-0)^2}[/tex]

[tex]r = \sqrt{16+36}[/tex]

[tex]r = \sqrt{52}[/tex]

So

[tex]r^2 = 52[/tex]

Then

[tex]x^2 + y^2 = r^2[/tex]

[tex]x^2 + y^2 = 52[/tex]

Step-by-step explanation:

the other answer is correct.

just for a little bit of explanation :

the first position after the decimal point is for tenths. the second position for hundredths. the third for thousandths. then ten-thousandths, hundred-thousandths, millionths, ...

so, you would need 1000 thousandths to have a 1 at the first position before the decimal point. everything less than that has to be a number after the decimal point. and thousandths have to end (writing from left to right) with the thousandths-position. hundredths with the hundredths-position and so on.

Answer:

A) 60

Step-by-step explanation:

P = 5+5+11+9+(5+11)+(9+5)

P = 60

Answer:

A. 60 m

Step explanation:

Perimeter for the small cube

5+5+5+5=20

Perimeter for the rectangle

9+9+11+11=40

Add 20 plus 40 to find the perimeter for the whole shape

20+40=60

Hope this helps

mid point =((4+(-4))/2,(-5+5)/2)

=(0,0)

The midpoint between the points (4, -5) and (-4, 5) is (0, 0).

To find the midpoint between two points ([tex]x_1, y_1[/tex]) and ([tex]x_2, y_2[/tex]), you can use the midpoint formula:

Midpoint = [tex]((x_1+ x_2)/2, (y_1+ y_2)/2)[/tex]

In this case, the two points are (4, -5) and (-4, 5).

So, the midpoint using the formula:

[tex]x_1[/tex] = 4

[tex]y_1[/tex] = -5

[tex]x_2[/tex]= -4

[tex]y_2[/tex] = 5

Midpoint

= ((4 + (-4)) / 2, (-5 + 5) / 2)

= (0 / 2, 0 / 2)

= (0, 0)

Therefore, the midpoint between the points (4, -5) and (-4, 5) is (0, 0).

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Answer:

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

Step-by-step explanation:

Given the data in the question;

Hypothesis;

Null hypothesis             : H₀ : Car accidents are equally distributed throughout the year

Alternative hypothesis : Hₐ : Car accidents are NOT equally distributed throughout the year

significance level ∝ = 0.05

x ;

Spring = 27

Summer = 39

Fall = 31

Winter = 53

Test Statistics;

Chi Square = ∑[ (O – E)²/E ]

                         O               E                   (O – E)²/E

Spring               27            37.4                2.94

Summer            39            37.4                0.06

Fall                    31             37.4                1.1267

Winter               53            37.4                6.4067

Total                 150           150                 10.5334

so; z = ∑[ (O – E)²/E ] = 10.5334

{from table}

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

In this exercise we have to use probability knowledge to calculate the distribution during the year, so we find that:

There is sufficient evidence to conclude that car accidents are not equally distributed throughout the year.

Given the data in the question;

Now the values ​​given in the statement can be exemplified below as:

In this way, we can assemble a table of values ​​with the statistical data previously informed and using the formula given below:

[tex]Z=\sum[\frac{(O-E)^2}{E}][/tex]

[tex]Z = 10.5334[/tex]

So:

[tex]\ \ \ \ \ \ \ \ \ \ \ O \ \ \ \ \ E \ \ \ \ (O - E)^2/E\\Spring \ \ 27 \ \ 37.4 \ \ \ \ 2.94\\Summer \ 39 \ 37.4 \ \ \ \ 0.06\\Fall \ \ \ \ \ \ 31 \ 37.4 \ \ \ \ 1.1267\\Winter \ \ \ 53 \ 37.4 \ \ \ 6.4067\\Total \ 150 150 \ 10.5334[/tex]

Hence, Since pvalue ( 0.0145 ) is less than significance level ( 0.05 ), so we reject null hypothesis.

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Answer:

12 ft

Step-by-step explanation:

we know the areas of the 2 top squares.

the area of a square is simply the square of its side length.

