Pls pls pls help me

Answer:

(-1.25, 0) or (-5/4, 0)

Step-by-step explanation:

The x-intercept is when y = 0, so let's plug 0 into the equation:

3(0) - 8x = 10

Now we use basic algebra to solve for x:

0 - 8x = 10

-8x = 10

x = -5/4 or -1.25

So the answer is (-1.25, 0) or (-5/4, 0).

Hope this helps (●'◡'●)

Answer:

Please find the complete question and the graph in the attached file.

Step-by-step explanation:

On the basis of the data,

The level of importance is [tex]\alpha = 0.01[/tex]

Freedom levels [tex]= n -1 = 13 -1 = 12[/tex]

For the right-tailed test, the critical value is [tex]t_c = 2.681[/tex]

(Partially t-table permitted [tex]\alpha = 0.01 \ and\ df =12[/tex])

Answer:

1. ΔA'B'C' = A' = (1, 1), B'(-1, 1), and C'(1, 4)

2. ΔA''B''C'' = A''(-7 1), B''(-15 1), and C''(-7, 4)

Step-by-step explanation:

1. The coordinates of the triangle ΔABC are; A(3, 1), B(5, 1), and C(3, 4)

The reflection of a line across the line x = 2, is given as follows

The distance between the x-coordinate of the preimage and the line of reflection which is parallel to the x-axis = The distance of the x-coordinate of the preimage from the line of reflection but opposite in sign

The distance from A(3, 1) from x = 2 is 3 - 2 = 1, therefore, the x-coordinate of the image, A' = 2 - 1 = 1, therefore, we have;

The coordinate of A' = (1, 1)

Similarly, we have; B(5, 1) (reflection across x = 2) → B'(-1, 1)

C(3, 4) (reflection across x = 2) → C'(1, 4)

Therefore when we reflect ABC across the line x = 2, we get ΔA'B'C', with A' = (1, 1), B'(-1, 1), and C'(1, 4)

2. Reflection of A'B'C' across the line x = -3, gives;

A'(1, 1) (reflection across x = -3) → A''(-7 1)

B'(-1, 1) (reflection across x = -3) → B''(-15 1)

C'(1, 4) (reflection across x = -3) → C''(-7, 4)

The coordinates of the reflection of ΔA'B'C' across the line x = -3 is ΔA''B''C'' = A''(-7 1), B''(-15 1), and C''(-7, 4)

[tex] \\ \tt \longmapsto 2 \frac{1}{3} \div 4\frac{1}{3} = \frac{7}{x} \\ \\ \tt \longmapsto \frac{7}{3} \div \frac{13}{3} = \frac{7}{x} \\ \\ \tt \longmapsto \frac{7}{3} \times \frac{3}{13} = \frac{7}{x} \\ \\ \tt \longmapsto \frac{7}{13} = \frac{7}{x} \\ \\ \tt \longmapsto 7x = 7 \times 13 \\ \\ \tt \longmapsto 7x = 91 \\ \\ \tt \longmapsto x = \frac{91}{7} \\ \\ \tt \longmapsto x = 13[/tex]

Answer:

[tex]x = 13[/tex]

Step-by-step explanation:

[tex] \frac{2 \frac{1}{3} }{4 \frac{1}{3} } = \frac{7}{x} \\ \frac{7}{3} \div \frac{13}{3} = \frac{7}{x} \\ \frac{7}{ 3} \times \frac{3}{13} = \frac{7}{x} \\ \frac{7}{13} = \frac{7}{x} \\ 7x = 13 \times 7 \\ x = \frac{13 \times 7}{7} \\ x = 13[/tex]

Answer:

B

Step-by-step explanation:

The central angle is twice the angle on the circumference, subtended on the same arc, then

a = 0.5 × 110° = 55° → B

the required measure of angle b inscribed in the circle is 125.

A figure is shown, in which a measure of b is to be determined.

The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by

(x - h)² + (y - k)² = r²,

where h, k is the coordinate of the circle's center on a coordinate plane, and r is the circle's radius.

Since, As shown in the figure

the angle subtended by an arc on center is twice the angle subtended by the same are to the point of circumference corresponding point on the circle.

Angle b ,
2b = 360 - 110
2b = 250
b = 250/2
b = 125

Thus, the required measure of angle b inscribed in the circle is 125.

