Please solve the question below 4

Answer:

The amount to be paid for insurance will be $ 937,500. In this context, it is reasonable that insurance costs increase proportionally, as the ride will have a greater use and, therefore, a greater exposure to risk.

Step-by-step explanation:

Given that the amusement park Diablo's Domain ride generated $ 250,000,000 in revenue, and the company paid $ 750,000 in insurance for that game ($ 3 for every $ 1,000 in profit), to determine the amount of insurance that should be paid if the winnings increase by 25% and the same proportion of 3/1000 to be paid is maintained, the following calculation must be made:

(250,000,000 x 1.25) x (3/1000) = X

312,500,000 x 0.003 = X

937,500 = X

Therefore, the amount to be paid for insurance will be $ 937,500.

(a) For some given x, A(x) gives the signed area under f(t) on the interval [a, x]. Since f(t) is simple to integrate, and with a = 2, you can compute it exactly:

A(x) = ∫₂ˣ f(t) dt

A(x) = ∫₂ˣ (3t + 2) dt

A(x) = (3/2 t ² + 2t ) |₂ˣ

A(x) = 3/2 x ² + 2x - 10

which is parabolic and easy to graph.

(b) Differentiating A(x) is also easy if you use the "closed" form above:

A'(x) = (3/2 x ² + 2x - 10)'

A'(x) = 3x + 2

and this function tells you how the area under f(t) changes as you adjust the size of the integration interval.

You can get the same result using the fundamental theorem of calculus:

A'(x) = d/dx ∫₂ˣ f(t) dt = f(x) = 3x + 2

Answer:

The first step is to slove the numbers in the brackets

Step-by-step explanation:

[(x+7) x -2] / 4 = 7

-2(x+7) / 4 = 7

-2x-14 / 4 = 7

-2x-14 = 28

-2x = 42

x = -21

PEMDAS

Answer:

z = 25

Step-by-step explanation:

adjacent angles in a rhombus are supplementary

3z - 15 + 7z - 55 = 180

10z - 70 = 180

10z = 250

z = 25

Answer:

please refer to the above attachment

Answer:

the probability of a client owning stocks OR bonds is 0.825

Step-by-step explanation:

The computation of the probability of a client owning stocks OR bonds is given below:

= P(stocks) + P(bonds) - P(stocks and bonds)

= 0.60 + 0.50 - (0.55 × 0.50)

= 0.60 + 0.50 - 0.275

= 0.825

Hence, the probability of a client owning stocks OR bonds is 0.825

Answer:

46.2

Step-by-step explanation:

46.188= 46.2

Answer:

D :)

Step-by-step explanation:

Answer:

Scale factor = 1.5

Step-by-step explanation:

Formula for the scale factor,

Scale factor = [tex]\frac{\text{Measure of one side of the Image}}{\text{Measure of one side of the preimage}}[/tex]

In this question, image is triangle Y and preimage is triangle X.

Scale factor of X to Y = [tex]\frac{15}{10}[/tex]

                                    = 1.5

Therefore, scale factor = 1.5 is the answer.

Answer:

1/8

Step-by-step explanation:

That's the same assignment I have and you just have to think it through mate.

Answer:

A 4040 bag sample 25.0425.0 grams. A level of significance of 0.020.02

the decision rule. Assume the standard deviation is known to be 11.011.0.

Step-by-step explanation:

Answer:

x = 2, y = 13

(2, 13)

Step-by-step explanation:

hope this helps!

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle ([tex]a[/tex], [tex]b[/tex], [tex]c[/tex]), but all angles are unknown ([tex]A[/tex], [tex]B[/tex], [tex]C[/tex]). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that [tex]a = 19[/tex], [tex]b = 16[/tex] and [tex]c = 11[/tex], then the missing angles are, respectively:

Angle A

[tex]a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A[/tex] (1)

[tex]A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)[/tex]

[tex]A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right][/tex]

[tex]A \approx 87.395^{\circ}[/tex]

Angle B

[tex]b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B[/tex] (2)

[tex]B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)[/tex]

[tex]B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right][/tex]

[tex]B\approx 57.271^{\circ}[/tex]

Angle C

[tex]C = 180^{\circ}-A-B[/tex]

[tex]C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}[/tex]

[tex]C = 35.334^{\circ}[/tex]

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.