Answer:
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. De las siguientes soluciones:
1. 20 ml de alcohol etílico mezcladas con 80 ml de agua.
2. 500 ml de agua con 20 g de sal disueltas (V Sln: 500ml).
3. 80 g de sal en 2 litros de agua.
a) Identifica el soluto y solvente de cada solución y explica ¿por qué?
b) Encuentra la concentración por peso de la solución número 3 c) Entre la disolución 2 y 3 ¿Cuál presenta mayor concentración?
por favor lo necesito para hoy ¡gracias!
Answer:
can u translate this to English? I might be able to help
a) Solution 1: Solute is ethyl alcohol, solvent is water. Solution 2 and 3: Solute is salt, solvent is water.
b) Concentration by weight of solution 3: Approximately 3.85%.
c) Solution 3 has a higher concentration than solution 2.
a) Solutions and their solutes and solvents:
Solution 1: The solute is ethyl alcohol, and the solvent is water. This is because ethyl alcohol is the substance that dissolves in water to form the solution.
Solution 2: The solute is salt, and the solvent is water. Salt is the substance that dissolves in water to form the solution.
Solution 3: The solute is salt, and the solvent is water. Similar to solution 2, salt is the substance that dissolves in water to form the solution.
b) Weight concentration of solution number 3:
The weight concentration is calculated by dividing the mass of the solute (80 g of salt) by the total mass of the solution (80 g of salt + 2000 g of water):
Weight concentration = (80 g / 2080 g) * 100% ≈ 3.85%
c) Comparison of concentrations between solution 2 and 3:
Solution number 3 has a higher concentration than solution 2, as the weight concentration of solution 3 is approximately 3.85%, while the exact amount of water is not provided for solution 2 to calculate its concentration. However, solution 2 contains only 20 g of salt dissolved in 500 ml of water, which implies that the concentration will be lower than solution 3. Therefore, solution number 3 has a higher concentration compared to solution 2.
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Specific heat capacity is _____.
greater for metal than for wood
the amount of heat required to raise the temperature of 1g of a substance 1 oC
represented by the symbol, Q
all of these
Answer:
all of this
Explanation:
High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to
purify chemical substances. The pressures used in this procedure range from around 500
kilopascals (500,000 Pa) to about 60,000 kPa (60,000,000 Pa). It is often convenient to know
the pressure in torr. If an HPLC procedure is running at a pressure of 3.20x10^8 Pa , what is its
running pressure in torr?
Express the pressure numerically in torr.
►
3.20 x 10^8 Pa = _____ torr
Answer:
2,400,000 torr (3 s.f.)
Explanation:
Convert the pressure from Pascal to atm first:
[tex]\boxed{1 \: atm = 101325 \:Pa }[/tex]
3.20 ×10⁸ Pa
= [(3.20 ×10⁸) ÷101325] atm
= 3158.2 atm (5 s.f.)
Convert atm to torr:
[tex]\boxed{1 \: atm = 760 \: torr}[/tex]
3158.2 atm
= (3158.2 ×760) torr
= 2400000 torr (3 s.f.)
What happens to a glass of sugar solution when sugar is added to it?
The number of moles of water increases.
The number of moles of water decreases.
The molarity of the solution increases.
The molarity of the solution decreases.
When sugar is added to a glass of sugar solution, the molarity of the solution increases. Details about molarity can be found below, which is the third option.
What is molarity?Molarity is a term used to identify the amount of solute, in moles, dissolved in a solvent by volume. Molarity is expressed as moles per liter (mol/L).
However, molarity is directly proportional to the amount of solute in solution. This means that as the amount of solute increases, molarity also increases.
Therefore, when sugar is added to a glass of sugar solution, the molarity of the solution increases.
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Which of the following is an example of a solution?
A. An iron alloy
B. Iron metal
C. Iron rust
D. An iron ore
Answer:
A: an iron alloy.
Explanation:
Because iron alloy consists of minor components that are distributed within the major component, which is the basic requirement for a solution.
What is the pressure in atm exerted by 1.8 g of H2 gas exert in a 4.3 L balloon at 27ºC? R = 0.821(L*atm) / (mol*K)
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The pressure in atm exerted by 1.8 g of H₂ gas exert in a 4.3 L balloon at 27ºC is 5.12 atm
What is Ideal gas law ?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Let's convert grams to moles (via molar mass).
Molar Mass (H₂) : 2 (1.008 g/mol)
Molar Mass (H₂) : 2.016 g/mol
1.8 grams H₂ 1 mole
---------------------- x ---------------------- = 0.893 moles H₂
2.016 grams
The Ideal Gas Law equation looks like this:
PV = nRT
In this equation,
P = pressure (atm) V = volume (L) n = moles R = Ideal Gas Constant (0.0821 L*atm/mol*K)T = temperature (K)After converting Celsius to Kelvin, you can put the given values into the equation and simplify to find the pressure.
