Answer:
hope it helps
Step-by-step explanation::
a) Consider a body having initial velocity 'u'. Suppose it is subjected to a uniform acceleration 'a' so that after time 't' its final velocity becomes 'v'. Now, from the definition of acceleration we know that:
Acceleration = Time taken Change in velocity or Acceleration = time taken
Final velocity- Initial velocity
So, a= t v−u
at=v−u and, v=u + at
where v= final velocity of the body
u= initial velocity of the body
a= acceleration
and t= time taken
(b) Initial velocity, u=54km/h=15m/s
Final velocity, v=0m/s
Time, t=8s
Acceleration, a=?
a= t v−u
= 8 0−15
= 8 −15 m/s 2
=−1.875m/s 2
Divide. Write your answer as a fraction in simplest form. − 10 2/7÷(−4 4/11)=
Answer:
33/14
Step-by-step explanation:
[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]
[tex] = - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]
[tex] = \frac{72}{7} \times \frac{11}{48} [/tex]
[tex] = \frac{3}{7} \times \frac{11}{2} [/tex]
[tex] = \frac{33}{14} [/tex]
stan dreamcatcher
Is the following number rational or irrational?
-117
Choose 1 answer:
Rational
Irrational
Answer:
-117 is irrational number
Answer:
Irrational
Step-by-step explanation:
Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.
Add.
(3x2 – 2x) + (4x-3)
O A. 7x2- 5x
O B. 12x3 - 14x2 + 6x
O C. 3x2 - 6x + 3
O D. 3x2 + 2x-3
Answer:
O D. 3x2 + 2x-3
Answer:
A.7x2-5x questions 2of 20
Trigonometric ratios
class 9
please answer my questions
Step-by-step explanation:
Hi there!
Please see the answer in the picture.
Hope it helps!
1. Approach
One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,
[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]
Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.
2. Problem (9)
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
As per the attached image, the following statements regarding the value of each ratio can be made:
[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]
Substitute,
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
Simplify,
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]
Thus, this equation is true.
2. Problem (10)
Use a similar strategy to evaluate this equation,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
Use the attached image to evaluate the ratios.
[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]
Substitute,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
Simplify,
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
Rationalize the denominator,
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]
[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]
[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]
[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]
[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]
Therefore, this equation is also true.
u4gent help needed
help me with the question of o.math
Answer:
1≤f(x)≤5
Step-by-step explanation:
-1≤x≤1
-2≤2x≤2 (Multiplied by 2 both side)
-2+3≤2x+3≤2+3 (Adding three both sides)
1≤f(x)≤5
Find the first three terms of the sequence given by the following.
a
n = 25-3(n − 1), n= 1, 2, 3, ...
A. 28, 25, 22
B. 25, 22, 19
C. 25, 28, 31
D. 28, 31, 34
the answer is
A. 28, 25, 22
HELP ITS DUE IN THE MORNING AND ITS 3:57
Answer:
A " (1,-2)
B " (4,0)
C " (6,-3)
Step-by-step explanation:
Hope it helped.
° ° °
a sum of money Doubles itself in 5 years what is rate of simple interest
Step-by-step explanationIf you are reading this say
thank u
The circumference of a circle is 20π. What is the area of the circle?
Answer:
The area of the circle is 100 square units.
Step-by-step explanation:
We are given that the circumference of a circle is 20π, and we want to determine its area.
Recall that the circumference of a circle is given by the formula:
[tex]\displaystyle C = 2\pi r[/tex]
Substitute:
[tex]20 \pi = 2 \pi r[/tex]
Solve for the radius:
[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]
The area of a circle is given by:
[tex]\displaystyle A = \pi r^2[/tex]
Since the radius is 10 units:
[tex]\displaystyle A = \pi (10)^2[/tex]
Evaluate:
[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]
In conclusion, the area of the circle is 100 square units.
