Answer:
The right solution is "36 years".
Step-by-step explanation:
Given:
Principle,
P = $2,340,260
Amount,
A = $3,393,377
Simple interest,
SI = 3,393,377 - 2,340,260
= $1,053,117
Rate of interest,
r = 1.25%
As we know,
⇒ [tex]SI=\frac{Prt}{100}[/tex]
By substituting the values, we get
⇒ [tex]1053117=\frac{2340260\times 1.25\times t}{100}[/tex]
⇒ [tex]10531170=292532.5\times t[/tex]
⇒ [tex]t=\frac{10531170}{292532.5}[/tex]
⇒ [tex]=36 \ years[/tex]
Volunteers who had developed a cold within the previous 24 hours were randomized to take either zinc or placebo lozenges every 2 to 3 hours until their cold symptoms were gone (Prasad et al., 2000). Twenty-five participants took zinc lozenges, and 23 participants took placebo lozenges. The mean overall duration of symptoms for the zinc lozenge group was 4.5 days, and the standard deviation of overall duration of symptoms was 1.6 days. For the placebo group, the mean overall duration of symptoms was 8.1 days, and the standard deviation was 1.8 days.
a. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the zinc lozenges.
b. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the placebo lozenges.
c. On the basis of the intervals computed in parts (a) and (b) and/or the picture you constructed in part (c), is it reasonable to conclude generally that taking zinc loz-enges reduces the overall duration of cold symptoms more than if taking a placebo? Explain why you think this is or is not an appropriate conclusion.
d. In their paper, the researchers say that they checked whether it was reasonable to assume that the data were sampled from a normal curve population and decided that it was. How is this relevant to the calculations done in parts (a) and (b)?
Answer:
a. (3.83952, 5.16049)
b. (7.32, 8.88)
c. The difference in the range of the confidence intervals suggest that taking the zinc loz-enges reduces the overall duration of cold symptoms
d. The assumptions required for the validity validity of a t-test include that the data is sampled from a source that have data that are normally distributed
Step-by-step explanation:
The given parameters are;
The number of participants that took zinc lozenges, n₁ = 25
The number of participants that took a placebo, n₂ = 23
The mean duration of the symptoms for the zinc lozenge group, [tex]\overline x_1[/tex] = 4.5 days
The standard deviation of overall duration, s₁ = 1.6 days
The mean duration of the symptoms for the placebo group, [tex]\overline x_2[/tex] = 8.1 days
The standard deviation, s₂ = 1.8 days
a. The 95% confidence interval if everyone in the population were to take zinc lozenges is given as follows;
[tex]CI=\bar{x}_1\pm t_{\alpha/2} \times \dfrac{s_1}{\sqrt{n_1}}[/tex]
n₁ = 25, the degrees of freedom (df) = n₁ - 1 = 24
The t-value for 95% confidence interval, with df = 24, with t = 2.064
Therefore, we have;
[tex]CI_{zl}=4.5 \pm 2.064 \times \dfrac{1.6}{\sqrt{25}}[/tex]
[tex]CI_{zl}[/tex] = 4.5 ± 0.66048
[tex]CI_{zl}[/tex] = (3.83952, 5.16049)
b. The 95% confidence interval if everyone in the population were to take the placebo is given as follows;
[tex]CI_p=\bar{x_2}\pm t_{\alpha/2} \times \dfrac{s_2}{\sqrt{n_2}}[/tex]
n₂ = 23, the degrees of freedom (df) = n₂ - 1 = 22
The t-value for 95% confidence interval, with df = 22, with t = 2.074
Therefore, we have;
[tex]CI_p =8.1 \pm 2.074 \times \dfrac{1.8}{\sqrt{23}}[/tex]
[tex]CI_p[/tex] = 8.1 ± 0.7784
[tex]CI_p[/tex] = (7.32, 8.88)
c. Based on the difference in the range of the 95% confidence interval for the mean duration of cold symptoms of the group that take zinc lozenges, (3.83952, 5.16049), and the mean of the group that are on a placebo, (7.32, 8.88), there is sufficient statistical evidence to suggest that there is a difference between the mean and taking zinc lozenges reduces the overall duration of cold symptoms more than if taking placebo
d. The assumptions required for validity when carrying out a t-test include;
i) The measurement scale is ordinal or continuous
ii) The sample is a simple random sample
iii) The data gives a normal distribution curve
iv) The sample size is reasonably large
v) The variance are homogeneous
Among these assumptions, the data must be randomly sampled from the population of interest and that the data variables follow a normal distribution
The common assumptions made when doing a t-test include those regarding the scale of measurement, random sampling, normality of data distribution, adequacy of sample size and equality of variance in standard deviation
Eighty percent of students surveyed said they feel more focused after exercising. Nine hundred fifty students were surveyed.
