Answer:
let me work on it
Step-by-step explanation:
Jackson's current salary is $36,000 per year. Each year his salary is 1.04 times the previous yeal's salary. What
will his salary be in his 5th year?
OA) $42,214.92
OB) $42,114.91
Use ratios to convert each measurement.
1. 3 yards = _____ feet
2. _____ cups= 5 gallons
3. 72 inches =_____ yards
4. ______ ounces = 5 pounds
5. ______ inches =7 feet
6. 24 feet = _____ yards
7. 40 pints = ______ gallons
8. 16 cups = ______ quarts and
9. ________ inches = 4 yards
10. 48 ounces = ________ Pounds
Answer:
1. 3 yards= 9 feet
2. 78 cups=5 gallons
3. 72 inches = 2 yards
4. 80 ounces = 5 pounds
5. 84 inches = 7 feet
6. 24 feet = 8 yards
7. 40 pints = 5 gallons
8. 16 cups = 5 quarts
9. 144 inches = 4 yard
10. 48 ounces = 3 pounds
Find Y. Do not round answer.
Answer:
Does the answer help you?
identify the area of a regular decagon with side length 2 m rounded to the nearest tenth
Answer:
Area = 14.8
Step-by-step explanation:
Area = 5/2 + a^2*sqrt(5 + 2 sqrt(5) )
This formula given the side length, calculates the area.
a = 2
Area = 2.5 + 2^2 * sqrt(5 + 2*sqrt(5) )
Area = 2.5 + 4 * sqrt(5 + 2*2.236)
Area = 2.5 + 4* sqrt(5+ 4.4721)
Area = 2.5 + 4*sqrt(9.4721)
Area = 2.5 + 4*3.0776
Area = 2.5 + 12.3107
Area = 14.8107
Answer:
A ≈ 30.8 m2
Step-by-step explanation:
Give one pair of supplementary angles and one pair of vertical angles shown in the figure below.
(a) Supplementary angles:
(b) Vertical angles:
Answer:
<5 and <6 are supplementary angles
<1 and <6 are vertical angles
what’s the answer?? please help
Answer:
W
Step-by-step explanation:
I done it before
Solve the equation.
3(n+4)=12(6n+4)
Answer:
n = -12/23
Step-by-step explanation:
A car is travelling in the velocity of 20 m/ s . After 30 sec it covers a distance of 1200 m. Calculate the acceleration of car and the final velocity of the car
Answer:
given values are:
u=20 m/st= 30 ss= 1200 mv= ?a=?s = ut + 1/2 at²1200 = 20×30 + 1/2 × 30²a
1200= 600 + 1/2 × 900a
600 = 450a
a = 600 / 450
a = 1.33 m/s²
v²= u² +2asv² = 20² +2 × 1.33 × 1200
v²= 400 + 3192
v = √3592
v = 59.9 ≈ 60 m/s
Help!!! please!!! Confused!
Martine grew at an average rate of 6cm/year for the first 18 years of her life. If Martine was 50 cm long when she was born, how tall was Martine when she turned 18?
Answer:
158cm
Step-by-step explanation:
Martine had the height of 50cm when born.
Every year she grows at an average rate of 6cm
So the the first 18 years will be 6cm × 18 = 108cm
She will be 108cm + 50cm = 158cm tall by the time she turns 18 years
50cm + (6 × 18)cm
50cm + (6 × 18)cm50cm + 108cm
50cm + (6 × 18)cm50cm + 108cm158cm
48-15÷{3×(-2-4+11)}+12
Answer:
35
Step-by-step explanation:
48-15÷(3×5)+12
48-15÷15+12
48-1+12
59
If fx) = 2х2 - 5 and g(x) = 3х+3, find (f-g)(x).
ОА. -Х? - 8
В. 3х - 2x2 - 2
Ос. 2х - 3x-2
OD. 2х2 – 3х – 8
Answer:
Solution given:
f(x)=2x²-5
g(x)=3x+3
now
(f-g) (x)=?
we have
(f-g)(x)=f(x)-g(x)
=2x²-5-(3x+3)=2x²-5-3x-3adding or subtracting common term=2x²-3x-8Answer:
[tex]2x^{2} - 3x - 8[/tex]
Step-by-step explanation:
Step 1: Define what (f-g)(x) means
(f-g)(x) means that we have two different functions, f(x) and g(x). (f-g)(x) is a shorter way of writing f(x) - g(x). Therefore you just plug in the equations and combine like terms.
Step 2: Find (f-g)(x)
[tex]f(x) = 2x^{2} - 5[/tex]
[tex]g(x) = 3x + 3[/tex]
[tex](f-g)(x) = 2x^{2} - 5 - (3x + 3)[/tex]
[tex](f-g)(x) = 2x^{2} - 5 - 3x - 3[/tex]
[tex](f-g)(x) = 2x^{2} - 3x - 8[/tex]
Answer: [tex]2x^{2} - 3x - 8[/tex]
The surface area of a cylinder is given by the formula
S = 30πr + 2πr2
How many times greater is this compared to a circle with A = πr2
Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2) , Given volume and lateral area: r = 2 * V / A_l , Given base area: r = √(A_b / (2 * π)) , Given lateral area and total area: r = √((A - A_l) / (2 * π)) .
.Prove a+ar+ar2+………+arn-1=a(rn -1 ) r-1
Answer:
See below.
Step-by-step explanation:
Call the sum of the first n terms S.
S = a + ar + ar^2 + ar^3 + ... + ar^(n -1)
Multiply both sides by r.
Sr = ar + ar^2 + ar^3 + ar^4 + ... + ar^n
No subtract S - Sr.
S = a + ar + ar^2 + ar^3 + ar^4 + ... + ar^(n -1)
(-) Sr = ar + ar^2 + ar^3 + ar^4 + ... + ar^(n - 1) + ar^n
-------------------------------------------------------------------
S - Sr = a - ar^n
S(1 - r) = a(1 - r^n)
S = a(1 - r^n)/(1 - r)
S = a(r^n - 1)/(r - 1)
a + ar + ar^2 + ar^3 + ... + ar^(n -1) = a(r^n - 1)/(r - 1)
Please help I will give you Brainlyest
Answer:
a. You can find the value of 4w by using inverse operations. Subtract 8 from both sides in the equation 4w+8=32. You will get 4w=24. Now, you divide 4 by both sides to get w by itself. You will soon get 6. Now multiply 6 and 4, coming to the conclusion that 4w=24.
b. To find the value of w using the value of 4w, which is 24, simply use inverse operations once more. Using the equation 4w=24, we can use division and divide 4 by both sides, leaving us with w by itself. We end up with w=6. The value of w is 6.
c. You can check if the value of w is correct by plugging in your number back into the equation. Our equation is 4w+8=32, so we replace w with 6, the value for w that we found. We end up with 4(6)+8=32. Multiply 4 by 6, ending up with 24, then add it to 8, coming up with 32. 4(6)+8=32, which shows us that 6 is the correct value for w.
Which statement is true about the given function?
Answer:
it's the 3rd option
Step-by-step explanation:
f(x) 0 over the intervals (–∞ –3)
Hope it's right
5. The distance between two given points (5,2) and (x,5) is 5 units. Find the possible values of x. *
============================================================
Explanation:
We'll use the distance formula here. Rather than compute the distance d based on two points given, we'll go in reverse to use the given distance d to find what the coordinate must be to satisfy the conditions.
We're given that d = 5
The first point is [tex](x_1,y_1) = (5,2)[/tex] and the second point has coordinates of [tex](x_2,y_2) = (x,5)[/tex] where x is some real number.
We'll plug all this into the distance formula and solve for x.
[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\5 = \sqrt{(5-x)^2+(2-5)^2}\\\\5 = \sqrt{(5-x)^2+(-3)^2}\\\\5 = \sqrt{(5-x)^2+9}\\\\\sqrt{(5-x)^2+9} = 5\\\\(5-x)^2+9 = 5^2\\\\(5-x)^2+9 = 25\\\\(5-x)^2 = 25-9\\\\(5-x)^2 = 16\\\\5-x = \pm\sqrt{16}\\\\5-x = 4 \ \text{ or } \ 5-x = -4\\\\-x = 4-5 \ \text{ or } \ -x = -4-5\\\\-x = -1 \ \text{ or } \ -x = -9\\\\x = 1 \ \text{ or } \ x = 9\\\\[/tex]
This means that if we had these three points
A = (5, 2)B = (1, 5)C = (9, 5)Then segments AB and AC are each 5 units long.
Which is 1/3+1/4?
FASTBRIDGE!!
