Answer:
73%
Step-by-step explanation:
write a thirdthird-degree polynomial expression that has only two terms with a leading term that has a coefficient of five and a constant of negative two
Answer:
5x^3-2
[tex]ax^{3} +bx^{2} +cx+d\\5x^{3}-given\\ d=-2-given\\5x^{3} -2[/tex]
Explanation:
The two terms are [tex]5x^3[/tex] and [tex]2[/tex]. Terms are separated by either a plus or minus.
We can write it as [tex]5x^3+(-2)[/tex] which is an equivalent form. Here the two terms are [tex]5x^3[/tex] and [tex]-2[/tex]. This is because adding a negative is the same as subtracting.
The coefficient is the number to the left of the variable.
The degree is the largest exponent, which helps form the leading term.
The third degree polynomial written above is considered a cubic binomial. "Cubic" refers to the third degree, while "binomial" means there are 2 terms.
We can write something like [tex]5x^3[/tex] as 5x^3 when it comes to computer settings.
3. Solve 6 + 5 √ 2 4 9 − 2 x = 7
Answer:
please mark my answer brainliest
Step-by-step explanation:
question is unclear to give u correct answer
the temp fell 3 degrees every hour for 5 hours what's the change in temperature
Answer:
-15
Step-by-step explanation:
If it fell 3 deg every hour for 5 hours so the equation is 3*5 plus a - sign because it dropped degrees
Prove for
mathematical
induction is the statement
is true
3+7+11+... (4n-1) = n(2n+1)
Answer:
Step-by-step explanation:
Hello, we want to prove that a proposition depending on n, that we can note P(n), is true for any n positive integer greater than 1. We need to follow several steps.
Step 1 - prove P(1)
For n = 1, n(2n+1)=1*3 =3 so we have
3 = 3, which is obviously true.
First step done!
Step 2 - for [tex]k\geq 1[/tex] we assume P(k) and we need to prove P(k+1)
We assume that 3+7+11+...+(4k-1)=k(2k+1)
so we can write that
3+7+11+...+(4k-1)+(4(k+1)-1)=k(2k+1)+(4k+4-1)=k(2k+1)+4k+3
[tex]=2k^2+k+4k+3\\\\=2k^2+5k+3[/tex]
and
(k+1)(2(k+1)+1)=(k+1)(2k+3)
[tex]=k(2k+3)+2k+3\\\\=2k^2+3k+2k+3\\\\=2k^3+5k+3[/tex]
These two expressions are the same so it means that P(k+1) is true, meaning that
3+7+11+...+(4k-1)+(4(k+1)-1)=(k+1)(2(k+1)+1)
Step 3 - The conclusion
Finally, we have just proved that
3+7+11+...+(4n-1)=n(2n+1) for any n positive integer > 0
Thank you
The given sum of arithmetic progression series 3+7+11+... (4n-1) = n(2n+1) is true.
What is Arithmetic progression?The difference between every two successive terms in a sequence is the same this is known as an arithmetic progression (AP).
The arithmetic progression has wider use in mathematics for example sum of natural numbers.
Natural number = 1,2,3,4,5,6,7,8...
Now it has the same difference between any two consecutive terms d =2-1 = 3-2.
The Sum of n terms of an AP is given by,
S= n/2[2a + (n-1)d ] where a is first term and d is common difference.
In our series 3+7+11+... (4n-1)
First term (a) = 3
Common difference (d) = 7 - 3 = 4
So the sum will be
S = n/2[2(3) + (n-1)4]
S = n[3 + 2(n - 1)]
S = n (2n + 1 ) = Right hand side.
Hence "The given sum of arithmetic progression series 3+7+11+... (4n-1) = n(2n+1) is true".
For more about Arithmetic progression,
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A student says that a coordinate grid under a dilation with the center at the origin and scale factor 2 does not change the grid. The image is still a coordinate grid. How do you respond?
Answer:
Dilation changes (x,y) values not the grid or coordinate plane. Basically, dilating a graph or a coordinate grid means the original coordinates you may have had will be changed with the dilation. For example, a triangle plotted had its original area of 26 dilated to an area of 58.
Type the missing number in this sequence:
1,
4,
,64, 256,
1,024
Answer:
16
Step-by-step explanation:
The sequence is 1, 4,...,64, 256, 1024
Notice that:
● 1 = 2^0
● 4 = 2^2
● 64 = 2^6
● 256 = 2^8
● 1024 = 2^10
Notice that we add 2 each time to the exponent so the missing number is:
● 2^(2+2) = 2^4 = 16
1. Hypothesis Test. Gender bias researchers compared the promotion rate of 412 women in manufacturing management positions to the national average which was known to be 75 months for a mostly male population. They measured the number of months each woman worked in middle management. Given a 0.01 level of significance, the correct statistical conclusion is to reject the null.
A. True
B. False
2. Hypothesis Test. Gender bias researchers compared the promotion rate of 412 women in manufacturing management positions to the national average which was known to be 75 months for a mostly male population. They measured the number of months each woman worked in middle management before being promoted to senior management, and found an average 79 months (s.d. = 19). Researchers want to know if women are promoted more slowly (i.e. after a larger number of months). What is the correct research conclusion?
A. Evidence suggests there is no difference in promotion rates.
B. Evidence suggests a small difference in promotion rates favoring males.
C. Evidence suggests a large difference in promotion rates favoring males.
D. No way to tell.
Answer:
1. B. False
2. B. Evidence suggests a small difference in promotion rates favoring males.
Step-by-step explanation:
The correct order of the steps of a hypothesis test is given following
1. Determine the null and alternative hypothesis.
2. Select a sample and compute the z - score for the sample mean.
3. Determine the probability at which you will conclude that the sample outcome is very unlikely.
4. Make a decision about the unknown population.
These steps are performed in the given sequence to test a hypothesis.
Urgent!!! Please simplify
Answer:
The answer is
3x² - 2x³Step-by-step explanation:
First factor (x+1)² out of the expression
That's
[tex] \frac{ ({x + 1})^{2} (6 \cos( \frac{\pi}{3} )) {x}^{2} - {x}^{3} \times 2 \sin( \frac{\pi}{2} ) }{ ({x + 1})^{2} } [/tex]
Reduce the expression by (x + 1)²
We have
[tex]6 \cos( \frac{\pi}{3} ) \times {x}^{2} - {x}^{3} \times 2 \sin( \frac{\pi}{2} ) [/tex]
Using trigonometric values table
[tex] \cos( \frac{\pi}{3} ) = \frac{1}{2} [/tex]
[tex] \sin( \frac{\pi}{2} ) = 1[/tex]
So we have
[tex]6 \times \frac{1}{2} \times {x}^{2} - {x}^{3} \times 2 \times 1[/tex]
Simplify
We have the final answer as
[tex] {3x}^{2} - 2 {x}^{3} [/tex]
Hope this helps you
Two basketball players average the same number of points per game. What information would be most helpful in
determining which player's game performances show the least variability?
the most and least points each player has scored in a game
the number of games each player has played
the average number of points each player's team scores per game
O the total number of points each player has scored
Answer:
number of games each player has played
the average number of points each player's team scores per
Step-by-step explanation:
number of games each player has played
the average number of points each player's team scores per
Let REPEAT TM = { | M is a TM, and for all s ∈ L(M), s = uv where u = v }. Show that REPEATTM is undecidable. Do not use Rice’s Theorem.
Answer:
Step-by-step explanation:
Let REPEAT [tex]_{TM[/tex]= { | M is a TM, and for all s ∈ L(M), s = uv where u = v }
To prove that REPEAT [tex]_{TM[/tex] is undecidable.
Let REPEAT [tex]_{TM[/tex] {| M is a TM that does not accept M}
Then, we form a TM u for L by applying TM v as a subroutine.
Assume Repeat is decidable
Let M be the algorithm that TM which decides the REPEATU = on input "s" simulate the M
Accept; if M ever enters the accept state
Reject; if M ever enters the reject state
U does not decide the REPEAT as it may loop over s
so REPEAT is undecidable
Starting at point A, a ship sails 18.9 km on a bearing of 190 degrees and then turns and sails 47.2km on a bearing of 318 degrees. Find the distance of the ship from point A. (Use trigonometry)
Answer:
Approximately 38.56 kilometers
Step-by-step explanation:
So, from the picture, we want to find x.
To do this, we can use the Law of Cosines. We simply need to find the angle between the two sides and then plug them into the Law of Cosines. First, the Law of Cosines is:
[tex]c^2=a^2+b^2-2ab\cos(C)\\[/tex]
The c in this equation is our x, and the C is the angle we need to find.
From the picture, you can see that angle C is the sum of the red and blue angles.
From a bearing of 190 degrees, we can determine that the red angle measures 10 degrees. Then by alternate interior angles, the other red angle must also measure 10 degrees.
From a bearing of 318 degrees, the remaining 48 degrees is outside the triangle. However, we have a complementary angle, so we can find the angle inside the triangle by subtracting in into 90. Therefore, the blue angle inside is 90-48=42 degrees.
Therefore, angle C is 42+10 which equals 52 degrees. Now we can plug this into our formula:
[tex]x^2=a^2+b^2-2ab\cos(C)\\\\x^2=(18.9)^2+(47.2)^2-2(18.9)(47.2)\cos(52)\\x=\sqrt{(18.9)^2+(47.2)^2-2(18.9)(47.2)\cos(52)}\\\text{Use a Calculator}\\x\approx38.5566 \text{ km}[/tex]
A caplet contains 325 mg of medication. How many caplets contain 975 mg of medication?
Answer:
3 capletsStep-by-step explanation:
Given 1 caplet = 325 mg of medication, to calculate the number of caplet 975mg of medication will contain, we will follow the steps below;
Let 1 caplet = 325 mg of medication
x caplet = 975 mg of medication
Cross multiply
325 * x = 1 * 975
325x = 975
Divide both sides by 325
325x/325 = 975/325
x = 3
Hence 3 caplets contains 975 mg of medication.
Find 0.01 more than 9.154
Answer:
Hey!
Your answer is 9.164!!
Step-by-step explanation:
Adding 0.01 means just adding 1 to THE DIGIT IN THE HUNDRETH PLACE...2 SPACES RIGHT OF DECIMAL POINT!
5+1=6
SUB IN:
9.164
Please help me answer the question
Answer:
fourth option
Step-by-step explanation:
Common difference is given by difference of two consecutive term
d = nth term - (n-1)th term
______________________________________
for all the series lets take second term as nth term
and first term as (n-1)th term
_________________________________________
for first series
n th term = -3 1/2 = -3.5
(n-1)th term = -5
therefore
d= -3.5 -(-5) = -3.5 +5 = 1.5
______________________________________
for second series
n th term = 4 1/2 = 4.5
(n-1)th term = 2 1/2 = 2.5
therefore
d= 4.5 -(2.5) =2
_________________________
for third series
n th term = 3
(n-1)th term =1.5
therefore
d= 3 - 1.5 = 1.5
__________________________________
for fourth series
n th term = -1.5
(n-1)th term = -4
therefore
d= -1.5 -(-4) = -1.5 + 4 = 2.5 = 2 1/2
___________________________________
Thus, based on above solution option four has common difference of 2 1/2
Tony rounded each of the numbers 1, 143 and 1, 149 to the nearest hundred which word correctly compares the rounding numbers
Full Question:
Tony rounded each of the numbers 1,143 and 1,149 to the nearest hundred. Which choice correctly compares the rounded numbers?
[tex]1,000 = 1,000[/tex]
[tex]1,140< 1,150[/tex]
[tex]1,100 = 1.100[/tex]
[tex]1,140>1,150[/tex]
Answer:
[tex]1,100 = 1,100[/tex]
Step-by-step explanation:
Given
1,143 and 1,149
Required
Which of the option is correct
We start by approximating both numbers to nearest digit
1,143; when approximated to nearest hundred is 1,100
1,149; when approximated to nearest hundred is also 1,100
Hence;
1,143 ≅ 1,100
1,149 ≅ 1,100
Comparing both results, we have that
[tex]1,100 = 1,100[/tex]
From the list of given options, option C is correct;
What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3,2), (8,2), and (5, -2)?
Answer: 20 sq. units .
Step-by-step explanation:
Let A(0, -2), B(3,2), C(8,2), and D(5, -2) are the points for the parallelogram.
First we plot these points on coordinate plane, we get parallelogram ABCD.
By comparing the y-coordinate of B and C with A and D , we get
height = 2+2 = 4 units
Also by comparing the x coordinates of A and D, we get base = 5-0= 5 units
Area of parallelogram = Base x height
= 5 x 4 = 20 sq. units
Hence, the area of a parallelogram ABCD is 20 sq. units .
NEED HELP ASAP!!!!!!!!!!
Answer:
Hey there!
A is correct. The +2 means shifted up two units, 1/2 means compressed by a factor of 1/2, and the -3 means to the left of three units.
Let me know if this helps :)
Please answer this correctly without making mistakes
Answer:
Put 1/10 in the box.
Step-by-step explanation:
Since, Bluepoint and Milford are at same distance from Weston, the distance further than this to Oakdale is 1/10 miles.
Best Regards!
Answer:
To Oakdale to Milford:
2/5 mi
Step-by-step explanation:
1/10 + 3/20 + 3/20
1/10 = 2/20
then;
2/20 + 3/20 + 3/20 = (2+3+3)/20 = 8/20
8/20 = 2/5
A box contains 30 widgets, 4 of which are defective. If 4 are sold at random, find the probability that (a) all are defective (b) none are defective.
Answer:
a. The probability that all are defective is 0.0003160493827
b. Probability that none are defective is 0.99968395
Step-by-step explanation:
Given that 4 of the 30 widgets contained on the box are defective, n = 4. The probability of picking a defective widget is p = 4/30 = 2/15.
Now, P(X = a) = (nCa)P^n(1 - P)^(n - a).
a. To find the probability that all are defective, we want to find P(X = 4)
= (4C4) × (2/15)^4 × (1 - 2/15)^(4 - 4)
= 1 × (2/15)^4 × 1
= 0.0003160493827
b. Probability that none are defective.
This is the same as saying (1 minus the probability that all are defective).
P = 1 - 0.0003160493827
= 0.99968395
which expression shows a way to find 2813×7
Answer:
19,691
Step-by-step explanation:
Answer:
2813 x 7 = 19691
Hope this helps!
The lengths of two sides of a triangle are 6cm and 8cm.Between what two measures should the length of the third side fall? PLEASE HELP !!!!!!!!
Answer: Search Results
Featured snippet from the web
In triangle sum of 2 sides must be greater than the 3rd side. So, the third > 8 - 6 = 2 and also the third < 8 + 6 = 14. So, the answer is 2 < third side < 14. The third side lies between(2,14).
Step-by-step explanation: Brainlyest please
find the response of the function at * (t=4) using Laplace transform (y() + 2y" + y = sint) y(0)=1, y (0)=-2, y"(0)=3 , y"(0)=0
Considering you have four initial conditions (the last of which should probably read [tex]y'''(0)=0[/tex]), I'm assuming the ODE is
[tex]y^{(4)}(t)+2y''(t)+y(t)=\sin t[/tex]
with [tex]y(0)=1[/tex], [tex]y'(0)=-2[/tex], [tex]y''(0)=3[/tex], and [tex]y'''(0)=0[/tex].
Take the Laplace transform of both sides, denoting the transform of [tex]y(t)[/tex] by [tex]Y(s)[/tex]:
[tex](s^4Y(s)-s^3y(0)-s^2y'(0)-sy''(0)-y'''(0))+2(s^2Y(s)-sy(0)-y'(0))+Y(s)=\dfrac1{s^2+1}[/tex]
Solve for [tex]Y(s)[/tex]:
[tex](s^4+2s^2+1)Y(s)-s^3+2s^2-5s+4=\dfrac1{s^2+1}[/tex]
[tex]Y(s)=\dfrac{1+(s^3-2s^2+5s-4)(s^2+1)}{(s^2+1)(s^4+2s^2+1)}[/tex]
Notice that
[tex]s^4+2s^2+1=(s^2+1)^2[/tex]
[tex]\implies Y(s)=\dfrac{1+(s^3-2s^2+5-4)(s^2+1)}{(s^2+1)^3}[/tex]
and simplify a bit to get
[tex]Y(s)=\dfrac{s^5-2s^4+6s^3-6s^2+5s-3}{(s^2+1)^3}[/tex]
Decompose [tex]Y(s)[/tex] into partial fractions:
