Answer:
The answer:
y=(x+2)²+7
Choose (B)
Answer:
5.
The sum of three consecutive odd numbers is equal to thirteen more than two
times the largest number. Let the first odd number be'n'.
(a)
Write the equation of the problem
Answer:
(1 mark)
(b)
Solve for'n' to find the first number
Answer:
(1 mark)
(C)
What are the values of the second and third odd numbers?
Answer:
(1 mark)
(d)
Show that the equation is true.
Answer:
Let the numbers be n, n+2, n+4
Sum equals too= 13+2(n+4), which is 2n+21
a) Equation--> n+n+2+n+4= 2n+21
b) Solution--> 3n+6= 2n+21
=> n= 15
c) Second number--> 17 (15+2)
Third number--> 19 (15+4)
d) 15+15+2+15+4=30+21
=> 51= 51
So, the equation is true.
And pls mark me brainliesttt :)))
what is the area of Ghana?
Answer:
its 238,535km²
Step-by-step explanation:
i hope it helps alot
What is the area of Ghana?
ඞ Ghana covers an area of [tex]\sf\purple{238,535\: km²}[/tex].
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
if sin (A+B)=1 and tan (A-B)=1/sqroot 3
are acute angles. find out the value of A and B
Answer:
A = 60° , B = 30°
Step-by-step explanation:
[tex]sin(A+B ) = 1\\\\\ \ \ (A + B) \ = \ \ sin^{-1} 1\\\\A + B = 90^\circ --(1)\\\\ \ tan (A - B) = \frac{1}{\sqrt{3}}\\\\(A-B) = tan^{-1}\frac{1}{\sqrt3}}\\\\A - B = 30^\circ --(2)\\\\ (1) + (2) => 2A = 120^\circ\\[/tex]
[tex]A = 60^\circ[/tex]
[tex]from \ (1) \\A + B = 90^\circ\\60^\circ + B = 90^\circ\\B = 90^\circ - 60^\circ\\B = 30^\circ[/tex]
She got the given variable
Answer:
125 ov?/70*5
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
70+5f=125. [exterior angle is equal to sum of interior opposite angles]
5f=125-70
5f=55
f=11
Can someone please help? U get points just from typing and I would really appreciate it.
The sum of two consecutive numbers is 131. What are the two numbers?
A. 64 and 65
B. 64 and 67
C. 65 and 66
D. 130 and 131
No links or fake answers pls. Thank you for understanding.
Answer:
C
Step-by-step explanation:
Consecutive numbers are directly next to each other on the number line, so B is already out of the question. Add each pair together to see which one is 131.
Answer:
C. 65 and 66
Step-by-step explanation:
Let x be first number
Then x + 1 be next number
x + (x + 1) = 131
2x + 1 = 131
2x = 130
x = 65
x + 1 = 66
The width of the rectangle shown below is 10 inches the length is 4 feet what is the area of the rectangle in square inches
Find the indicated area of the sector surrounded in bold.
Answer:
75.36 yd² (≈ 75.4 yd²)
Step-by-step explanation:
GIVEN :-
Angle subtended by the arc at center of circle (θ) = 135°Radius of the circle = 8 ydTO FIND :-
Area of the sectorGENERAL FORMULAE TO BE USED IN THI QUESTION :-
Lets say there's an arc which subtends θ angle in the center of the circle & radius of the circle is 'r'.
Area of the sector = [tex]\frac{\theta}{360} \times \pi r^2[/tex]
SOLUTION :-
Area of the sector = [tex]\frac{\theta}{360} \times \pi r^2[/tex]
[tex]= \frac{135}{360} \times \pi (8)^2[/tex]
[tex]= \frac{3}{8} \times 64 \times 3.14[/tex]
[tex]= 3 \times 8 \times 3.14[/tex]
[tex]=75.36 \; yd^2[/tex]
You are studying the color patterns of a species of iris that can be yellow, purple, or red. If you are performing a chi-squared test to compare the number of each you find in a field to the number you would expect to find based on the pollinators in the area, how many degrees of freedom would you have in your analysis
Answer:
Number of degrees of freedom = 2
Step-by-step explanation:
The degree of freedom in such type of chi-Square test depend on the number of phenotypes of the a particular species produced in a given cross.
Here the total phenotype number is three i.e yellow, purple, or red
Hence, the number of degrees of freedom = total number of phenotype - 1
Number of degrees of freedom = total number of phenotype - 1
Number of degrees of freedom = 3-1
Number of degrees of freedom = 2
Camden is creating a model of a pyramid. The model created will need to be scaled up from the blueprint.
If segments DE and AB are parallel, which of the following expressions will help Camden determine the length of DC?
DC equals EC times AC all over BC
DC = EC
DC equals EC times AC all over AB
DC = AB
Answer:
A) DC equals EC times AC all over BC.
Step-by-step explanation:
We know that:
[tex]DE\parallel AB[/tex]
Then by corresponding angles:
[tex]\angle CAB\cong \angle CDE\text{ and } \angle CBA\cong \angle CED[/tex]
So, by AA-Similarity:
[tex]\Delta CDE\sim \Delta CAB[/tex]
Corresponding sides of similar triangles are in proportion. Hence:
[tex]\displaystyle \frac{DC}{AC}=\frac{EC}{BC}[/tex]
By multiplying both sides by AC:
[tex]\displaystyle DC=\frac{EC\cdot AC}{BC}[/tex]
DC is equal to EC times AC over BC.
Hence, our answer is A.
Answer:
DC equals EC times AC all over BC
Step-by-step explanation:
Will Mark Brainlest help step by step. (The ratio of two men present age is 3:4 and this will be 7:9 after 4 years what are their present age)
Answer:
24 and 32
Step-by-step explanation:
Let their present ages be x and y
Therefore, x
[tex] \frac{x}{y} = \frac{3}{4} [/tex]
we have 4x = 3y
4x - 3y = 0......................(I)
After four years,
[tex] \frac{x + 4}{y + 4} = \frac{7}{9} [/tex]
we have, 9(x + 4) = 7(y + 4)
9x + 36 = 7y + 28
9x - 7y = -8 ........................(ii)
Solving (I) and (ii) simultaneously
4x - 3y = 0
9x - 7y = -8
multiply eqn I by 9 and equation (ii) by 4 and subtract result
36x - 27y = 0...............(iii)
36x - 28y = -32...........(iv)
subtracting (iv) from (iii) we have,
y = 32
substituting y back in equation (I)
4x - 3y = 0
4x -3(32) = 0
4x - 96 = 0
4x = 96
x = 24
Their ages are 24 and 32
M∠1 is less than m∠2 by 40 degrees. What is m∠1 and m∠2
i need y’all help asap
In a right triangle, angle C measures 40°. The hypotenuse of the triangle is 10 inches long. What is the approximate length of the side adjacent to angle C?
6.4 inches
7.7 inches
8.4 inches
13.1 inches
Answer:
The cosine function is: adjacent/hypotenuse = cos (40). We know the hypotenuse length is 10, so the equation is now adjacent/10 = cos (40). Solving for adjacent length we get 7.7 inches.
Answer:
the answer is B: 7.7 inches
Step-by-step explanation:
did the test go 100%
h(x)=6/(x-3), find h(5)
h(5) means the value of h(x) at x = 5. So what we have to do is to substitute x = 5 in the function.
We are given the function h(x) below:
[tex] \large{h(x) = \frac{6}{x - 3} }[/tex]
Substitute x = 5 in the equation.
[tex] \large{h(5) = \frac{6}{5 - 3} \longrightarrow \frac{6}{2} }[/tex]
Simplify in the simplest form.
[tex] \large{h(5) = \frac{3}{1} \longrightarrow 3}[/tex]
Thus h(5) is 3.
Answer
h(5) = 3Hope this helps! Let me know if you have any doubts.
Choose the appropriate condition for the following pairs of triangles to be congruent.
Answer:
1. ASA, 2. SSS, 3. ASA
Step-by-step explanation:
1. It is given to us that these two triangles share two of the same angles. We can also see that they share a side together. 2 angles and a side means ASA.
2. It is given to us that these two triangles share two of the same side lengths. We can also see that they share a side together. 2 sides gives us SSS.
3. It is given to us that these two triangles share 1 of the same angles and 1 of the same side lengths. We can also see that they share a vertical angle, which by definition means they have the same measurement. 2 angles and a side gives us ASA.
