Pls help quick. (Geomery question)

Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD?

Answer: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]

Step-by-step explanation:

[tex]f(x)=10x^{3}\\y=10x^{3}[/tex]

switch the x and y:

[tex]x=10y^{3}[/tex]

Now solve for y:

[tex]x=10y^{3} \\\frac{x}{10} =y^{3} \\\sqrt[3]{\frac{x}{10} } =y\\[/tex]

Therefore, the inverse of that function is: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]

Answer:

C. 37.8 units

Step-by-step explanation:

ED = 17/ cos(38°) = 17 / 0.7880 = 21.6 units

DF = 17× tan (38°) = 17× 0.7813 = 13.3 units

CD = 10/13.3 × 21.6 = 16.2 units

so, the length of CE = 21.6+16.2 = 37.8 units

Hi

we know that sin(A+B)=Sin(A)Cos(B)-Cos(A) Sin (B)

cos(2x)=1-2sin²(x)

sin(2x)=2sin(x)cos(x)

Exp:- Sin(3x)=Sin(x+2x)

Sin(x)cos(2x)+cos(x)sin(2x)

sin(x){1-2sin²(x)}+2cos²(x)sin(x)

sin(x)-2sin³(x)+2sin(x){1-sin²(x)}

sin(x)-2sin³(x)+2sin(x)-2sin³(x)

3sin(x)-4sin³(x)

Hope it helps....

Answer:

Step-by-step explanation:

a.) it's just mean, variance

so here it's just 12,6.25

b.) For the x bar thing just divide the variance by the number of people (mean stay the same)

the variance is then (2.5²/34)= .1838

which makes it (12,.1838)

c.) here we don't use x bar (and so it's normal (12,2.5²))

p(11.6) = (11.6-12)/(2.5)= -.16 = .4364

p(12.4)= (12.4-12)/2.5 = .16= .5636

.5636-.4364= .1272

d.) here we use x bar because it's asking for an average so it's normal (12, .1838)

same deal

p(11.6)=(11.6-12)/√.1838= -.93295= .1762

p(12.4)= (12.4-12)/√.1838= .93295= .8238

.8238-.1762= .6476

d.) no because they're probably IID

f.) It's average so here we use x bar

q1 is just the 25th percentile

the 25th percentile is -.6745

-.6745=(x-12)/(√.1838)= 11.711

q3 is the 75th percentile

.6745=(x-12)/√.1838

x=12.289

The interquartile range is just the difference between the two

12.289-11.711= .5784

Answer:

a) The difference is of -37, that is, this pulse rate is 37 beats per minute below the mean.

b) 2.68 standard deviations below the mean.

c) Z = -2.68.

d) Z-score below -2, so a pulse rate of 39 beats per minute is significantly low.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the​ females?

Difference between 39 and 76, so 39 - 76 = -37.

The difference is of -37, that is, this pulse rate is 37 beats per minute below the mean.

b. How many standard deviations is that​ [the difference found in part​ (a)]

Standard deviation of 13.8, so:

-37/13.8 = -2.68

So 2.68 standard deviations below the mean.

c. Convert the pulse rate of 39 beats per minutes to a z score.

2.68 standard deviations below the mean, so Z = -2.68.

d. If we consider pulse rates that convert to z scores between −2 and 2 to be neither significantly low nor significantly​ high, is the pulse rate of 39 beats per minute​ significant?

Z-score below -2, so a pulse rate of 39 beats per minute is significantly low.

Answer:

P = side a + side b + side c

Step-by-step explanation:

The perimeter of any polygon is all sides added together.

Answer:

3 X sides please mark me brainlist

the e-function stuff can be confusing sometimes, but notices that g(x) / the blue line, is just somewhat lower, rest is the same.

how much lower? look at the y-intercepts

f(0)= "about 5"

g(0)= "about -3"

with this y-intercept only option c can work

Answer:

the first wheel ever built

Answer:

The first wheel ever built

Step-by-step explanation

(*) Sorry for my late answer but I hope this helps others that are looking for this.