Learn more about circle here:

brainly.com/question/11833983

#SPJ5

Answer:

0.3927 m²

Step-by-step explanation:

Since a post is open at both ends, then it means it has no top nor bottom and as such the surface area is;

S.A = 2πrh

Where;

r is radius

h is height

We are given;

diameter; d = 50mm = 0.05 m

We know that; radius = diameter/2 = 0.05/2 = 0.025 m

Height; h = 2.5 m

Thus;

S.A = 2 × π × 0.025 × 2.5

S.A = 0.3927 m²

Answer:

A

Step-by-step explanation:

I did not look up the actual numbers, but it can only be A.

of course, the whole aim is larger than the nucleus, which is why C is impossible with its negative exponent (which would make the whole aim smaller than the nucleus).

and B. can't be true, because it is so big 10¹⁴ times bigger than a 10-¹⁵ atom ? this would make the whole atom the size of about 10-¹ meters. so, 10 cm. a single hydrogen atom would be bigger than a tennis ball. which it isn't.

so, that only leaves A.

Answer:

$43,799.50

Step-by-step explanation:

USing the formula:

A = P(1+r)ⁿ

n is the time = 5

1 + r = 1.04

P = 36,000

Substitute the values into the formula

A = 36000(1.04)⁵

A = 36,000(1.2166529024)

A = 43,799.50

Hence the value in the fifth year will e $43,799.50

Answer:

C.

[tex]{ \tt{ = \frac{ {x}^{6} - x }{4y} }} \\ = { \tt{ \frac{ {( - 4)}^{6} - ( - 4) }{4(4)} }} \\ = 256.25[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{\dfrac{x^6-x}{4y}}[/tex]

[tex]\mathsf{= \dfrac{-4^6-(-4)}{4(4)}}[/tex]

[tex]\mathsf{-4^6}\\\mathsf{= -1\times 4\times4\times4\times 4\times4\times4}\\\mathsf{\mathsf{= \bf -4,096}}[/tex]

[tex]\mathsf{4\times4}\\\mathsf{= \bf 16}[/tex]

[tex]\mathsf{= \dfrac{-4,096- (-4)}{16}}[/tex]

[tex]\mathsf{-4,096-(-4)}\\\mathsf{= -4,096+4}\\\mathsf{= \bf -4,092}[/tex]

[tex]\mathsf{= \dfrac{-4,092}{16}}\\\\\\\large\textsf{REDUCE IT \& YOU HAVE YOUR ANSWER!}[/tex]

[tex]\mathsf{=\dfrac{-1,023}{4}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf -\dfrac{1,023}{4}}\huge\textsf{ (Option \bf D.)}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

D) 80°

Step-by-step explanation:

(n - 2)180 = 4(180) = 720

78 + 134 + 136 + 132 + 2x + x = 720

3x + 480 = 720

3x = 240

x = 80

Answer:

The answer is D:80 degrees.

Step-by-step explanation:

Find the unit rate by dividing price by total units:

0.98 / 4 pints = 0.245 per pint

1.46/ 6 pints = 0.243 per pint

The 6 pint size has a lower price per point so it is the better deal.

Answer: The second deal is cheaper (6 pints for £1.46)

======================================================

Explanation:

We'll need to convert all the money values to the same format. Either we make everything in terms of pence, or everything in terms of pounds. Otherwise, it's like comparing apples to oranges.

If we go with pence, then the £1.46 converts to 146 pence (multiply by 100).

If we rounded each result to the nearest whole pence, then 24.5 rounds to 25 and 24.33 rounds to 24.

In summary, the unit costs for deals 1 and 2 are 25p and 24p in that order.

The second deal is cheaper by 1 pence per pint. In other words, you save about 1 pence for each pint purchased.

Answer:

5

Step-by-step explanation:

(4/7)/(?/-6)=(-24/35)

(4/7)×(-6/?)=(-24/35)

(4×-6)/(?×7)=(-24/35)

-24/(?×7)=(-24/35)

-->7×?=35

-->?=35÷7

-->?=5

Answer:

y = x + 6

x = 1

y = ¼(x - 5) + 3

Step-by-step explanation:

Vetices are;

A(1,5), B(5,3) and C(-3, -2)

Thus;

Median of AB is; D = (1 + 5)/2, (5 + 3)/2

D = (3, 4)

Median of BC is; E = (5 + (-3))/2, (3 + (-2))/2

E = (1, 0.5)

Median of AC is; F ; (-3 + 1)/2, (-2 + 5)/2

F = (-1, 1.5)

Thus, the median lines will be;

CD, AE & BF.

