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Which expressions are equivalent to 2^5/6^5?


A 1/3

B 3^-5

C (-4)^-5

D 2^5 *6^-5

Step-by-step explanation:

the cost of 1 kg mangoes = 147/ 5

= Rs. 29.40

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Answer:

cost of 1 kg mango = rupees 29.4

Step-by-step explanation:

cost of 5 kg mangoes =rupees 147

cost of 1 kg mango =?

Now, lets find cost of 1 kg mangoes

CP od 1 kg mangoes = cost of 5 kg mangoes/5 kg

=rupees 147/5

=rupees 29.4

Answer

Value of a3³+b³-3ab = -1

Explanation

Given a+b=-1----(1)

On cubeing both sides of equation (1), we get

(a+b)³ = (-1)³

Call 98%

we know the algebraic identity:

(x+y)³ = x³+y³ + 3xy(x+y)

=> a³ + b³ +3ab(a+b)= -1

=> a³ + b³ +3ab(-1)=-1

/* from (1)*/

=> a³ + b³-3ab = -1

Therefore,

Value of a³+b³-3ab = -1

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Answer:

28 square units

Step-by-step explanation:

The area of a rectangle is A = l x w.

The length of this rectangle is 7 square units.

The width is 4 square units.

7 x 4 = 28 square units

Answer:

hello

Step-by-step explanation:

Answer:

The multiples of 2 between 1 and 15 are

2, 4, 6, 8, 10, 12, 14

The multiples of 5 are

5, 10, 15

So, there are seven multiples of 2 and three multiples of 5.

The probability of getting a multiple of 2 is

P=\frac{7}{15}= 0.47 (or \ 47\%)P=

15

7

=0.47(or 47%)

The probability of getting a multiple of 5 is

P=\frac{3}{15}=0.2 (or \ 20\%)P=

15

3

=0.2(or 20%)

Now, the probability of getting a multiple of 2 or 5 is

P=0.47+0.20=0.67 (or \ 67\%)P=0.47+0.20=0.67(or 67%)

Therefore, the answer is 67%.

Remember that the probability of one event happening OR another event happening is the sum of the probabilities of those events.

Step-by-step explanation:

hope it helps

Answer:

Step-by-step explanation:

That would be 3.017:  three and seventeen thousandths

Answer:

The slope of line k is - 4 .

Step-by-step explanation:

The slope of given line p is 1/4

Let the slope of line k which is perpendicular to is m.

When the two line are perpendicular to each other, the product of the slopes  is always negative 1.

So, the slope of line k is given by

[tex]m=- \frac{1}{\frac{1}{4}}\\\\m = - 4[/tex]

Answer:

262.50

Step-by-step explanation:

350 x .25 (25 %)=87.50

350-87.50=262.50

or

350x.75=262.50

Note: The image of G after the dilation must be G'(5,-5) instead of G'(5,5).

Given:

The vertices of a rectangle are E(4,8), F(2,8), G(2,-2) and H(-4,-2).

The rectangle is dilated with the origin as the center of dilation so that G's is located at (5,-5).

To find:

The algebraic representation that represents this dilation.

Solution:

If a figure is dilated by factor k with origin as the center of dilation, then the dilation is defined as:

[tex](x,y)\to (kx,ky)[/tex]              ...(i)

Let the given rectangle is dilated by factor k with origin as the center of dilation. Then,

[tex]G(2,-2)\to G'(k(2),k(-2))[/tex]

[tex]G(2,-2)\to G'(2k,-2k)[/tex]

The image of G after dilation is G'(5,-5). So,

[tex](2k,-2k)=(5,-5)[/tex]

On comparing both sides, we get

[tex]2k=5[/tex]

[tex]k=\dfrac{5}{2}[/tex]

So, the scale factor is [tex]k=\dfrac{5}{2}[/tex].

Substituting [tex]k=\dfrac{5}{2}[/tex] in (i), we get

[tex](x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)[/tex]

Therefore, the required algebraic representation to represents this dilation is [tex](x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)[/tex].

Step-by-step explanation:

everything can be found in the picture

The graph of the function f(x)=ax²+bx+c could have the factor of f(x) be ( x + 2) (x - 3)

A relation is a function if it has only One y-value for each x-value.

We can set two functions y₁=x+2 and y₂=x-3

Let us draw these two functions on the graph

We observe that the function  f(x)=ax²+bx+c  intersects y₁ and y₂.

y₁ intersects x axis at (-2, 0)

y₁ intersects y axis at (0, 2)

y₂ intersects x axis at (3, 0)

y₂ intersects y axis at (0, -3)

Hence, the graph of the function f(x)=ax²+bx+c could have the factor of f(x) be ( x + 2) (x - 3)

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Note that the perpendicular bisector to line PQ is constructed and attached accordingly. Here is how to do it.