100% in the test :)

Answer:

24

Step-by-step explanation:

To find the range, you must subtract the lowest value from the highest value in the data set. If you organize the set from least to greatest, 72 is the lowest, and 96 is the highest.

So, 96 - 72 = 24, which is the range.

Answer:

Step-by-step explanation:

180-90=2b+b

90=3b

90/3=b

30=b

2b=2*30

   =60

180-90=a+a

90=2a

a=90/2

a=45

the answer is 45 degrees

hope it helps!!let me know if it does

Answer:

a= 15°

Step-by-step explanation:

> use the fact that the sum of angles in a triangle is 180°

> based on the picture in the small right triangle we have b° +2b° +90° =180°

b +2b +90 =180° , combine like terms

3b +90 = 180, subtract 90 from both sides of the equation

3b = 90, divide by 3 both sides of the equation

b = 30°

> angle b has a ray that continues as a line so it makes an 180° angle and we have the acute triangle so we can write that

a + a+ (180-b) =180, substitute b

2a + 180-30 =180, subtract 180 from both sides, and add 30 to both sides

2a=30, divide by 2 both sides

a= 15°

Answer:

53.08 ft

Step-by-step explanation:

The pressure at the bottom of the tank, P = ρgh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water in tank.

Since the pressure at the bottom of the tank, P = ρgh, making h subject of the formula, we have

h = P/ρg

Since P = 23 psig = 23 × 1 psig = 23 × 6894.76 Pa = 158579.48 Pa

Substituting the values of the other variables into h, we have

h = P/ρg

h = 158579.48 Pa/(1000 kg/m³ × 9.8 m/s²)

h = 158579.48 Pa/(9800 kg/m²s²)

h = 16.18 m

h = 16.18 × 1 m

h = 16.18 × 3.28 ft

h = 53.08 ft

Answer:

Z = 50

Step-by-step explanation:

Given the following data;

Z = 187

x = 64

y = 6

Translating the word problem into an algebraic expression, we have;

Z = k√x/y

First of all, we would find the constant of proportionality, k;

187 = k√64/6

187 * 6 = k√64

1122 = 8k

k = 1122/8

k = 140.25

To find z, when x and y = 9

Z = 140.25√9/9

Z = (140.25 * 3)/9

Z = 420.75/9

Z = 46.75 ≈ 50

Note: The values in the latter part of the question isn't explicitly stated, so I assumed a value of 9 for both x and y.

Answer:

3/14

Step-by-step explanation:

Assuming you draw one after the other without replacement, you have a 1/2 chance of drawing blue the first time, and after one is taken out, you have 7 left. In order to draw 2 blues you would have to have a blue the first time, so there would be 3 blue left. Multiplying the 2 probabilities gets 1/2*3/7= 3/14. Double check that though.

Answer:

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Step-by-step explanation:

Given

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]

Required

Solve

Start with the bracket

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]

Evaluate all exponents

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]

Evaluate all products

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Answer:

2/5

Step-by-step explanation:

There are a total of 4+3+2+1=10 marbles in the bag. Since there is an equal chance of drawing any marble from the bag, the chances of drawing a red marble is equal to the number of red marbles divided by the total number of marbles.

What we're given:

Therefore, the probability of drawing a red marble is:

[tex]\frac{4}{10}=\boxed{\frac{2}{5}}[/tex]

Answer: Most probably

Step-by-step explanation:

Answer:

9x

Step-by-step explanation:

Quick maths, I dont really have an explaination pls give me brainliest ;-;.

Answer:

option a.

[tex] + - \frac{13}{5} [/tex]

Step-by-step explanation:

[tex]25x^2\: - \:169 = 0 [/tex]

[tex]25x^2 = 169[/tex]

[tex] {x}^{2} = \frac{169}{25} [/tex]

[tex]x = + - \sqrt{ \frac{169}{25} } [/tex]

[tex]x = + - \frac{13}{5} [/tex]

Answer:

3x−4y=9 −3x+2y=9

Add these equations to eliminate x: −2y=18

Then solve−2y=18

for y: −2y=18 −2y −2 = 18 −2 (Divide both sides by -2)

y=−9

Now that we've found y let's plug it back in to solve for x.

