pls answer correct
for class 9 only

Pls Answer Correctfor Class 9 Only

Answers

Answer 1

Answer:

hope it helps

Step-by-step explanation::

a) Consider a body having initial velocity 'u'. Suppose it is subjected to a uniform acceleration 'a' so that after time 't' its final velocity becomes 'v'. Now, from the definition of acceleration we know that:  

Acceleration =  Time taken  Change in velocity  or Acceleration =  time taken

                Final velocity- Initial velocity    

So, a=  t v−u

​ at=v−u  and, v=u + at  

where v= final velocity of the body

u= initial velocity of the body

a= acceleration

and t= time taken  

(b) Initial velocity, u=54km/h=15m/s

Final velocity, v=0m/s

Time, t=8s

Acceleration, a=?

a=  t v−u

​  =  8 0−15

​  =  8 −15 ​  m/s  2

=−1.875m/s  2


Related Questions

Select all that apply.
What are the angle measures in a 30-60-90 right triangles?
90°
150°
60°
120°
30°

Answers

Answer:

90°,60°&30°

Step-by-step explanation:

A 30-60-90 triangle is a right triangle with angle measures of 30º, 60º, and 90º (the right angle). Because the angles are always in that ratio, the sides are also always in the same ratio to each other.

Find the first three terms of the sequence given by the following.
a
n = 25-3(n − 1), n= 1, 2, 3, ...

A. 28, 25, 22
B. 25, 22, 19
C. 25, 28, 31
D. 28, 31, 34

Answers

the answer is

A. 28, 25, 22

1 pump can fill a pool in 8 hours the other pump can fill the pool in 10 hours if both of the pumps were turned on at the same time to fill the pool how long will it take

Answers

Answer:

4 4/9 hours

Step-by-step explanation:

In one hour pump1 can fill 1/8 of the tank and pump2 can fill 1/10 of the tank.

Two pumps can fill:

1/8 + 1/10 = 5/40 + 4/40 = 9/40 of the tank in one hour

Time required to fill the tank:

1/(9/40) = 40/9 = 4 4/9 hours

Am I suppose to substitute the variables with random numbers in order to answer these questions???

Translation A maps (x, y) to (x + n, y + 1). Translation B maps (x, y) to (x +s, y + m).
1. Translate a point using Translation A, followed by Translation B. Write an algebraic rule for the final image of the point after this composition.
2. Translate a point using Translation B, followed by Translation A. Write an algebraic rule for the final image of the point after this composition.
3. Compare the rules you wrote for parts (a) and (b). Does it matter which translation you do first? Explain your reasoning.

Answers

9514 1404 393

Answer:

(x, y) ⇒ (x +n +s, y +1 +m)(x, y) ⇒ (x +s +n, y +m +1)they are identical in effect; order does not matter

Step-by-step explanation:

Substitute the expressions.

A then B

After the first translation, the value of x is (x+n). Put that as the value of x in the second translation.

  x ⇒ x +s . . . . . . . . . the definition of the second translation

  (x+n) ⇒ (x+n) +s . . . the result after both translations

The same thing goes for y. After the first translation, its new value is (y+1).

  y ⇒ y +m . . . . . . . . the definition of the second translation

  (y+1) ⇒ (y+1) +m . . . the result of both translations

Then the composition of A followed by B is (x, y) ⇒ (x +n +s, y +1 +m).

__

B then A

The same reasoning applies. After the B translation, the x-coordinate is (x+s) and the y-coordinate is (y+m). Then the A translation changes these to ...

  x ⇒ x +n . . . . . . . . . . definition of translation A

  (x+s) ⇒ (x+s) +n . . . . translation A operating on point translated by B

  y ⇒ y +1 . . . . . . . . . . . definition of translation A

  (y+m) ⇒ (y+m) +1 . . . . translation A operating on point translated by B

The composition of B followed by A is (x, y) ⇒ (x + s + n, y + m + 1).

__

You should recognize that the sums (x+n+s) and (x+s+n) are identical. The commutative and associative properties of addition let us rearrange the order of the terms with no effect on the outcome.

The two translations give the same result in either order.

Which is the graph of y = [x]-2?