How many gallons equal 26 liters
Answer:
6.8 gallions i believe. im not quite sure
I don't understand need help?
9514 1404 393
Answer:
2. (only)
Step-by-step explanation:
The Pythagorean theorem tells you the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. To determine if these are right triangles, determine if that condition is met.
1. 3^2 +5^2 = 9 + 25 = 34 ≠ (√35)^2 . . . . not a right triangle
2. 5^2 +4^2 = 25 +16 = 41 = (√41)^2 . . . a right triangle
3. 6^2 +8^2 = 36 +64 = 100 ≠ (√10)^2 . . . . not a right triangle
4. 3^2 +3^2 = 9 +9 = 18 ≠ (3√3)^2 = 27 . . . . not a right triangle
find the mean value of the following. 5, 11, 4, 10, 8, 6
Am I suppose to substitute the variables with random numbers in order to answer these questions???
Translation A maps (x, y) to (x + n, y + 1). Translation B maps (x, y) to (x +s, y + m).
1. Translate a point using Translation A, followed by Translation B. Write an algebraic rule for the final image of the point after this composition.
2. Translate a point using Translation B, followed by Translation A. Write an algebraic rule for the final image of the point after this composition.
3. Compare the rules you wrote for parts (a) and (b). Does it matter which translation you do first? Explain your reasoning.
9514 1404 393
Answer:
(x, y) ⇒ (x +n +s, y +1 +m)(x, y) ⇒ (x +s +n, y +m +1)they are identical in effect; order does not matterStep-by-step explanation:
Substitute the expressions.
A then BAfter the first translation, the value of x is (x+n). Put that as the value of x in the second translation.
x ⇒ x +s . . . . . . . . . the definition of the second translation
(x+n) ⇒ (x+n) +s . . . the result after both translations
The same thing goes for y. After the first translation, its new value is (y+1).
y ⇒ y +m . . . . . . . . the definition of the second translation
(y+1) ⇒ (y+1) +m . . . the result of both translations
Then the composition of A followed by B is (x, y) ⇒ (x +n +s, y +1 +m).
__
B then AThe same reasoning applies. After the B translation, the x-coordinate is (x+s) and the y-coordinate is (y+m). Then the A translation changes these to ...
x ⇒ x +n . . . . . . . . . . definition of translation A
(x+s) ⇒ (x+s) +n . . . . translation A operating on point translated by B
y ⇒ y +1 . . . . . . . . . . . definition of translation A
(y+m) ⇒ (y+m) +1 . . . . translation A operating on point translated by B
The composition of B followed by A is (x, y) ⇒ (x + s + n, y + m + 1).
__
You should recognize that the sums (x+n+s) and (x+s+n) are identical. The commutative and associative properties of addition let us rearrange the order of the terms with no effect on the outcome.
The two translations give the same result in either order.
solve for w.
-9/7=-2/3w-1/2
Answer: [tex]w=\frac{33}{28}[/tex]
Step-by-step explanation:
To solve for w, we want to isolate w.
[tex]-\frac{9}{7}=-\frac{2}{3}w-\frac{1}{2}[/tex] [add both sides by 1/2]
[tex]-\frac{11}{14}=-\frac{2}{3}w[/tex] [multiply both sides by -3/2]
[tex]w=\frac{33}{28}[/tex]
Now we know that [tex]w=\frac{33}{28}[/tex].
Answer:
[tex]\sf w=\dfrac{33}{28} \\[/tex]
Step-by-step explanation:
[tex]\sf -\dfrac{9}{7} =-\dfrac{2w}{3} -\dfrac{1}{2}[/tex]
First, take -2w/3 to the left side.
[tex]\sf -\dfrac{9}{7}+\dfrac{2w}{3} = -\dfrac{1}{2}[/tex]
Then, add 9/7 to both sides.
[tex]\sf \dfrac{2w}{3} = -\dfrac{1}{2}+\dfrac{9}{7}[/tex]
Make the denominators the same and add the fractions.