=>

81 ft² means side length is 9 ft.

225 ft² means side length is 15 ft.

these are also 2 of the sides of the right triangle.

the third side we get by using Pythagoras :

c² = a² + b²

with c being the side opposite of the 90 degree angle.

so,

225 = 81 + x²

as x is also the third side of the triangle.

=> 144 = x²

x = 12 ft

Answer:

surface area of the triangular pyramid

=(1/2×9×7.8)+(3×1/2×9×12.3)

=35.1+166.05

=201.15 inch²

Answer: The company will recognize commission expense in the amount of $2,400 in December

Step-by-step explanation:

Based on the information given in the question, the company will recognize commission expense in the amount of $2,400 in December.

A commission is regarded as a fee which is paid to a salesperson by a company in exchange for completing a sale.

It should be noted that in the accrual basis of accounting, commission should be recorded in the same period as when the sale generated was generated.

Answer:

b. The company will recognize commission expense in the amount of $2,400 in December.

Step-by-step explanation:

Based on the information given the statements that is true will be: THE COMPANY WILL RECOGNIZE COMMISSION EXPENSE IN THE AMOUNT OF $2,400 IN DECEMBER reason been that each salesperson were paid a commission in the amount of $800 for each cycle sold, which is 3 cycles during the month of December.

Calculation to determine the Commission Expense

Commission Expense=$800*3 cycles

Commission Expense=$2,400

Therefore The company will recognize commission expense in the amount of $2,400 in December.

Answer:

Step-by-step explanation:

Answer:

348 kiwis

Step-by-step explanation:

Jamie is packing Kiwie fruits into a tray

Each tray holds 58 kiwis

He can put 6 trays in a crate

Hence when the craye is full the number of kiwis it will contain can be calculated as follows

°= 58×6

= 348 kiwis

Answer:

4.2 hours

Step-by-step explanation:

Answer:

wat

Step-by-step explanation:

Answer:

11. (a) 3/4+1/2=5/4

   (b) 4/5= 8/10 , 16/20

12. 8 children don't like choc ice cream

Step-by-step explanation:

11. 3/4 +2/4=5/4(change 1/2 by making it the same as the one next to it)

12. 3/5 of 20 = 12

     20-12=8

Answer:

21.161

Step-by-step explanation:

use Pythagoras theorem ti find your slant height

then you use your formula which

[tex]1 \3\pi {r }^{2} h[/tex]

Answer:

Volume of cone = 686π/3 or 718.67 in³

Step-by-step explanation:

Given the following data;

Radius, r = 7 in

Height, h = 14 inches

From the diagram, we can see that the object is a cone

To find the volume of a cone;

Mathematically, the volume of a cone is given by the formula;

[tex] V = \frac{1}{3} \pi r^{2}h[/tex]

Where;

V is the volume of the cone.

r is the radius of the base of the cone.

h is the height of the cone.

Substituting into the equation, we have;

[tex] Volume = \frac{1}{3} * \frac {22}{7} *7^{2}*14 [/tex]

[tex] Volume = \frac{1}{3} * 22 * 7 * 14 [/tex]

[tex] Volume = \frac{1}{3} * 2156 [/tex]

[tex] Volume = 718.67 [/tex]

Volume of cone = 718.67 in³ or 686π/3 in³

Hi there!  

»»————-　★　————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]{ \tt{y = x + 2 - - - (a)}} \\ { \tt{ {x}^{2} + {y}^{2} = 10 - - - (b) }} \\ substitute \: for \: y \: in \: (b) : \\ { \tt{ {x}^{2} + {(x + 2)}^{2} = 10 }} \\ { \tt{ {x}^{2} + {x}^{2} + 4x + 4 = 10 }} \\ { \tt{2 {x}^{2} + 4x - 6 = 0}} \\ { \tt{ {x}^{2} + 2x - 3 = 0 }} \\ { \boxed{ \bf{x = 1 \: and \: - 3}}} \\ in \: (a) : \\ y = x + 2 \\ { \boxed{ \bf{y = 3 \: and \: - 1}}}[/tex]