PLEASE HELP TIMED PLEASE

Answers

Answer:

3rd graph

Step-by-step explanation:

Point Q is located at (-4, 6). Point R is located at (8, 6).
What is the distance from point Q to point R?

Answers

Step-by-step explanation:

Hi there!

Given;

Point Q is located at (-4, 6). Point R is located at (8, 6).

Note: Use distance formula.

Now;

[tex](d) = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]

Keep all values;

[tex](d) = \sqrt{ {(8 + 4)}^{2} + ( {6 - 6)}^{2} } [/tex]

Simplify;

[tex](d) = \sqrt{( {12)}^{2} } [/tex]

Therefore, the distance is 12 units.

Hope it helps!

How many gallons equal 26 liters

Answers

Answer:

6.8 gallions i believe. im not quite sure

Write an equation of a line perpendicular to y = -1/5x + 5
that passes through the point (-1,-3)
Select one:
a. y = 5x + 2
b.y = 2x - 5
c.y = -5x - 5
d. y = -5x + 2

Answers

A. y=5x+2
Please like

Please help me with this problem.

Answers

Answer:

1/4a -1/6b + 1/10c

Step-by-step explanation:

1/2 a  -1/3 b + 1/5c   + -1/4a + 1/6 b - 1/10c

Combine like terms

1/2a - 1/4a   -1/3b + 1/6b    +1/5c - 1/10 c

2/4a -1/4a    -2/6b + 1/6b   +2/10c -1/10c

1/4a -1/6b + 1/10c

1/2a-1/3b+1/5c+(-1/4a)+1/6b-1/10c1/2a-1/4a-1/3b+1/6b+1/5c-1/10c2-1/4a-2+1/6b+2+2-1/10c1/4a-1/6b+1/10c

find the missing length indicated​

Answers

Answer:

240

Step-by-step explanation:

We are given a right triangle. Based on the leg rule, the following equation shows how the length of a leg in a right triangle relates with the segments connected to the hypotenuse:

Hypotenuse/leg = leg/part

Where,

Hypo = 400

Leg = x

Part = 144

Substitute

400/x = x/144

Cross multiply

400*144 = x*x

57,600 = x²

√57,600 = x

240 = x

x = 240

Is the following number rational or irrational?
-117
Choose 1 answer:
Rational
Irrational

Answers

Answer:

-117 is irrational number

Answer:

Irrational

Step-by-step explanation:

Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.

find the mean value of the following. 5, 11, 4, 10, 8, 6​

Answers

5+11+4+10+8+6 = 44
44/6 = 7.33….


answer: 7.33…..

In the number 9663 which places contain digits where one dogit is 10 times as great as the other?

Answers

Answer: Hundreds and tens place values (the two copies of '6')

Explanation:

We're looking for where the digits are the same, which would be those two copies of '6'

The first 6 on the left is in the hundreds place. It represents 600

The other 6 is in the tens place, and it represents 60

The jump from 60 to 600 is "times 10".

HELP ITS DUE IN THE MORNING AND ITS 3:57​

Answers

Answer:

A " (1,-2)

B " (4,0)

C " (6,-3)

Step-by-step explanation:

Hope it helped.

° ° °

a sum of money Doubles itself in 5 years what is rate of simple interest​

Answers

Step-by-step explanationIf you are reading this say

thank u

Which ordered pair can be plotted together with these four points, so the resulting graph still represents a function?
•(2, -1)

•(2, -2)

•(-2, 2)

•(-1, 2)

Answers

Answer:

-1,2 can be plotted together with these four points ...

0.25(4f-3)=0.005(10f-9)
Simplify the following

Answers

Answer:

apoco la propiedad asociativa en los siguiente ejercicio 25x11x18=

The circumference of a circle is 20π. What is the area of the circle?

Answers

Answer:

The area of the circle is 100 square units.

Step-by-step explanation:

We are given that the circumference of a circle is 20π, and we want to determine its area.