[tex]\sf \dfrac{2w}{3} = -\dfrac{1*7}{2*7}+\dfrac{9*2}{7*2}\\\\\sf \dfrac{2w}{3} = -\dfrac{7}{14}+\dfrac{18}{14}\\\\\sf \dfrac{2w}{3} = \dfrac{-7+18}{14}\\\\\sf \dfrac{2w}{3} = \dfrac{11}{14}[/tex]
Use cross multiplication.
[tex]\sf 2w*14=11*3\\\\28w=33[/tex]
Divide both sides by 28.
[tex]\sf w=\dfrac{33}{28} \\[/tex]
Which is the graph of y = [x]-2?
PLEASE HELP TIMED PLEASE
Answer:
3rd graph
Step-by-step explanation:
In the number 9663 which places contain digits where one dogit is 10 times as great as the other?
Answer: Hundreds and tens place values (the two copies of '6')
Explanation:
We're looking for where the digits are the same, which would be those two copies of '6'
The first 6 on the left is in the hundreds place. It represents 600
The other 6 is in the tens place, and it represents 60
The jump from 60 to 600 is "times 10".
Help what is x
When x^5 is 225
Answer:
Solution given:
x^5=225
we have
x=[tex] \sqrt[5]{225} [/tex]
x=2.9541
Hello!
[tex] \bf {x}^{5} = 225[/tex]
Extract the radical on both sides of the equation.[tex] \bf x = \sqrt[5]{225} [/tex]
[tex] \bf x ≈2.95418[/tex]
Answer: x ≈ 2,95418
Good luck! :)
Point Q is located at (-4, 6). Point R is located at (8, 6).
What is the distance from point Q to point R?
Step-by-step explanation:
Hi there!
Given;
Point Q is located at (-4, 6). Point R is located at (8, 6).
Note: Use distance formula.
Now;
[tex](d) = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]
Keep all values;
[tex](d) = \sqrt{ {(8 + 4)}^{2} + ( {6 - 6)}^{2} } [/tex]
Simplify;
[tex](d) = \sqrt{( {12)}^{2} } [/tex]
Therefore, the distance is 12 units.
Hope it helps!
[tex]x + 0.25 = -0.25[/tex]
Answer:
x = -0.5
Step-by-step explanation:
x + 0.25 = -0.25
x = -0.25 - 0.25
x = -0.5
Describe the pattern in the following sequence and list the next three terms:
4, 8, 16, 32, ...
I’ll mark brainliest! Please help me
find the missing length indicated
Answer:
240
Step-by-step explanation:
We are given a right triangle. Based on the leg rule, the following equation shows how the length of a leg in a right triangle relates with the segments connected to the hypotenuse:
Hypotenuse/leg = leg/part
Where,
Hypo = 400
Leg = x
Part = 144
Substitute
400/x = x/144
Cross multiply
400*144 = x*x
57,600 = x²
√57,600 = x
240 = x
x = 240
0.25(4f-3)=0.005(10f-9)
Simplify the following
Answer:
apoco la propiedad asociativa en los siguiente ejercicio 25x11x18=
Which ordered pair can be plotted together with these four points, so the resulting graph still represents a function?
•(2, -1)
•(2, -2)
•(-2, 2)
•(-1, 2)
Answer:
-1,2 can be plotted together with these four points ...
428363939+42724289292952926263938
Answer:
4.2724289e
+22
Step-by-step explanation:
mzmznznxnxnznxn no n n j j h h h h h h hh h h &
The midpoint of a segment is (6,−4) and one endpoint is (13,−2). Find the coordinates of the other endpoint.
A. (20, -6)
B. (-1, 0)
C. (-1, -6)
D. (20, 0)
Answer:
(-1,-6)
Step-by-step explanation:
(13 + x)/2 = 6
13+x= 12
x = -1
~~~~~~~~~~~~~~~
(-2 + y ) / 2 = -4
-2 + y = -8
y = -6
The coordinates of the other endpoint will be (-1,-6). The correct option is C.