P = ? atm R = 0.0821 L*atm/mol*K
V = 4.3 L T = 27 °C + 273.15 = 300.15 K
n = 0.893 moles
PV = nRT
P (4.3 L) = (0.893 moles) (0.0821 L*atm/mol*K)( 300.15 K)
P (4.3 L) = 22.0021
P = 5.12 atm
Therefore, The pressure in atm exerted by 1.8 g of H₂ gas exert in a 4.3 L balloon at 27ºC is 5.12 atm
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Describe weighted average
Answer:
Explained below
Explanation:
In simple average, we just add all the given data variables and divide it by the number of data given.
However, when it comes to weighted average, what we do is that we multiply each given variable by their weights and then divide the sum of that by the sum of the weights.
Thus, if the variables are denoted by x and their weights are denoted by y, then we have;
Weighted average = Σ(xy)/Σy
Determine the mass of 6.33 mol of iron(II) nitrate.
Answer:
1822.72 g
Explanation:
Applying,
n = R.M/M.M.................. Equation 1
Where n = number of moles of iron(II) nitrate, R.M = Reacting mass of iron(II) nitrate, M.M = molar mass of Iron(II) nitrate.
Make R.M the subject of the equation
R.M = n×M.M............. Equation 2
From the question,
Given: n = 6.33 mol
Constant: M.M of iron(II) nitrate = 287.95 g/mol
Substitute these values into equation 2
R.M = 6.33(287.95)
R.M = 1822.72 g
Hence the mass of iron(II) nitrate is 1822.72 g
The world is made up of
Answer:
Explanation:
The world is made up of living beings .
its not a question but i wanted to tell you guys that if you guyz like my answers then please don't forget to give like and follow at the same time. I am not forcing you to follow only if you guyz like my answer then like or follow. THANKS FOR READING..
Answer:
thank you for this oibnki
Answer:
Sure I'll go ahead and like your answers and follow you if that's what you wanted! :)
Explanation:
c. The element in group 2 and period 3 is -
Answer:
Magnesium
Explanation:
Hope this helps!
What is the mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water?
The mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water is 29.7%.
What is mass percent ?Mass percent is a means to describe a component in a specific combination or to convey a concentration. The mass percentage used to describe the solution composition indicates the mass of solute contained in a given mass of solution.
To determine the mass percent of an element in a compound, we divide the mass of the element in one mole of the compound by the compound's molar mass and multiply the result by 100.
Given:
Number of moles = 0.64 moles
Moles of sodium fluoride = Given mass/molar mass
0.64 moles = Mass / 42
Mass = 26.88gram
Mass % = Mass of solute/ mass of solution × 100
= 26.88/90.48 × 100
= 29.7 %
Thus, 29.7 % is the mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water
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Select the structure corresponding to trans-3-octene.
Answer: B
Explanation:
Answer:
The Correct Answer Is B.
what do you mean by 1 joule work
Answer:
Joule is the SI unit of work. 1 Joule is amount of work done when a force of 1 Newton displaces a body through a distance of 1m in the direction of the force applied.
what is the percentage composition of water in crystallization of oxalic acid
Answer:
5.17 percentage is water
Explanation:
answer from gauth math
How is a slump different from creep?
Answer:
Is this chemistry or ELA!
What is the purpose of a catalyst in the production of hydrogen?
Select the correct answer.
- to increase the rate at which water molecules decompose
- to decrease the amount of oxygen produced
- to decrease the temperature of the reaction
- to increase the activation energy of the reaction
The purpose of a catalyst in the production of hydrogen is to increase the rate at which water molecules decompose.
What is a catalyst-A catalyst is a substance that increases the rate of a chemical reaction without itself being consumed or produced during the reaction. As a result, catalysts assist in speeding up chemical reactions while also decreasing the amount of energy needed for the reaction to occur. In hydrogen production, catalysts are used to speed up the decomposition of water into hydrogen and oxygen. The use of catalysts lowers the activation energy required for the reaction to occur, resulting in a faster reaction rate and lower operating temperatures.What is the process of hydrogen production?Hydrogen production has various methods, and one of the most commonly used methods is water electrolysis. In this method, water molecules are split into hydrogen and oxygen using an electric current passed through an electrode. Water is broken down into hydrogen and oxygen during the process, with the assistance of a catalyst. During this process, a catalyst like platinum or nickel is employed to speed up the chemical reaction of water decomposition.
