These questions all involve special cases of the ideal gas law, namely Boyle's, Charles', and Gay-Lussac's Laws. The ideal gas law relates together the absolute pressure (P), volume (V), the absolute temperature (T), and number of moles (n) of a gas by the following:
PV = nRT
where R is the universal gas constant.
The special cases of the ideal gas law are obtained by holding constant all but two of the variables of a gas.
Boyle's Law relates the pressure and volume of a given mass of gas at a constant temperature: PV = k or P₁V₁ = P₂V₂.
Charles' Law relates the volume and temperature of a given mass of gas at a constant pressure: V/T = k or V₁/T₁ = V₂/T₂.
Gay-Lussac's Law relates the pressure and temperature of a given mass of gas at a constant volume: P/T = k or P₁/T₁ = P₂/T₂.
Depending on what we're given and instructed to find in each question, we can figure out which law to use.
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Question 2:
We are given the volume of a gas at some pressure, and we're to find the new volume of the gas at a different pressure. Here, we use Boyle's Law: P₁V₁ = P₂V₂ where P₁ = 60 atm, V₁ = 20.0 L, and P₂ = 30 atm. We want to find V₂, which we can determine by rearranging the equation into the form V₂ = P₁V₁/P₂. Note that pressure and volume are inversely related according to Boyle's Law; since we're decreasing the pressure, the new volume of the gas should be greater than the initial volume of 20.0 L.
V₂ = (60 atm)(20.0 L)/(30.0 atm) = 40.0 L.
So, at 30 atm, the balloon will have a volume of 40.0 L.
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Question 3:
This is another Boyle's Law question. The standard pressure (our initial pressure) is 1 atm. Here, we are decreasing the volume of the gas, and we want to find the new pressure; the pressure of the gas should thus increase proportionally (the pressure will be greater than 1 atm). Rearranging Boyle's Law to solve for P₂, we get P₂ = P₁V₁/V₂.
P₂ = (1 atm)(8.00 L)/(3 L) = 2.67 atm.
So, the new pressure of the gas is 2.67 atm (or 3 atm if we're considering V₂ to comprise one significant figure).
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Question 4:
Here, we are increasing the temperature of a gas at a known pressure, and we want to determine what the new pressure will be. This is a Gay-Lussac's Law question; from the law, we see that pressure and temperature are directly proportional. Since we're increasing the temperature of the gas, we should expect the pressure of the gas to be greater than the initial 200 atm. Gay-Lussac's Law rearranged to solve for P₂ gives us P₂ = P₁T₂/T₁. When working with gas laws, temperatures must be in Kelvin (°C + 273.15 = K). So, T₁ = 300.15 K, T₂ = 350.15 K, and P₁ = 200 atm.
P₂ = (200 atm)(350.15 K)/(300.15 K) = 233 atm.
So, if the temperature is increased from 27 to 77 °C, the pressure of the gas in the tennis ball will be 233 atm. Here, it's ambiguous how many sig figs to use; if we use one sig fig per P₁, then our P₂ would equal P₁, which I think would be an absurd for a question to ask for. I would stick with either 233 atm or 230 atm (following the two sig figs of the temperatures), or you may go with however you've been instructed.
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Question 5:
This is a Charles' Law question; we're looking for the new volume of a gas when the temperature of the gas is increased. As was the case in Gay-Lussac's Law, the two parameters in Charles' Law—volume and temperature—are directly proportional. Since the temperature of the gas is increased, we should expect the new volume of the gas to also increase (V₂ will be greater than 5.00 L). Temperatures should be in Kelvin.
V₂ = V₁T₂/T₁ = (5.00 L)(300.15 K)/(250.15 K) = 5.99 L.
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Question 6:
Another Charles' Law question. As with question 5, we want to find the new volume of the gas after a change in temperature. This time, the final temperature is lower than the initial temperature, so we should expect that V₂ will be less than the initial 0.5 L. Again, temperatures in Kelvin.
V₂ = V₁T₂/T₁ = (0.5 L)(313.15 K)/(493.15 K) = 0.317 L.
So, the volume of the balloon when it is fully cooled by your refrigerator will be 0.317 L.
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Question 7:
This is yet another Charles' Law question, and, again, we are solving for V₂ after a change in temperature. Since the final temperature is greater than the initial temperature, V₂ should be greater than 2.2 L. Again, the temperatures should be in Kelvin.
V₂ = V₁T₂/T₁ = (2.2 L)(653.15 K)/(453.15 K) = 3.17 L.
The new volume of the gas is 3.17 L ≈ 3.2 L (two sig figs).
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Question 8:
We return to Gay-Lussac's Law here; pressure and temperature are directly proportional, and the temperature of the gas is increased. Thus, P₂ should be greater than 3 atm. Again, remember that temperatures must be in Kelvin.
