Please someone answer this asap

Answer:

Ionization Energy = 9 eV

Explanation:

If we apply the law of conservation of energy to the given situation, we will get the following equation:

[tex]Energy\ of\ Photon = Ionization\ Energy + Kinetic\ Energy\ of\ Electron\\[/tex]

where,

Energy of Photon = 10 eV

Ionization Energy = ?

Kinetic Energy of Electrons = 1 eV

Therefore,

[tex]10\ eV = Ionization\ Energy + 1\ eV\\Ionization\ Energy = 10\ eV - 1\ eV[/tex]

Ionization Energy = 9 eV

Answer:

2200 L

Explanation:

There are 22.4 L in 1 mole of neon so if you have 98.2 L, then you have 98.2 mole x (22.4 L/mole) = 2200 L of neon.

Answer:

D

Explanation:

D is the answer because 2 is needed to know

Answer:

B) 3 and 7

Explanation:

i just took the test

The temperature of a gas sample rises, the molecules quicken, and as a result, the root mean square molecular speed rises.

Degree of warmth or coolness determined by a specific scale

The temperature of a gas sample rises, the molecules quicken, and as a result, the root mean square molecular speed rises.

In a gas, the speed of the molecules is inversely related to the molar mass of the gas and inversely proportional to temperature.

The rate of diffusion is inversely related to the square root of the gas's molar mass, according Graham's law of Diffusion.

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# SPJ2

Answer:

28.466256

Explanation:

answerA) 100 mL

Explanation:

At constant temperature and number of moles, Using Boyle's law  

Given ,  

V₁ = 200 mL

V₂ = ?

P₁ = 60 kPa

P₂ = 120 kPa

The new volume of the gas is 100mL

Boyle's law is use to calculate the volume of a gas in relation with its pressure. The Boyle's law equation is as follows:

P1V1 = P2V2

Where;

P1 = initial pressure of the gas (torr)

P2 = final pressure of the gas (torr)

V1 = initial volume of the gas (mL)

V2 = final volume of the gas (mL)

According to the information of this question, the pressure on 200mL of a gas changed from 380 torr to 760 torr. Hence;

V1 = 200mL

V2 = ?

P1 = 380torr

P2 = 760torr

Using P1V1 = P2V2

V2 = P1V1/P2

V2 = (380 × 200) ÷ 760

V2 = 76000 ÷ 760

V2 = 100mL

Hence, the new volume of the gas is 100mL

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Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

The energy of a photon can be calculated from Planck's equation E = hc/λ

Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s

Energy of one mole of photons = N₀ × hc/λ

wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m

Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷

Energy of one mole of photons = 2.30 × 10⁵ J/mol

Energy required to raise the temperature of a given mass of a substance, E = mcΔT

Where m is mass of substance,  c is specific heat capacity,  ΔT is temperature difference

Mass ofnwternin the pool = volume × density

Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30

Energy required = 1.16 × 10¹⁰ J

Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol

Number of moles of photons required = 5.04 × 10⁴ moles

Answer:

CO2 + MgO

Explanation:

We want the number of each element on the Reactants (Left side) to be equal to the number of each element on the Product side (Right side).

Answer:

I don't understand the question

Explanation:

what is your name

Answer:

1. 2 M

2. 2 M

Explanation:

1. Determination of the final concentration.

Initial Volume (V₁) = 2 L

Initial concentration (C₁) = 6 M

Final volume (V₂) = 6 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

6 × 2 = C₂ × 6

12 = C₂ × 6

Divide both side by 6

C₂ = 12 / 6

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

2. Determination of the final concentration.

Initial Volume (V₁) = 0.5 L

Initial concentration (C₁) = 12 M

Final volume (V₂) = 3 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

12 × 0.5 = C₂ × 3

6 = C₂ × 3

Divide both side by 3

C₂ = 6 / 3

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

Answer: New volume of the solution is 100 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 3 mL,     [tex]M_{1}[/tex] = 200 M

[tex]M_{2}[/tex] = 6 M,     [tex]V_2[/tex] = ?

Formula used to calculate the new volume of solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]

Thus, we can conclude that new volume of the solution is 100 mL.

Answer:

[tex]m_{Pb(NO_3)_2}^{leftover}=38.34g[/tex]

Explanation:

Hello there!