[tex]\dfrac{s^5-2s^4+6s^3-6s^2+5s-3}{(s^2+1)^3}=\dfrac{a_0+a_1s}{s^2+1}+\dfrac{b_0+b_1s}{(s^2+1)^2}+\dfrac{c_0+c_1s}{(s^2+1)^3}[/tex]
[tex]s^5-2s^4+6s^3-6s^2+5s-3=(a_0+a_1s)(s^2+1)^2+(b_0+b_1s)(s^2+1)+(c_0+c_1s)[/tex]
[tex]s^5-2s^4+6s^3-6s^2+5s-3=a_1s^5+a_0s^4+(2a_1+b_1)s^3+(2a_0+b_0)s^2+(a_1+b_1+c_1)s+(a_0+b_0+c_0)[/tex]
[tex]\implies\begin{cases}a_1=1\\a_0=-2\\2a_1+b_1=6\\2a_0+b_0=-6\\a_1+b_1+c_1=5\\a_0+b_0+c_0=-3\end{cases}[/tex]
[tex]\implies a_0=-2,a_1=1,b_0=-2,b_1=4,c_0=1,c_1=0[/tex]
So we have
[tex]Y(s)=\dfrac{s-2}{s^2+1}+\dfrac{4s-2}{(s^2+1)^2}+\dfrac1{(s^2+1)^3}[/tex]
Split up the first term to get two easy inverse transforms:
[tex]L^{-1}\left[\dfrac s{s^2+1}\right]=\cos t[/tex]
[tex]L^{-1}\left[-\dfrac2{s^2+1}\right]=-2\sin t[/tex]
Also split up the second term, but use the convolution theorem, which says
[tex]L\left[(\alpha \ast \beta)(t)\right]=A(s)\cdot B(s)[/tex]
where [tex]A(s)[/tex] and [tex]B(s)[/tex] are the Laplace transforms of [tex]\alpha(t)[/tex] and [tex]\beta(t)[/tex], respectively, and the convolution is defined by
[tex](\alpha \ast \beta)(t)=\displaystyle\int_0^t\alpha(\tau)\beta(t-\tau)\,\mathrm d\tau[/tex]
Take
[tex]A(s)=\dfrac{4s}{s^2+1}\text{ and }B(s)=\dfrac1{s^2+1}[/tex]
so that
[tex]\alpha(t)=4\cos t\text{ and }\beta(t)=\sin t[/tex]
and their convolution is
[tex]L^{-1}\left[\dfrac{4s}{(s^2+1)^2}\right]=(\alpha \ast \beta)(t)=2t\sin t[/tex]
Next, take
[tex]A(s)=-\dfrac2{s^2+1}\text{ and }B(s)=\dfrac1{s^2+1}[/tex]
[tex]\implies \alpha(t)=-2\sin t\text{ and }\beta(t)=\sin t[/tex]
[tex]\implies L^{-1}\left[-\dfrac2{(s^2+1)^2}\right]=t\cos t-\sin t[/tex]
You can treat the third term similarly, but with an extra step. First compute
[tex]L^{-1}\left[\dfrac1{(s^2+1)^2}\right][/tex]
by taking
[tex]A(s)=B(s)=\dfrac1{s^2+1}[/tex]
[tex]\implies \alpha(t)=\beta(t)=\sin t[/tex]
Then
[tex]L^{-1}\left[\dfrac1{(s^2+1)^2}\right]=\dfrac{\sin t-t\cos t}2[/tex]
Next, take
[tex]A(s)=\dfrac1{(s^2+1)^2}\text{ and }B(s)=\dfrac1{s^2+1}[/tex]
[tex]\implies \alpha(t)=\dfrac{\sin t-t\cos t}2\text{ and }\beta(t)=\sin t[/tex]
[tex]\implies L^{-1}\left[\dfrac1{(s^2+1)^3}\right]=\dfrac{(3-t^2)\sin t-3t\cos t}8[/tex]
Thus we end up with the solution,
[tex]y(t)=(\cos t-2\sin t)+(2t\sin t+t\cos t-\sin t)+\dfrac{(3-t^2)\sin t-3t\cos t}8[/tex]
[tex]\boxed{y(t)=\dfrac{(8+5t)\cos t+(-21+16t-t^2)\sin t}8}[/tex]
16.72911 liters rounded to the nearest whole is
liters
17 is the answer
(Mark me brainliest)
On a coordinate plane, a line goes through (negative 3, 3) and (negative 2, 1). A point is at (4, 1). What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (4, 1)? y − 1 = −2(x − 4) y – 1 = Negative one-half(x – 4) y – 1 = One-half(x – 4) y − 1 = 2(x − 4)
Answer:
y - 1 = -2(x - 4).
Step-by-step explanation:
First, we need to find the slope. Two sets of coordinates are (-3, 3), and (-2, 1).
(3 - 1) / (-3 - -2) = 2 / (-3 + 2) = 2 / (-1) = -2.
