POSSIBLE POIN
Based on records from the past several seasons the probability of the Madison Math Team winning a competition is p(win)-0.875
If they compete in 24 competitions, how many will they win?

The type of correlation not associated with scatterplots is an indefinite correlation

Correlation or dependence is any statistical relationship, whether causal or not, between two random variables or bivariate data.

Correlation can only be between -1 and 1 but not outside these values.

Hence the type of correlation not associated with scatterplots is an indefinite correlation

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Answer:

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.

length = 1 yd, width = 20 yd

length = 2 yd, width = 10 yd

length = 10 yd, width = 2 yd

length = 20 yd, width = 1 y

Step-by-step explanation:

6/20

3/10 (simplified)

do you want the percentage?

Answer:

[tex]\frac{3}{10}[/tex]

Step-by-step explanation:

The multiplies of 3 from 1-20 are:

3, 6, 9, 12, 15, 18

Since there are [tex]20-1+1=20[/tex] numbers from 1-20 inclusive, the probability that a ball is a multiple of 3 is [tex]\frac{6}{20}=\boxed{\frac{3}{10}}[/tex]

Answer:

B. Evidence

Step-by-step explanation:

Reference: like when your drawing something and you want to make sure that you draw the hair the same way some other person did.

Cite: That’s when you give the credits to someone or something 90% sure

Hope this helps :)

Answer:

£72000

Step-by-step explanation:

According to the Question,

Thus, 5 ⇒ 9000 People

So, 4 ⇒ 7200 People(Men)

      1 ⇒ 1800 People(Women)

Thus, The amount of money made from tickets sold to men is 7200 total Men x £10 Per Ticket Cost ⇒ £72000.

Answer:

Last option

Step-by-step explanation:

First method :

Red Line:

Take 2 coordinates through which the line passes. Let it be (0, 7) and (14, 0).

[tex]slope, m=\frac{ 0-7}{14-0} = -\frac{7}{14} = -\frac{1}{2}[/tex]

[tex]Equation : (y - 7) = -\frac{1}{2}(x)[/tex]

                [tex]2y - 14 = -x\\2y + x = 14\\4y + 2x = 28[/tex]                  [tex][ multiply \ by \ 2 \ on \ both \ sides][/tex]

Blue Line:

Take coordinates through which the line passes.

Let it be (-4, -12) and (-10, -9).

[tex]slope, m = \frac{-9 + 14}{-10} = \frac{5}{-10} = -\frac{1}{2}[/tex]

[tex]equation : (y + 12) = -\frac{1}{2} (x+4)\\[/tex]

              [tex]y = -\frac{1}{2}x - 2 - 12\\\\y = -\frac{1}{2}x -14\\\\2y = -x - 28\\\\-2y = x +28[/tex]

Second Method:

From the graph it is clear the lines are parallel. The slopes of line parallel to each other are equal. So convert each equation into standard line equation form :y = mx + b

And check for set of equation whose slope are same.

First set :

[tex]y = 10x - 15 \\\\=> slope = 10\\\\-9x + 2y = 10\\2y = 9x + 10\\\\y = \frac{9}{2}x + 5 => slope = \frac{9}{2}[/tex]

Slopes are not equal.

Second set :

[tex]2y = 2x + 5\\y = x + \frac{5}{2}\\slope = 1\\\\\\3x -4y = -5\\4y = 3x + 5\\\\\y = \frac{3}{4}x + \frac{5}{4}\\\\slope = \frac{3}{4}[/tex]

Slopes are not equal.

Third set :

[tex]y = 3x +10 \\slope = 3\\\\\\2x - 3y = -6\\3y = 2x +6\\\\y = \frac{2}{3}x + 2\\\\slope = \frac{2}{3}[/tex]

Slopes are not equal.

Fourth set :

[tex]2x + 4y = 28\\4y = -2x +28\\\\y = -\frac{1}{2}x + 7\\\\slope = -\frac{1}{2}\\\\\\-2y = x + 28\\\\y = -\frac{1}{2}x - 14\\\\slope = -\frac{1}{2}[/tex]

Slopes are same.

Answer:

The probability to get the vowel is 1/4.

Step-by-step explanation:

The number of elements in sample space, n(S) = 20

The number of elements in event, n (E) = 5

The probability to get the vowel is

[tex]P(E) =\frac{n(E)}{n(S)}\\\\P(E)=\frac{5}{20}\\\\P(E) = \frac{1}{4}[/tex]

Answer:

Two hours

Step-by-step explanation:

The Royal Flush:

$65 + $30(per hour) = $95(for one hour)

$95 + $30 = $125(for two hours

The Leaky Faucet:

$35 + $45(per hour) = $80(for one hour)

$80 + $45 = $125(for two hours)

Therefore, it would take two hours for both of the repair services to have the same total.