In this case, given the chemical reaction by which the sodium chloride reacts with lead (II) nitrate and the former is the limiting reactant, it is possible to calculate the mass of lead (II) nitrate that are actually consumed according to the 2:1 mole ratio between them:

[tex]m_{Pb(NO_3)_2}=15.3gNaCl*\frac{1molNaCl}{58.44gNaCl}*\frac{1molPb(NO_3)_2}{2molNaCl} *\frac{331.21gPb(NO_3)_2}{1molPb(NO_3)_2} \\\\m_{Pb(NO_3)_2}=43.36gPb(NO_3)_2[/tex]

Thus, the leftover of lead (II) nitrate is:

[tex]m_{Pb(NO_3)_2}^{leftover}=81.70g-43.36g\\\\m_{Pb(NO_3)_2}^{leftover}=38.34g[/tex]

Best regards!

Answer:

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂

Answer:

The main similarity between carbohydrates, proteins and fats is that they are all used for energy.

Explanation:

I hope this helps, have a blessed day.

Answer:

According to the kinetic molecular theory of gases, the average speed and kinetic energy of gas molecules would INCREASE.

Explanation:

In the kinetic molecular theory of gases, assumptions were made based on macroscopic properties of gas (pressure, volume and temperature) which are as a result of the microscopic properties like the position and the speed of the gas molecules. The kinetic molecular theory explains the behaviour of gases through the following 5 assumptions made about an ideal gas;

--> Molecules of a gas are in constant and rapid motion in straight lines until they collide with one another and with the walls of their containers.

--> The actual volume occupied by the had is negligible compared with the volume of the container.

--> Forces of attraction or repulsion between the molecules of a gas are negligible

--> The collision between the molecules is perfectly elastic.

--> The average kinetic energy of the gas molecules is proportional to the temperature of the gas.

Because gas molecules are in constant motion, it has kinetic energy which can be altered when there is increase in pressure. An increase in pressure will cause gas molecules to collide more frequently with one another. This in turn leads to increase in average speed and the kinetic energy of the individual molecules.

Answer:

11.6 mol O₂

Explanation:

In order to solve this problem we need to convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂). To do so we'll use a conversion factor containing the stoichiometric coefficients of the balanced reaction:

Answer:

lenses is used to refract light inward or outward

there are two type of lenses. Concave and convex lense

Convex lense converge ray of light

Concave lense diverge ray of light

useful application =:

=> camera

=> flashlight

=> lasers

=> Binoculars and Telescope

hope it helps

Answer:

Explanation:

Lenses are made of glass or other transparent materials for light. They are optically dense so light slows down on entering it. It is called refraction which bends the light on entering and leaving the lenses.

Refraction by lenses can be used for all kinds of optical applications, e.g. camera, telescope, magnifying glasses, solar heating.

Answer: C not really sure thoo

The question is incomplete, the complete question is;

A student determines the number of moles of water in a

hydrated metal oxide by weighing a clean, dry crucible

and lid while the crucible is empty, then reweighing the

crucible and lid with a sample of the hydrate, heating the

crucible and lid with a Bunsen burner and then

reweighing the crucible and lid with the sample after

cooling to room temperature. Which error will result in

too high a value for the amount of water of hydration?

(A) The heating is conducted only once instead of the

three times recommended by the procedure.

(B) The lid is left off the crucible when it is weighed

with the hydrated oxide.

(C) The metal oxide reacts partially with oxygen in the

air, forming a compound in a higher oxidation state.

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Answer:

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Explanation:

It is possible to determine the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate. The crucible and lid with the sample are heated, cooled and reweighed.

As this process is going on, suppose some of the heated oxide is spilled from the crucible, then the mass of heated or anhydrous oxide decreases leading to a consequent increase in the number of moles of water in the hydrated metal oxide, hence the answer above.

The too high a value for the amount of water of hydration error is occur due to heating of given hydrated sample.

Hydrated compounds are those compounds in which water molecule is present with the normal compound.

To get the correct value of weight of hydrated compound, first we have to weigh the empty crucible and lid and then with sample of compound in the crucible and lid. After this substract empty weigh of crucible & lid from the sample-crucible-lid weigh. If we substract the weigh from heated sample crucible and lid, then we get the error because the hydrated water molecule may decompose due to heating and moles of water increases.

Hence, error will occur if we heat the sample.

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Answer:

0.5875L

Explanation:

concentration = mole/ volume

n(LiCl) = 20 / (7 + 35.5) = 0.47 mol

volume = mole / conc.

volume = 0.47 /0.8

= 0.5875 dm³ = 0.5875L

Answer:

A. it allows results to be reviewed and reproduced by other scientists.

Answer:

a

Explanation:

Answer:

D

Explanation:

The rest have characteristics of a plant cell

Answer:

Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.

Explanation: