Answer:Scientific Investigations
Explanation:
fill in the term to complete each sentence
a wave carries___ from one place to another.
mechanical waves carry energy through___.
Energy
A material medium
A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.
What is a wave?A wave is a phenomenon that flows across a material medium without leaving any lasting mark.
Mechanical or electromagnetic waves can be used to classify them. Transverse and longitudinal are the two main forms.
A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.
Hence the correct options for the fill-in-the-blanks are energy and a material medium.
To learn more about the wave refer to the link;
brainly.com/question/3004869
Find the x-component of this vector: 47.3 m 39.4 ° Remember, angles are measured from the + x axis. x-component (m)
The x-component of the vector is 36.55 m.
Components of vectorsThe components of a vector include both x and y components. The x-component is determined along x-axis, while y-component is determined along y-axis.
Vx = Vcosθ
Vy = Vsinθ
where;
Vx is the x-component of the vectorVy is the y-component of the vectorX-components of the vectorThe x-component of the vector is calculated as follows;
x = 47.3 x cos(39.4)
x = 36.55 m
Thus, the x-component of the vector is 36.55 m.
Learn more about x-component of vector here: https://brainly.com/question/13416288
What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 K? Use the equation: -mv2
2
For m, use 0.02000 kg. Remember that R = 8.31 J/(mol-K).
= ER
3
2
nRT
A. 1540 m/s
B. 876 m/s
C. 87.6 m/s
O D. 15,400 m/s
Answer:
v = 876 m/s
Explanation:
It is given that,
Number of mol of Neon is 2 mol
Temperature, T = 308 K
Mass, m = 0.02 kg
Value of R - 8.31 J/mol-K
We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,
[tex]\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s[/tex]
So, the correct option is (B).
What did Thomson’s and Rutherford’s experiments have in common? They both used charged particles in their experiments. They both used emission spectra to discover electron clouds. They both compared the atom to an indivisible sphere. They both discovered electron clouds.
Answer:
Both Thomson and Rutherford used charged particles in their experiments.
Explanation: