Question 12 of 20
How does decreasing the length of a wire affect a circuit?
A. It reduces the resistance caused by the wire.
B. It reduces the voltage carried by the wire.
O C. It increases the resistance caused by the wire.
D. It increases the current passing through the wire.

Answer:

Wheres the charts??

Explanation:

Answer:

Honestly for me it's a bit too blurry. Sorry luv.:(

Explanation:

Answer:

100 Watts

Explanation:

These equations are needed to work out the answer:

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

Answer:

All fluids exert pressure like the air inside a tire. The particles of fluids are constantly moving in all directions at random. As the particles move, they keep bumping into each other and into anything else in their path. These collisions cause pressure, and the pressure is exerted equally in all directions.

Explanation:

Answer:

b

Explanation:

Answer:

The answer is A) 29 meters

Explanation:

I got this question right on the test! :)

Answer:

The starting height of the ball is approximately 0.604 m

Explanation:

The given parameters are;

The mass of the the ball = 0.050

The speed with which it travels through the top loop = 2 m/s

The given height at which the ball moves at 2 m/s = 0.40 m

Therefore, we have;

1/2·m·v² = m·g·h

1/2·v² = g·h

h = 1/2·v²/g = 1/2 × 2²/9.81 ≈ 0.204

The additional height = h = 0.204 m

Therefore;

The starting height of the ball  ≈ The given height at which the ball moves at 2 m/s + h

The starting height of the ball  ≈ 0.40 + 0.204 = 0.604 m

The starting height of the ball ≈ 0.604 m.

When any object in rest, then potential energy is present. But when object is in motion then object have kinetic energy.

Starting height of the ball is 0.604 m.

We know that, when any object is start from rest, then potential energy is converted into kinetic energy.

     [tex]\frac{1}{2}mv^{2} =mgh[/tex]

Where m is mass of object, g is gravitational acceleration , h is height and v is velocity of object. (value of g = 9.81 m/ second square)

from above equation,

we get,     extra height        [tex]h=\frac{v^{2} }{2g} \\\\h=\frac{4}{2*9.81}\\\\h=0.204[/tex] meter

The starting height of the ball will be sum of the height at which ball moves 2 m/s and extra height.

Starting height = 0.40 + 0.204 = 0.604 meter.

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Answer:

the answer is the core

Explanation:

the core is composed of iron and nickel

heat food, warm water

Answer:

As frequency increases, wavelength decreases. Frequency and wavelength are inversely proportional. This basically means that when the wavelength is increased, the frequency decreases and vice versa.

Explanation:

A wave's velocity is independent of its intensity and equal to the product of its wavelength and frequency (number of vibrations per second) so, velocity remains constant if you increase the frequency.

Frequency is defined as the no of waves that are passing from the point in respect to a given time. Frequency can be measured in Hertz. Humans, whose capacity to hear is normal, can hear between the frequency of 20 Hertz to 20000 Hertz.

In mathematical form, the frequency is the factor of one divided by the time period. The number of cycles or vibrations a body in periodic motion makes in one unit of time.

Wavelength reduces as frequency rises. The relationship between frequency and wavelength is inverse. In essence, this means that the frequency reduces as the wavelength increases and vice versa.

Frequency ∝ 1 / Wavelength

Velocity = Frequency  ×  Wavelength

Thus, it remains constant.

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Explanation:

C. Atomic numbers....

Answer:

atomic numbers

Explanation:

In order for two atoms to be different, they have to have a different number of protons. Protons are represented by the atomic number. Thus, atoms of two DIFFERENT elements must have different atomic numbers.

I took the test and got 100%

Hope this helps!

Answer:

Explanation:

Given:

Specific heat of gold  = 0.031cal/°C

Specific heat of silver  = 0.057cal/°C

To know the metals that will heat up faster, we must understand the meaning of specific heat capacity.

It is the amount of heat required to raise the temperature of 1g of a substance by 1°C.

Now,

The higher the specific heat capacity the more energy it is required to heat up the substance.

So, Gold with a specific heat capacity of 0.031cal/°C  will heat up faster.

Answer:37

Explanation:

Answer:

a covalent

Explanation:

ionic bonding involves only the transfer of electrons but not exchange of electrons

Answer: C. work and time

Explanation: hope this helps

Answer:

Explanation:

From the information given:

We can properly determine the distance where the fish appear in the air viewing it from in front of the bowl by using the formula:

[tex]\dfrac{n_i}{d_o}+\dfrac{n_2}{d_1}= \dfrac{n_2-n_1}{r}[/tex]

where;

[tex]n_1[/tex] = refractive index in the air;  = 1.33  &

[tex]n_2[/tex] = refractive index in water. = 1

[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]

[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{4.7\ cm}[/tex]

[tex]\dfrac{1}{d_i}= - 0.26726 \ cm[/tex]

[tex]d_i =\dfrac{1}{ - 0.26726 \ cm}[/tex]

[tex]\mathbf{d_i }[/tex] = - 3.74 cm

2)

To determine where the fish appear to be when it is  38.9 cm from the front surface of the bowl by using the formula:

[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]

[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{38.9\ cm}[/tex]

[tex]\dfrac{1}{d_i}=- 0.0184759 \ cm[/tex]

[tex]d_i = \dfrac{1}{- 0.0184759 \ cm}[/tex]

[tex]\mathbf{d_i = }[/tex] -54.12  cm

Answer:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

Explanation:

Answer: i think its b

sorry if im wrong

Explanation:

Answer:

2m 13[tex]\frac{1}{3}[/tex]s

Explanation:

1.5m = 1s

200m = [tex]\frac{200}{1.5}[/tex] × 1s

          = 133[tex]\frac{1}{3}[/tex]s

          = 2m 13[tex]\frac{1}{3}[/tex]s

Answer:

The first law is an object won’t change its place unless a force hits it

The second law is the force on an object equivalent to the mass times its acceleration

The third law is when two object meet, they both apply forces on each other making them go in opposite directions

Explanation:

Answer:

C

Explanation:

Answer:

A = 0.188 m²

Explanation:

First we find the distance between the plates by using the formula of electric field intensity:

E = ΔV/d

d = ΔV/E

where,

d = distance between plates = ?