The line will be parallel to the given line, so the slope is the same.
Now that we have a point and the slope, we can construct an equation in point-slope form.
y1 = 1, x1 = 4, and m = -2.
y - 1 = -2(x - 4).
Hope this helps!
The slope of the line passing parallel to the given line and passes through the point (4, 1) is y = -2x + 9
The equation of a straight line is given by:
y = mx + b
where y, x are variables, m is the slope of the line and b is the y intercept.
The slope of the line passing through the points (-3,3) and (-2,1) is:
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\\\m=\frac{1-3}{-2-(-3)} \\\\m=-2[/tex]
Since both lines are parallel, hence they have the same slope (-2). The line passes through (4,1). The equation is:
[tex]y-y_1=m(x-x_1)\\\\y-1=-2(x-4)\\\\y=-2x+9[/tex]
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A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack of crackers to the number of calories in each snack pack of trail mix. A number line goes from 65 to 115. Crackers's whiskers range from 70 to 100, and the box ranges from 75 to 85. A line divides the box at 80. Cookies's whiskers range from 70 to 115, and the box ranges from 90 to 105. A line divides the box at 100. Which statement is true about the box plots
OPTIONS:
A. The interquartile range of the trail mix data is greater than the range of the cracker data.
B. The value 70 is an outlier in the trail mix data.
C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.
D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
Answer:
D.
Step-by-step explanation:
With the given information about how the box plot looks like, let's examine each option to see if they are true or not.
Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."
The interquartile range of trail mix data = 105 - 90 = 15
Range of cracker data = 100 - 70 = 30
Option A is NOT TRUE.
Option B: "The value 70 is an outlier in the trail mix data."
This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.
Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."
Upper quartile of the trail mix data = 105
Max value of cracker data = 100
This statement is NOT TRUE.
Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."
The greater the range value, the greater the variation. Thus,
Range value of the trail mix data = 115 - 70 = 45
Range value of the cracker data = 100 - 70 = 30
This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.
Answer: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
pls what is the nearest 100 of 49
Answer:
the nearest hundred is 50
Su Jean is driving from phoenix to houston. A distance of 1185 miles. After driving for 4 hours she calculates that she has driven 237 miles. What portion of the distance does she have left to drive?
Answer:
4/5
Step-by-step explanation:
237/1185 = .2 = 1/5
meaning there's 4/5 left
Help me solve this!!!
Answer:
54°
Step-by-step explanation:
Let ∠CYX=x
AB║CD
∠AXE=∠CYX (corresponding angles)
∠AXE=3∠CYX-108
x=3x-108
3x-x=108
2x=108
x=108/2=54°
∠AXE=∠CYX=x=54°
∠BXY=∠AXE=54° (Vertically opposite angles)
Solve the system by graphing y=-4x-2 -2x+y=-2 Plot both lines and point of intersection by moving the dots to the correct location
Answer:
The point of intersection is (0,-2).
Step-by-step explanation:
Equation 1: [tex]y=-4x-2[/tex]
Equation 2 : [tex]-2x+y=-2[/tex]
Plot the lines on the graph
Refer the attached figure
Equation 1: [tex]y=-4x-2 ---- Red[/tex]
Equation 2 : [tex]-2x+y=-2 ---- Blue[/tex]
Point of intersection : A point where both the lines intersect is called point of intersection.
So, Both lines intersect at point (0,-2)
So, Point of intersection is (0,-2)
Hence The point of intersection is (0,-2).
micah drove 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday, he drove 1 1/3 fewer miles than he had driven on Monday. How many miles did they drive in total
Answer:
9.5
Step-by-step explanation:
Monday: [tex]4\frac{1}{4}[/tex]
Tuesday: [tex]2\frac{2}{3}[/tex]
Wednesday: [tex]4\frac{1}{4} - 1\frac{1}{3}[/tex]
Total: [tex]4\frac{1}{4} + 2\frac{2}{3} + (4\frac{1}{4} - 1\frac{1}{3})[/tex]
Start by subtracting [tex]4\frac{1}{4} and[/tex] [tex]1\frac{1}{3}:[/tex] [tex]\frac{35}{12}[/tex]
Now, add them all up: [tex]4\frac{1}{4} + 2\frac{2}{3} + \frac{35}{12} = 9.5[/tex]
Therefore, Micah drove 9.5 miles in total.
