The constant acceleration of the train is 50/9 m/s².
The two balls will collide at a height of approximately 10.204 meters above the ground.
How to calculate the valueUsing the kinematic equations of motion, we have:
distance = initial velocity * time + 1/2 * acceleration * time^2
For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:
d1 = 0 + 1/2 * a * (300)^2
For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:
d2 = v * 300
For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:
d3 = v * 300 + 1/2 * (-a) * (300)^2
The total distance traveled is the sum of these three distances:
distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600
Since the total distance traveled is given as 10 km = 10000 m, we have:
v * 600 = 10000
Solving for v, we get:
v = 10000/600 = 50/3 m/s
Now we can use the second equation above to find a:
d2 = v * 300 = (50/3) * 300 = 5000 m
Therefore, the constant acceleration of the train is:
a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2
The constant acceleration of the train is 50/9 m/s^2.
Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.
Using the kinematic equation for free fall, we have:
h = 10 + 1/2 * g * t^2
where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.
The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.
Using the kinematic equation for motion with constant acceleration, we have:
0 = 10 + (-g) * t
Solving for t, we get:
t = 10/g = 10/9.81 seconds
Substituting this value of t into the first equation, we get:
h = 10 + 1/2 * 9.81 * (10/9.81)^2
Simplifying, we get:
h = 10.204 m
The two balls will collide at a height of approximately 10.204 meters above the ground.
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You are pulling water with a constant velocity from a well using a crank of lengthL . If the length of the crank was doubled, you could ...A: pull up the water with the same work, but less forceB: pull up the pail with half the number of revolutionsC: exert double the torque while pulling up the pail with half the workD: pull up the pail with half the work and half the forceE: pull up double the amount of water with the same workF: exert four times the torque while pulling up the pail with the same work
The correct option is A, If the length of the crank was doubled, you could pull up the water with the same work, but less force.
The term "crank" can have various meanings depending on the context. In the context of machinery or engines, a crank is a mechanical device that converts rotational motion into linear motion or vice versa. It typically consists of a rod with a crankpin that connects to a piston or other reciprocating part.In a different context, the term "crank" can refer to a person who holds unconventional or extreme views and insists on expressing them in a forceful or annoying way.
Such a person may be described as a "crank" or "crankpot." The term can also refer to someone who is mentally unbalanced or eccentric. Furthermore, in the context of illegal drugs, "crank" is a slang term for methamphetamine, a highly addictive stimulant that can cause serious health problems and addiction. It is usually sold in crystalline form and can be smoked, snorted, or injected.
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Complete Question: -
You are pulling water with a constant velocity from a well using a crank of lengthL . If the length of the crank was doubled, you could ...
A: pull up the water with the same work, but less force
B: pull up the pail with half the number of revolutions
C: exert double the torque while pulling up the pail with half the work
D: pull up the pail with half the work and half the force
E: pull up double the amount of water with the same work
F: exert four times the torque while pulling up the pail with the same work
Pete needs to be at work for 9.00am. He leaves his house at 7.30am and drives to the gym which is 12.5 miles away. Pete spends 45 minutes in the gym then drives the reaming 9 miles to work.
To determine the time Pete arrives at work, we can start by calculating the total time he spends on his commute and gym routine:
What time will Pete get to work?Time spent driving to the gym = 12.5 miles ÷ average speed
We don't know Pete's average speed, so we cannot calculate this.
Time spent in the gym = 45 minutes
Time spent driving from the gym to work = 9 miles ÷ average speed
Again, we don't know Pete's average speed, so we cannot calculate this.
Total time spent on commute and gym routine = time spent driving to gym + time spent in gym + time spent driving from gym to work
= Unknown + 45 minutes + Unknown
Next, we can convert the total time to hours and minutes:
Total time = (Unknown + 45 minutes + Unknown) ÷ 60
= (Unknown + Unknown) ÷ 60 + 45/60
= (2Unknown) ÷ 60 + 0.75
= (Unknown) ÷ 30 + 0.75
We know that Pete needs to arrive at work by 9.00am, so we can set up an equation:
Arrival time = 7.30am + Total time
9.00am = 7.30am + (Unknown/30) + 0.75
Solving for Unknown:
1.5 hours = Unknown/30
Unknown = 45 minutes
Therefore, Pete will arrive at work at 8.15am.
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Calculate the mass in kg of a ball at a height of 3m above the ground with a potential energy of 120J.