Write down an original equation: 3x−4y=9

Substitute−9for y in 3x−4y=9: 3x−(4)(−9)=9

3x+36=9(Simplify both sides of the equation)

3x+36+−36=9+−36(Add -36 to both sides)

3x=−27 3x 3 = −27 3 (Divide both sides by 3) x=−9

Answer: x=−9 and y=−9

Hope This Helps!!!

Answer:

[tex] { - 3}^{2} + (4 + 7)(2) \\ = - 9 + 22 \\ = 13[/tex]

Answer:

[tex]{ \tt{5x + 3 \geqslant 48}} \\ { \tt{5x \geqslant 45}} \\ { \tt{x \geqslant 9}}[/tex]

Answer:

x[tex]\geq[/tex]9

Step-by-step explanation:

5x+3[tex]\geq \\[/tex]48  /-3

5x[tex]\geq[/tex]45   //5

x[tex]\geq[/tex]9

Answer:

B. 14

Step-by-step explanation:

It's asking for function f + function g. Then it wants you to use 2 as the x value. So you have:

(f+g)(x) = 2x^2 + 3x + x - 2

(f+g)(x) = 2x^2 + 4x -2

Then using 2 as x:

(f+g)(2) = 2(2^2) + 4* 2 -2

(f+g)(2) = 8 + 8 - 2

(f+g)(2) = 14

Hope that helps, and let me know if I did any of that wrong.

Answer:

The unlimited mileage plan would save money for Lia from 410 miles onwards.

Step-by-step explanation:

Since Lia can rent a van for either $ 90 per day with unlimited mileage or $ 50 per day with 250 free miles and an extra 25 ¢ for each mile over 250, to determine for what number of miles traveled in one day would the unlimited mileage plan save Lia money, the following calculation must be performed:

90.25 - 50 = 40.25

40.25 / 0.25 = 161

161 + 250 = 411

Therefore, the unlimited mileage plan would save money for Lia from 410 miles onwards.

Answer:

it would take 30 and a half days to make 240 cookies

Answer:

8

Step-by-step explanation:

5 = 40

1 = x

Then we multiply by the rule of crisscrossing

5 x X = 40 x 1

5x = 40 then divide both by 5

X = 8

Answer:

GMM,pooled OLC,even cross country OLC are most variables not difficult panel data analysis

Answer:

a) The 60th percentile of the diameters is of 25.0177 millimeters.

b) The 67th percentile of the diameters is of 25.0308 millimeters.

c) The diameter of the hole should be of 24.8562 millimeters.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 25.0 millimeters and standard deviation 0.07 millimeter.

This means that [tex]\mu = 25, \sigma = 0.07[/tex]

(a) Find the 60th percentile of the diameters.

This is X when Z has a p-value of 0.6, so X when Z = 0.253.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.253 = \frac{X - 25}{0.07}[/tex]

[tex]X - 25 = 0.253*0.07[/tex]

[tex]X = 25.0177[/tex]

The 60th percentile of the diameters is of 25.0177 millimeters.

(b) Find the 67th percentile of the diameters.

This is X when Z has a p-value of 0.67, so X when Z = 0.44.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.44 = \frac{X - 25}{0.07}[/tex]

[tex]X - 25 = 0.44*0.07[/tex]

[tex]X = 25.0308[/tex]

The 67th percentile of the diameters is of 25.0308 millimeters.

(c) A hole is to be designed so that 2% of the ball bearings will fit through it. The bearings that fit through the hole will be melted down and remade. What should the diameter of the hole be.

This is the 2nd percentile, which is X when Z has a p-value of 0.08, so X when Z = -2.054.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-2.054 = \frac{X - 25}{0.07}[/tex]

[tex]X - 25 = -2.054*0.07[/tex]

[tex]X = 24.8562[/tex]

The diameter of the hole should be of 24.8562 millimeters.