P₂ = P₁T₂/T₁ = (3 atm)(298.15 K)/(288.15 K) = 3.1 atm.
So, the pressure inside the can after the temperature rise is 3.1 atm. Not a big increase, but an increase nonetheless.
Help hurry please !!!!!
Put the steps of the carbon cycle in order using Step 1 as your starting point.
Step 1: Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form.
The animal dies and decomposes, returning nitrogen back to the soil.
Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins..
An animal eats a plant and the nitrogen becomes part of the animal’s proteins.
Answer:
Carbon moves from the atmosphere to plants. ...
Carbon moves from plants to animals. ...
Carbon moves from plants and animals to soils. ...
Carbon moves from living things to the atmosphere. ...
Carbon moves from fossil fuels to the atmosphere when fuels are burned. ...
Carbon moves from the atmosphere to the oceans.
Explanation:
Answer:
step 4 , 2 , 3
Explanation:
Calculate the enthalpy change for the photosynthesis of gluclose
Answer:
jhdgafhgafhagfhafg
Explanation:
A watt is
A. 1 cal/s.
B. 1 joule/s.
C. 1 s/cal.
D. 1 s/joule.
Answer:
The answer would be B. 1 joule/s.
Explanation:
The answer is B because the power in general is normally defined as energy over time. Watts are defined as 1 Watt = 1 Joule per second (1W = 1 J/s) which means that 1 kW = 1000 J/s.
Another reason why it's B is because I had the same exact question in class, I took a screenshot of it a day ago:
Hope this helps
3.A binary mixture consisting of 50.7 mol % n-butane (1) and the balance iso-butane (2) enters a flash chamber operating at 9.6 bar and 344 K. Use the truncated virial equation of state (equation 3.36 in the textbook) to estimate the composition of the vapor and liquid phases leaving the flash chamber.
How many mL of 0.100M Ca(OH) are needed to titrate 20.0mL of 0.300M H2SO4
Answer:
60.0 mL
Explanation:
Using CAVA = CBVB
CA = 0.300M
VA = 20.0 mL
CB = 0.100M
VB = ?
VB = CAVA
CB
VB = 0.300 * 20/ 0.100
VB = 60.0 mL
A 5.0 L air sample at a temperature of -50°C has a pressure of 800.00 mmHg. What
the new pressure if the temperature is raised to 100°C and the volume expands to 7.0
L?
Answer:
956 mmHg
Explanation:
The combined gas law states that P1V1/T1 = P2V2/T2 when moles of gas are constant. We're looking for P2, so solve all of that for P2. Make sure you convert your temperatures to Kelvin by adding 273 to the Celsius temperatures.
P2 = P1V1T2/T1V2
P1 = 800.00 mmHg
V1 = 5.0 L
T2 = 100 + 273 = 373 K
T1 = -50 + 273 = 223 K
V2 = 7.0 L
P2 = (800.00 mmHg)(5.0 L)(373 K) / (223 K)(7.0 K) = 956 mmHg
A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62.5 mL of the base. The concentration of H2SO4 is ________ M. A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62.5 mL of the base. The concentration of H2SO4 is ________ M. 0.150 0.234 0.300 0.469 0.938
Answer: The concentration of [tex]H_2SO_4[/tex] is 0.234 M
Explanation:
According to the neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1[/tex] = basicity [tex]H_2SO_4[/tex] = 2
[tex]M_1[/tex] = molarity of [tex]H_2SO_4[/tex] solution = ?
[tex]V_1[/tex] = volume of [tex]H_2SO_4[/tex] solution = 50.0 ml
[tex]n_2[/tex] = acidity of [tex]NaOH[/tex] = 1
[tex]M_1[/tex] = molarity of [tex]NaOH[/tex] solution = 0.375 M
[tex]V_1[/tex] = volume of [tex]NaOH[/tex] solution = 62.5 ml
Putting in the values we get:
[tex]2\times M_1\times 50.0=1\times 0.375\times 62.5[/tex]
[tex]M_1=0.234M[/tex]
Therefore concentration of [tex]H_2SO_4[/tex] is 0.234 M
Please balance the equation C7H16 + CoF3 = C7F16 + HF +CoF2
with solutions
b. how many grams of CH6 is needed to react with 20.0 grams of HF?
C. how many particles of CoF3 is needed to react with 40.0 grams of CzF16?
d. how many grams of CH16 will be produce from 2.03 x 10 molecule of CoFs?
e. Find the Limiting reactant and exXcess reactant in CF16?
6g of CH16
6g of CoFa
f. Find the theoretical yield from CzFi6?
g. What is the percent yield of C;F16 if the actual yield is 1.28 g ?