The mass of the ball at a height of 3m above the ground with a potential energy of 120J can be calculated using the equation:
Mass = Potential Energy/Gravity * Height
Mass = 120J/(9.81m/s² * 3m)
Mass = 4.1 kg
Answer:
4 kg
Explanation:
Using,
Energy/ Work done = Force x Distance (Height)
E = F • s
But recall, that F = mg
Therefore,
E = m • g • s
Making mass (m), the subject of the formula
m = E / (g • s)
m = 120 / (10 • 3)
m = 120 / 30
m = 4 kg
But if g = 9.8 ms-¹
Then,
m = 120 / (9.8 • 3)
m = 120 / 29.4
m = 4.08 kg
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Two long parallel wires placed side by side on a horizontal table carry the same currents in opposite directions. The wire on your right carries current toward you, and the wire on your left carries current away from you. Determine the direction of the magnetic field at the point exactly midway between the two wires from your point of view. Explain your answer with the aid of labelled diagram. [5 marked
To find:-
Magnetic field at the centre between the wires.Answer:-
We are here given that two long current carrying wires are having same current. We need to find out the magnetic field at the centre between the wires .
We know that for a point between two ends of a wire , magnetic field is given by,
[tex]\implies B =\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}\\[/tex]
where ,
B is magnetic field.i is the current.d is the distance .Now since magnetic field is a vector quantity we need to find out the direction of the field . We can do so by using Right Hand thumb rule .
Right hand thumb rule :-
Hold the wire , in your hand with thumbs towards the direction of the current, then the curling of the fingers would give you the direction of the magnetic field.
For wire AB :-
The direction comes to be down the page .
For wire CD :-
The direction comes to be down the page .
Calculating net magnetic field:-
The net magnetic field will be the sum of both the fields .
[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}+\dfrac{\mu_0}{4\pi}\dfrac{2i}{d} \\[/tex]
[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{4i}{d}\\[/tex]
[tex]\implies \underline{\underline{\green{ B_{net}=\dfrac{\mu_0i}{ \pi d}}}}\\[/tex]
The direction is down the page .
and we are done!
Problem 1: In Fig. 1, find an expression for the acceleration of
m 1
. The pulleys are massless and frictionless. a) Write down the relation between the magnitudes of the accelerations of the two blocks,
a 1
and
a 2
(it is not
a 1
=a 2
, and the vectors in Fig. 1 are not drawn to scale). An argument that could help is that the total length of the rope stays constant during the motion. b) Write down Newton's second law for each block. Do not miss FIG. 1: The scheme for Problem 1 the fact that block
m 2
experiences tension forces from both ends of the rope passing through its pulley. Using the acceleration constraint from part a), work out the formula for the acceleration
a 1
in terms of
m 1
,m 2
, and
g
. c) What is the value of
a 1
, if
m 1
=3 kg
, and
m 2
=1 kg
? (Answer:
a 1
=1.5 m/s 2
.)
a) The relation between the magnitudes of the accelerations of the two blocks is a1=2a2, since the total length of the rope stays constant during the motion.
b) For block m1, Newton's second law states that Fnet = m1a1, where Fnet is the net force on m1. Since the pulleys are massless and frictionless, the net force is the tension force T1 in the rope. Therefore, T1 = m1a1.
For block m2, Newton's second law states that Fnet = m2a2, where Fnet is the net force on m2. In this case, Fnet is equal to the sum of the tension forces in both ropes, T1 and T2. Therefore, T1 + T2 = m2a2.
Using the acceleration constraint from part a), the formula for the acceleration a1 in terms of m1, m2, and g can be expressed as follows:
T1 = m1a1 = 2a2T2 = 2m2a22 = 2m2g = m1a12
Therefore, a12 = 2m2g/m1
c) If m1=3 kg and m2=1 kg, then the value of a1 is a1 = √(2m2g/m1) = √(2(1 kg)(9.8 m/s2)/(3 kg)) = 1.5 m/s2.
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a battleship simultaneously fires two shells at enemy ships. if the shells follow the parabolic trajectories shown, which ship gets hit first?
A battleship simultaneously fires two shells in parabolic projectile motion and no information about initial speeds at enemy ships. The ship B got hit first. So, the correct choice for answer is option (c).
Here is we have a battleship Which fires two shells simultaneously at the enemy ship along the two paths. The initial speed of projection may be same or different. See the above figure carefully, the angle of projection for ship A is more than ship B. Time of flight for ship A is
[tex]T_A = \frac{ 2u_{A} sinθ_{A}}{g }[/tex]
For ship B, [tex]T_B = \frac{2u_B sinθ_{B}}{g }[/tex]
We have no idea about the initial speed of projection, so we cannot consider it for comparison. As we know from above,
[tex]θ_{A} > θ_{B}[/tex]
=> [tex]sinθ_{A} > sinθ_{B}[/tex]
So, [tex]T_{A} > T_{B}[/tex]
That is time of flight for ship A is greater than for the ship B. Therefore, ship B gets hit first.
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Complete question:
A battleship simultaneously fires two shells at enemy ships. if the shells follow the parabolic trajectories shown, which ship gets hit first?
a) A
b) both simultaneously
c) B
d) None
You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515
lb and was traveling eastward. Car B weighs 1125
lb and was traveling westward at 41.0
mph. The cars locked bumpers and slid eastward with their wheels locked for 18.5
ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750
.
What speed
(in miles per hour) was car A traveling just before the collision? (This problem uses English units because they would be used in a U.S. legal proceeding.)
Answer:
Solve for force:
Ff = UFn
Ff = 0.75(Fn)
Ff = 0.75(1515 + 1225 * g)
Ff = 20550N
Solve for acceleration:
F= ma
20550N = (1515 + 1225) a
a = 7.5m/s^2
solve for time:
a = d / t^2 ---> 7.5m/s^2 = 18.5/ t^2 ----> t = 0.85s
solve for velocity final
Impulse = F * t = 20550N * 0.85s
mv^2 = Impulse = 17467.5
(1515 + 1125)v^2 = 17467.5
vf = 2.5m/s
Plug in stuff:
1515 * v1 + 1125 * (-18.3m/s) = (1515 + 1125) * 2.5m/s
v1 = 9.23
Note: I converted 41mph(v2) to 18.3m/s, which is negative because "westward" is in the negative direction.
Explanation: Inelastic collision
I'm not sure but my guess is we can solve for the force of friction using the coefficient of friction. With that, we can solve for the acceleration in F = ma, and use that to solve for the time the two cars slide. And using that we can solve for the impulse, which is just the Force of friction times that time, which is also our momentum. Since we know the momentum, we can solve for the velocity of the two objects after the collision. Using that velocity, we can use the equation( m1v1 + m2v2 = (m1+m2)vf ), plug in the known quantities and solve for v1.(Note: don't forget to convert mph to mps and 18.5ft to meters)
Extra: I'm guessing because the two cars slide, the only force acting on them is the force of friction(so it's our net force), hence the Fnet = ma.
A diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track. Determine the average power developed.
The average power developed by a diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track = 200 kW.
How to calculate average power?The first kinematic equation is v=v0+at , where v is the final velocity, v0 is the initial velocity, a is the constant acceleration, and t is the time
According to given information:
v = 10, v0= 0 , t= 100s, m=400
v=v0+at
10= 0+a(100)
a= 0.1 m/s²
∑ F =ma <==> F= 400(10 ³ )(0.1) = 40(10 ³)N
Pavg = F. Vavg = 40(10 ³)(10/2) = 200 kW
It represents the typical quantity of work completed or energy converted per unit of time. When the context clearly indicates it, the average power is frequently referred to as "power".
The instantaneous power overrides the average power as time interval t gets closer to zero.
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This hair-dryer has a plastic case. It is connected to a mains socket by a 3-pin plug.
The cable connecting the hair-dryer to the plug contains only two wires.
Write down the colour of the insulation on the wires.
Wire 1
Wire 2
(ii)
Which of the usual three wires is not needed?
=
This hair-dryer is safe to use without the third wire. Explain why.
Wire 1 and Wire 2 are typically insulated with one of three standard colors: black, white, or red.
The wire that is not needed is the earth wire, which is typically green or yellow with green stripes. The earth wire is used for safety purposes to provide a path for current to flow to the ground in case of a fault or short circuit, but is not strictly necessary for the operation of the hair-dryer.
The hair-dryer is safe to use without the earth wire because it is double-insulated. This means that the hair-dryer has two layers of insulation between the live and neutral wires and the outer casing, which provides an extra level of protection against electrical shocks. Double-insulated appliances are designed to operate safely without the need for an earth wire, and are marked with a symbol consisting of a square inside another square to indicate this.
What is an earth wire?
An earth wire, also known as a ground wire or protective earth (PE) wire, is a safety wire used in electrical wiring systems. It is designed to provide a path for electrical current to flow to the ground in the event of an electrical fault, such as a short circuit or a surge.
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Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 27.5 m/s (about 62 mph ) around the turn, what is the race car's centripetal (radial) acceleration? What is the Coefficient of friction?
Answer:
Explanation:
The centripetal acceleration of the race car is given by the formula:
a = v^2 / r
where v is the speed of the race car and r is the radius of the turn.
Substituting the given values, we get:
a = (27.5 m/s)^2 / 57.0 m = 13.3 m/s^2
So the centripetal acceleration of the race car is 13.3 m/s^2.
To find the coefficient of friction, we need to use the formula:
f = μN
where f is the force of friction, μ is the coefficient of friction, and N is the normal force.
The normal force is equal to the weight of the car, which we can calculate as:
N = mg
where m is the mass of the car and g is the acceleration due to gravity (9.81 m/s^2).
Assuming the mass of the car is 1500 kg, we get:
N = 1500 kg × 9.81 m/s^2 = 14,715 N
The force of friction is equal to the centripetal force required to keep the car moving in a circle:
f = ma = (1500 kg)(13.3 m/s^2) = 19,950 N
Substituting the values of N and f into the formula for friction, we get:
19,950 N = μ(14,715 N)
Solving for μ, we get:
μ = 1.35
So the coefficient of friction is 1.35.
what are the difference between a planetary fly by and a planter orbit insertion. list 6 thing for each, find the answer for NASA.gov
Answer:
Explanation:
Planetary Flyby:
The spacecraft does not go into orbit around the planet; instead, it uses the planet's gravity to change its speed and direction.
The spacecraft's closest approach to the planet is usually brief, ranging from a few minutes to a few hours.
The spacecraft is able to capture images and data during the brief encounter with the planet.
The spacecraft's trajectory can be adjusted to perform multiple flybys of different planets or moons.
The spacecraft does not require a large amount of fuel to perform a flyby, making it a cost-effective option for exploration.
Flybys are useful for studying a planet's atmosphere, magnetic field, and gravitational field.
Planetary Orbit Insertion:
The spacecraft goes into orbit around the planet, allowing for long-term study and data collection.
The spacecraft's orbit can be adjusted to achieve different scientific objectives, such as mapping the planet's surface or studying its atmosphere.
The spacecraft must have enough fuel to slow down and enter orbit, making it a more expensive option than a flyby.
The spacecraft's orbit can be stable or elliptical, depending on the scientific objectives and mission requirements.
The spacecraft may require several trajectory adjustments to achieve the desired orbit.
Orbit insertion allows for more detailed and comprehensive study of a planet's geology, climate, and magnetic field.
Problem 23.13 One type of antenna for receiving AM radio signals is a square loop of wire, 0.16 m on a side, that has 20 turns. Part A If the magnetic field from the radio waves changes at a rate of 8.4 × 10-4 T/s and is perpendicular to the loop, what is the magnitude of the induced emf in the loop? Express your answer to two significant figures and include appropriate units. Value Units Submit My Answers Give Up back Continue
The induced emf by the formula that we have can be obtained as 4.3 * 10^-4 V.
What is the induced emf?The induced emf (electromotive force) is the voltage that is generated in a conductor when there is a change in the magnetic field that surrounds the conductor. This phenomenon is known as electromagnetic induction and was discovered by Michael Faraday in the 19th century.
The induced emf is created by the interaction between the magnetic field and the moving charges in the conductor. When the magnetic field changes, it creates an electric field that pushes the charges in the conductor, creating a current flow.
Using emf = NAdB/dt
= 20 * (0.16)^2 * 8.4 × 10-4 T/s
4.3 * 10^-4 V
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1.- What is net net charge on the sweater? Why?
2.- What is the net charge on the balloon? Why?
ASAP pls and thank you!!
When students brush balloons against their wool sweaters or hair, electrons are moved from the wool or hair to the balloon. As a result, the balloon has a net negative charge, whereas the garment or hair, having shed negative charges, has a net positive charge.
What is net charge?The term "net" refers to the sum after both positive and negative costs have been deducted. So, if something has 321 positive charges and 319 negative charges, the overall charge is 321 - 319 = +2. The overall charge is 37 - 42 = -5 if it includes 37 positive charges and 42 negative charges.
Electrons are negatively charged, whereas protons are favourably charged. Atoms have an identical amount of electrons and protons and have a net charge of zero. This makes atoms always neutral.
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Two moles of oxygen gas, which can be regarded as an Ideal gas with Cv = 22,1 JK 'mol, are maintained at 273k in a volume of 0,1 m ³ under 1 Sothermal conditions. Then, the gas is compressed reversibly to half of its original volume at constant pressure calculate P₁ and P2 Cp W, Show all derivation steps qp
Answer:
P1 = 45,174 Pa
P2 = 90,348 Pa
W = 2,259 J
Q = 2,259 J
ΔS = 0
Explanation:
We can use the ideal gas law, PV = nRT, to solve this problem. Since the gas is at constant temperature (isothermal), we can simplify this to PV = constant.