Note that the first stage is to draw a line PQ. But this has already been done.

Next is to place the compass on P as shown in the image above. If you allow you compass (locked at the same degree) to rotate about point P, you will get a circle. However, that is not the objective.

If you also place your compass on point Q, locked to the same degree as when it was on P, and take a rotation around point Q, you will also get a circle.

At some point, you will notice that both circles intersect at two point, which we can call AB₁ and AB₂.

Now you are done with the compass. Take up your ruler, and place it such that it meet both AB₁ and AB₂ but allowing you space to mark a line connecting both points.

Next, using your live or online pencil tool, draw the line from AB₁ to AB₂. Now you have the Perpendicular bisector which you can call AB₁₂.

Note that a perpendicular bisector is a line or plane that intersects a line segment at its midpoint, forming a right angle and dividing the segment into two equal parts.

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Answer:

you got it keep working

Step-by-step explanation:

Answer:

D.(4^1/2)^4

hope this helps

have a good day :)

Step-by-step explanation:

Answer: y−26=4(x−1)

Step-by-step explanation:

Answer:

Y=3/2X + 3

Step-by-step explanation:

Y= mX + b

b is the y intercept or the Y number for when the point is in place o for X

(0, 3) is the Y intersect so b is 3

this is shown on the diagram I drew below

m is the slope of the line and can be calculated

m = change in Y/ Change in X

Our change in Y is 6-3

And out change is X is 2-0

So

m = 3/2

This is shown on the image below

Y=3/2X + 3

Answer: 140 square inches OR 140 inches^2

Step-by-step explanation:

To start, you can create a net of the shape. Or, you can just use the numbers you are given. Find the area of the triangles, and then add the area of the base.

Base: 8*7 = 56

Triangles: [TIP: DON’T DIVIDE BY 2! IT’S A WASTE OF TIME! JUST MULTPLY BY TWO TO GET THE VALUE OF THE FOUR TRIANGLES!]

Triangles:

(6*7)*2=x

42*2=84

Then, add the two area values together.

84+56= 140

Add the units (ONLY IN SQUARE INCHES, BECAUSE WE ARE NOT FINDING THE AREA!)

Answer:

1

Step-by-step explanation:

Given :

[tex]\frac{1}{6}[/tex]   divided by [tex]\frac{1/2}{3}[/tex]

Now, it can be solving as:

[tex]\frac{1/6}{\frac{\frac{1}{2} }{3} } \\=\frac{\frac{1}{6} }{\frac{1}{6} } \\=1[/tex]

Simplest form of given equation is 1

Answer:

Multiplication properly of equality

Answer:

tan 260 = 5.670

Step-by-step explanation:

What is tangent (260) rounded to the nearest hundredth

Given data

θ=260

We want to find the value of

tan θ

Hence, from table

tan 260= 5.670

Answer:

Step-by-step explanation:

Let's FOIL this out and get it into standard form. That gives us:

[tex]h(t)=-4.9t^2+490[/tex] For #1, then:

The height of something when it is on the ground is 0; that means that the h(t) is 0. This allows us to factor the quadratic and solve for t:

[tex]-4.9t^2=-490[/tex] and divide both sides by 4.9 to get

[tex]t^2=100[/tex] so

t = 10. Notice that one of the factors for that quadratic is 10 - t. That factor represents the time it takes to hit the ground. So you might ask why, then, we FOILed this out in the first place if the answer was ight in front of our noses. The reason is becase of #2 that is asking us what the initial height of the object was. That is found in the standard form...in the constant in particular. The initial height is 490 m. That's how you know (because the constant represents the height from which an object is dropped in either free fall, which this is, or in parabolic motion).

Answer:

p=-5

Step-by-step explanation:

5p-3p=-2-8

2p=-10

p=-5

Answer:

∠ BOC = 30°

Step-by-step explanation:

Given ∠ COF = 150°

∠ BOC + ∠ COF = 180° ( BF is a straight angle ) , that is

∠ BOC + 150° = 180° ( subtract 150° from both sides )

∠ BOC = 30°

Answer:

[tex]AB[/tex] is parallel to [tex]CD[/tex] ([tex]AB ||CD[/tex])

Step-by-step explanation:

In a set of parallel lines cut by the traversal, [tex]\angle AHG[/tex] and [tex]\angle DGH[/tex] are alternate interior angles. In a set of parallel lines cut by a traversal, alternate interior angles are always equal. Therefore, since [tex]\angle AHG=\angle DGH=115^{\circ}[/tex] (they are equal), the lines AB and CD must be parallel.

*A set of parallel lines proves that alternate interior angles are always equal, but the converse is also true in that equal alternate interior angles proves a set of parallel lines. This is because if you changed the angle measure of either of the angles, the relative slope of the lines must change and they would no longer be parallel.

Answer:

where is the problem

Step-by-step explanation: