Answers
Answer: The second bubble thing is correct you have picked the wrong one.
Related Questions
what is the answer to this question: 3.75x =60
Answers
Answer:
x = 16
Step-by-step explanation:
If 3.75x would equal to 60, then x would equal to 60/3.75, which would be 16
Hope this helps!
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answers
A= 1029
B=7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
Answers
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
The greatest possible number whose digits are all even numbers from 1 to 9
Answers
Answer:
8642Step-by-step explanation:
Our even numbers from 1-9 are:
2,4,6,8The largest possible number using the even numbers once is 8642.
Hoped this helped
Which expression is equal to 3x/x+3+x−2/x
Answers
Answer: 6+x−2/x
Step-by-step explanation:
3x/x+3+x−2/x
3+3+x−2/x
6+x−2/x
================
Or, if you love crazy fractions:
3x/x+3+x−2/x
3x/x−2/x+3+x
(1/x)(3x−2)+3+x
the sum of three whole numbers in a row is 57. what are the three numbers?
Answers
Answer:
18, 19, 20
Step-by-step explanation:
(n) + (n + 1) + (n + 2) = 57
3n + 3 = 57
3n = 57 - 3 = 54
n = 54/3 = 18
three numbers are 18, 18+1, 18+2
18, 19, 20
Answer:
18,19,20
Step-by-step explanation:
x + (x+1) + (x+2) = 57
x + x + 1 + x + 2 = 57
Combine like terms
3x + 3 = 57
subtract 3 from both sides
3x = 54
divide both sides by 3
x = 18
The answer is 18, 19, 20
Since we know the value of x, we can look at it like this:
x + (x+1) + (x+2) --- > 18 + (18+ 1) + (18+2) --> 18 + 19 + 20
the common multiple of 4 and 20 is? a.3 b.4 c.8 d.20
Answers
Answer:
i belive its A
Step-by-step explanation: hope this helps :)
Answer:
B. 4
Step-by-step explanation:
4 times 5 is 20 and 20 divided by 5 is 4
Can someone help plz
Answers
Can someone help me with this please
Answers
Answer:
y=1/2x
Step-by-step explanation:
Answer:
10
9
8
7
6
5
4
3
2
1
0 1 2 3 4 5 6 7 8 9 10
Step-by-step explanation:
So the arrow is pointing at 10 and 5
Answer 10 5
Not 5
its 10 5
So the answer is 10 5
Can someone help’ it’s due today pls help pls pls
Answers
Answer:
MQP = 138
Step-by-step explanation:
Since the angle bisector always divides the angle in half exactly, we know both of the angle measures we have are the same, and set it up like this: 5x + 19 = 2x + 49 (subtract 2x from both sides) 3x + 19 = 49 (subtract 19 on both sides) 3x = 30 (divide by 3) x = 10
Substitute that x value (10) into the original equations in place of x for each angle to get MQN = 69 and NQP = 69
Add the two values to get 138. MQP = 138
Answer:
138
Step-by-step explanation:
QN bisects ∠MQP. ⇒ ∠MQN = ∠NQP
5x + 19 = 2x + 49
Subtract 19 from both sides
5x = 2x + 49 - 19
5x = 2x + 30
Subtract 2x from both sides
5x -2x = 30
3x = 30
x = 30/3
x = 10
∠MQN = 5x + 19
= 5*10 + 19
= 50 +19
= 69
∠MQP = ∠MQN +∠NQP = 69 + 69 = 138
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Answers
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
Jonnell has finished 20% of an art project that has taken him a total of 3 hours so far. If he continues to work at the same rate, how many hours will it take for him to complete the entire project?
Answers
Answer:
15 hours
Step-by-step explanation:
20%=3 hours
times 5 both sides
100%=15 hours
Which of the following is true?
|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5
Answers
Answer:
|-4| < |-5|
Step-by-step explanation:
because if modules is given sub sign will be deducate
Jonas has bought three t-shirts. Each t-shirt was the same price. After using a 10% off coupon the total charge was 95 what was the cost of each t-shirt
Answers
Answer:
35 5/27
Step-by-step explanation:
You just have to set up an equation:
0.9/95 = 1/x
And if you cross-multiply, you get:
0.9x=95
Which means x is 95/0.9 which is 105 5/9. So, if all three t-shirts costed 105 5/9, and they all costed the same, then one t-shirt costs 35 5/27.
In each bouquet of flowers, there are 2 roses and 5 white carnations. Complete the table to find how many roses and carnations there are in 4 bouquets of flowers.
Answers
Answer:
28roses 70carnations
Step-by-step explanation:
4+6+8+10=28
10+15+20+25=70
Maybe i think
6p - 5 =13
3
-3
12
15
Answers
Answer:
6p=13+5
6p=18
p=18/6
p=3
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answers
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
solve pls brainliest
Answers
Answer:
[tex]18 {m}^{2} [/tex]
Step-by-step explanation:
[tex]area \: = 6m \times 4m \\ = 24 {m}^{2} \\ \\ grass \: area = 3m \times 2m \\ = 6 {m}^{2} \\ \\ cement \: area \: = 24 {m}^{2} - 6 {m}^{2} \\ = 18 {m}^{2} [/tex]
Answer:
18 m^2
Step by step explanation:
In these types of math problems, we have two ways to solve.