Answer:

[tex]let \: total \: distance \: be \: x \\ 30\% \: of \: x = 9 \\ \frac{30}{100} \times x = 9 \\ 30x = 900 \\ x = 30 \\ total \: distance = 30 \: miles[/tex]

The total distance Mira plan to run is 30 miles.

Percentage is a way of expressing a number as a fraction of 100. It is often denoted using the symbol ‘%’. For example, 25% is the same as 25/100 or 0.25. Percentages are used to express how large or small one quantity is relative to another quantity.

Given that, Mira has run 9 miles.

Let the total distance be x miles.

Distance is 30% of the total distance she plans to run

Here, 30% of x =9

30/100 ×x=9

30x=900

x=900/30

x=30

Therefore, the total distance Mira plan to run is 30 miles.

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Step-by-step explanation:

First, given that we must use point slope form, we can define that as

y - y₁ = m (x-x₁), with m being the slope .

To find the slope, we can use the equation

[tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]. Two points on the graph are (0, 1) and (1, 3). For these points, when calculating the slope, 0 and 1 represent x₁ and y₁ respectively, while 1 and 3 represent x₂ and y₂ respectively Using this formula, we can plug our points in to get

[tex]\frac{3-1}{1-0} = 2/1 = 2[/tex]

as our slope. Therefore, our equation is

y - y₁ = 2 (x-x₁).

For our first point, (0,1), we can simply plug 0 in for x₁ and 1 in for y₁ to get

y - 1 = 2(x-0) as one equation

Next, for (1,3) we can plug 1 for x₁ and 3 for y₁ to get

y - 3 = 2 (x-1) as our other equation

4x + 5 = 3x +4

4x - 3x = 4-5

x = -1

value of x is equal to -1

Answer:

x = -1

Step-by-step explanation:

4x + 5 = 3x +4 (subtract 3x from both sides)

-3x        -3x

=1x         =0

rewrite: x + 5 = 4 (subtract 5 from both sides)

                  -5  -5

                  =0  =-1

Therefore x = -1 (Please mark brainliest hope i helped :)

Answer:

(3p+10q)

Step-by-step explanation:

9p^2 - 100q^2

Rewriting

(3p)^2 - (10q)^2

This is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(3p-10q) (3p+10q)

Answer:

( 3p + 10 q)

Step-by-step explanation:

9 p ² - l00 q ²

(3p)² - ( 10 q) ²

( a ² - b ² = ( a + b) ( a - b) )

( 3p - 10 q) ( 3 p + 10 q)

Answer:

8r6s3 – 13r5s4 + r4s5 – 5r3s6 it is D

Step-by-step explanation:

The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Given that;

The expression is,

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

Now, We can find the difference as;

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

⇒ (8r⁶s³ – 9r⁵s⁴ – 4r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ – 5r³s⁶

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Thus, The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

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Answer:

I think 2 points

Step-by-step explanation:

I may be wrong bc I suck at algebra. literally who is gonna use algebra ever?

Answer: two points hope it helps

Answer:

43 hours

Step-by-step explanation:

[tex]\frac{y}{1} :\frac{408}{9.5}[/tex]

y × 9.5 = 408 × 1

9.5y = 408

9.5y ÷ 9.5 = 408 ÷ 9.5

[tex]y=42\frac{18}{19}[/tex]

43 hours

Given:

In a right angle triangle, the measures of two legs are 5 ft and 5.6 ft. The measure of the hypotenuse is x.

To find:

The value of x.

Solution:

Pythagoras theorem: In a right angle triangle,

[tex](Hypotenuse)^2=(Base)^2+(Perpendicular)^2[/tex]

Using Pythagoras theorem, we get

[tex](x)^2=(5)^2+(5.6)^2[/tex]

[tex]x^2=25+31.36[/tex]

[tex]x^2=56.36[/tex]

Taking square root on both sides, we get

[tex]x=\sqrt{56.36}[/tex]

[tex]x=7.50733[/tex]

[tex]x\approx 7.5[/tex]

The measure of missing side is 7.5 ft. Therefore, the correct option is D.

Answer:

23

Step-by-step explanation:

The absolute value of any number is just the positive version of that number. For example the absolute value of -12 is 12.

Hope this helps! :)

Answer:

SA= 882cm^2

Step-by-step explanation:

SA=2( width*length + hight*length + hight*width )

SA=2( 9*20+ 9*20+ 9*9)

SA= 2*441

SA=882cm^2

Answer:

B'(2,4) & C'(1,0)

Step-by-step explanation:

According To the Question,

Given, We have an ∆ABC that has coordinates A(3, 1), B(5, 5) and C(4, 1).