Students Who Feel More Focused after Exercise
20%
20%
20%
20%
20%
How many students said they feel more focused after exercising?
Answer:
760
Step-by-step explanation:
Which one goes where?:( WILL GIVE BRAINLIEST!<33
Answer:
1 pair of parallel sides: B
2 pairs of parallel sides: A, D
3 pairs of parallel sides: C
Step-by-step explanation:
When two lines are parallel, they will never intersect.
A batter gets 6 hits in 12 times at bat. What is the experimental
probability that she will get a hit in her next time at bat?
Answer:
1/2 or 50% or .5
Step-by-step explanation:
She hits at .500 that's pretty good. I'd take her on my fantasy team.
I got 7 but I’m confused
Answer:
27
Step-by-step explanation:
3v+6=5v-8
3v+14=5v
14=2v
v=7
3*7+6
21+6
27
u were right on 7 u just need to plug it into the equation
Find B
Plzz find the right answer and don’t just guess
Answer:
Step-by-step explanation:
using pythagoras theorem
a^2 + b^2 = c^2
B^2 + 8^2 = 15^2
B^2 + 64 + 225
B^2 = 225 - 64
B^2 = 161
B = [tex]\sqrt{161}[/tex] OR 12.7
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out the maximum amount of profit the company can make, to the nearest dollar.
y=−9x^2+571x−3884
gradient of line AB (3,7) and (5,11)
Answer:
Gradient is change in y over change in x.
gradient = y1-y2 ÷ x1-x2
=7-11 ÷ 3-5
=-4 ÷ -2
=2
Use the slope/gradient formula below:
[tex] \large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]
This formula is for when we want to find the gradient when we have two given points. (We also call it Rise Over Run or changes of y over the changes of x.)
We are given two points which are (3,7) and (5,11). Substitute these points in the equation. (the ordered pairs are in (x,y) and not (y,x))
[tex] \large{m = \frac{11 - 7}{5 - 3} } \\ \large{m = \frac{4}{2} \longrightarrow \boxed{m = 2}}[/tex]
Hence, the gradient of AB is 2.
Answer
gradient is 2Find the missing angle measurements of HFG ? , fill in the boxes
Answer:
Angle HFG = 24 degrees
Step-by-step explanation:
From the diagram, we have the following;
Angle EFH and angle HFG are complementary (they add up to be 90 degrees)
angle EFH + angle HFG = 90
Angle HFG = 90-66
Angle HFG = 24 degrees
Which graph of f(x) = 1/4(4)c?
Answer:
f(x)= 1/4
(4)
x
for x=1→f(1)=
4
1
⋅4
1
=1→(1; 1)
for x=2→f(2)=
4
1
⋅4
2
=
4
1
⋅16=4→(2; 4)
Answer: The graph nr 4.
Other method:
f(x)=\dfrac{1}{4}\cdot4^x=4^{-1}\cdot4^x=4^{x-1}f(x)=
4
1
⋅4
x
=4
−1
⋅4
x
=4
x−1
Used:
\begin{gathered}a^{-1}=\dfrac{1}{a}\\\\a^n\cdot a^m=a^{n\cdot m}\end{gathered}
a
−1
=
a
1
a
n
⋅a
m
=a
n⋅m
Draw the graph of y = 4^x and next shift it 1 unit right.
