It does not appear that police can use a shoe print length to estimate the height of a male.
The given parameters are:
[tex]\begin{array}{cccccc}{Shoe\ Print} & {28.6} & {29.4} & {32.2} & {32.4} & {27.3} \ \\ Height (cm) & {172.5} & {176.7} & {188.4} & {170.1} & {179.2} \ \end{array}[/tex]
Rewrite as:
[tex]\begin{array}{cccccc}{x} & {28.6} & {29.4} & {32.2} & {32.4} & {27.3} \ \\ y & {172.5} & {176.7} & {188.4} & {170.1} & {179.2} \ \end{array}[/tex]
See attachment for scatter plot
To determine the correlation coefficient, we extend the table as follows:
[tex]\begin{array}{cccccc}{x} & {28.6} & {29.4} & {32.2} & {32.4} & {27.3} & y & {172.5} & {176.7} & {188.4} & {170.1} & {179.2} & x^2 & {817.96} & {864.36} & {1036.84} & {1049.76} & {745.29} & y^2 & {29756.25} & {31222.89} & {35494.56} & {28934.01} & {32112.64} & x \times y & {4933.5} & {5194.98} & {6066.48} & {5511.24} & {4892.16} \ \end{array}[/tex]
The correlation coefficient (r) is:
[tex]r = \frac{\sum(x - \bar x)(y - \bar y)}{\sqrt{SS_x * SS_y}}[/tex]
We have:
[tex]n =5[/tex]
[tex]\sum xy =4933.5+5194.98+6066.48+5511.24+4892.16 =26598.36[/tex]
[tex]\sum x =28.6+29.4+32.2+32.4+27.3=149.9[/tex]
[tex]\sum y =172.5+176.7+188.4+170.1+179.2=886.9[/tex]
[tex]\sum x^2 =817.96+864.36+1036.84+1049.76+745.29=4514.21[/tex]
[tex]\sum y^2 =29756.25+31222.89+35494.56+28934.01+32112.64=157520.35[/tex]
Calculate mean of x and y
[tex]\bar x = \frac{\sum x}{n} = \frac{149.9}{5} = 29.98[/tex]
[tex]\bar y = \frac{\sum y}{n} = \frac{886.9}{5} = 177.38[/tex]
Calculate SSx and SSy
[tex]SS_x = \sum (x - \bar x)^2 =(28.6-29.98)^2 + (29.4-29.98)^2 + (32.2-29.98)^2 + (32.4-29.98)^2 + (27.3-29.98)^2 =20.208[/tex]
[tex]SS_y = \sum (y - \bar x)^2 =(172.5-177.38)^2 + (176.7-177.38)^2 + (188.4-177.38)^2 + (170.1-177.38)^2 + (179.2-177.38)^2 =202.028[/tex]
Calculate [tex]\sum(x - \bar x)(y - \bar y)[/tex]
[tex]\sum(x - \bar x)(y - \bar y) = (28.6-29.98)*(172.5-177.38) + (29.4-29.98)*(176.7-177.38) + (32.2-29.98)*(188.4-177.38) + (32.4-29.98)*(170.1-177.38) + (27.3-29.98) *(179.2-177.38) =9.098[/tex]
So:
[tex]r = \frac{\sum(x - \bar x)(y - \bar y)}{\sqrt{SS_x * SS_y}}[/tex]
[tex]r = \frac{9.098}{\sqrt{20.208 * 202.028}}[/tex]
[tex]r = \frac{9.098}{\sqrt{4082.581824}}[/tex]
[tex]r = \frac{9.098}{63.90}[/tex]
[tex]r = 0.142[/tex]
Calculate test statistic:
[tex]t = \frac{r}{\sqrt{\frac{1 - r^2}{n-2}}}[/tex]
[tex]t = \frac{0.142}{\sqrt{\frac{1 - 0.142^2}{5-2}}}[/tex]
[tex]t = \frac{0.142}{\sqrt{\frac{0.979836}{3}}}[/tex]
[tex]t = \frac{0.142}{\sqrt{0.326612}}[/tex]
[tex]t = \frac{0.142}{0.5715}[/tex]
[tex]t = 0.248[/tex]
Calculate the degrees of freedom
[tex]df = n - 2 = 5 - 2 = 3[/tex]
The [tex]t_{\alpha/2}[/tex] value at:
[tex]df =3[/tex]
[tex]t = 0.248[/tex]
[tex]\alpha = 0.01[/tex]
The value is:
[tex]t_{0.01/2} = \±5.841[/tex]
This means that we reject the null hypothesis if the t value is not between -5.841 and 5.841
We calculate the t value as:
[tex]t = 0.248[/tex]
[tex]-5.841 < 0.248 < 5.841[/tex]
Hence, we do not reject the null hypothesis because they do not appear to have any correlation.