Option B is 1/3 + 1/4.
1/3 + 1/4 is equal to 7/12.
Here, we have,
To find the sum of 1/3 and 1/4, you need to have a common denominator.
The common denominator of 3 and 4 is 12.
To make the fractions have the same denominator, you can convert them as follows:
1/3 = (1/3) * (4/4) = 4/12
1/4 = (1/4) * (3/3) = 3/12
Now that both fractions have a denominator of 12, you can add them together:
1/3 + 1/4 = 4/12 + 3/12 = (4+3)/12 = 7/12
Therefore, 1/3 + 1/4 is equal to 7/12.
now, from the given options, we have,
in option B. it is indicating that,
2/6 + 1/4
=> 1/3 + 1/4.
Hence, Option B is 1/3 + 1/4.
To earn more on addition click:
brainly.com/question/29560851
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what do you mean by trigonometry
Answer:
Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangle
If the ratio of raisins to bran flakes in a box of raisin bran flakes cereal is 3:27, how many raisins are there in a box that contains 3,000 raisins and brand flakes?
Answer:
300 raisins
Step-by-step explanation:
sum the parts of the ratio, 3 + 27 = 30 parts
Divide the total by 30 for the value of one part of the ratio.
3000 ÷ 30 = 100 ← value of 1 part of the ratio , then
3 parts = 3 × 100 = 300 ← number of raisins in a box
Bro please help I will Mark you as brainlist
the first one is, yes by AA
the second is no you cannot
Factorise 7a³b²_14a²b³
Answer:
7a²b²(a - 2b)
Step-by-step explanation:
Given
7a³b² - 14a²b³ ← factor out 7a²b² from each term
= 7a²b²(a - 2b)
5/9+8/9 can someone please help me with this math question? All I know is that you have to add the fractions, Express the sum as a proper fraction or a mixed number.
Answer:
13/9
Step-by-step explanation:
Given
5/9 + 8/9
Both fractions have the same denominator.
Therefore, pick one of the denominator and add the numerators
5/9 + 8/9
= (5+8) / 9
= 13/9
5/9 + 8/9 = 13/9
Find the volume of the water tank shown.
Depth: 1.8 m
Diameter : 2.4m
Volume = ? m3 (nearest m3)
Answer:
Step-by-step explanation:
r = d/2
r = 2.4 m/2 = 1.2
h = 1.8
pi = 3.14
Volume = pi * r^2 * h
Volume = 3.14 * 1.2^2 * 1.8
Volume = 8.139
Volume = 8 to the nearest m^3
What are the solutions to 3( x + 2)(x – 9) = 0
Mark Brainliest if correct:
x = -2, 9
Step-by-step explanation:
x2: x + 2 = 0
x = -2
x1: x - 9 = 0
x = 9
x = -2, 9
Hi everyone, I’m currently trying to dive into some lessons before school starts and I’m taking algebra 2 this year and the lessons that I am currently studying about is imaginary numbers. I had a few questions so if anyone could help me out that’d be great! Starting off, while watching the video, the guy explaining says that j^4 = 1 because it is like j times j^3 and I’m just confused because I don’t understand where they got the 1 from…
Someone PLEASE help me.
Solve for the indicated variable in the parentheses.
y= 5x*6 (x)
Step-by-step explanation:
a is the answer if is wrong I'm sorry
what is the answer for 17-51 163
Answer:
The answer is -51146
Step-by-step explanation:
Just substract simple
If no grouping symbols or exponents are in an expression, then do _____ first.
Helppppp me plss, I’ll mark u as brainlest
[tex] \large\color{lime}\boxed{\colorbox{black}{Answer : - }}[/tex]
We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, cos(A + B) = cos 90º = 0
A, 3-2x=3(x+4)-x-1
B, 5x(x-1)-4(x-1)=0
Answer:
Step-by-step explanation:
[tex]\displaystyle \Large \boldsymbol{} \tt a) \ 3-2x=3(x+4)-x-1\\\\3-2x=3x+12-x-1 \\\\3-12+1=3x+2x-x \\\\4x=-8 \\\\\boxed{ \tt x=-2} \\\\\\b) \ 5x\underline{(x-1)}-4\underline{(x-1)}=0 \\\\\\(5x-4)(x-1)=0 \Longrightarrow \boxed{ \tt x_1=0.8 \ \ ; \ \ x_2=1}[/tex]