A researcher conducted a paired sample t-test to determine if advertisements were viewed more in the morning (before noon) or in the evening (after 5pm) for eight different universities. The results were as follows:
Morning Evening
Morning Evening
Mean 32 40.625
Variance 89.71428571 504.5536
Observations 8 8
Pearson Correlation 0.343785438
Hypothesized Mean Difference 0
df 7
t Stat -1.152587077
P(T<=t) one-tail 0.143458126
t Critical one-tail 1.894578605
P(T<=t) two-tail 0.286916252
t Critical two-tail 2.364624252
Is there a significant difference between morning and evening access to the university advertisements?
a. Yes, there was a significant difference between Morning (M= 32), and Evening (M=40.625), (t [7] = .28, p < .05).
b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).
c. Yes, there was a significant difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15 p < .05).
d. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p < .05).
Answer:
b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).
Step-by-step explanation:
The critical value for one tailed test is t ∝(7) > 1.895
A one tailed test is performed to test the claim that advertisements were viewed more in the morning (before noon) or in the evening (after 5pm)
The null and alternative hypotheses are
H0: μm = μe vs Ha μm > μe
where μm is the mean of the morning and μe is the mean of evening.
The calculated value of t = -1.152587077 which is less than the critical region hence the null hypothesis cannot be rejected .
P(T<=t) one-tail 0.143458126 > 0.05
If two tailed test is performed the critical region is t Critical two-tail 2.364624252
and the calculated t value is -1.152587077 which again does not lie in the critical region .
Hence μm = μe or μm ≤ μe
P(T<=t) two-tail 0.286916252 > 0.025
Therefore
b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).
Option b gives the best answer.
Module 07: Project Option 1
Instructions
First, you need to come up with an activity. If you are having trouble thinking of what to do, here are some ideas:
• How many jumping jacks can you do in a minute?
• How many times can you write your full address in a minute?
• How many points can you score in a game in three minutes?
• How many pages of a book can you read in four minutes?
• How far can you walk in five minutes?
Feel free to be creative or even to come up with an activity you think your teacher has not seen before.
Now that you have decided what your activity is going to be, it’s time to get started.
Part 1: Record Information
Spend a short amount of time (one to five minutes) doing your activity. Answer the following questions:
1. What was the activity?
2. How long did you spend doing your activity?
3. How much of the activity did you complete in the time period? (Example: I did 24 sit-ups in one minute.)
4. Which of these variables is your dependent variable?
5. Which one is the independent variable?
6. Write a sentence that describes the relationship between the dependent variable and the independent variable. (Hint: Ratio language can help.)
(Questions 1 to 3 are worth 1 point each; questions 4 to 6 are worth 2 points each.)
Part 2: Prepare a Table
Assuming that you could complete the activity at the same rate over different time periods, how much of the activity could you complete in two minutes, three minutes, four minutes, and five minutes? (Note: If you spent two minutes doing your activity, then you should edit the table below and use multiples of 2 up to 10).
You may use the table below for your variables.
Time (minutes)
0 0
1
2
3
4
5
Part 3: Prepare a Graph
Create a graph to show your relationship. Make sure you include all the parts for a graph and show the data clearly. Include a title for the graph and label the x- and y-axes.
Part 4: Write an Equation
Based on your recorded values, write an equation that represents the relationship between the time you spent doing the activity and the amount of the activity you completed. Make sure to define your variables.
Follow-up questions
7. If you were able to maintain this rate of your activity for 12 minutes, how much of the activity would you be able to complete?
8. How long would it take you to reach 100 for the number of times you did your activity?
9. Which representation do you believe is the best way to share this information with someone else? This is your opinion. No answer is right or wrong.
Answer:
See below
Step-by-step explanation:
Feel free to be creative or even to come up with an activity you think your teacher has not seen before.
Liked that. So let's be creative.
Part 1: Record Information
Spend a short amount of time (one to five minutes) doing your activity. Answer the following questions:
1. What was the activity?
I am from Japan and practice Kendo (feel free to search about it). Suppose you are doing suburi. You did 100 joge suburi.
2. How long did you spend doing your activity?
Suppose it took you 5 minutes.
3. How much of the activity did you complete in the time period? (Example: I did 24 sit-ups in one minute.)
You did 100 joge suburi in 5 minutes. It means [tex]\dfrac{100}{5} = 20 \text{ per minute}[/tex]
4. Which of these variables is your dependent variable?
If you want to calculate how much suburi you did in an amount of time [tex]x[/tex], given the time in minutes, we can write the function
[tex]y = f(x)=20x[/tex]
Therefore, the dependent variable is the number of suburis. More precisely it is given by [tex]y[/tex]. On the other hand, the independent variable is [tex]x[/tex], the time.
Considering the example: I did 24 sit-ups in one minute.
sit-ups is the dependent variable and the number of minutes represents the independent variable.
Note: The number of sit-ups will depend on the time. 24 is the coefficient. In this case, the function would be
[tex]g(x) = 24x[/tex]
5. Which one is the independent variable?
The time in minutes.
6. Write a sentence that describes the relationship between the dependent variable and the independent variable. (Hint: Ratio language can help.)
You can write: The ratio of suburi done is 100:5 or 20:1 because for every 1 minute passed you did 20 suburis.
Part 2: Prepare a Table
Assuming that you could complete the activity at the same rate over different time periods, how much of the activity could you complete in two minutes, three minutes, four minutes, and five minutes? (Note: If you spent two minutes doing your activity, then you should edit the table below and use multiples of 2 up to 10).
You may use the table below for your variables.
Time (minutes) Quantity of suburi
0 0
1 20
2 40
3 60
4 80
5 100
Part 3: Prepare a Graph
Create a graph to show your relationship. Make sure you include all the parts for a graph and show the data clearly. Include a title for the graph and label the x- and y-axes.
This part I will let it to your. But is is just a linear graph.
Part 4: Write an Equation
Based on your recorded values, write an equation that represents the relationship between the time you spent doing the activity and the amount of the activity you completed. Make sure to define your variables.
[tex]y = f(x)=20x, \forall x \in\mathbb{Z}_{\geq 0}[/tex]
[tex]y: \text{number of suburis}[/tex]
[tex]x: \text{time}[/tex]
7. If you were able to maintain this rate of your activity for 12 minutes, how much of the activity would you be able to complete?
For [tex]x=12[/tex]: [tex]y = f(12)=20\cdot 12 = 240[/tex]
240 suburis
8. How long would it take you to reach 100 for the number of times you did your activity?
5 minutes.
9. Which representation do you believe is the best way to share this information with someone else? This is your opinion. No answer is right or wrong.
The function is the best because it describes all the variables easily.
There are 924 people in a theatre.
383 of the people are men.
356 of the people are women.
2
of the children are boys.
5
Work out how many girls are in the theatre
[tex]924 - (383 + 356 + 2 + 5 )[/tex]
Answer:
Step-by-step explanation:
total no. of people in the theatre = 924
men=383
women=356
boy children =2
doing workout 5
total=746
no. of girls= 924-746=178
Therefore, the number of girls are in the theatre are 178.
Need to pass please help
Did I answer this correctly? Drag each tile to the correct box. Not all tiles will be used. Arrange the steps to solve this system of linear equations in the correct sequence.
Put the following in order:
A. Subtract 3x + 3y = -6 (obtained in step 1) from 2x – 3y = -9 (given) to solve for x.
B) Substitute the value of x in the first equation (x + y = -2) to get y = 1.
C) The solution for the system of equations is (-3, 1).
D) x = -15
E) The solution for the system of equations is (-15, 13).
F) Add 3x + 3y = -6 (obtained in step 1) to 2x – 3y = -9 (given), and solve for x.
G) x = -3
H) Substitute the value of x in the first equation (x + y = -2) to get y = 13.
J) Multiply the first equation by 3: 3(x + y) = 3(-2) 3x + 3y = -6.
Remember that only 5 can be used.
9514 1404 393
Answer:
your 3rd step should be x = -3
Step-by-step explanation:
When you combine the equations in step 2, you get ...
5x = -15
Dividing by 5 gives the solution for x:
x = -3
This is what your Step 3 should show. This is the value that is consistent with the remaining steps.
Answer:9514 1404 393
Step-by-step explanation:
If the surface area of the box in the diagram is 204.25 square feet, what is the value of ‘x’?
the length is 10ft
the height is 6.5ft
what would x
A. 3 ft
B. 2.25 ft
C. 4.5 ft
D. 5 ft
Note: Consider x be the breadth of the box.