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Can I please get help it’s urgent . Find the lateral surface area and volume of the solid object.
27. Which statement is true about the system x+3y=11 y=r-7 a. (8,-1) is a solution to both equations, so it is a solution to the system b. (8,-1) is a solution to one equation but not the other, so it is a solution to the system C. (8,-1) is a solution to one equation but not the other so it is not the solution to the system d. (8,-1) is not a solution to either equation, so it is not a solution to the system
Answer:b. (8,-1) is a solution to one equation but not the other, so it is a solution to the system
Step-by-step explanation:
27. Which statement is true about the system
x+3y=11
y=r-7
a. (8,-1) is a solution to both equations, so it is a solution to the system
b. (8,-1) is a solution to one equation but not the other, so it is a solution to the system
C. (8,-1) is a solution to one equation but not the other so it is not the solution to the system
d. (8,-1) is not a solution to either equation, so it is not a solution to the system
Onetta goes to the food court to get a salad and sandwich for lunch. The Daily Deli has 8 varieties of sandwiches and 3 salads. Better Bites has 2 varieties of sandwiches and 7 salads. The Lunch Spot has 5 varieties of sandwiches and 8 salads. Determine the number of ways Onetta can select a sandwich and a salad.
Answer:
Onetta can salect a sandwich and a salad in 78 different ways.
Step-by-step explanation:
Since Onetta goes to the food court to get a salad and sandwich for lunch, and the Daily Deli has 8 varieties of sandwiches and 3 salads, while Better Bites has 2 varieties of sandwiches and 7 salads, and the Lunch Spot has 5 varieties of sandwiches and 8 salads, to determine the number of ways Onetta can select a sandwich and a salad, the following calculation must be performed:
8 x 3 + 2 x 7 + 5 x 8 = X
24 + 14 + 40 = X
78 = X
Therefore, Onetta can salect a sandwich and a salad in 78 different ways.
Evaluate 3x ^ 2 + 3x - 9 , when x = 2
A=-3
B=3
C=9
D=27
Answer:
C. 9
Step-by-step explanation:
Start plugging in the number 2
3(2)^2+3(2)-9
6^2+6-9
12+6-9
18-9
9
Given $f(x) = \frac{\sqrt{2x-6}}{x-3}$, what is the smallest possible integer value for $x$ such that $f(x)$ has a real number value? Please show steps. Thank you!
(I rewrote the question without the symbols, they are the same question)
Given f(x) = {2x-6}/{x-3}, what is the smallest possible integer value for x such that f(x) has a real number value? Thank you!
===========================================================
Explanation:
The given function is
[tex]f(x) = \frac{\sqrt{2x-6}}{x-3}[/tex]
which is the same as writing f(x) = ( sqrt(2x-6) )/(x-3)
The key for now is the square root term. Specifically, the stuff underneath. This stuff is called the radicand.
Recall that the radicand cannot be negative, or else the square root stuff will result in a complex number. Eg: [tex]\sqrt{-4} = 0+2i[/tex]
The question is basically asking: what is the smallest x such that [tex]\sqrt{2x-6}[/tex] is a real number?
Well if we made 2x-6 as small as possible, ie set it equal to 0, then we can find the answer
[tex]2x-6 = 0\\\\2x = 6\\\\x = 6/2\\\\x = 3\\\\[/tex]
I set the radicand equal to 0 because that's as small as the radicand can get (otherwise, we're dipping into negative territory).
So 2x-6 set equal to 0 leads to x = 3.
This means x = 3 produces the smallest radicand (zero) and therefore, it is the smallest allowed x value for that square root term.
But wait, if we tried x = 3 in f(x), then we get...
[tex]f(x) = \frac{\sqrt{2x-6}}{x-3}\\\\f(3) = \frac{\sqrt{2*3-6}}{3-3}\\\\f(3) = \frac{\sqrt{0}}{0}\\\\[/tex]
which isn't good. We cannot have 0 in the denominator. Dividing by zero is not allowed. The result is undefined. It doesn't even lead to a complex number. So we'll need to bump x = 3 up to x = 4. You should find that x = 4 doesn't make the denominator 0.
----------------
In short, we found that x = 3 makes the square root as small as possible while staying a real number, but it causes a division by zero error with f(x) overall. So we bump up to x = 4 instead.
please help me with this on the image
Answer:
6ab
Step-by-step explanation:
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective.
a. Suppose a sample of 865 floppy disks is drawn. Of these disks, 112 were defective. Using the data, estimate the proportion of disks which are defective.
b. Suppose a sample of 865 floppy disks is drawn. Of these disks, 112 were defective. Using the data, construct the 95% confidence interval for the population proportion of disks which are defective.
Answer:
a) 0.1295
b) The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).
Step-by-step explanation:
Question a:
112 out of 865, so:
[tex]\pi = \frac{112}{865} = 0.1295[/tex]
Question b:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 865, \pi = 0.1295[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 - 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1071[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 + 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1519[/tex]
The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).
©/17
Correct
Question 1 of 17, Step 1 of 1
Write a mixed number to describe the length of the ribbon shown in the figure below.
Please enter your answer in the box below.
Inches
Answer
How to enter your answer
If your answer is a whole number, enter it in the left most box and leave the numerator and denominator boxes blank.
9514 1404 393
Answer:
3 3/8 inches
Step-by-step explanation:
If you spend a little time looking at the marks on the ruler, you see that the smallest marks divide each inch into 8 parts. The ribbon comes to the 3rd small mark* after the 3-inch mark, so the length of the ribbon is 3 3/8 inches.
_____
* Technically, it is the second small mark, as the marks are small, medium, small. It marks the end of the third space, where each space is 1/8 inch.
You need to design a rectangle with a perimeter of 14.2 cm. The length must be 2.4 cm. What is the width of the
rectangle? (You might want to draw a picture.)
a) Let w = the width of the rectangle. Write the equation you would use to solve this problem.
b) Now solve your equation
* cm.
The width of the rectangle must be. Cm
Part (a)
Answer: 2(2.4+w) = 14.2--------------
Explanation:
L = 2.4 = length
W = unknown width
The perimeter of any rectangle is P = 2(L+W)
We replace L with 2.4, and replace P with 14.2 to get 14.2 = 2(2.4+w) which is equivalent to 2(2.4+w) = 14.2
========================================================
Part (b)
Answer: w = 4.7--------------
Explanation:
We'll solve the equation we set up in part (a)
2(2.4+w) = 14.2
2(2.4)+2(w) = 14.2
4.8+2w = 14.2
2w = 14.2-4.8
2w = 9.4
w = 9.4/2
w = 4.7
The width must be 4.7 cm.
Workbook
WB-21
38. What is the circumference of a circle that has a diameter of 12 inches? (Use
3.14 for 1.)
a. 15.14 inches
b. 37.68 inches
c. 376.8 inches
d. 9.42 inches
Answer:
37.68
Step-by-step explanation:
Formula for finding the circumference of a circle is C = 2πr
If you substitute the numbers in you should get 37.68.
Can’t find answers online to check mine.
Answer:
3. 100% = 1
3/4 = 0.75
Now, 0.75 is halfway between 0.5 and 1, so Chris is correct.
4. 10% = 10/100 = 0.1
3/5 = 0.6
Now, 0.2 is not halfway between 0.1 and 0.6, so Emily is wrong.
Answer:
3 đúng 4 wrong
Step-by-step explanation:
100%=1
giữa 0, 5 và 1 =(0,5+1)/2=3/4
10%= 0,1
giữa 0,1 và 3/5 =(0,1+3/5)/2= 0,35 #0,2
Help with question b please
9514 1404 393
Answer:
(a) 5.82 cm (correctly shown)
(b) 10.53 cm
Step-by-step explanation:
a) The length BC can be found from the law of sines:
BD/sin(C) = BC/sin(D)
BC = BC·sin(C)/sin(D) = (6 cm)sin(48°)/sin(50°) ≈ 5.82 cm
__
b) The angle ABD is the sum of the angles shown:
angle ABD = 50° +48° = 98°
We know the lengths BA and BD and the included angle ABD, so we can use the law of cosines to find AD.
AD² = BA² +BD² -2·BA·BD·cos(98°)
AD² ≈ 8² +5.82² -2(8)(5.82)(-0.139173) ≈ 110.8411
AD ≈ √110.8411 ≈ 10.53 . . . . cm
PAIesung
0 Weber
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Reading list
- Blake bought a motorcycle for $550 last year and sold it for $330 this year. What is his sale
price as a percentage of his purchase price?
Answer:
The sale price was 60% of the purchase price.
Step-by-step explanation:
Given that Blake bought a motorcycle for $ 550 last year and sold it for $ 330 this year, to determine what is his sale price as a percentage of his purchase price, the following calculation must be performed:
550 = 100
330 = X
330 x 100/550 = X
33000/550 = X
60 = X
Therefore, the sale price was 60% of the purchase price.