Thus;

Equation of CD is;

(y - (-3))/(x - (-2)) = (-2 - 4))/(-3 - 3)

(y + 4)/(x + 2) = -6/-6

y - 4 = 1(x + 2)

y = 4 + x + 2

y = x + 6

Equation of AE;

(y - 5)/(x - 1) = (0.5 - 5)/(1 - 1)

(y - 5)/(x - 1) = -4.5/0

Cross multiply to get;

0(y - 5) = -4.5(x - 1)

-4.5x = -4.5

x = 1

Equation of BF;

(y - 3)/(x - 5) = (1.5 - 3)/(-1 - 5)

(y - 3)/(x - 5) = -1.5/-6

(y - 3)/(x - 5) = 1/4

y - 3 = ¼(x - 5)

y = ¼(x - 5) + 3

Answer:

See explanation

Step-by-step explanation:

A 3rd degree binomial with a constant term of 8

A binomial expression is an expression which has only terms such as: x² + 5

The degree of a polynomial is the term with the highest exponent on its variable.

Example: the expression above x² + 5

The exponent of variable, x is 2

So, it is a 2nd degree polynomial

We also have 1st degree polynomial where the highest exponent on the variable is 1

3rd degree polynomial where the highest exponent on the variable is 3

A 3rd degree binomial with a constant term of 8

1. There must be a variable, let say x

2. The highest exponent on the variable must be 3

3. There must be a constant 8

4. The expression must have two terms only

It could be x² + 8 where the coefficient of x is 1

2x² + 8

3x² + 8

It could take any form as long as the highest exponent on the variable is 3 and there are just two terms

Answer:

-5x^2+88

Step-by-step explanation:

Answer:

x = - 4

Step-by-step explanation:

Given a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

Then the equation of the axis of symmetry is

x = - [tex]\frac{b}{2a}[/tex]

f(x) = 2x² + 16x - 19 ← is in standard form

with a = 2, b = 16

Then the equation of the axis of symmetry is

x = - [tex]\frac{16}{4}[/tex] = - 4

Answer:

2x+5x+3x=180°

10x=180°

x=180/10

x=18° ans..

Answer:

18

Step-by-step explanation:

Sum of angles in a straight line is 180,

2x + 5x + 3x = 180

10x = 180

x = 180 / 10

x = 18

Answer:

46

Step-by-step explanation:

4 * 22 ÷ 2 + 2

Multiply and divide from left to right

88 ÷ 2 + 2

44 +2

Add

46

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{\dfrac{4\times22}{2}+2}[/tex]

[tex]\mathsf{4\times22 = \bf 88}[/tex]

[tex]\mathsf{\dfrac{88}{2}+2}[/tex]

[tex]\mathsf{\dfrac{88}{2}=\bf 44}[/tex]

[tex]\mathsf{= 44 + 2}[/tex]

[tex]\mathsf{\bf = 46}[/tex]

[tex]\huge\checkmark\boxed{\huge\textsf{Possible answer \#1: \bf 46}}\huge\checkmark[/tex]

[tex]\huge\text{OR........}[/tex]

[tex]\mathsf{\dfrac{4\times2^2}{2}+2}[/tex]

[tex]\mathsf{2^2}[/tex]

[tex]\mathsf{= 2\times2}[/tex]

[tex]\mathsf{= \bf 4}[/tex]

[tex]\mathsf{= \dfrac{4\times4}{2}+2}[/tex]

[tex]\mathsf{4\times4}[/tex]

[tex]\mathsf{\bf = 16}[/tex]

[tex]\mathsf{= \dfrac{16}{2}+2}[/tex]

[tex]\mathsf{\dfrac{16}{2}}[/tex]

[tex]\mathsf{= \bf 8}[/tex]

[tex]\mathsf{= 8 + 2}[/tex]

[tex]\mathsf{\bf = 10}[/tex]

[tex]\huge\checkmark\boxed{\huge\textsf{Possible answer \#2: \bf 10}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

The x intercept is (-7.5,0) and the y-intercept is (0,5.5)

Answer:

Solution given:

[tex]\bold{4*3^{x+1}-9^{x}=27}[/tex]

let 3^xbe a

4*a*3-a²=27

a²-12a+27=0

a²-9a-3a+27=0

a(a-9)-3(a-9)=0

(a-9)(a-3)=0

either

a=9

3^x=3²

:.x=2

or

a=3

3^x=3^1

x=1

x=2,1

Answer:

10m-5t

Step-by-step explanation:

3(4m-3t) - 2(m-2t)

(12m - 9t) + (-2m+4t)

12m-2m - 9t+4t

10m-5t

Answer:

Step-by-step explanation:

3(4m - 3t) = 12m - 9t    

-2(m - 2t) = -2m + 4t

Write the 2 terms together.