Given that there are two moles of oxygen gas in a volume of 0.1 m^3 at 273 K, we can calculate the initial pressure as follows:
P1V1 = nRT
P1 = nRT/V1
P1 = (2 mol)(8.31 J/mol.K)(273 K)/(0.1 m^3)
P1 = 45,174 Pa
Next, we compress the gas reversibly to half of its original volume (i.e. V2 = 0.05 m^3) at constant pressure. We can use the same equation, PV = constant, and the fact that the pressure is constant to solve for the final pressure:
P1V1 = P2V2
P2 = P1V1/V2
P2 = (45,174 Pa)(0.1 m^3)/(0.05 m^3)
P2 = 90,348 Pa
Now, we can calculate the work done during the compression process using the equation:
W = -PΔV
where ΔV is the change in volume (i.e. V2 - V1 = -0.05 m^3), and the negative sign indicates that work is done on the system during compression. Substituting the values, we get:
W = -(45,174 Pa)(-0.05 m^3)
W = 2,259 J
Finally, we can calculate the heat added to the system using the first law of thermodynamics:
ΔU = Q - W
where ΔU is the change in internal energy (which is zero since the temperature is constant), Q is the heat added to the system, and W is the work done on the system (which is negative). Solving for Q, we get:
Q = ΔU + W
Q = 0 J + 2,259 J
Q = 2,259 J
Since the temperature is constant, the heat added to the system is equal to the change in enthalpy:
ΔH = Q = 2,259 J
We can also calculate the change in entropy using the equation:
ΔS = nCv ln(T2/T1)
where Cv is the molar heat capacity at constant volume (which is given as 22.1 J/K.mol), and ln(T2/T1) is the natural logarithm of the ratio of final and initial temperatures. Since the temperature is constant, ΔS = 0.
Therefore, the final answers are:
P1 = 45,174 Pa
P2 = 90,348 Pa
W = 2,259 J
Q = 2,259 J
ΔS = 0
A uniform disk with a mass of 190 kg and a radius of 1.1 m rotates initially with an angular speed of 950 rev/min. A constant tangential force is applied at a radial distance of 0.5 m. How much work must this force do to stop the wheel? Answer in units of kJ.
Answer:
Explanation:
We can use the work-energy principle to find the work done by the applied force to stop the disk. The work-energy principle states that the work done by all forces acting on an object is equal to the change in its kinetic energy:
W = ΔK
where W is the work done, and ΔK is the change in kinetic energy.
Initially, the disk is rotating with an angular velocity of 950 rev/min. We need to convert this to radians per second, which gives:
ω_initial = (950 rev/min) × (2π rad/rev) × (1 min/60 s) = 99.23 rad/s
The initial kinetic energy of the disk is:
K_initial = (1/2) I ω_initial^2
where I is the moment of inertia of the disk about its axis of rotation. For a uniform disk, the moment of inertia is:
I = (1/2) m R^2
where m is the mass of the disk, and R is the radius. Substituting the given values, we get:
I = (1/2) (190 kg) (1.1 m)^2 = 115.5 kg m^2
Therefore, the initial kinetic energy of the disk is:
K_initial = (1/2) (115.5 kg m^2) (99.23 rad/s)^2 = 565201 J
To stop the disk, the applied force must act opposite to the direction of motion of the disk, and must cause a negative change in the kinetic energy of the disk. The force is applied at a radial distance of 0.5 m, which gives a torque of:
τ = F r
where F is the magnitude of the force. The torque causes a negative change in the angular velocity of the disk, given by:
Δω = τ / I
The work done by the applied force is:
W = ΔK = - (1/2) I Δω^2
Substituting the given values, we get:
W = - (1/2) (115.5 kg m^2) [(F r) / I]^2
The force F can be eliminated using the equation for torque:
F = τ / r = (Δω) I / r
Substituting this into the equation for work, we get:
W = - (1/2) (115.5 kg m^2) [(Δω) I / r I]^2
= - (1/2) (115.5 kg m^2) (Δω / r)^2
Substituting the values for Δω and r, we get:
W = - (1/2) (115.5 kg m^2) [(F r / I) / r]^2
= - (1/2) (115.5 kg m^2) [(2 Δω / R) / (2/5 m R^2)]^2
= - (1/2) (115.5 kg m^2) (25/4) (2 Δω / R)^2
= - 90609 J
where we have used the expression for the moment of inertia of a uniform disk and the given values for the mass and radius. The negative sign indicates that the work done by the applied force is negative, which means that the force does negative work (i.e., it takes energy away from the system). The work done by the force to stop the disk is therefore 90609 J, which is -90.6 kJ (to two decimal places).
An observer counts 4 complete water waves passing by the end of a dock every 10 seconds. What is the
frequency of the waves?
a) 4,0 Hz
b) 0.40 Hz
() 40 Hz
d) 2.5 Hz
The frequency of the water wave is 0.4Hz (option B).
How to calculate frequency?Frequency is the quotient of the number of times (n) a periodic phenomenon occurs over the time (t) in which it occurs.
The frequency of a wave can be calculated by dividing the number of occurrence by time as follows;
f = n/t
Where;
f = frequencyn = number of times of occurrencet = timeAccording to this question, an observer counts 4 complete water waves passing by the end of a dock every 10 seconds. The frequency can be calculated as follows:
f = 4/10
f = 0.4Hz
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Select the correct answer. In a given chemical reaction, the energy of the products is greater than the energy of the reactants. Which statement is true for this reaction? A. Energy is absorbed in the reaction. B. Energy is released in the reaction. C. No energy is transferred in the reaction. D. Energy is created in the reaction. E. Energy is lost in the reaction. Reset Next
A tiny solid ball (I = (2/5)Mr^(2)) rolls without slipping on the inside surface of a hemisphere as shown in Fig. 10-12. (The ball is much smaller than shown.) If the ball is released at A, how fast is it moving as it passes (a) point-B, and (b) point-C? Ignore friction losses. [Hint: Study the two previous questions. When it comes to the ball’s descent, its own radius is negligible.]
At point B, the ball is moving at a speed of around 2.05 m/s. At point C, the ball is moving at a speed of roughly 3.67 m/s.
Is velocity the same as speed?Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.
(a) The ball has plummeted to a height at point B of h = r(1 - cos), where r is the hemisphere's radius and is the angle formed by the vertical and the line connecting A and B.
The ball loses as much potential energy as it gains in kinetic energy:
mgh = (1/2)mv² + (1/2)Iω²
Since the ball is rolling without slipping, we have v = rω. Also, for a solid sphere or ball, I = (2/5)mr^2.
By simplifying and substituting these formulas, we obtain:
mgh = (7/10)mv²
Solving for v, we get:
v = √((10/7)gh)
Substituting the given values, we get:
v = √((10/7) x 9.8 m/s² x 0.5 m x (1 - cos(30°)))
≈ 2.05 m/s
(b) The ball has dropped through a height of h = 2r at point C. Applying the same simplifications and conservation of energy equation as before, we arrive at:
mgh = (7/5)mv²
Solving for v, we get:
v = √((5/7)gh)
By simplifying and substituting these formulas, we obtain:
v = √((5/7) x 9.8 m/s² x 1.0 m)
≈ 3.67 m/s.
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Estimat the number and wattage of lamps. which would be required to illuminate a workshop space 60x1.5 meteres by means of lamps mounted 5 metres above the working Plane The average illumination required is about 100 wt. coefficient of utilisation = 0.4 luminous efficiency 16 lumens per watt. Assume a space-height ratio of unity and a cundle Power depreciation of 20%
The number and wattage of lamps required to illuminate the workshop would be approximately 8 lamps and 70 watts respectively.
Wattage calculationTo estimate the number and wattage of lamps required to illuminate a workshop space of 60x1.5 meters, we can follow these steps:
Calculate the area of the workshop:
Area = length x widthArea = 60m x 1.5mArea = 90 square metersDetermine the total lumens required:
Lumens = area x average illuminationLumens = 90 sq m x 100 luxLumens = 9000 lumensAdjust for the coefficient of utilization and luminous efficiency:
Effective lumens = lumens / (coefficient of utilization x luminous efficiency)Effective lumens = 9000 / (0.4 x 16)Effective lumens = 1406.25 lumensAdjust for space-height ratio and candle power depreciation:
Effective lumens per lamp = effective lumens x space-height ratio x (1 - depreciation)Effective lumens per lamp = 1406.25 x 1 x (1 - 0.2)Effective lumens per lamp = 1125 lumensDetermine the number of lamps required:
Number of lamps = total lumens required / effective lumens per lampNumber of lamps = 9000 / 1125Number of lamps = 8 lamps (rounded up)Determine the wattage of each lamp:
Wattage per lamp = effective lumens per lamp / luminous efficiencyWattage per lamp = 1125 / 16Wattage per lamp = 70.3 watts (rounded up)Therefore, approximately 8 lamps with a wattage of 70 watts each would be required to illuminate the workshop space.
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) at the instant 7.6 s after the switch is closed, calculate the charge on the capacitor. (2) substitute numerical values into q(t)
The charge on the capacitor at 7.6 s after the switch is closed is 54.87 µC.
The charge on the capacitor can be calculated using the formula,
Q = Q₀(1-e^(-t/RC))
where Q₀ is the initial charge on the capacitor,
t is the time elapsed,
R is the resistance and
C is the capacitance.
Substituting the given values
Q₀ = 60 µC,
R = 10kΩ,
C = 2 µF, and
t = 7.6 s,
we get
[tex]Q = 60 µC(1-e^(-7.6/(10 \times 10³ \times 2\times 10^-6))[/tex]
= 54.87 µC
Thus, the charge on the capacitor at 7.6 s after the switch is closed is 54.87 µC.
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When a water heater is rated to operate at 240 volts but is operated at 208 volts, the water heater will take___ time to heat the water.Select one:a. moreb. the samec. less
a. more When a water heater is rated to operate at 240 volts but is operated at 208 volts, the lower voltage means that the heating element in the water heater will not receive as much power as it is designed.
What is a power ?Power is the rate at which work is done or energy is transferred, typically measured in watts or horsepower. It represents the amount of energy used or transferred per unit time.
Mathematically, power is defined as the product of force and velocity, or the product of current and voltage. The unit of power is the watt (W), which is equal to one joule of energy per second.Power is an important concept in physics, engineering, and technology. It is used to describe the output of engines, motors, generators, and other devices that convert energy from one form to another. In everyday life, power is used to measure the rate at which electricity is consumed by appliances and electronics, and to compare the performance of different machines and tools.
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Two blocks of unequal mass are tied together with a massless string that does not stretch and connected via a frictionless and massless pulley. Mass one, M1, rests on a frictionless table top. Mass two, M2, is released and both blocks begin to move....
The blocks accelerate at the same rate since they are connected. What is the acceleration?
The blocks accelerate at the same charge for the reason that they're linked. The acceleration is a value between zero and g.
Acceleration is a physical concept that refers to the rate of change of an object's velocity with respect to time. When an object's velocity changes, either by speeding up or slowing down, it is said to be accelerating.
Acceleration plays an important role in many aspects of physics, from the motion of celestial bodies to the behavior of particles in a particle accelerator. The magnitude of acceleration is the rate at which an object's velocity changes, and it is measured in units of meters per second squared (m/s^2) in the International System of Units (SI). There are several factors that can cause an object to accelerate, such as a force acting on it, a change in its direction of motion, or a combination of both.
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true/false. A nuclear family includes a pair of adults, their children, and any grandparents who live in the family.
The nuclear family is considered the most essential family unit because it is the family unit with the most fundamental relationships. that's why the Given statement is False.
In a nuclear family, parents and their children live in a household. A nuclear family is a type of family structure that consists of a pair of adults and their children, but not grandparents who live in the family.
It is also called the traditional family, and it is considered to be the basic family unit.A nuclear family is a small family consisting of two parents and their children.
A nuclear family is often known as the basic family unit since it is a family structure consisting of two parents and their children. It is also considered the most prevalent family structure in many countries around the world.
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imagine that the blue light and orange light from the source were blocked. what color would how be present in the spectrum of light observed
Everything but blue & orange would now be present in the spectrum of light observed.
Spectrum refers to a range of different wavelengths of electromagnetic radiation. Electromagnetic radiation is a form of energy that travels through space and includes different types such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different wavelength and frequency, and together they make up the electromagnetic spectrum.
The concept of spectrum is used in a variety of fields, including physics, astronomy, and telecommunications. The spectrum of electromagnetic radiation is essential for many technologies, such as radios and televisions, cell phones, and medical imaging devices, as they all rely on the transmission and reception of specific wavelengths of electromagnetic radiation.
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Complete Question: -
Imagine that the blue light and orange light from the source were blocked. What color(s) would now be present in the spectrum of light observed?
The energy of a photon is inversely proportional to its wavelength. True or Flase
False. E=hf, where h is Planck's constant, c is the speed of light, f is the frequency, and is the wavelength; and E=hc/, where E is directly proportional to frequency and inversely proportional to wavelength.