What is the midpoint of the line?Divide the measurement of the distance between the two end locations by 2. The middle of that line is located at this separation from either end.
A coordinate plane is a 2D plane that is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.
Given that the midpoint of a segment is (6,−4) and one endpoint is (13,−2).
The x- coordinate will be calculated as:-
(13 + x)/2 = 6
13+x= 12
x = -1
The y-coordinate will be calculated as:-
(-2 + y ) / 2 = -4
-2 + y = -8
y = -6
Therefore, the coordinates of the other endpoint will be (-1,-6). The correct option is C.
To know more about midpoints of the line follow
https://brainly.com/question/24431553
#SPJ2
Please help me with this problem.
Answer:
1/4a -1/6b + 1/10c
Step-by-step explanation:
1/2 a -1/3 b + 1/5c + -1/4a + 1/6 b - 1/10c
Combine like terms
1/2a - 1/4a -1/3b + 1/6b +1/5c - 1/10 c
2/4a -1/4a -2/6b + 1/6b +2/10c -1/10c
1/4a -1/6b + 1/10c
Let $x$ be the smallest number in the following list, and let $y$ be the second smallest number (that is, the smallest number other than $x$). \[ 5, \qquad -22, \qquad \frac{-4}{7}, \qquad \frac{-3}{-5}, \qquad 3, \qquad \frac{-8}{13} \]Find $\frac{x-y}{y}$. Express your answer as a fraction in simplest form.
Answer:
139/4
Step-by-step explanation:
and find that\[
\frac{4}{7}\cdot \frac{13}{13} = \frac{4\cdot 13}{91}=\frac{52}{91}, \text{and}
\]\[
\frac{8}{13}\cdot \frac{7}{7} = \frac{8\cdot 7}{91} = \frac{56}{91}.
\]Thus $\frac{8}{13}$ is larger than $\frac{4}{7}$, which tells us that $-\frac{8}{13}$ is smaller than $-\frac{4}{7}$. Thus, $x=-22$, $y=-\frac{8}{13}$, and\begin{align*}
\frac{x-y}{y}&=\frac{-22-\left(-\frac{8}{13}\right)}{-\frac{8}{13}}\\
&=\left(-22\cdot \frac{13}{13}+\left(\frac{8}{13}\right)\right)\cdot \left(-\frac{13}{8}\right)\\
&=\left(\frac{-286+8}{13}\right)\cdot \left(-\frac{13}{8}\right)\\
&=\left(-\frac{278}{13}\right)\cdot \left(-\frac{13}{8}\right)\\
&=\boxed{\frac{139}{4}}.
\end{align*}
1 pump can fill a pool in 8 hours the other pump can fill the pool in 10 hours if both of the pumps were turned on at the same time to fill the pool how long will it take
Answer:
4 4/9 hoursStep-by-step explanation:
In one hour pump1 can fill 1/8 of the tank and pump2 can fill 1/10 of the tank.
Two pumps can fill:
1/8 + 1/10 = 5/40 + 4/40 = 9/40 of the tank in one hourTime required to fill the tank:
1/(9/40) = 40/9 = 4 4/9 hoursSelect all that apply.
What are the angle measures in a 30-60-90 right triangles?
90°
150°
60°
120°
30°
Answer:
90°,60°&30°
Step-by-step explanation:
A 30-60-90 triangle is a right triangle with angle measures of 30º, 60º, and 90º (the right angle). Because the angles are always in that ratio, the sides are also always in the same ratio to each other.
Write an equation of a line perpendicular to y = -1/5x + 5
that passes through the point (-1,-3)
Select one:
a. y = 5x + 2
b.y = 2x - 5
c.y = -5x - 5
d. y = -5x + 2