Calculate the number of total atoms in 195 grams of Ni(OH)2.
1.267 x 10 ^ 24 is the total number of atoms
The oxidation state for Cl is A. -1 as a reactant and +1 as a product B. -1 as a reactant and 0 as a product C. -1 as a reactant and -1 as a product D. +1 as a reactant and +1 as a product
Answer:
no sure
Explanation:
If aqueous solutions of Ba(OH)2 and HNO3 are mixed, what products are formed? Select one: a. BaN2(s) + H2O(l) b. Ba(NO3)2(aq) + H2O(l) c. Ba(s) + H2(g) + NO2(g) d. Ba2O(s) + NO2(g) + H2O(l) e. Ba3N2(s) + H2O(l)
Answer: Ba(NO3)2(aq) + H2O(l)
Explanation:
8. The density of a gas at 350 C is 0,087 g/L. Compute the density at STP.
Answer:
0.20 g/L
Explanation:
Step 1: Calculate the molar mass of the gas (M)
At T = 350 °C = 623 K and P = 1 atm (we will assume this data), the density (ρ) of the gas is 0.087 g/L. We can calculate the molar mass of the gas using the following expression.
ρ = P × M/R × T
M = ρ × R × T/P
M = 0.087 g/L × (0.0821 atm.L/mol.K) × 623 K/1 atm = 4.5 g/mol
Step 2: Calculate the density of the gas at STP
At standard temperature (T = 273.15 K) and standard pressure (P = 1 atm), the density of the gas is:
ρ = P × M/R × T
ρ = 1 atm × 4.5 g/mol /(0.0821 atm.L/mol.K) × 273.15 K = 0.20 g/L
where do the sun rays hit Earth's surface nearly at right angles
Answer:
The Sun Ray's hit earths surface at Earths Equator
What is the molarity (M) of a solution that has 0.50 moles of solute dissolved in 1.0
liter of solution?
Answer:
it is 0.50=0.5 M
Explanation:
Molarity definition is measure the concentration of solution.
and the rule is
molarity(M)= moles of solute/volume of solution in liters
Ex: 2.1 M MgCl2= 2.1 mole MgCl2/ L MgCl2 solution
C3H8, + 5O2
+ 5O2,3CO2 + 4H20
If 2.50 moles of C3H8react, how many moles of H20 are produced?
Answer:
[tex]from \: the \: equation \\ 1 \: moles \: of \: propane \: produce \: 4 \: moles \: of \: water \\ 2.50 \:moles \: of \: propane \: will \: produce \: ( \frac{(2.50 \times 4)}{1} ) \: moles \\ = 10 \: moles \: of \: water[/tex]
10) Is the chemical equation balanced?
2 Al + Fe2O3
2Fe + Al2O3
Answer: Yes , the equation is balanced.
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The given chemical equation is:
[tex]2Al+Fe_2O_3\rightarrow 2Fe+Al_2O_3[/tex]
As the number of atoms on reactant side is equal to the number of atoms on product side, the equation is balanced.
Question 3
Which of the objects on the shelf has the greatest inertia?
10 kg
5 kg
2kg
a
b
2 kg
5 kg
10 kg
С
d
The all have the same inertia
Which of these is most likely made of pieces of rock that are weathered by water and wind?
O A diamonds
OB sand
OC grass
OD vegetables
Answer:
The answer would be sand.
Explanation:
Sand is weathered down tiny pieces of rock. Sand flows down rivers to shores and slowly builds up to form beaches.
Answer:
The Answer is gonna be B sand
Do not abuse or misuse any piece of drawing instrument. ASAPPPP
One gallon of gasoline (C8H18) weights about 6.3 pounds. Burning gasoline with excess of oxygen forms water and carbon dioxide. When 3.1 gallons of gasoline burn, how many pounds of CO2 emit into the air?
FW: C = 12; H = 1; O = 16.
Answer:
60 pounds of CO₂ are emited into the air
Explanation:
The combustion of gasoline occurs as follows:
C₈H₁₈(l) + 25/2O₂(g) ⇄ 8CO₂(g) + 9H₂O
Where 1 mole of gasoline produce 8 moles of CO₂
To solve this question we must find the moles of gasoline in 3.1 gallons. 8 times these moles are the moles of CO₂ produced. With the moles of CO₂ we can find its pounds as follows:
Pounds gasoline:
3.1 gallons * (6.3 pounds / gallon) = 19.53 pounds
Grams gasoline:
19.53 pounds * (453.592g / pound) = 8859g
Moles gasoline -Molar mass C8H18: 114.23g/mol-
8859g * (1mol / 114.23g) = 77.55 moles gasoline
Moles CO₂:
77.55 moles gasoline * (8 mol CO₂ / mol Gasoline) = 620.4 moles CO₂
Mass CO₂ - Molar mass: 44.01g/mol-
620.4 moles CO₂ * (44.01g / mol) = 27304g CO₂
Pounds CO₂:
27304g CO₂ * (1lb / 453.592g) =
60 pounds of CO₂ are emited into the airWhat is the molar mass of AlCl3
Answer:
133.34 g/moles
Explanation:
but to make life easy it could be 133.4 g/ moles as well
It takes 53.0 J to raise the temperature of an 11.0 g piece of unknown metal from 13.0∘C to 24.3 ∘C. What is the specific heat for the metal?