Recall that the circumference of a circle is given by the formula:

[tex]\displaystyle C = 2\pi r[/tex]

Substitute:

[tex]20 \pi = 2 \pi r[/tex]

Solve for the radius:

[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]

The area of a circle is given by:

[tex]\displaystyle A = \pi r^2[/tex]

Since the radius is 10 units:

[tex]\displaystyle A = \pi (10)^2[/tex]

Evaluate:

[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]

In conclusion, the area of the circle is 100 square units.

Trigonometric ratios
class 9
please answer my questions​

Answers

Step-by-step explanation:

Hi there!

Please see the answer in the picture.

Hope it helps!

1. Approach

One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]

Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.

2. Problem (9)

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

As per the attached image, the following statements regarding the value of each ratio can be made:

[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]

Substitute,

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

Simplify,

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]

Thus, this equation is true.

2. Problem (10)

Use a similar strategy to evaluate this equation,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

Use the attached image to evaluate the ratios.

[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]

Substitute,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

Simplify,

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

Rationalize the denominator,

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]

[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]

[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]

[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]

[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]

Therefore, this equation is also true.

Divide. Write your answer as a fraction in simplest form. − 10 2/7÷(−4 4/11)=

Answers

Answer:

33/14

Step-by-step explanation:

[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]

[tex] = - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]

[tex] = \frac{72}{7} \times \frac{11}{48} [/tex]

[tex] = \frac{3}{7} \times \frac{11}{2} [/tex]

[tex] = \frac{33}{14} [/tex]

stan dreamcatcher

Help what is x
When x^5 is 225

Answers

Answer:

Solution given:

x^5=225

we have

x=[tex] \sqrt[5]{225} [/tex]

x=2.9541

Hello!

[tex] \bf {x}^{5} = 225[/tex]

Extract the radical on both sides of the equation.

[tex] \bf x = \sqrt[5]{225} [/tex]

[tex] \bf x ≈2.95418[/tex]

Answer: x 2,95418

Good luck! :)

solve for w.
-9/7=-2/3w-1/2

Answers

Answer: [tex]w=\frac{33}{28}[/tex]

Step-by-step explanation:

To solve for w, we want to isolate w.

[tex]-\frac{9}{7}=-\frac{2}{3}w-\frac{1}{2}[/tex]            [add both sides by 1/2]

[tex]-\frac{11}{14}=-\frac{2}{3}w[/tex]                 [multiply both sides by -3/2]

[tex]w=\frac{33}{28}[/tex]

Now we know that [tex]w=\frac{33}{28}[/tex].

Answer:

[tex]\sf w=\dfrac{33}{28} \\[/tex]

Step-by-step explanation:

[tex]\sf -\dfrac{9}{7} =-\dfrac{2w}{3} -\dfrac{1}{2}[/tex]

First, take -2w/3 to the left side.

[tex]\sf -\dfrac{9}{7}+\dfrac{2w}{3} = -\dfrac{1}{2}[/tex]

Then, add 9/7 to both sides.

[tex]\sf \dfrac{2w}{3} = -\dfrac{1}{2}+\dfrac{9}{7}[/tex]

Make the denominators the same and add the fractions.

[tex]\sf \dfrac{2w}{3} = -\dfrac{1*7}{2*7}+\dfrac{9*2}{7*2}\\\\\sf \dfrac{2w}{3} = -\dfrac{7}{14}+\dfrac{18}{14}\\\\\sf \dfrac{2w}{3} = \dfrac{-7+18}{14}\\\\\sf \dfrac{2w}{3} = \dfrac{11}{14}[/tex]

Use cross multiplication.

[tex]\sf 2w*14=11*3\\\\28w=33[/tex]

Divide both sides by 28.

[tex]\sf w=\dfrac{33}{28} \\[/tex]

Add.
(3x2 – 2x) + (4x-3)
O A. 7x2- 5x
O B. 12x3 - 14x2 + 6x
O C. 3x2 - 6x + 3
O D. 3x2 + 2x-3

Answers

Answer:

O D. 3x2 + 2x-3

Answer:

A.7x2-5x questions 2of 20

The midpoint of a segment is (6,−4) and one endpoint is (13,−2). Find the coordinates of the other endpoint.

A. (20, -6)
B. (-1, 0)
C. (-1, -6)
D. (20, 0)

Answers

Answer:

(-1,-6)

Step-by-step explanation:

(13 + x)/2 = 6

13+x= 12

x = -1

~~~~~~~~~~~~~~~

(-2 + y ) / 2 = -4

-2 + y = -8

y = -6

The coordinates of the other endpoint will be (-1,-6). The correct option is C.

What is the midpoint of the line?

Divide the measurement of the distance between the two end locations by 2. The middle of that line is located at this separation from either end.

A coordinate plane is a 2D plane that is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

Given that the midpoint of a segment is (6,−4) and one endpoint is (13,−2).

The x- coordinate will be calculated as:-

(13 + x)/2 = 6

13+x= 12

x = -1

The y-coordinate will be calculated as:-

(-2 + y ) / 2 = -4

-2 + y = -8

y = -6

Therefore, the coordinates of the other endpoint will be (-1,-6). The correct option is C.

To know more about midpoints of the line follow

https://brainly.com/question/24431553

#SPJ2

Let $x$ be the smallest number in the following list, and let $y$ be the second smallest number (that is, the smallest number other than $x$). \[ 5, \qquad -22, \qquad \frac{-4}{7}, \qquad \frac{-3}{-5}, \qquad 3, \qquad \frac{-8}{13} \]Find $\frac{x-y}{y}$. Express your answer as a fraction in simplest form.

Answers

Answer:

139/4

Step-by-step explanation:

and find that\[

\frac{4}{7}\cdot \frac{13}{13} = \frac{4\cdot 13}{91}=\frac{52}{91}, \text{and}

\]\[

\frac{8}{13}\cdot \frac{7}{7} = \frac{8\cdot 7}{91} = \frac{56}{91}.

\]Thus $\frac{8}{13}$ is larger than $\frac{4}{7}$, which tells us that $-\frac{8}{13}$ is smaller than $-\frac{4}{7}$. Thus, $x=-22$, $y=-\frac{8}{13}$, and\begin{align*}

\frac{x-y}{y}&=\frac{-22-\left(-\frac{8}{13}\right)}{-\frac{8}{13}}\\

&=\left(-22\cdot \frac{13}{13}+\left(\frac{8}{13}\right)\right)\cdot \left(-\frac{13}{8}\right)\\

&=\left(\frac{-286+8}{13}\right)\cdot \left(-\frac{13}{8}\right)\\

&=\left(-\frac{278}{13}\right)\cdot \left(-\frac{13}{8}\right)\\

&=\boxed{\frac{139}{4}}.

\end{align*}

Describe the pattern in the following sequence and list the next three terms:
4, 8, 16, 32, ...

I’ll mark brainliest! Please help me

Answers

Ummm it’s kind of easy but this is my way of doing it
Multiples of 4 after continuing 2 digits skip one multiple and continue;-;

[tex]x + 0.25 = -0.25[/tex]

Answers

Answer:

x = -0.5

Step-by-step explanation:

x + 0.25 = -0.25

x = -0.25 - 0.25

x = -0.5

I don't understand need help?

Answers

9514 1404 393

Answer:

  2. (only)

Step-by-step explanation:

The Pythagorean theorem tells you the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. To determine if these are right triangles, determine if that condition is met.

  1. 3^2 +5^2 = 9 + 25 = 34 ≠ (√35)^2 . . . . not a right triangle

  2. 5^2 +4^2 = 25 +16 = 41 = (√41)^2 . . . a right triangle

  3. 6^2 +8^2 = 36 +64 = 100 ≠ (√10)^2 . . . . not a right triangle

  4. 3^2 +3^2 = 9 +9 = 18 ≠ (3√3)^2 = 27 . . . . not a right triangle

u4gent help needed
help me with the question of o.math​

Answers

Answer:

1≤f(x)≤5

Step-by-step explanation:

-1≤x≤1

-2≤2x≤2 (Multiplied by 2 both side)

-2+3≤2x+3≤2+3 (Adding three both sides)

1≤f(x)≤5

428363939+42724289292952926263938

Answers

Answer:

4.2724289e

+22

Step-by-step explanation:

mzmznznxnxnznxn no n n j j h h h h h h hh h h &

answer: 4.2724289e+22
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