When an electric current is applied to the catalyst, water molecules are broken apart, releasing hydrogen and oxygen atoms.Catalysts lower the activation energy of the reaction, allowing it to occur faster than it would otherwise. In hydrogen production, catalysts are crucial since they enable the reaction to occur at a lower temperature, reducing energy consumption and minimizing operating costs. As a result, the use of catalysts is essential to the production of hydrogen.
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can you answer with working out
Re-word this statement: Ionic Radii are changing as you move down the column because the atoms in lower rows have more energy levels, which makes the valence electrons farther from the nucleus, so it takes less energy for them to be pulled away.
The Ionic radii are changing as you move across a row because each element has one more proton, which increases the attraction of the nucleus.
Answer:
ty po hehe
Explanation:
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g) silver nitrate + magnesium chloride → silver chloride + magnesium nitrate
Answer:
AgNo3+Mgcl2--->Agcl2+Mg(No3)2
I hope this helps
the text of oxygen gas in the laboratory
Explanation:in testing for oxygen a glowing splint is used.
the glowing splint is brought in the presence of the test tube containing the gas
the glowing splint rekindles or lights up showing that oxygen is present.
this is a positive test because oxygen supports burning or combustion
Question 5
1.00 g of He, 14.0g F2, and 19.0 g Ar are placed in a 13.0-L container at 20.0 °C.
The total pressure (in atm) in the container is _____ atm.
1 point
Answer:
2.03 atm
Explanation:
Number of moles of He = 1g/4g/mol = 0.25 moles
Number of moles of F2 = 14.0g/38 g/mol = 0.37 moles
Number of moles of Ar=19.0g/40g/mol = 0.48 moles
Total number of moles = 0.25 + 0.37 + 0.48 = 1.1 moles
From;
PV=nRT
P= pressure of the gas mixture
V= volume of the gas mixture
n= total number of moles of the gas mixture
R= gas constant
T= temperature of the gas mixture
P= nRT/V
P= 1.1 × 0.082 × 293/13
P= 2.03 atm
How much water will the measuring cup have if you poured 1/2 of it out?
In the figure a cyclist moves A to B and then to C.he could also go through the shortest path AC. Depending on this fact solve the following questions: Find the length of AC .Find the displacement and total distance covered.
Answer:
hope it helps you see the attachment for further information
Can compound take part in chemical reaction?
Answer:
YES!
Explanation:
Suppose that three isotopes of element X occur in nature as follows:
The relative atomic mass of the naturally occurring mixture of element X is
Answer:
107.5 amu
Explanation:
isotopes: fractional Wt Avg
isotopes: isotopic mass %Abundance abundance (amu)
X110 110 60 0.60 66.0
X105 105 30 0.30 31.5
X100 100 10 0.10 10.0
∑ atm mass contributions = 107.5 amu*
*amu = atomic mass units
write any two conditions at which a body of certain mass weightless
Answer:
A body becomes weightless in a zero-gravity scenario and when a force is applied to a body that is equal and opposite to the force of gravity. If the body is falling only under the influence of gravity.
Answer:
A body becomes weightless in a zero-gravity scenario and when a force is applied to a body that is equal and opposite to the force of gravity.If the body is falling only under the influence of gravity.
Please help me with my work
Answer:
2
Explanation:
There's 2 Hydrogen and Chlorine molecules on the right side with one Zinc. So the left side needs to have a coefficient of 2 on the hydrochloric acid, or HCl.
- calculate relative formula mass
[N=14, O=16, Mg=24, Al=27]
1) Mg(NO3)2
- calculate relative molecular mass
[H=1, C=12, O=16]
1) C4H10
2) CH3COOH
Mg(NO3)2:-
[tex] \\ \sf \longmapsto \: 24u+2(14u+3\times 16u)[/tex]
[tex] \\ \sf \longmapsto \: 24u+2(14u+48u)[/tex]
[tex]\\ \sf \longmapsto \: 24u+2(62u)[/tex]
[tex] \\ \sf \longmapsto \: 24u+(124u)[/tex]
[tex] \\ \sf \longmapsto \: 148u[/tex]
please help with the attached picture question 21, 22, 23
Explanation:
21. The given molecule for cracking is tetradecane.
On cracking it forms one mole of decane (C10H22) and two moles of ethene gas.
The chemical equation is shown below:
[tex]C_1_4H_3_0->C_1_0H_2_2+2C_2H_4[/tex]
22. The essential condition for the formation of an ester is the reaction of alcohol and acid in presence of concentrated sulfuric acid.
Thus among the given options, the first option is the correct one.
23. Isomers of butanol are shown below:
It is 2-butanol.
The position of -OH group changes to the second carbon.