Answer:
Heat absorbed = mS△T
51 = ( 8.2/1000)Kg ×S (11.5)
51×1000= 8.2 (11.5)S
S = 51000/94.3
S = 540.8 J/kg K
Using the weather radar map shown here, infer at which lettered point the most likely tornado formation and damage would
occur.
es )
A)
А
B)
B
C С
D
D
Answer:
c
Explanation:
this is because it makes sense
Answer:
d
Explanation:
Is anyone good at chemistry if so can someone help me please ?
(NO LINKS)
Question 15
We're given the [OH⁻] as 8.34 × 10⁻¹² M. Using the formula pOH = -log[OH⁻], the pOH of this solution would be -log(8.34 × 10⁻¹²) ≈ 11.08.
The pOH is, for lack of a better term, the "opposite" of pH: A pOH of 7 is neutral; a pOH less than 7 is basic; and a pOH greater than 7 is acidic.
This follows from the relation, pH + pOH = 14. In this case, with a pOH of 11.08, our pH would be 14 - 11.08 = 2.92, which is acidic (pH < 7).
Thus, the correct answer choice is B.
Like in a cat's eye, the human pupil changes shape in response to changes in
the environment. What is the most likely function of this structure?
A. To allow humans to read
B. To allow humans to see clearly in different levels of light
C. To allow humans to see shades in color
D. To allow humans to see at varying distances
Answer:
B.
Our pupils contract and expand depending on the amount of light at any given time in order to avoid being blinded and to see better in the darkness.
Worth 100 points plus ill mark brainliest
How many grams of sodium phosphate ( Na₃PO₄ )are required to make 125 milliliters of a 0.240 Molar solution?
4.92
6.48
8.44
12.5
Answer:
4.92 grams of sodium phosphate (Na₃PO₄) are required to make 125 milliliters of a 0.240 M.
Explanation:
Molarity is a measure of concentration that indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case:
Molarity= 0.240 Mnumber of moles= ?volume= 125 mL= 0.125 LReplacing in the definition of molarity:
[tex]0.240 M=\frac{number of moles}{0.125 L}[/tex]
Solving:
number of moles= 0.240 M*0.125 L
number of moles= 0.03 moles
Being the molar mass of sodium phosphate 164 g/mole, that is, the mass of one mole of the compound, you can calculate the mass of 0.03 moles using the following rule of three: if 1 mole of the compound has 164 grams, 0.03 moles contains how much mass?
[tex]mass=\frac{0.03 moles*164 grams}{1 mole}[/tex]
mass= 4.92 grams
4.92 grams of sodium phosphate (Na₃PO₄) are required to make 125 milliliters of a 0.240 M.
How is water used in society
Answer:
Water can be used for direct and indirect purposes. Direct purposes include bathing, drinking, and cooking, while examples of indirect purposes are the use of water in processing wood to make paper and in producing steel for automobiles. The bulk of the world's water use is for agriculture, industry, and electricity.
Explanation:
Answer:
water is used for drinking, bathing, cooking, agriculture etc
Which of the following astronomical bodies would most likely be the largest?
1. A dwarf star from a nearby solar system
2. A comet
3. One of the gas giants in our solar system
4. Ganymede, the largest moon of Jupiter
Answer:
1
because a dwarf star will seemlarge because of the in ability of any human being to see d sun
A correct statement of Henry's law is: a. The concentration of a gas in solution is inversely proportional to temperature. b. The concentration of a gas in solution is directly proportional to the mole fraction of solvent. c. The concentration of a gas in solution is independent of pressure. d. The concentration of a gas in a solution is inversely proportional to pressure. e. None of these.
Answer:
e. None of these.
Explanation:
Hey there!
In this case, since the Henry's law is defined in terms of pressure, henry's constant and pressure, as shown below:
[tex]C=K_H*P[/tex]
Whereas C is the concentration, KH the Henry's constant and P the pressure, we infer that the concentration of a gas solution is directly proportional to the pressure, which is not the group choices, therefore, the answer is e. None of these.
Best regards!