1) Directly find the area of the shaded area.
2)Find the unshaded area and then minus that from the total area.
In this case, I will use the second way.
The grass area (unshaded) is 3 x 2 = 6 m^2 ( 6 square meters )
The total area (grass + cement) is 4 x 6 = 24 m^2 ( 24 square meters )
Now, we want the area of the cement part but the grass's area is also in the total.
So, we minus 6m^2 from 24m^2.
Then we get 18m^2.
And that is the answer.
I hope it helps.
(Note : because this problem is easy, you can use both ways but most use the second way. There may also be problems where we can use only the first or second way.)
Help me this question is so hard i fried up my brain yesterday working on it for so long!!!!
Answers
Hello there! (:
The answer is 9.
3^4=3*3*3*3 (81)
3^2=9
81:9=9
So the answer is 9.
Hope it helps! If you have any question or query, feel free to ask! (:
~An excited gal
[tex]SparklingFlower[/tex]
BRAINLIEST, 5 STARS, AND A THANKS FOR WHOEVER HELPS!
Which statement about the answer to this problem is most accurate?
5\6−3\8=19\24
The answer 19\24 is reasonable because both fractions are closer to 1\2 than they are to 1, making the difference close to 0.
The answer 19\24 is reasonable because 5\6 and 3\8 are both closer to 1 than to 1\2, making the difference close to 0.
The answer 19\24 is not reasonable because 5\6 is closer to 1 than to 1\2, and 3\8 is close to 1\2, making the difference close to 1\2.
The answer 19\24 is not reasonable because 5\6 is closer to 1\2 than to 1, and 3\8 is closer to 0 than to 1\2, making the difference close to 1\2.
Answers
Answer:
The answer 19\24 is not reasonable because 5\6 is closer to 1 than to 1\2, and 3\8 is close to 1\2, making the difference close to 1\2.
Step-by-step explanation:
Answer:
1/2 1 0
Step-by-step explanation:
Express the tan G as a fraction in simplest terms.
Answers
Answer:
[tex]\frac{\sqrt{70} }{5}[/tex]
which rotation about its center will carry a regular hexagon onto itself
Answers
(2x+y)2-y2 if x=-3 y=4 and z=-5
Answers
-12
Hope this helps!
pasagot po please
answer it please
Answers
Answer:
24 I hope help you yieeeeeee
Answer:
ummmmmmmmmmm itsssssssss
Step-by-step explanation:
Find the perimeter of a rectangle whose length is 12 longer than its width
with an area of 45 square feet. To earn 5 points write the mathematical
sentence, the value of Length, width and perimeter
Answers
Answer:
l = 21
w = 9
P = 60
Step-by-step explanation:
l = 12 + w
A = l*w = 45
substitute l = 12 +w
45 = (12 + w) * w
45 = 12w + w^2
w^2 + 12w - 45 = 0
w^2 + 2*6*w +36 = 45 + 36 (added 36 on both sides 6^2)
(w + 6) ^2 = 45+36 = 81
w + 6 = +-9
As width cannot be negative w = 9
so l = 12 + 9
= 21
Perimeter = P = 2 (l + b)
= 2 ( 21 + 9)
= 2 (30)
= 60
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
Answers
It a acute
Hope this help you :)
what is the awnser and solve for C
2c=6–3c
Answers
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
[tex]\fbox \colorbox{black}{ \colorbox{white}{C} \: \: \: \: \: \: \: \: \colorbox{white}{ = } \: \: \: \: \: + \colorbox{white}{6/5}}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
Let's find the value of c ~
[tex]2c = 6 - 3c[/tex][tex]2c + 3c = 6[/tex][tex]5c = 6[/tex][tex]c = \dfrac{6}{5} \: \: or \: \: 1.2[/tex]Answer:
c= -6
Step-by-step explanation:
2c -6 = 3c
we move all to the left
2c -6 (3c)= 0
add everything and the variables
-1c - 6 = 0
move all terms containing c to the left everything else to the right
-1c = 6
c=6/-1
c=-6
What is 8 times larger than 3
Answers
8 x 3 = 24 for should be 24
Only because 8 times larger than three seems like a multiplication problem..
I hope this helps if it is correct!
Answer:
(8+1) x 3 = 27
Step-by-step explanation:
this is correct rather than 8 x 3 = 24 because both sides of 8x3=24 are equal rather than the sum being greater than the statement.
HELP ME OUT PLEASE!!!
WILL GIVE BRAINLIEST!!!
Answers
Answer:
-4 9/10, -4 3/4, -4.2
Step-by-step explanation:
A. -4.9
B. -4.75
C. -4.2
ANSWER:
-4 9
10
-4 3
10
-4.2
Step-by-step explanation:
HOPE IT HELPSSSS
what's the slope (3,-1) and (-2,5)
Answers
Answer:
slope = - [tex]\frac{6}{5}[/tex]
Step-by-step explanation:
Calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (3, - 1 ) and (x₂, y₂ ) = (- 2, 5 )
m = [tex]\frac{5-(-1)}{-2-3}[/tex] = [tex]\frac{5+1}{-5}[/tex] = [tex]\frac{6}{-5}[/tex] = - [tex]\frac{6}{5}[/tex]