Which equation models the same quadratic relationship as function f? f(x) = 2x^2 - 12x + 11
A) y = 2(x + 6)^2 + 2
B) y = 2(x - 3)^2 -7
C) y = 2(x - 6)^2 + 5
D) y = 2(x + 3)^2 - 7
Answer:
im not sure but i think the answer is C) y = 2(x - 6)^2 + 5
The equation models the same quadratic relationship as function f(x) = 2x^2 - 12x + 11 will be 2(x-3)²-7.Option B is correct.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, the function is,
f(x) = 2x^2 - 12x + 11
We have to find the equation models the same quadratic relationship as the given function,
⇒2x²-12x+11
Take common 2 in the complete equation,
⇒2(x²-6x+11/2)
Add and subtract 9 from the complete equation,
⇒2(x²-6x+9-9+11/2)
Rearrange the equation as,
⇒2[(x-3)²-(7/2)]
⇒2(x-3)²-7
Thus, the equation models the same quadratic relationship as function f(x) = 2x^2 - 12x + 11 will be 2(x-3)²-7.Option B is correct.
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Hi- how do we calculate the distance from C to D? Thanks so much!
Answer:
CD=20
Step-by-step explanation:
Use the pythagorean theorem: a²+b²=c²
(20√2)²-20²=a²
400(2)-400
800-400=400
√400=20
. Tachycardia means ...................heart rate a) fast b) slow c) irregular d) arrhythmic
Answer:
no entiendo inglés........,
Hi,
Answer:
Tachycardia is a fast heart rate
NO LINKS OR ANSWERING WHAT YOU DON'T KNOW. THIS NOT A TEST OR AN ASSESSMENT. PLEASE HELP ME WITH THESE MATH QUESTIONS FOR AN ASSIGNMENT!!! Chapter 10 part 1
1. What is an extraneous solution and what type of functions might they occur in?
2. Given a vertical asymptote and horizontal asymptote, how would you begin to find an expression for a rational function?
Answer:
1.
An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
Mr. Thomas invested an amount of ₱13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be ₱3508, what was the amount invested in Scheme B?
9514 1404 393
Answer:
₱6400
Step-by-step explanation:
Let 'b' represent the amount invested in scheme B. Then 13900-b is the amount invested in scheme A. The total interest for 2 years is then ...
14%(13900-b)(2) +11%(b)(2) = 3508
1946 -0.03b = 1754 . . . . . . divide by 2, simplify
-0.03b = -192 . . . . . . . . . subtract 1946
b = 6400 . . . . . . . . . . . divide by -0.03
The amount invested in scheme B was ₱6400.
Reflect figure E across the x-axis and then reflect across the y-axis. What is the resulting figure?
rectangle D
B
rectangle B
9
rectangle C
10
rectangle A
Answer:
2nd option, rectangle B
Step-by-step explanation:
After reflexion, the figure will be at the left side of x=-5
Find m/c.
A
18 in
12 in
C
B
28 in
Trevor is studying a polynomial function f(x). Three given roots of f(x) are -7, 2i, and 7. Trevor concludes that f(x) must
be polynomial with degree 3. Which statement is true?
Answer:
B Trevor isn't correct because -2i must also be a root
Step-by-step explanation:
A Trevor is correct.
B Trevor is not correct because –2i must also be a root.
C Trevor is not correct there cannot be an odd number of roots.
D Trevor is not correct because there cannot be both rational and complex roots.
statements^^^^^^
The statement that f(x) must be a polynomial with degree 3 is not necessarily true based on the given roots.
What is a function?A function has an input and an output.
A function can be one-to-one or onto one.
It simply indicated the relationships between the input and the output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
We have,
Since one of the roots is complex (2i), it follows that the coefficients of f(x) must be complex as well, and therefore f(x) must be a polynomial with complex coefficients.
However, it is possible for f(x) to have a higher degree than 3.
For example,
The polynomial (x + 7)(x - 2i)(x + 2i)(x - 7) has degree 4 and has the given roots of -7, 2i, and 7. Therefore, f(x) could be a polynomial with degree 4 or higher.
Thus,
The statement that f(x) must be a polynomial with degree 3 is not necessarily true based on the given roots.
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g Jack is polling New Yorkers to determine what proportion of them want to legalize recreational marijuana. How many New Yorkers should the sample to ens
Answer:
1006
Step-by-step explanation:
Take proportion, p = 62%
n = (Z² * pq) / M.E²
Margin error = 0.03
p = 62% = 0.62
q = 1 - p = 1 - 0.62 = 0.38
Zcritical at 95% = 1.96
n = (1.96² * (0.62*0.38)) / 0.03²
n = 0.90508096 / 0.0009
n = 1005.6455
n = 1006
Sample size = 1006
Plz show steps for this
Answer: Choice D. 3 : r=3
Step-by-step explanation:
Easiest method and probably only method given the graph without knowing exact points besides an asymptote at x=-3.