Now, After a translation, the coordinates of A' are (0,0) .

Then, the coordinate of B' & C' Also changes the same as like A' .

A(3,1) ⇒ A'(0,0)      {here from x-axis it reduce 3 and from y-axis it reduce 1}

Same as Above,

B(5,5) ⇒ B'(2,4)

&, C(4,1) ⇒ C'(1,0) .

Answer:

25

Step-by-step explanation:

Moving it down does not change the length.

Answer:

Es ydjwj rjsbt djeiweke

Answer:

Square root of 12

Square root of 20

Step-by-step explanation:

An irrational number contains an infinite decimal.

All other numbers are perfect squares, resulting in whole numbers.

The square root of 9 is 3 because 3 × 3 = 9.

The square root of 12 is 3.464....

The square root of 16 is 4.

The square root of 20 is 4.472....

The square root of 25 is 5.

Answer:

2 1/6 or 13/6

Step-by-step explanation:

Equation: [tex]\frac{1}{3}[/tex] × 6[tex]\frac{1}{2}[/tex]

Distribute: (1/3) ( 6 + 1/2)

(1/3)(6) + (1/3)(1/2)

2 + 1/6

2 1/6 or 13/6

Answer:

[tex]\int\limits {\int\limits_R {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Step-by-step explanation:

Given

[tex]x - y = 0[/tex]

[tex]x - y = 7[/tex]

[tex]x + y = 0[/tex]

[tex]x + y = 6[/tex]

Required

Evaluate [tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex]

Let:

[tex]u=x+y[/tex]

[tex]v =x - y[/tex]

Add both equations

[tex]2x = u + v[/tex]

[tex]x = \frac{u+v}{2}[/tex]

Subtract both equations

[tex]2y = u-v[/tex]

[tex]y = \frac{u-v}{2}[/tex]

So:

[tex]x = \frac{u+v}{2}[/tex]

[tex]y = \frac{u-v}{2}[/tex]

R is defined by the following boundaries:

[tex]0 \le u \le 6[/tex]  ,  [tex]0 \le v \le 7[/tex]

[tex]u=x+y[/tex]

[tex]\frac{du}{dx} = 1[/tex]

[tex]\frac{du}{dy} = 1[/tex]

[tex]v =x - y[/tex]

[tex]\frac{dv}{dx} = 1[/tex]

[tex]\frac{dv}{dy} = -1[/tex]

So, we can not set up Jacobian

[tex]j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right][/tex]

This gives:

[tex]j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right][/tex]

Calculate the determinant

[tex]det\ j = 1 * -1 - 1 * -1[/tex]

[tex]det\ j = -1-1[/tex]

[tex]det\ j = -2[/tex]

Now the integral can be evaluated:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex] becomes:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{x^2 - y^2}} \, *\frac{1}{|det\ j|} * dv\ du[/tex]

[tex]x^2 - y^2 = (x + y)(x-y)[/tex]

[tex]x^2 - y^2 = uv[/tex]

So:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{|det\ j|}\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *|\frac{1}{-2}|\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{2}\, dv\ du[/tex]

Remove constants

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 {\int\limits^7_0 {ue^{uv}} \, dv\ du[/tex]

Integrate v

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 \frac{1}{u} * {ue^{uv}} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 e^{uv} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du[/tex]

Integrate u

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0[/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}][/tex]

Open bracket

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}][/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Answer: [tex]\text{m}\angle T=45^{\circ}[/tex]

Step-by-step explanation:

Given: In ΔSTU, [tex]\text{m}\angle S = (2x+10)^{\circ}[/tex] , [tex]\text{m}\angle T = (3x-9)^{\circ}[/tex], [tex]\text{m}\angle U = (6x-19)^{\circ}[/tex]

To find: [tex]\text{m}\angle T[/tex].

We know that the sum of all the angles of a triangle is [tex]180^{\circ}[/tex].

In ΔSTU,

[tex]\text{m}\angle S+\text{m}\angle T+\text{m}\angle U=180^{\circ}\\\\ 2x+10+3x-9+6x-19=180\\\\ 11x-18=180\\\\11x =180+18\\\\11x=198\\\\x=\frac{198}{11}\\\\ x=18[/tex]

[tex]\text{m}\angle T = (3(18)-9)^{\circ}\\\\=(54-9)^{\circ}\\\\= 45^{\circ}[/tex]

Hence, [tex]\text{m}\angle T=45^{\circ}[/tex]

Answer:

A = -7.5   B = -17.5

Step-by-step explanation:

A + B = -25

A = B + 10

Plug the second equation into the first equation:

B + 10 + B = -25

2B = -35

B = -17.5

Plug that value into the first equation:

A - 17.5 = -25

A = -7.5