The inverse relationship between a photon's energy and what?With respect to the wavelength of the radiation, photon energy is inversely proportional.
What is a photon's wavelength-related energy?Two formulas can be used to determine a photon's energy: E = h f is a formula that can be used if the photon's frequency is known. This equation, sometimes known as Planck's equation, was created by Max Planck.
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I need some help with this problem
Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.
What Does Tensile Force Mean?Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.
When a tensile force is applied to a substance, a stress equivalent to the applied force forms, contracting the cross-section and elongating the length.
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b) what is the probability that an average of 22 shields will absorb more than 17.1 j/kg? use 4 decimal places.
The probability that an average of 22 shields will absorb more than 17.1 J/kg is approximately 0.3085.
where X is the random variable representing the energy absorbed per kilogram of the shield.
To calculate this probability, we need to know the distribution of X.
From the given information, we know that X follows a normal distribution with mean μ = 16.8 J/kg and standard deviation σ = 0.6 J/kg.
Thus, we can standardize X as follows:
Z = (X - μ)/σZ ~ N(0, 1)
P(X > 17.1) = P((X - μ)/σ > (17.1 - μ)/σ)
= P(Z > (17.1 - 16.8)/0.6)
= P(Z > 0.5)
Using a standard normal table, we can find the probability that Z > 0.5 to be 0.3085 (rounded to 4 decimal places).
Therefore, the probability that an average of 22 shields will absorb more than 17.1 J/kg is approximately 0.3085.
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Two pieces of clay, one white and one gray, are thrown through the air. The
m
white clay has a momentum of 25 kg, and the gray clay has a
S
momentum of -30 kg immediately before they collide.
What is the magnitude and direction of their final momentum immediately
after the collision?
Your answer should have one significant figure.
h
kg.
m
-
m
S
S
we can't give a specific direction for the final momentum.
What is momentum?
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum is expressed as:
Momentum (p) = mass (m) x velocity (v)
p = m x v
To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
The initial total momentum of the system is:
p_initial = p_white + p_gray = 25 kg m/s - 30 kg m/s = -5 kg m/s
Since there are no external forces acting on the system, the total momentum of the system after the collision must also be -5 kg m/s. Therefore, the final momentum of the system is:
p_final = -5 kg m/s
The direction of the final momentum can be found by looking at the directions of the initial momenta. Since the white clay has positive momentum and the gray clay has negative momentum, we can say that the white clay is moving to the right and the gray clay is moving to the left before the collision.
During the collision, the two clays will exert forces on each other, causing them to change direction and possibly even break apart. Without more information about the collision, we can't say for sure what the direction of the final momentum will be. It could be to the left or to the right, or some combination of the two. Therefore, we can't give a specific direction for the final momentum.
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Please do help me. Nonsense answers will be reported.
An object is thrown horizontally with a speed of 30 m/s from the top of a building. Complete the table below for the indicated time interval. Use g≈ 10 m/s²)
The time that was taken for the movement of the item is observed as 3 seconds.
How do you use the equations of motion?The equations of motion describe the motion of objects in terms of their position, velocity, acceleration, and time.
For the equation;
v = u + at
This equation relates the final velocity (v) of an object to its initial velocity (u), acceleration (a), and time (t). If three of these variables are known, the equation can be rearranged to solve for the unknown variable.
We know that;
v = u - gt
We know that the object would come to rest after being thrown.
0 = 30 - 10t
-30 = - 10t
t = 3 seconds
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At one instant an object in free fall is moving downward at 50 meters per second. One second later its speed is about
A) 25 m/s. B) 50 m/s. C) 55 m/s. D) 60 m/s. E) 100 m/s.
The correct answer is C) 55 m/s. An object in free fall accelerates due to gravity, which means its speed increases by about 9.8 m/s2 every second. So in one second, its speed increased from 50 m/s to 50 + 9.8 = 59.8 m/s. Since it is impossible for the object to have a speed of 59.8 m/s, the closest answer is C) 55 m/s.
Given,An object in free fall is moving downward at 50 meters per second.At one-second later its speed is about.To find: The speed of the object at one second laterSolution:Let us assume that the object moves with an acceleration of ‘g’.Given, Initial velocity, u = 50 m/s
Time taken, t = 1sWe know that the velocity of an object in freefall is given by:v = u + gtFrom the above equation, we can calculate the final velocity of the object after one secondv = u + gtv = 50 + 9.8 × 1v = 50 + 9.8v = 59.8 ≈ 60 m/sTherefore, the final velocity of the object after one second is 60 m/s.Hence, the correct option is (D) 60 m/s.
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