Since we know there is an asymptote at x=-3, we just solve for the denominator and find r, when x=-3.
We are setting equation equal to 0, because when the denominator is 0, the graph has an asymptote at that point.
x+r=0
-3+r=0
r=3
Answer:
r=3
Step-by-step explanation:
simplify
log(125) + log(625) / log(25) - log(5)
Answer:
3.39794000867
Step-by-step explanation:
first add log 125 and 625 and divide the answer by log 25 and minus the answer by 5
Answer:
The answer is 7.
how old is sherif now ? ahmed is eight years younger than sherif in seven years, the sum of their ages will be 7/10 th of 100
Answer:
32year
Step-by-step explanation:
let Ahmed be x years then sheriff will be x+8
in 7years time
sheriff will be x+8+7=x+15
Then Ahmed will be x+7
sum of their ages will be 7\10×100=70years
x+15+x+7=70
collect like terms
2x+22=70
2x=70-22
2x/2=48/2
x=24years
Sheriff=24+8
32years
:
The width of a rectangle is 5 cm more than triple its length. The perimeter of the
rectangle is 240 cm. What is the length and width of the rectangle?
9514 1404 393
Answer:
length: 28.75 cmwidth: 91.25 cmStep-by-step explanation:
Let L represent the length of the rectangle. Then the width is W=5+3L, and the perimeter is ...
P = 2(L+W)
240 = 2(L +(5 +3L))
120 = 5 +4L
115 = 4L
115/4 = L = 28.75 . . . . cm
W = 5+3L = 5 +3(28.75) = 91.25 . . . . cm
The length and width of the rectangle are 28.75 cm and 91.25 cm.
The lines shown below are parallel. If the green line has a slope of -2, what is
the slope of the red line?
Answer:
Hi! There's no picture, but we don't need that to find the answer. Parallel lines always have the same slope. I suppose you're saying that the green and red line are parallel -- so, the red line's slope is also -2.
-2 <--
Hope this helps!! Have a nice day & please mark brainliest if you don't mind!
A runner increases his velocity from 0 m/s to 20 m/s in 2.0 s. What was his average acceleration?
Answer:
[tex]a = \frac{dv}{dt } = \frac{20 - 0}{2} = 10[/tex]
$17,818 is invested, part at 11% and the rest at 6%. If the interest earned from the amount invested at 11% exceeds the interest earned from the amount invested at 6% by $490.33, how much is invested at each rate? (Round to two decimal places if necessary.)
Answer:We know the total amount of money invested. $17818
x+y=17818,
We know that the difference in interest earned by the two accounts is $490.33
0.11*x-0.06*y=490.33
x=17818-y
We substitute for x
0.11*(17818-y)-0.06*y=490.33
We multiply out
1959.98-0.11y-0.06*y=490.33
We combine like terms.
1469.65=0.17*y
Isolate y
y=1469.65/0.17
y=8645 at 6%
Calculate x
x=17818-8645
x=9173 at 11%
Check
0.11*9173-0.06*8645=490.33
interest earned at 11%=1009.03
interest earned at 6%=518.70
1009.03-518.7=490.33
490.33=490.33
Since this statement is TRUE and neither amount is negative then all is well.We know the total amount of money invested. $17818
x+y=17818,
We know that the difference in interest earned by the two accounts is $490.33
0.11*x-0.06*y=490.33
x=17818-y
We substitute for x
0.11*(17818-y)-0.06*y=490.33
We multiply out
1959.98-0.11y-0.06*y=490.33
We combine like terms.
1469.65=0.17*y
Isolate y
y=1469.65/0.17
y=8645 at 6%
Calculate x
x=17818-8645
x=9173 at 11%
Check
0.11*9173-0.06*8645=490.33
interest earned at 11%=1009.03
interest earned at 6%=518.70
1009.03-518.7=490.33
490.33=490.33
Since this statement is TRUE and neither amount is negative then all is well.
At the end of 2 years, P dollars invested at an interest rater compounded annually increases to an amount, A dollars, given by the following formula.
A = P(1+r)?
Find the interest rate if $192 increased to $363 in 2 years. Write your answer as a percent..
-
Annual compound interest rate = % (Type an integer or a decimal.)
Answer:
37.5%
Step-by-step explanation:
A=P(1+r)^t
363=192*(1+r)^2
1.375=1+r, r=0.375=37.5%