Find the inverse of y=5^x-9
(the -9 is not in the power)
Step-by-step explanation:
y = 5^x -9
5^x = y + 9
x = ^5 log (y+9)
f~'(x) = ^5 log (x+9)
Find the sum of the first seven prime numbers that have a units digit of 7.
Answer:
7, 17, 37, 47, 73, 79, 97
Step-by-step explanation:
they have 7's as one of their digits
What is the length of /AB?
Answer:
[tex]\sqrt{53}[/tex]
Step-by-step explanation:
Enter a range of values for x.
=============================================================
Explanation:
Ignore the sides that are 'a' units long.
We'll compare the sides that are 26 units and 27 units long. We see the 27 unit side is larger, which makes the 93 degree angle larger than the 3x-9 degree angle.
Symbolically, we would say
3x-9 < 93
At the same time, the 3x-9 is also larger than 0
So
3x-9 > 0 or 0 < 3x-9
Put together, we can form this compound inequality
0 < 3x-9 < 93
-------------------
Let's isolate x like so
0 < 3x-9 < 93
0+9 < 3x-9+9 < 93+9 .... add 9 to all sides
9 < 3x < 102
9/3 < 3x/3 < 102/3 .... divide all sides by 3
3 < x < 34
x is any number between 3 and 34, but cannot equal either endpoint
For example, x = 10 is valid since 3 < 10 < 34 is true. But x = 50 is not a solution since 3 < 50 < 34 is false. We can't have x = 3 and we also can't have x = 34 either, but we can have anything in between those endpoints.
grade 7 work please help
there is 2 questions 5 and 6
Answer:
For 5 the yellow square stays the same, while the blue adds 2 each time.
5. 1(2x) something like that.
6. 3 is 6 4 is 7 5 is 8
I have gotten too old for this, my bad somethings just dont make sense anymore.
Answer:
5.
a. 2 blue blocks added
b. 2 blue blocks are added on the top blue blocks
c.y = 2x +3
6.
a.
1,4
2,5
3,6
4,7
5,8
b. starting off with 4 triangles and ending with a bottom triangle a triangle is added first from the top, then the bottom for each increase (increment)
c. y = x+4
Step-by-step explanation:
all the answers are up
What is the distance between the following points?
Which is a common factor of 1 and 2?
A.
0
B.
C.
D.
1
2
4
ОА
B
С
D
Answer:
The common factor is 1.
Step-by-step explanation
The common factor of 1 and 2 is 1 since 1x2=1.
GIJL is a trapezoid with mid segment of HK. If IJ =7 cm and GL=15 cm, what is the length of HK?
Consider IJ and GL are the parallel sides of the trapezoid.
Given:
In a trapezoid GIJL, HK is the mid segment, IJ =7 cm and GL=15 cm.
To find:
The length of the mid segment HK.
Solution:
The length of the mid segment of a trapezoid is:
[tex]\text{Midsegment}=\dfrac{b_1+b_2}{2}[/tex]
where, [tex]b_1,b_2[/tex] are two parallel side or bases of the trapezoid.
HK is the mid segment, and the parallel sides are IJ =7 cm and GL=15 cm. So, the length of the mid segment is:
[tex]HK=\dfrac{IJ+GL}{2}[/tex]
[tex]HK=\dfrac{7+15}{2}[/tex]
[tex]HK=\dfrac{22}{2}[/tex]
[tex]HK=11[/tex]
Therefore, the length of HK is 11 units.
HELPPP PLS!! WILL MARK BRAINLIEST!! #plato
Drag each tile to the correct box.
Arrange the entries of matrix A in increasing order of their cofactor values.
Answer:
a23, a31, a21, a11, a12, a33
Step-by-step explanation: I got it right on Edumentum.
