Point A is located at (-2,-2). Plot all of the points 3 units away that have the same y-coordinate as point A.

Answer:

Points are ( 1, -2) , (-5, -2)

Step-by-step explanation:

the given point is A ( -2, -2)

If we fix the y coordinate , then we can change only x coordinate

As we want point 3 unit away

So, add 3 and subtract 3 from x coordinate to find the resultant point

If we add 3 to x coordinate , we get

-2 + 3 = 1

So the point be ( 1, -2)

If we subtract 3 to x coordinate , we get

-2 - 3 = -5

So the point be ( -5, -2)

The graph is as follows :

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look yall i got 10 math questions if you get all ten right brainlliest so if yall could help a man out here it would be great
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1.)Which of the following best describes the squaring property of equality?
A.
if a=b,then [tex]a^{2} =b^{2}[/tex]
B
if [tex]a\leq b then a^{2} \leq b^{2}[/tex]
C
[tex]if a\geq b then a^{2} \geq b^{2}[/tex]
D
[tex]if a \neq b then a^{2} \neq b^{2}[/tex]

2.)Solve for x.
[tex]\sqrt{x-2} =9[/tex]
A.
11
B.
20
C.
83
D
no solution

3.)The length of a side of a square is [tex]\sqrt{x^{2}-4 }[/tex] If the area of the square is 12, find x.
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B.
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C.
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D.
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A.
no solution
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C.
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D.
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5.)solve for x[tex]x^{2} +5=30[/tex]

A.
±25
B.
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6.)The acceleration of an object can be described by the equation[tex]a=\frac{2d}{t²} where a is acceleration, d is the distance, and t is time. Suppose an object accelerates for a distance of 15 meters. Which of the following equations relates the time to the acceleration?
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B.
[tex]t=\sqrt{\frac{a}{15} }[/tex]
C.
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D.
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7.)The acceleration of an object can be described by the equation [tex]a=\sqrt{\frac{2d}{t²} }[/tex] , where a is acceleration, d is the distance, and t is time. Suppose an object accelerates at a rate of 5 meters per second squared. Which of the following equations relates the time of the acceleration to the distance?
A.
[tex]t=\sqrt{10d}[/tex]
B.
[tex]t=\sqrt{2d}[/tex]
C.
[tex]t=\sqrt{\frac{5d}{2} }[/tex]
D.
[tex]t=\sqrt{\frac{2d}{5} }[/tex]

8.)Solve for x [tex]\sqrt{2x+8}=2[/tex]

A.
2
B.
–3
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–2
D.
no solution

9.)Solve for x:[tex]\sqrt{3x-2}=2[/tex]

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2
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[tex]-\frac{2}{3}[/tex]
C.
–2
D.
no solution

10.)What is the first step to solve the equation [tex]x^{2} -3=15[/tex]
A.
Take the square root of [tex]x^{2}[/tex], 3, and 15.
B.
Square 15.
C.
Add 3 to both sides of the equation.
D.
Add 1 to both sides of the equation.

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The club has a total of 240 players.
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