Reactants which do not continue to completion are called reactants

Answer:

condensation

Explanation:

the water has condensed from the gaseous form into rain drops

Answer:

precipitation

Explanation:

Answer:

40.0L of SO2 are produced

Explanation:

To solve this question we need to find the moles of O2 using PV = nRT in order to find the moles. Thus, we can find the limiting reactant and the moles (And volume) of SO2 produced as follows:

Moles O2:

n = PV/RT

n = 1.20atm*55.0L / 0.082atmL/molK*358K

n = 2.25 moles of O2.

Clearly, limiting reactant is O2.

The moles of SO2 produced are:

2.25 moles of O2 * (8mol SO2 / 11mol O2) = 1.6351 moles SO2

Volume SO2:

V = nRT/P

V = 1.6351 moles SO2*0.082atmL/molK*358K / 1.20atm

V = 40.0L of SO2 are produced

Answer:

Explanation:

Given the equation:

[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}[/tex]

The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.

The first step is to determine the algebraic value on the numerator.

Algebraic value = 9.8 - 231

= 7.49

The absolute uncertainty = [tex]\sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}[/tex]

absolute uncertainty = [tex]\sqrt{(0.3)^3 + (0.01)^2}[/tex]

= [tex]\sqrt{0.09 + 0.0001}[/tex]

= 0.300167

∴

[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)

The division process now is:

[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}[/tex]

Relative uncertainty = [tex]\dfrac{(\pm 0.300167)}{7.49}\times 100 \ , \ \dfrac{(\pm 0.6) }{8.5} \times 100[/tex]

Relative uncertainty = ±4.007565% ,  ±7.058824%

[tex]\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}[/tex]

[tex]\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}[/tex]

[tex]\text{Relative uncertainty} = \sqrt{65.88757349}[/tex]

[tex]\text{Relative uncertainty} = 8.117116[/tex]

≅ 8%

The algebraic value = [tex]\dfrac{7.49}{8.5}[/tex]

= 0.881176

≅ 0.88

The percentage of the relative uncertainty =[tex]\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100[/tex]

By cross multiplying:

[tex]\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}[/tex]

[tex]\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}[/tex]

[tex]\text{Absolute uncertainty} (\%) = 0.0715260[/tex]

[tex]\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}[/tex]

Finally:

[tex]\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}[/tex]

Answer:

[tex]m_{H_2O}=0.676gH_2O[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:

[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]

Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:

[tex]0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O[/tex]

Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:

[tex]m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O[/tex]

Regards!

Answer:

3.6124 m/kg

Explanation:

Molality is calculated as moles of solute (mol) divided by kilogram of solvent (kg). Here, we can find these numbers by using the 35.4%, which gives us  35.4 g of H3PO4 and 100 g of solution to work with.

To go from grams to moles for the phosphoric acid, you need to find the molar mass of the compound or element and divide the grams of the compound or element by that molar mass.

Here, the molar mass for phosphoric acid is 97.9952 g/mol. The equation would look like this:

35.4 g x 1 mol / 97.9952 g = 0.3612422 mol

Next, the 100 g of solvent can easily be converted to 0.1 kg of solvent.

To find the molality, divide the moles of solute and kilograms of solution.

0.3612422 mol / 0.1 kg = 3.6124 m/kg

Copper has a density of 8950 kg/m3 = 8.95 kg/dm3 = 8.95 g/cm3. Water has a density of 1000 kg/m3 = 1000 g/L = 1 kg/dm3 = 1 kg/L = 1 g/cm3 = 1 g/mL.

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Answer: The excess weight of the luggage is 15.5 kg and its percentage is 77.5%

Explanation:

Given values:

Maximum amount of luggage allowed = 20 kg

Amount of luggage man is carrying = [3.5 + 15 + 2 + 15] kg = 35.5 kg

Excessive weight of the luggage carried = Amount of luggage carrying - Maximum amount of luggage allowed

Excessive weight of the luggage carried = [35.5 - 20] = 15.5 kg

To calculate the percentage of excess weight, we use the equation:

[tex]\% \text{excess weight}=\frac{\text{Excess weight carried}}{\text{Maximum allowed}}\times 100[/tex]

Putting values in above equation, we get:

[tex]\% \text{excess weight}=\frac{15.5kg}{20kg}\times 100\\\\\% \text{excess weight}=77.5%[/tex]

Hence, the excess weight of the luggage is 15.5 kg and its percentage is 77.5%

Answer:

matter i think

Explanation:

matter i am pretty sure

The law that allows calories to be determined by heat (energy) transfer from one substance to another, but it is never destroyed is first law of thermodynamics.

Energy cannot be generated or destroyed, only changed in form, according to the basic law of thermodynamics.

Hence first law of thermodynamics justify the given statement.

