report of "fan made of plastic bottle" with string

Answer:

s=0.204m

Explanation:

Assuming that the arrow is thrown horizontally and there is no air resistance, we can use the following formula to calculate the launch angle 0:

tan(0) = opposite/adjacent = height/distance

where opposite is the height that the arrow reaches and adjacent is the distance to the balloon.

Rearranging the formula, we get:

0 = arctan(height/distance)

0 = arctan(height/3)

Taking the tangent of both sides, we get:

tan(0) = tan(arctan(height/3))

tan(0) = height/3

Now, we need to find the height of the arrow. Using the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (0m/s, at maximum height), u is the initial velocity (2m/s), a is acceleration (-9.8m/s^2, due to gravity) and s is the distance travelled vertically until the arrow reaches maximum height.

At maximum height, the final velocity is 0m/s. Therefore, we have:

0 = (2m/s)^2 + 2(-9.8m/s^2)s

Solving for s, we get:

s = 0.204m

Therefore, the height of the arrow is approximately 0.204m.

The images that shows the terms have been attached to this answer.

What does the terms mean?

A  crest refers to the highest point or peak of a wave. It represents the maximum positive displacement or upward excursion of the wave from its rest position.

A trough is the maximum negative displacement or downward excursion of the wave from its rest position.

The amplitude of a wave refers to the maximum displacement or distance from the rest position to either the crest or the trough.

The wavelength is the  distance between two adjacent crests or two adjacent troughs. In other words, it is the length of one complete wave cycle.

Period is the the duration between two corresponding points in a wave, such as two adjacent crests or troughs passing a fixed point.

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The examples of light behaving like an electromagnetic wave are Compton scattering, interference through two slits, diffraction through one slit, and refraction.

Light is a type of electromagnetic radiation that is composed of electromagnetic waves. Light behaves like an electromagnetic wave in several ways. Electromagnetic waves are transverse waves that travel through a vacuum. They don't need a medium to propagate. Light can behave like an electromagnetic wave in several ways. Let's discuss each option in the question.
Compton scattering: Compton scattering is a phenomenon in which an incident X-ray or gamma-ray photon collides with an electron resulting in a scattered photon and a recoiling electron. It can only be explained by assuming that light behaves as both waves and particles. Therefore, Compton scattering is an example of light behaving like an electromagnetic wave.
Interference through two slits: When light passes through two narrow slits separated by a distance that is small compared to the wavelength of the light, it will diffract and interfere. The interference pattern will be characterized by bright and dark fringes. This phenomenon is an example of light behaving like an electromagnetic wave.
Diffraction through one slit: When light passes through a single narrow slit, it diffracts and creates an interference pattern similar to that produced by two slits. This phenomenon is an example of light behaving like an electromagnetic wave.
Photoelectric effect: The photoelectric effect is a phenomenon in which electrons are ejected from a metal surface when light shines on it. The photoelectric effect can be explained by assuming that light behaves as a stream of particles or photons. Therefore, the photoelectric effect is not an example of light behaving like an electromagnetic wave.
Refraction: Refraction is the bending of light as it passes from one medium to another, such as from air to water. It can be explained by assuming that light behaves like an electromagnetic wave. Therefore, refraction is an example of light behaving like an electromagnetic wave.

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Answer:

I think its could be C

Explanation:

I think c because it makes the most sense and seems logical

The distance to the star in parsecs is given as 20 pc.

Using the absolute magnitude (M) and apparent magnitude (m) relation, we can find the star's apparent magnitude:

m - M = -5 + 5 log(d)

where d is the distance to the star in parsecs.

Plugging in the values we have, we get:

m - (-0.66) = -5 + 5 log(20)

m = 3.34

Therefore, this star's apparent magnitude is 3.34.

The star's luminosity is 160 times that of the Sun.

Using the Stefan-Boltzmann law, we can find the star's radius:

L = 4πR²σT⁴

where L is the luminosity, R is the radius, σ is the Stefan-Boltzmann constant, and T is the surface temperature.

We can write the ratio of the star's luminosity to that of the Sun as:

L/Lsun = (R/Rsun)²(T/Tsun)⁴

Plugging in the values we have, we get:

160 = (R/Rsun)²(4000/5800)⁴

Solving for R, we get:

R = 10.7 R⊙

Therefore, this star's radius is 10.7 times that of the Sun.

Using Wien's law, we can find the wavelength at which the star radiates the most energy:

λmax = 2.898 × 10⁶ / T

Plugging in the values we have, we get:

λmax = 724.5 nm

Therefore, this star radiates most of its energy at a wavelength of 724.5 nm.

The star's surface temperature is 4000 K.

Using the Harvard spectral classification system, we can find the star's spectral class based on its surface temperature:

O B A F G K M
50,000 10,000 7500 6000 5200 3700 2400

The star's surface temperature falls in the range of a K-type star.

Therefore, this star's spectral class is K.

Finally, we can use the definition of parallax to find the star's parallax:

p = 1/d

where p is the parallax in arcseconds and d is the distance to the star in parsecs

The given statement, "A precondition for perfect competition is that the product should be homogeneous" is true.

Perfect competition is a market structure in which numerous small firms compete against each other with identical or homogeneous products, and no one firm can influence the market price independently.

In a perfectly competitive market, there is free entry and exit of firms, perfect knowledge of the market, and no barriers to entry.What does homogeneous mean?Homogeneous products refer to goods or services that are identical or very similar in nature and have the same level of quality and features. Examples of homogeneous products include agricultural goods, basic raw materials, commodities, and so on.

In perfect competition, all firms offer identical products to customers. Homogeneous products are essential to ensure that no single firm has an advantage over others in terms of quality or price. If there were differences in quality or price, customers would prefer to buy from the firm with the lowest price or highest quality. This would give that firm a competitive advantage over others in the market.

As a result, it would no longer be a perfectly competitive market, since one firm could influence the market price independently. Therefore, the precondition for perfect competition is that the product should be homogeneous, which means that all firms should offer identical or very similar products to their customers.

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The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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For the beam and loading shown below (a), (b), and (c),

(a) draw the shear and bending-moment diagrams,

(b) determine the maximum absolute values of the shear and bending moment.

(a)