ΔV = Potential Difference = 4 KV = 4000 V

E = Electric Field = 2 x 10⁸ V/m

Therefore,

d = 4000 V/(2 x 10⁸ V/m)

d = 2 x 10⁻⁵ m

Now, we find the Area of Plates by using formula of capacitance:

C = A∈₀∈r/d

where,

C = Capacitance = 0.25 μF = 0.25 x 10⁻⁶ F

A = Area of Plates = ?

∈₀ = Permittivity of free space = 8.85 x 10⁻¹² C/N.m²

∈r = Dielectric Constant = 3

Therefore,

0.25 x 10⁻⁶ F = A(8.85 x 10⁻¹² C/N.m²)(3)/(2 x 10⁻⁵ m)

A = (0.25 x 10⁻⁶ F)(2 x 10⁻⁵ m)/(3)(8.85 x 10⁻¹² C/N.m²)

A = 0.188 m²

Answer:

17.5 m/s

Explanation:

We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.

Answer:Volume

Explanation:

Density = mass/ Volume

Answer:

Volume

Explanation:

Answer:

Average speed = ( 2V + V1 + V2)/4

Explanation:

Given that a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.

Since the distance is covered at equal intervals of time, and

Speed = distance/time

For the first half distance,

V = distance/t

Cross multiply

Distance = Vt

For the second half distance

(V1 + V2)/2 = distance/t

Distance = t(V1 + V2)/2

The average speed = total distance/ total time.

Average speed = [Vt + t( V1 + V2)/2] ÷ 2t

Average speed = (2Vt + V1t + V2t)/4t

Average speed = t( 2V + V1 + V2)/4t

Time t will cancel out

Average speed = ( 2V + V1 + V2)/4

Answer:

t = 9.14 s

Explanation:

We first analyze the accelerating motion by applying first equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car before turning off engine

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 25 m/s²

t₁ = time taken in accelerating motion

Therefore,

Vf₁ = 25t₁   ---------- equation (1)

Now, we apply second equation of motion:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = distance covered during accelerating motion

Therefore,

s₁ = (0)t₁ + (1/2)(25)t₁²

s₁ = 12.5 t₁²   ----------- equation (2)

Now, we analyze the decelerating motion by applying first equation of motion:

Vf₂ = Vi₂ + a₂t₂

where,

Vf₂ = Final Speed of Car = 0 m/s

Vi₂ = Initial Speed of Car after turning off engine

a₂ = deceleration of car = - 3 m/s²

t₂ = time taken in decelerating motion

Therefore,

Vi₂ = 3t₂   ---------- equation (3)

Now, we apply second equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered during decelerating motion

Therefore,

s₂ = (Vi₂)t₂ + (1/2)(-3)t₂²

s₂ = Vi₂ t₂ - 1.5 t₂²  

using equation (3):

s₂ = 3 t₂² - 1.5 t₂²

s₂ = 1.5 t₂²   ------------ equation (4)

Now, we know that the Final Velocity of accelerating motion (Vf₁) is equal to the initial velocity of decelerating motion (Vi₂):

Vf₁ = Vi₂

using equation (1) and equation (3):

25 t₁ = 3 t₂

t₁ = 0.12 t₂   ------------ equation (5)

Also, we know that sum of the distances is 200 m:

s₁ + s₂ = 200

using equation (2) and equation (4):

12.5 t₁² + 1.5 t₂² = 200

using equation (5):

12.5 (0.12 t₂²) + 1.5 t₂² = 200

3 t₂² = 200

t₂² = 200/3

t₂ = 8.16 s

substitute this in equation (5):

t₁ = 0.12(8.16 s)

t₁ = 0.97 s

Hence, the minimum time required for this motion is:

t = t₁ + t₂ = 0.97 s + 8.16 s

t = 9.14 s

If the pull is done horizontally, then the net force on the car is

∑ F = T - f = (1500 kg) (3 m/s²)

where T is the magnitude of the tension in the towing cable, and f is the friction which points in the opposite direction. Then

T = f + (1500 kg) (3 m/s²)

T = 2500 N + 4500 N

T = 7000 N

Answer:

t = 0.0689 s

Explanation:

Given that,

Mass of a basketball, m = 0.622 kg

Initial velocity, u = 4.23 m/s (downward or negative)

Final velocity, v = 3.85 m/s (up of positive)

Average force, F = 72.9 N

We need to find the time it was in contact with the floor. The force is given by :

[tex]F=ma\\\\F=m\dfrac{v-u}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{0.622\times (3.85-(-4.23))}{72.9}\\\\t=0.0689\ s[/tex]

So, the time of contact is 0.0689 s.

F=m*a

350N=m*1.4m/s^2

m=350N/1.4m/s^2=250kg