Given:
The surface area of the box is 204.25 square feet.
Length of the box = 10 ft
Breadth of the box = x ft
Height of the box = 6.5 ft
To find:
The value of x.
Solution:
The surface area of a cuboid is:
[tex]SA=2(lb+bh+hl)[/tex]
Where, l is length, b is breadth and h is height of the cuboid.
Putting [tex]SA=204.25, l=10,\ b=x,\ h=6.5[/tex] in the above formula, we get
[tex]204.25=2(10\times x+x\times 6.5+6.5\times 10)[/tex]
[tex]204.25=2(10x+6.5x+65)[/tex]
[tex]204.25=2(16.5x+65)[/tex]
Using distributive property, we get
[tex]204.25=2(16.5x)+2(65)[/tex]
[tex]204.25=33x+130[/tex]
[tex]204.25-130=33x[/tex]
[tex]74.25=33x[/tex]
Divide both sides by 33.
[tex]\dfrac{74.25}{33}=x[/tex]
[tex]2.25=x[/tex]
Therefore, the correct option is B.
Express the ratio below in its simplest form. 1.5 : 1
Answer:
3 :2.
Step-by-step explanation:
1.5 : 1
Multiply both numbers by 2:
i this gives 3:2
Find the area of the figure described
Answer:
153.94
Step-by-step explanation:
A=πr2=π·72≈153.93804
hope this helps!
please mark brainiest<3
please help me find the area
Answer:
165 square ft
Step-by-step explanation:
find the number of terms in an AP given that it's first and last terms are a & 37a respectively and it's common difference is 4a
Answer:
Substitute the values give into the nth term of the arithmetic progression and solve this the steps are give above in the picture
Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 70 mph. The westbound train travels at 90 mph. How long will it take for the two trains to be 192 miles apart.
Answer:
1.2 hours
Step-by-step explanation:
Recall :
Distance = speed * time
Let the time taken = x
Creating an equation for the question :
Distance of train A + Distance of train B = 192
70 * x + 90 * x = 192
70x + 90x = 192
160x = 192
x = 192 / 160
x = 1.2
It takes 1.2 hours to be 192 miles apart.
How many and what type of solutions does 7x^2−4x+3 have? 1 rational solution 2 rational solutions 2 irrational solutions 2 nonreal solutions
Answer:
2 non real solutions.
Step-by-step explanation:
We need to use discriminant,
for ax²+bx+c=0
The discriminat is b²-4ac
If the discriminant is,
→ less than 0, then 0 real solutions
→ equal to 0, then 1 real solutions
→ more than 0, then 2 real solutions
Given that,
7x²−4x+3=0
a=7, b=-4, and c=3
→ (-4)²-4(7)(3)
→ 16-84
→ -68
You can see this is less than 0, then non real solutions. [2 nonreal solutions]
Answer:
Solution given:
7x²-4x+3=0
taking common 7
7(x²+4/7*x+3/7)=0
x²+2*x*2/7+(2/7)²-(2/7)²+3/7=0
(x+2/7)²=-17/49
x+2/7=[tex]\sqrt{\frac{17}{49}}[/tex]
x=±√(17)/7-2/7
taking positive
x=√(17)/7-2/7
x=0.39
taking positive
x=-√(17)/7-2/7
x=-0.87
2:unreal number
Which figure has at least one line of symmetry?
Answer:
it the first diagram for this question.
Find the largest possible rectangular area you can enclose, assuming you have 128 meters of fencing. What is the (geometric) significance of the dimensions of this largest possible enclosure?
Answer:
Step-by-step explanation:
let the length=x
width=y
P=2(x+y)=128
x+y=128/2=64
y=64-x
area A=xy=x(64-x)=64x-x²
[tex]\frac{dA}{dx} =64-2x\\\\\frac{dA}{dx} =0,gives~64-2x=0,x=32\\\frac{d^2A}{dx^2} =-2<0 ,at ~x=32[/tex]
so A or area is maximum if x=32
y=64-32=32
or it is a square of edge=32 meters.
questions 1 and 2, please
Answer:
too blurry cant read it
Step-by-step explanation:
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