Answer:
a23, a31, a21, a11, a12, a33
Step-by-step explanation:
Please answer thanks! Brainliest
Step-by-step explanation:
The last two answers is correct
Answer:
4
Step-by-step explanation:
The answer to T - H is negative
can someone pls help for brainlest
Answer:
area of the larger figure=32 yd×37 yd
=1184 yd²
area of the smaller figure=21 yd ×26 yd
=546 yd²
area of the shaded region=1184 yd² -546 yd²
=638 yd²
Can someone please help me get surface area and lateral surface area
Answer:
Step-by-step explanation:
suface area of base=1/2×9×7.8=9×3.9=35.1 yd²
lateral surface area=3×1/2×9×10=135 yd²
total surface area=135+35.1=170.1 yd²
i assumed it is an equilateral triangular base.
as √(7.8²+4.5²)=9.0049≈9
The area of a triangle is 92 and its height is 23 what is its base?
Answer:
7.36
Step-by-step explanation:
Area=92
Height=23
Base=?
Area=1/2*base*height
92=1/2*23*height
92=12.5*height
920/125=height
7.36=height
Pleae mention unit in answer
Mark me as brainliest
A distributor needs to mix some Terraza coffee that normally sells for $9.00 per pound with some Kona coffee that normally sells for $13.50 per pound to create 50 pounds of a mix that can sell for $9.54 per pound. How many pounds of each kind of coffee should they mix?
Answer:
Step-by-step explanation:
Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:
#lbs x $/lb = Total
T
K
Mix
Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:
#lbs x $/lb = Total
T 9
K 13.50
Mix
Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound
#lbs x $/lb = Total
T 9
K 13.50
Mix 50 9.54
Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:
#lbs x $/lb = Total
T x x 9 = 9x
K 50 - x x 13.50 = 675 - 13.50x
Mix 50 x 9.54 = 477
The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:
9x + 675 - 13.5x = 477 and
-4.5x = -198 so
x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.
Find mZP.
P
26
2./13
R
mZP =
I’m confused
Answer:
45 degrees
Step-by-step explanation:
Since we have a right triangle, we use the appropriate trigonometric ratio
The angle marked P faces QR and that makes it the opposite side
PR faces the right angle and that makes it the hypotenuse
The trigonometric ratio that links the opposite and the hypotenuse is the sine
It is the ratio of the opposite to the hypotenuse
Thus;
sin P = √26/2 √13
Sin P = √2/2
P = arc sin √2/2
P = 45 degrees
Given the points A(-3, -2) and B(6, 1), determine the coordinates of point P on directed line segment that partitions in the ratio 2/1.
Answer:
[tex]P = (3,0)[/tex]
Step-by-step explanation:
Given
[tex]A = (-3,-2)[/tex] ---- [tex](x_1,y_1)[/tex]
[tex]B = (6,1)[/tex] --- [tex](x_2,y_2)[/tex]
[tex]m:n =2:1[/tex]
Required
The coordinates of P
This is calculated as:
[tex]P = (\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}][/tex]
So:
[tex]P = (\frac{2*6+1*-3}{2+1},\frac{2*1+1*-2}{2+1})[/tex]
[tex]P = (\frac{9}{3},\frac{0}{3})[/tex]
[tex]P = (3,0)[/tex]
Simplify the expression. –(10)–2
100
–100
Answer:
-12, 0
Step-by-step explanation:
How many tiles would be in figure 100? Help :/
Answer: pretty sure it is 201 tiles
please mark me brainlies. That would be helpful
Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.
Answer:
Step-by-step explanation:
Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.
Your
Lisa and Susan are driving to college together. They look at a map to find out how far they have to drive. On the map, Lisa measures the distance to be 4.5 inches. How many miles do they have to drive if the map scale is 1 in. = 40 mi?
A. 10 miles
B. 220 miles
C. 1/10 miles
D. 180 miles
Answer:
d 180 miles
Step-by-step explanation:
4.5×40= 180 miles
The actual distance to college Lisa and Susan going together is 180 miles.
What is a scale factor?The scale factor defines a variable in a ratio of two different measurements.
Sometimes drawings of large models are represented in a scale factor of a smaller unit.
Given, The map scale is 1 in. = 40 mi.
Lisa and Susan are driving to college together, On the map, Lisa measures the distance to be 4.5 inches.
Therefore,
The actual distance to college is,
= (4.5×40) miles.
= 180 miles.
learn more about scale factors here :
https://brainly.com/question/30215119
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