12m - 9t -2m + 4x

12m - 2m - 9t + 4t

10m - 5t

Answer:

?

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√[6 - (-5)]² + (6 - 6)²

√(11)² + (0)²

√121

= 11

Answer: c = 72

Step-by-step explanation:

You didn't tell us which segment has a length of c, but I'm assuming you meant WX because it corresponds to PA. If two figures are similar, we know that their side length are in proportion. With this, we can set up our proportion[tex]\frac{18}{24} =\frac{c}{96}[/tex] where c is the length of WX. By cross multiplying and dividing, you get  72 for the value of c.

Answer:

Total mixture = (8x + 15y) / 100

Step-by-step explanation:

Butterfat x:

= 8% of x

= 8/100 * x

= (8 * x) / 100

= 8x / 100

Butterfat y:

= 15% of y

= 15/100 * y

= (15 * y) / 100

= 15y / 100

Total mixture = butterfat x + butterfat y

= 8x / 100 + 15y / 100

= (8x + 15y) / 100

Total mixture = (8x + 15y) / 100

Answer:

2 sets I think

Step-by-step explanation:

what are the answer choices

Answer:

1       a

2      b

3      c

4      d

Step-by-step explanation:

1b

2d

3c

4a

Answer:

10(4) > 10,000

10-(4) > 0.0001

10(4)/10(2) > 0.000001

10-(4) * 10(2) > 1/10(4) 0.01

Step-by-step explanation:

Answer:

triangle abc = acb

Step-by-step explanation:

ist right answer of this test

Answer:

triangle 1st one ABC=abc

Answer:

YES by SAS

triangle TUV is similar to triangle TLM

Step-by-step explanation:

The ratios of the sides

24/6 = 4

36/9 = 4

so the sides are similar

We know angle UTV = angle LTM because they are vertical angles

we have side included angle side

The triangles are similar by SAS  ( side angle side)

triangle TUV is similar to triangle TLM

Answer:

hope it helps mark me brainlieast!

Step-by-step explanation:

For triangle ABC with sides  a,b,c  labeled in the usual way,

c2=a2+b2−2abcosC  

We can easily solve for angle  C .

2abcosC=a2+b2−c2  

cosC=a2+b2−c22ab  

C=arccosa2+b2−c22ab  

That’s the formula for getting the angle of a triangle from its sides.

The Law of Cosines has no exceptions and ambiguities, unlike many other trig formulas. Each possible value for a cosine maps uniquely to a triangle angle, and vice versa, a true bijection between cosines and triangle angles. Increasing cosines corresponds to smaller angles.

−1≤cosC≤1  

0∘≤C≤180∘  

We needed to include the degenerate triangle angles,  0∘  and  180∘,  among the triangle angles to capture the full range of the cosine. Degenerate triangles aren’t triangles, but they do correspond to a valid configuration of three points, namely three collinear points.

The Law of Cosines, together with  sin2θ+cos2θ=1 , is all we need to derive most of trigonometry.  C=90∘  gives the Pythagorean Theorem;  C=0  and  C=180∘  give the foundational but often unnamed Segment Addition Theorem, and the Law of Sines is in there as well, which I’ll leave for you to find, just a few steps from  cosC=  … above. (Hint: the Law of Cosines applies to all three angles in a triangle.)

The Triangle Angle Sum Theorem,  A+B+C=180∘ , is a bit hard to tease out. Substituting the Law of Sines into the Law of Cosines we get the very cool

2sinAsinBcosC=sin2A+sin2B−sin2C  

Showing that’s the same as  A+B+C=180∘  is a challenge I’ll leave for you.

In Rational Trigonometry instead of angle we use spreads, squared sines, and the squared form of the formula we just found is the Triple Spread Formula,

4sin2Asin2B(1−sin2C)=(sin2A+sin2B−sin2C)2  

true precisely when  ±A±B±C=180∘k , integer  k,  for some  k  and combination of signs.

This is written in RT in an inverted notation, for triangle  abc  with vertices little  a,b,c  which we conflate with spreads  a,b,c,  

(a+b−c)2=4ab(1−c)  

Very tidy. It’s an often challenging third degree equation to find the spreads corresponding to angles that add to  180∘  or zero, but it’s a whole lot cleaner than the trip through the transcendental tunnel and back, which almost inevitably forces approximation.