To know more about thermodynamics, visit the below link:
https://brainly.com/question/26035962

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Answer:

Explanation: hell noo

Answer: The absorbance for a solution is 0.0028

Explanation:

To calculate the absorption of a solution, the equation by Beer-Lambert law is used:

[tex]A=\varepsilon \times b\times C[/tex]

OR

[tex]A=\varepsilon \times b\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex]

where,

A = absorbance = ?

[tex]\varepsilon[/tex] = molar absorptivity = [/tex]15000m^2mol^{-1}L[/tex]

b = path length = 1 cm = 0.01 m                 (Conversion factor: 1 m = 100 cm)

Given mass of [tex]\beta-[/tex] carotene = 0.1 mg = 0.0001 g     (Conversion factor: 1 g = 1000 mg)

Molar mass of [tex]\beta-[/tex] carotene = 536 g/mol

Volume of solution = 10 mL

Putting values in equation 1:

[tex]A=15000\times 0.01\times \frac{0.0001\times 1000}{536\times 10}\\\\A=0.0028[/tex]

Hence, the absorbance for a solution is 0.0028

Answer:

ethyl ethanoate and water

Explanation:

At the point when one fluid doesn't blend in with another yet glides on top of it, an isolating pipe can be utilized to isolate the two fluids. Oil glides on water. This combination can be isolated utilizing an isolating channel as demonstrated on the following page.  

Ethyl liquor and water are two miscible fluids.   Refining is a cycle that can be utilized to isolate an unadulterated fluid from a combination of fluids. An isolating channel can be utilized to isolate the parts of the combination of immiscible fluids.

The answer is ethyl ethanoate and water. Hope this helps you!

A substance will react with oxygen to form water and carbon. ... dioxide.

Answer:

it will rain and there the other defined for precipitation snow and sleet and hail

Explanation:

Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.

H2 CO3 (acid)↔H+ + HCO3- (base)

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Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:

We input the given data:

And solve for n:

Finally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:

Answer:

Malachite

Explanation:

Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!

Answer:

[tex]V_l=67mL[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=375mL[/tex]

Final Volume [tex]V_2=308mL[/tex]

Generally the equation for Left-Over is mathematically given by

 [tex]V_l=V_1-V_2[/tex]

 [tex]V_l=375-308[/tex]

 [tex]V_l=67mL[/tex]

Answer: Hello the reaction related to your question is missing attached below is the reaction

answer : attached below

Explanation:

The structure of the neutral organic product formed in the reaction is attached below.

The neutral organic product formed is ESTER

The reaction in the question is Anhydride on reaction with alcohol

Answer:

the representative elements are elements where the the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3-11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.

Explanation:

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Answer: el texto no es tan claro

Answer:

1. B

2.B

3.B

4.C

5.C

Explanation:

I hope this help you

Answer:

The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.

Their classification of primary, secondary, and tertiary alcohols are -

1-pentanol -

2-pentanol -

3-pentanol

2-methylbutan-1-ol

2-methylbutan-2-ol

3-methylbutan-2-ol

3-methylbutan-1-ol

2,2-dimethylpropanol

Answer:

Explanation:

The information below explains how dehydration of alcohol occurs to produce alkene.

Under the influence of a catalyst, alcohol dehydrates to produce an alkene and water. To produce alkene and water, the reaction eliminates the OH group from alcohol containing the carbon atom and the hydrogen atom from a neighboring carbon atom via the same molecule.

The –OH group in alcohol contribute two(2) electrons to H+ out from the acid reagent, resulting in the formation of an alkyloxonium ion. This ion serves as an excellent leaving group, allowing a carbocation to form. The nucleophile which acts as the deprotonated acid subsequently attacks and creates a double bond with the hydrogen next to the carbocation.

Answer:

The pH of pure water (H20) is 7 at 25oC, but when exposed to the carbon dioxide in the atmosphere this equilibrium results in a pH of approximately 5.2. Because of the association of pH with atmospheric gasses and temperature, it is strongly recommended that the water be tested as soon as possible.

Answer:

For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column

Answer:

0.8853 mL

Explanation:

First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:

Then we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:

Finally we calculate the required mL of suspension, using its concentration:

Answer: Sodium element has 1 valence electron and chlorine element has 7 valence electrons.

Explanation:

Valence electrons are defined as the electrons that are present in the outermost shell.

An ionic compound is formed when the complete transfer of electrons takes place from one element (usually metals) to another element (usually non-metals).

To know this, we need to write the electronic configuration of each element.

Sodium is the 11th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^1[/tex]

It has 1 valence electron

Chlorine is the 17th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^23p^5[/tex]

It has 7 valence electrons

Hence, sodium element has 1 valence electron and chlorine element has 7 valence electrons.

Answer:

Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option observations conclusions reaction ΔΗ is (pick one) The reverse of this reaction is always spontaneous. A As is (pick one) This reaction is spontaneous except below ΔΗ is (pick one) 38. °C but proceeds at a faster rate above (pick one) 91. °C As is ΔΗ iS (pick one) Crystallization of a pure compound is C spontaneous only below 146. °C. AS is (pick one) X